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024

Case 024Hedging with futuresCore

An airline hedging 60,000 tonnes of jet fuel with 1,000-barrel crude futures gets a regression of jet fuel price changes on crude futures changes: slope 0.71, standard error 0.08, R-squared 0.64, 36 observations. Read it, set the hedge, and say how much risk it removes.

Wolverine TradingChicago · 2016

1The situation

Zanskar Airways will buy 60,000 tonnes of jet fuel over the next quarter at market prices. There is no liquid jet fuel future, so treasury plans to hedge with crude oil futures of 1,000 barrels each; treat one tonne of jet fuel as 7.9 barrels.

An analyst has regressed the monthly change in the jet fuel price on the monthly change in the crude futures price, both in rupees per barrel, over the last three years. The output shows an intercept of 0.42 with a standard error of 1.10, a slope of 0.71 with a standard error of 0.08, an R-squared of 0.64 and 36 observations.

2Your task

Which numbers in the output matter for the hedge, how many contracts does the airline trade and on which side, how much of the price risk does that remove, and how confident can treasury be in the number?

Quick check

Before computing: an R-squared of 0.64 means the hedge cuts the standard deviation of fuel cost by how much?

Worked solution

Try it on paper, then open one step at a time.

30-second answerThe answer to give first

Buy 337 crude futures: 0.71 times 474,000 barrels of exposure is 336,540 barrels, 336.5 contracts of 1,000. The slope is the minimum-variance hedge ratio, and the R-squared of 0.64 says the hedge removes 64% of the variance of fuel cost, which cuts its standard deviation by 40%. The standard error of 0.08 puts the ratio between about 0.55 and 0.87, or 260 to 414 contracts, but the variance left barely changes across that range. The intercept does not enter the hedge.

Step 1Which numbers in the output matter?

Think of a tailor fitting a suit from a customer's measurements: three numbers matter, and the rest of the form is filing. The slope, 0.71, is the minimum-variance hedge ratioThe number of units of a futures contract per unit of exposure that makes the variance of the hedged position as small as possible. It equals the regression slope of exposure price changes on futures price changes.: on average, jet fuel moves 0.71 rupees for each rupee crude futures move, so each barrel of fuel needs 0.71 barrels of futures. The R-squared, 0.64, is the share of the variance of jet fuel changes that crude explains, which is the share the hedge can remove. The standard error, 0.08, says how precisely the slope is known. The intercept, 0.42 with a standard error of 1.10, is a drift in jet fuel that crude does not explain; it is statistically zero and plays no part in the hedge.

Read three numbers from the output, then the hedge is one line of arithmeticRegression: d(jet fuel) on d(crude future), monthlyObservations36R-squared0.640Adj R-squared0.629CoefStd errtIntercept0.4201.1000.38d(crude)0.7100.0808.88slope 0.71: hedge ratio, futures per unitstd err 0.08: the ratio is 0.55 to 0.87 at 95%R-squared 0.64: share of variance hedgedThe intercept is not used: the hedge is on changes.The hedgeExposure60,000 t x 7.9 = 474,000 bblFutures per barrel0.71Barrels to hedge0.71 x 474,000 = 336,540Contracts of 1,000 bbl336.5, so buy 337Variance removed64%Std dev of cost cut by1 - sqrt(0.36) = 40%
The output gives the slope, 0.71, its standard error, 0.08, and the R-squared, 0.64; the hedge is 0.71 times 474,000 barrels over 1,000 barrels a contract, 336.5, so the airline buys 337 contracts and removes 64% of the variance of its fuel cost.
Step 2How many contracts, and on which side?
The relationship
N=h×QqF=0.71×60,000×7.91,000=336.54≈337N = h \times \frac{Q}{q_F} = 0.71 \times \frac{60{,}000 \times 7.9}{1{,}000} = 336.54 \approx 337
hthe hedge ratio, the regression slope 0.71
Qthe exposure in barrels, 60,000 tonnes times 7.9
q_Fbarrels per futures contract, 1,000
What it says in wordsScale the exposure by the slope and divide by the contract size: 336.5 contracts, rounded to 337.

The airline buys fuel, so it loses when prices rise and needs a position that gains when they rise. It buys 337 crude futures: the exposure is 60,000 times 7.9, 474,000 barrels, the slope scales that to 336,540 barrels of crude, and at 1,000 barrels a contract that is 336.5. A one-for-one hedge of 474 contracts sounds safer and is not: because crude futures move more than jet fuel relative to their correlation, over-hedging adds crude risk back. The table puts the three choices side by side, using the correlation of 0.8 and the ratio of volatilities the slope implies.

HedgeContractsVariance leftStd dev left
None0100%100%
Minimum variance, h = 0.7133736%60%
One for one, h = 1.047446.7%68.3%
Low end of the 95% range, h = 0.5526039.3%62.7%
High end of the 95% range, h = 0.8741439.3%62.7%
The 337-contract hedge leaves 36% of the variance and 60% of the standard deviation of fuel cost; a one-for-one hedge of 474 contracts leaves 46.7% of the variance, and anywhere in the slope's 95% range leaves no more than about 39%.
Step 3How much risk does it remove, and how sure can treasury be?

The hedge removes 64% of the variance of fuel cost, which means the standard deviation falls to the square root of 0.36, 60% of its unhedged level, a 40% cut. Treasury should report the 40%, because budgets are discussed in rupees, not squared rupees. The slope's t-statistic is 0.71 over 0.08, about 8.9, so the relationship is not in doubt, but the 95% range of the slope runs from about 0.55 to 0.87, 260 to 414 contracts. That sounds like a wide range for a hedge; the figure shows why it matters less than it looks. The variance left is a U-shaped curve with a flat bottom, so a hedge ratio anywhere in that range leaves between 36% and about 39% of the variance.

Variance left against hedge ratio: a flat-bottomed U with its low at 0.7125%50%75%100%0.00.20.40.60.81.01.21.4hedge ratio (futures barrels per barrel of fuel)variance of fuel cost left0.71: 337 contracts, 36% left1.0: 474 contracts,46.7% leftno hedge: 100% leftShaded bandslope 0.55 to 0.87,260 to 414 contractsvariance left staysbetween 36% and 39%the bottom is flat, so theestimate error costs little
The share of fuel cost variance left falls from 100% with no hedge to 36% at a ratio of 0.71 and rises to 46.7% at one for one, and across the slope's 95% range of 0.55 to 0.87 it stays at or under about 39%, so the estimate error costs little.

Say the limits. The regression is on three years of monthly data, and the relationship between jet fuel and crude moves with refinery margins, which can widen sharply in a supply shock exactly when the airline most needs the hedge; 36% of the variance, the crack spread, stays unhedged. The hedge is set on monthly changes, while the airline buys fuel through a quarter, so the hedge should be layered across the purchase dates rather than closed at once. The conversion of 7.9 barrels a tonne is an average that varies with density. And futures are margined daily: a fall in crude means cash calls on the futures while the cheaper fuel saves money only later. The judgement: buy about 337 contracts, report a 40% cut in cost volatility, and say plainly that the crack spread is the risk left.

Where candidates lose it

Candidates read R-squared as the cut in risk and promise the CFO that the hedge removes 64% of fuel cost volatility. It removes 64% of the variance; the standard deviation, which is what a budget feels, falls by 40%.

The second loss is hedging one for one, 474 contracts, because the airline wants to be fully covered. That leaves more variance than the 337-contract hedge, because the extra contracts add crude risk the airline does not have.

What the interviewer asks next

  • The analyst reruns the regression on daily data and gets a slope of 0.52 with an R-squared of 0.41. Which do you use for a quarterly hedge, and why?
  • Brent and a gasoil future are both available. How would you decide between them, or use both?
  • The airline wants to hedge only rises in fuel price. What would that cost, and how would you size it?
  • Why would you regress price changes rather than price levels?

Asked at Wolverine Trading, Prop Trading, Chicago, 2016 (Wall Street Oasis): minitab output, but could've been another statistical software output and you were asked to identify to things from that output

← Case 023An exporter sold USD 2 million forward at 83.60 for this week, but the buyer will pay a month late. Spot is 84.40 and one-month forward points are plus 0.25. Cancel and rebook: what is the cash flow today, and what effective rate is achieved?Case 025 →An options desk is short gamma of 8,000 shares per rupee on a Rs 400 stock, delta hedged, when news gaps it 8% to Rs 432. Implied volatility jumps from 30% to 38% and vega is minus Rs 1.5 lakh a point. Estimate the loss, the new delta, and what you do in the next ten minutes.

Company names and figures are illustrative.

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