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Derivatives Foundation interview preparation

The full derivatives syllabus from no-arbitrage pricing through the Greeks, the volatility surface, swaps, CDS and clearing, plus the Indian index-options market. Every question is either traced to a named firm from a public candidate report, or tagged at desk level when we could not trace it - we do not invent attributions.

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Question bank

100 questions, mapped to the firms that asked them

Questions
100
Traced to a firm
29
Firms
19
Updated
September 2026
Asked at
All firmsMSMorgan Stanley4Nomura4Akuna Capital2Amundi2HSBC2PIMCO2Bank of America1Barclays1Citadel1DRW1Goldman Sachs1Jane Street1Millennium Management1Mizuho1Old Mission Capital1RCRBC Capital Markets1Scotiabank1UBS1Wells Fargo Securities1
Topic
All topicsForwards and futures10Options basics8Option pricing7The Greeks10Volatility7Option strategies9Swaps and rates7Credit derivatives4Market structure and clearing6Indian derivatives8Trading and markets9Brainteasers6Fit9
Level
AnyCoreIntermediateHard
Type
AnyTechnicalCaseMarket viewBrainteaserFit
Showing 1–4 of 4 · filtered from 100Clear filters
  1. 019Explain how you would price an option.Option pricingIntermediatetechnicalDRWQuantitative Trading · Chicago · 2025

    Say this

    By replication, not by forecasting. I build a portfolio of the underlying and cash that reproduces the option's payoff in every state, and the option has to cost what that portfolio costs, or there is an arbitrage. Everything else — binomial trees, Black-Scholes, Monte Carlo — is just machinery for doing that in different settings.

    Then walk it

    1. Start with the simplest case, one period, two states. If the stock goes to 110 or 90 and I hold a 100-strike call, I can find a number of shares and a cash amount that pays exactly 10 in the up state and 0 in the down state. That portfolio's cost today is the option price.
    2. The striking thing is that the real probabilities never appear. They cancel, because I am hedging rather than betting. That is why the answer is the same whether you think the stock is going up or down, and it is the single most important idea in the subject.
    3. Equivalently, discount the expected payoff under the risk-neutral measure, where the underlying is assumed to drift at the risk-free rate. Same number, and easier to compute.
    4. Take that to many small steps and it becomes the binomial tree; take the limit and you get Black-Scholes, a closed form for a European option on a lognormal underlying. For a path-dependent payoff you simulate instead, and for an American feature you need a tree or a backward induction so you can test early exercise at every node.
    5. Then the practical part, which is where the real work is. The only unobservable input is volatility, so in practice the model is run backwards: I take the market price and solve for implied volatility, then trade the volatility rather than the price.
    6. And the limitation up front: replication assumes continuous hedging with no transaction costs and no gaps. In the real world I hedge discretely and pay spread, so my realised profit and loss is implied minus realised volatility, less the cost of hedging — which is why a theoretically fair option can still lose money.

    Where candidates lose it

    Leading with the Black-Scholes formula. DRW and every prop shop are asking whether you understand replication and risk-neutral valuation, not whether you can recall a closed form. If you cannot explain why the real-world probability drops out, you have not answered the question.

    Expect next

    • Why do the real-world probabilities disappear?
    • Now price it in a two-step tree and tell me what changes.
    • What is the one input you cannot observe, and what do you do about it?

    Reported by candidates at DRW (Quantitative Trading, Chicago, 2025). Source: Wall Street Oasis.

  2. 021Explain Black-Scholes.Option pricingIntermediatetechnicalGoldman SachsWealth Management · Zurich · 2025

    Say this

    It is a closed-form price for a European option, derived from the insight that an option can be perfectly hedged with the underlying. If you can hedge it, its price cannot depend on your view or on risk appetite — only on volatility, time, rates and the distance to the strike. The formula is the answer to that hedging argument, not a forecasting model.

    Then walk it

    1. The derivation in one line: build a portfolio that is long the option and short delta of the stock, and the random term cancels. What is left grows at the risk-free rate, and imposing that gives a differential equation whose solution is the formula.
    2. In words, the call price is the discounted expected payoff under a lognormal distribution: spot times N of d1, less the discounted strike times N of d2. N of d2 is roughly the risk-neutral probability of finishing in the money; spot times N of d1 is the expected value of the stock you receive if you do.
    3. So the inputs are spot, strike, time, rate, dividend and volatility. Five are observable. Volatility is not, which means in practice the formula is used inverted — you put the market price in and read the implied volatility out.
    4. That is its real job on a desk. Nobody believes the assumptions. It is a translation device that turns option prices in dollars into a single comparable number in volatility terms, so you can compare a one-month Nifty option with a two-year S&P option on the same axis.
    5. For a private client I would put it plainly: the formula prices the insurance. The further out of the money, the shorter the time and the calmer the market, the cheaper the insurance — and the fair price of that insurance is what the model gives you.
    6. The limitation, said before being asked: it assumes constant volatility and continuous, costless hedging, and it assumes prices do not jump. All three are false, which is why the market charges a different implied volatility for every strike. That pattern is the volatility smile, and it is the market's way of correcting the model.

    Where candidates lose it

    Writing out the formula and naming the terms without ever saying why the hedging argument removes the drift. And on a wealth management desk specifically: if you cannot restate it in one plain sentence about the price of insurance, you have failed the actual test, which was whether you can explain it to a client.

    Expect next

    • Which assumption fails worst in practice?
    • What does N of d2 actually represent?
    • If nobody believes the assumptions, why is it still on every screen?

    Reported by candidates at Goldman Sachs (Wealth Management, Zurich, 2025). Source: Wall Street Oasis.

  3. 022List the Black-Scholes assumptions and tell me where each one fails.Option pricingHardtechnicalQuant tradingRisk management

    Say this

    Six that matter: lognormal returns with constant volatility, continuous trading with no transaction costs, no jumps, a constant known risk-free rate, no dividends or a known continuous yield, and European exercise. Every one of them fails, and the market patches each failure in a different way — which is why the volatility surface has the shape it does.

    Then walk it

    1. Constant volatility fails first and worst. Volatility clusters and mean-reverts, so a single number cannot price every strike and maturity. The market's patch is to quote a different implied volatility per strike and expiry, which is the smile and the term structure.
    2. Lognormality fails in the tails. Real return distributions are fat-tailed and negatively skewed — a 5 standard deviation daily move should be a once-in-millennia event and happens every few years. The patch is the skew: out-of-the-money puts trade at higher implied volatility because the model underprices crashes.
    3. No jumps fails on any event date. A takeover or an earnings gap moves price discontinuously, so a delta hedge does not protect you through it. The patch is jump-diffusion and local-volatility models, and in practice a trader simply pays up for gamma into events.
    4. Continuous costless hedging fails always. You hedge at discrete intervals and pay bid-offer, so your realised profit and loss has a hedging error term whose size scales with your rebalance frequency. The patch is to widen the spread you quote.
    5. Constant rates and known dividends fail on long-dated equity options, where dividend uncertainty is a first-order risk and you need a stochastic rate model. For short-dated index options neither matters much.
    6. And European exercise fails for single-stock American options, where dividends make early exercise rational. That needs a tree or a numerical method, not a formula. The meta-point: Black-Scholes is used as a quoting convention rather than a belief, and the smile is the accumulated record of everywhere it is wrong.

    Where candidates lose it

    Listing assumptions without connecting each to an observable market feature. The strong version of this answer says 'fat tails plus no jumps equals the skew you see on the screen'. If you cannot link the failure to the smile, you are reciting a textbook page.

    Expect next

    • Which single assumption would you relax first if you were building a pricer?
    • So is the smile a model failure or market information?
    • How does discrete hedging show up in your profit and loss?
  4. 023What do d1 and d2 actually mean in Black-Scholes?Option pricingHardsuperdayQuant tradingProp trading firms

    Say this

    N of d2 is the risk-neutral probability the option finishes in the money. N of d1 is the delta of the call, and it is also the probability of finishing in the money under a measure where the stock, rather than cash, is the numeraire. The gap between them, which is the volatility times root time, is why delta is not the same as the probability of exercise.

    Then walk it

    1. Read the formula as two pieces. The discounted strike times N of d2 is what you expect to pay, weighted by the chance you pay it. Spot times N of d1 is what you expect to receive, and it has to be weighted by the value of the stock conditional on exercise, not just the chance of it.
    2. That conditioning is the whole distinction. When the option finishes in the money, the stock is on average higher than its unconditional expectation, so the receipt leg needs a bigger weight. Hence d1 exceeds d2 by sigma root t.
    3. d2 equals the log of forward over strike, minus half the variance, all divided by sigma root t. It is a standardised distance to the strike measured in volatility units — a z-score.
    4. N of d1 being the delta is not a coincidence, it is the hedging argument: the number of shares you hold equals the probability-weighted claim on the stock.
    5. Useful desk consequence: a 25-delta option does not have a 25 percent chance of expiring in the money. For a call the probability is lower than the delta, and the gap widens with volatility and maturity. Retail traders systematically get this wrong when they size positions off delta.
    6. The caveat: all of this is under the risk-neutral measure, so N of d2 is not the real-world probability of exercise. Real-world probability needs the actual drift, which nobody knows. Quoting risk-neutral probabilities as real ones is the standard error.

    Where candidates lose it

    Calling N of d1 a probability without saying under which measure, or claiming delta is the chance of expiring in the money. The interviewer is specifically testing whether you know delta and probability of exercise are different numbers, and why.

    Expect next

    • So is a 25-delta call's probability of exercise higher or lower than 25 percent?
    • Why is d1 greater than d2 by exactly sigma root t?
    • Is N of d2 the real-world probability of exercise?

Firm tags come from public, anonymous candidate reports on Wall Street Oasis: strong signal, not sworn testimony. Firms are named as the places a question was reported, not as partners of Fin Maverick. Answers are written for this page to show how to think out loud; they are not scripts to recite.

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