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  1. 058A market maker knows that 30% of the orders she receives come from traders who know the true value is exactly Rs 1 above or below the mid. The other 70% are uninformed and buy or sell at random. How wide must her bid-ask spread be just to break even?Market making and trading gamesCoreProp and quant trading firmsVolatility and relative value funds

    Try it first

    How wide must the full spread be?

    Show the worked solution

    The spread must be Rs 0.60: a bid Rs 0.30 below the mid and an offer Rs 0.30 above it. Call the half-spread s. Each uninformed order earns her s on average. Each informed order trades on the side where the value really is Rs 1 away, so she loses 1 minus s. Breaking even needs 0.7s = 0.3(1 - s), which gives s = 0.30.

    Why do some of the people who trade with you cost you money?

    A shop that buys second-hand phones pays the same price to every seller, but the sellers who know their phone is faulty are the keenest to sell. A quote is an offer made to everyone, and the people who know more take it only when it hurts you. The spread is the fee charged to the whole crowd to pay for the few who know more, which is called adverse selectionThe tendency for the counterparties who choose to trade with you to be the ones who know the trade is good for them..

    How do you set up the break-even?

    Charge a half-spread s on each side. An uninformed order is as likely to be a buy as a sell and carries no information, so on average it earns you s; an informed order buys at your offer only when the value is Rs 1 above the mid, so it costs you 1 minus s. Weight each by how often it arrives and set the total to zero: 0.7s - 0.3(1 - s) = 0, so s = 0.30 and the spread is Rs 0.60.

    The relationship
    0.7 s=0.3 (1−s)  ⇒  s=0.30,spread=2s=0.600.7\,s = 0.3\,(1 - s) \;\Rightarrow\; s = 0.30, \qquad \text{spread} = 2s = 0.60
    sthe half-spread, the distance from the mid to the bid or the offer
    0.7the share of orders from uninformed traders
    1 - swhat an informed trade takes: the Rs 1 value gap less the half-spread crossed
    What it says in wordsThe spread earned from uninformed flow must pay for the expected loss to informed flow.
    Expected profit per order: what uninformed flow pays, what informed flow takesHalf-spread Rs 0.20, spread Rs 0.40+0.14-0.24-0.10uninformed70% x 0.20informed30% x 0.80net per orderlossHalf-spread Rs 0.30, spread Rs 0.60+0.21-0.210.00uninformed70% x 0.30informed30% x 0.70net per orderbreak even
    At a half-spread of Rs 0.20 she earns Rs 0.14 an order from uninformed flow but loses Rs 0.24 to informed flow, a loss of Rs 0.10; at Rs 0.30 she earns and loses Rs 0.21 each, the break-even spread of Rs 0.60.

    What moves the spread?

    Two things: how much of the flow is informed and how much the informed know. In general the half-spread is s = aV, where a is the informed share and V is how far the true value sits from the mid, so doubling either doubles the spread. Here 0.3 x 1 = 0.3. That is why quotes widen ahead of a results announcement, when more of the flow may know something, and in small stocks, where one piece of news moves the value a long way. The model leaves out inventory risk and competing quoters, both of which move a real spread; say so.

    Where candidates lose it

    The common slip is answering Rs 0.30, which is the half-spread, or quoting a width without saying where the bid and offer sit. Name both sides: bid at the mid minus 0.30, offer at the mid plus 0.30.

    The deeper loss is charging each informed trade the full Rs 1 and forgetting that the informed trader also crosses the spread, which gives 0.7s = 0.3 and s of about 0.43. Her loss to an informed order is the value gap less the half-spread.

    What the interviewer asks next

    • Half the flow is now informed. What spread breaks even?
    • You receive three buy orders in a row. Should you move your mid, and which way?
    • A rival quotes Rs 0.40 wide. What happens to the mix of flow you receive?
  2. 059A stock trades at Rs 1,000 and pays no dividend. A six-month European call struck at Rs 1,000 costs Rs 60 and the matching put costs Rs 45. Six-month simple interest is 3%. Is there an arbitrage, and how do you lock it in?Options and payoffsCoreVolatility and relative value fundsProp and quant trading firms

    Try it first

    What should the call minus the put be worth?

    Show the worked solution

    Yes: buy the call, sell the put, short the stock and lend Rs 970.87, which collects about Rs 14.13 today with nothing owed at expiry. Put-call parity says the call less the put should equal the stock less the present value of the strike, 1,000 minus 1,000/1.03, about Rs 29.13. The market prices that gap at Rs 15, so the call is cheap against the put by about Rs 14.

    What does a call minus a put actually pay?

    Imagine agreeing today to buy a used car in six months at a fixed price. If car prices rise you gain the difference; if they fall you lose it. A long call with a short put at the same strike does exactly that: at expiry it pays the stock price minus the strike, whichever way the stock moved. So it must cost the same as buying the stock today with money borrowed against the strike, 1,000 minus 970.87, which is Rs 29.13. That identity is put-call parityFor European options on the same stock, strike and expiry, call minus put equals the stock price minus the present value of the strike, less the value of any dividends..

    The relationship
    C−P=S−K1+r=1,000−1,0001.03≈29.13C - P = S - \frac{K}{1 + r} = 1{,}000 - \frac{1{,}000}{1.03} \approx 29.13
    C, Pthe call and put prices, Rs 60 and Rs 45
    Sthe stock price today, Rs 1,000
    Kthe strike, Rs 1,000
    rsix-month simple interest, 3%
    What it says in wordsA call less a put is worth the stock less the strike discounted to today.

    How do you build the trade?

    Buy what is cheap and sell what is dear. The option version of the forward, long call and short put, costs Rs 15; the cash version, long stock bought with borrowed money, is worth Rs 29.13, so buy the option version and sell the cash version. Buy the call for 60, sell the put for 45, short the stock for 1,000 and lend 970.87 at 3%. The cash left over today is Rs 14.13, worth about Rs 14.55 at expiry.

    At expiry the four legs cancel; the profit was collected on day one-200-100+100+20008009001,0001,1001,200Stock price at expiry, Rslong call + short put = stock - 1,000short stock + loan repaid = 1,000 - stocknet: 0 at every priceCash today, RsBuy the call-60.00Sell the put+45.00Short the stock+1,000.00Lend PV of strike-970.87Collected today+14.13Fair call - put = 29.13Market: 15. Gap 14.13
    At expiry the long call and short put pay the stock price minus Rs 1,000 while the short stock and the maturing Rs 1,000 loan pay Rs 1,000 minus the stock price, so the package nets to zero at every price and the Rs 14.13 collected at the start is kept.

    What could stop the arbitrage working?

    Say what you assumed. The lock holds only if the options are European, the stock pays no dividend before expiry, and you can short the stock without a borrowing fee that eats the Rs 14. A dividend lowers the forward and so the fair gap; an American put can be exercised against you early; a hard-to-borrow stock charges a fee. A gap this size in a liquid name usually means one of those is present, so your first question back is which one.

    Where candidates lose it

    The common loss is comparing the call and the put directly, seeing the call is dearer and deciding it must be the one to sell. Parity says the call should be dearer, by about Rs 29; the trade depends on whether the actual gap is too wide or too narrow.

    The second is forgetting to discount the strike and calling zero fair, or using 3% of the stock, Rs 30, which is close but wrong. Say the formula before the numbers, then build the four legs.

    What the interviewer asks next

    • The stock will pay a Rs 20 dividend before expiry. Is there still an arbitrage, and which way?
    • The call is Rs 80 and the put Rs 45. What trade do you put on now?
    • Why does parity hold exactly for European options but only as a band for American ones?
  3. 061How many flips of a fair coin do you expect to need before you see two heads in a row? Why is the answer different if you wait for a head followed by a tail?Random walks and Markov chainsCoreSCSquarepoint CapitalLondon · 2025

    Try it first

    What are the expected waits for HH and for HT?

    Show the worked solution

    Six flips on average for two heads in a row, and four for a head then a tail. Track how far along the pattern you are. For HH, a tail at any point sends you back to the start, including right after a head. For HT, a head after a head keeps you one step away, so progress is never lost. Solving the two small chains gives 6 and 4.

    Why do two equally likely patterns take different times?

    Think of two ladders where a slip costs you differently. On one, slipping from the first rung drops you to the ground; on the other, you can only ever slip back to the first rung. Both patterns are equally likely in any given pair of flips, but after one head the wrong next flip costs you everything for HH and nothing for HT. A head then a tail breaks HH and restarts it; a head then a head is still a perfect start for HT.

    A failed HH attempt sends you home; a failed HT attempt keeps your placeWaiting for H HStartOne HHHH 1/2H 1/2T 1/2T 1/2: back to the startFrom one H: 4Expected: 6 flipsWaiting for H TStartOne HHTH 1/2T 1/2T 1/2H 1/2: still one headFrom one H: 2Expected: 4 flips
    In the HH chain a tail from the one-head state falls back to the start, so the expected wait is 6 flips; in the HT chain a head from the one-head state stays where it is, so progress is never lost and the wait is 4 flips.

    How do you solve the chain?

    Let E0 be the expected flips still needed from the start and E1 after one head. For HH, E0 = 1 + E1/2 + E0/2 and E1 = 1 + E0/2, because a tail from one head sends you back, and these solve to E1 = 4 and E0 = 6. For HT, the one-head state just waits for a tail, which takes 2 flips on average, and reaching the first head takes 2 more, giving 4. Say the states out loud before the algebra; the interviewer wants to hear them named.

    The relationship
    E0=1+12E1+12E0,E1=1+12⋅0+12E0  ⇒  E0=6E_0 = 1 + \tfrac12 E_1 + \tfrac12 E_0, \qquad E_1 = 1 + \tfrac12 \cdot 0 + \tfrac12 E_0 \;\Rightarrow\; E_0 = 6
    E0expected flips still needed from the start
    E1expected flips still needed after one head
    1the flip you are about to make
    What it says in wordsEach state's expected wait is one flip plus the average wait from wherever that flip sends you.

    What is the general pattern?

    Patterns that can fail back to nothing take longer. The expected wait for n heads in a row is 2 to the power n + 1, minus 2: 2, 6 and 14 flips for one, two and three heads. This is a Markov chainA process whose next step depends only on the current state, not on how it got there, so it can be solved state by state. at heart, and the same state-by-state method handles anything that depends on a path: a streak, a barrier, a drawdown rule on a trading book.

    Where candidates lose it

    The usual wrong answer is 4 for both, reached by noting that each pattern has a one-in-four chance in a pair of flips. That treats the flips as separate pairs, which they are not: a pattern can start at any flip, and what happens after a failure depends on the pattern.

    The second loss is setting up one equation instead of two. Name the states, start and one head, and write one equation for each.

    What the interviewer asks next

    • How many flips do you expect to need for three heads in a row?
    • Two players race: one wins at the first HH, the other at the first HT. Who is more likely to win?
    • With a coin that lands heads 60% of the time, how long do you expect to wait for HH?

    Asked at Squarepoint Capital, Quantitative Research, London, 2025 (Wall Street Oasis): statistical problems e.g. # of throws expected to get 2 heads in a row

  4. 063The sample variance computed with n minus 1 in the denominator is an unbiased estimator of the population variance. Is its square root an unbiased estimator of the standard deviation?Statistics and estimationCoreSCSquarepoint CapitalLondon · 2026

    Try it first

    Is the square root of the unbiased sample variance unbiased for the standard deviation?

    Show the worked solution

    No. The square root of the unbiased variance underestimates the standard deviation on average. The square root is concave, so by Jensen's inequality the average of the square roots is below the square root of the average. For normal data with two observations the estimate averages about 0.80 sigma; the bias shrinks as the sample grows, to about 6% at five observations and under 1% at thirty.

    Why does taking a square root break unbiasedness?

    Two square rooms have floor areas of 4 and 16 square metres, so their sides are 2 and 4 metres. Average the areas, 10, and take the root: 3.16 metres. Average the sides instead: 3 metres. Averaging and then taking a square root gives a bigger answer than taking square roots and then averaging, because the square root bends downwards. The sample variance is right on average, so the average of its square roots must fall short of the true standard deviation.

    Average first, then take the root: the curve sits above the chord00.511.520.511.5Variance estimateits square root0.04 gives 0.21.96 gives 1.4root of the average: 1.0average of the roots: 0.8Average sample SD / true SDnormal data, n observationsn = 20.79820.2% lown = 50.9406.0% lown = 100.9732.7% lown = 300.9910.9% low
    Two equally likely variance estimates of 0.04 and 1.96 average to the true variance of 1.0, but their square roots, 0.2 and 1.4, average only 0.8, below the true standard deviation of 1.0, because the square-root curve bends downwards.

    How big is the bias?

    It depends on the sample size and on the distribution. For normal data the expected sample standard deviation is c4 times sigma, with c4 about 0.80 at n = 2, 0.94 at n = 5, 0.97 at n = 10 and 0.99 at n = 30. At n = 2 you can check it directly: the sample standard deviation is the gap between the two draws divided by the square root of 2, and the average gap between two normal draws is 2 sigma over the square root of pi, which leaves the square root of 2/pi, about 0.798.

    The relationship
    E[s]=c4(n) σ<E[s2]=σ,c4(2)=2/π≈0.798E[s] = c_4(n)\,\sigma < \sqrt{E[s^2]} = \sigma, \qquad c_4(2) = \sqrt{2/\pi} \approx 0.798
    sthe square root of the unbiased sample variance
    sigmathe true standard deviation
    c4(n)the correction factor for normal data, below 1 for every n
    What it says in wordsThe average sample standard deviation is a fixed fraction of the true one, and that fraction is below one.

    Does it matter in practice?

    Sometimes. With a year of daily returns the bias is a rounding error; with a handful of monthly returns for a new fund it is not. A manager with five monthly returns has a volatility estimate that averages about 6% too low under normality, which flatters a Sharpe ratioAverage excess return divided by the standard deviation of returns, a measure of return per unit of risk. before anyone has looked at fat tails. Dividing by c4 removes the bias for normal data, but the fix depends on the distribution, so name the assumption. And unbiased is not the same as most accurate.

    Where candidates lose it

    The trap is assuming unbiasedness carries through any function of an estimate. It carries through straight-line transformations only; the square root is curved, so the property is lost.

    The second loss is saying it is biased without the direction or the size. Say biased low, give the Jensen reason in one sentence, and quote about 0.80 at two observations, shrinking towards 1 as the sample grows.

    What the interviewer asks next

    • Is the square of an unbiased estimator of the standard deviation unbiased for the variance?
    • Why does the sample variance divide by n minus 1 rather than n?
    • Which estimator of sigma has the lowest mean squared error for normal data?

    Asked at Squarepoint Capital, Quantitative Research, London, 2026 (Wall Street Oasis): Is the square root of the unbiased estimator for sample variance unbiased for standard deviation?

  5. 064An exporter earns Rs 100 of revenue, 60% of it billed in dollars, and has Rs 85 of costs, all paid in rupees. The rupee weakens from 80 to 88 to the dollar. What happens to its operating margin?Valuation, accounting and macro riddlesCoreLong-short equity fundsGlobal macro funds

    Try it first

    What is the operating margin after the move?

    Show the worked solution

    The margin rises from 15% to about 19.8%, and operating profit rises 40%. Each dollar now buys 10% more rupees, which turns Rs 60 of dollar revenue into Rs 66, so revenue reaches Rs 106. Costs are all in rupees and stay at Rs 85, so profit climbs from Rs 15 to Rs 21, and 21 over 106 is 19.8%. A 6% rise in revenue becomes a 40% rise in profit.

    Why does a weaker rupee help this company so much?

    Think of a tutor in Pune who teaches some students abroad for fees in dollars and pays rent and a salary in rupees. When the rupee weakens, each dollar fee converts into more rupees while the rent does not move. A currency move lands on the revenue billed in the foreign currency and on nothing else, so when every cost is local the whole gain drops into profit. Here the gain is Rs 6, on a profit that started at only Rs 15.

    A weaker rupee lifts dollar revenue; rupee costs stay putAt 80 rupees to the dollar4060-8515rupee salesdollar salesrupee costsprofitRevenue 100, margin 15.0%At 88 rupees to the dollar4066 (+6)-8521rupee salesdollar salesrupee costsprofitRevenue 106, margin 19.8%
    Before the move, Rs 40 of rupee revenue and Rs 60 of dollar revenue less Rs 85 of rupee costs leave Rs 15 of profit, a 15% margin; at 88 to the dollar the dollar revenue is worth Rs 66, costs stay at Rs 85 and profit rises to Rs 21, a 19.8% margin.

    How do you size the profit move quickly?

    Chain three numbers. The dollar buys 10% more rupees, 60% of revenue is exposed, so revenue rises 6%; a thin 15% margin turns that Rs 6 into a 40% rise in profit. The ratio of the profit change to the revenue change, 40 over 6, almost 7 times, is the company's operating leverageHow much operating profit moves for a given move in revenue, high when most costs are fixed or unaffected by the change. to the currency. An analyst on a long-short book uses that multiplier to judge how much of a stock's move a currency view is really driving.

    The relationship
    margin=40+60×8880−8540+60×8880=21106≈19.8%\text{margin} = \frac{40 + 60 \times \tfrac{88}{80} - 85}{40 + 60 \times \tfrac{88}{80}} = \frac{21}{106} \approx 19.8\%
    40revenue billed in rupees, unchanged
    60 x 88/80dollar revenue restated at the new rate, Rs 66
    85costs, all in rupees, unchanged
    What it says in wordsRestate only the dollar-billed revenue at the new rate, hold rupee costs fixed, and divide profit by the new revenue.

    What would you check before trusting the new margin?

    Three things that often shrink the gain. Hedges, pricing and imported inputs: a company that sold its dollars forward keeps the old rate until the hedges roll off, buyers abroad may push for lower dollar prices, and any imported materials get dearer too. Each one eats into the Rs 6. The 19.8% is the unhedged, first-round answer; naming those three tells the interviewer you would not stop at it.

    Where candidates lose it

    The first slip is saying the margin is unchanged because revenue and costs both grow. Only the dollar-billed revenue moves; rupee costs stay where they were, and that asymmetry is the whole point.

    The second is applying the 10% to all Rs 100 of revenue, which gives Rs 110 and a 22.7% margin. Only 60% of revenue is billed in dollars, so revenue rises 6%, not 10%.

    What the interviewer asks next

    • Half of the costs are imported and paid in dollars. What is the new margin?
    • The company hedged half its dollar revenue at 80. What margin does it report this year?
    • What does the same move do to an importer with the mirror-image structure?
  6. 070A portfolio is split equally between two assets, each with 15% annual volatility. Their correlation is 0.2 in normal markets and 0.8 in a crisis. What is the portfolio's volatility in each regime?Portfolio and risk mathsCoreMulti-manager platformsQuant and systematic funds

    Try it first

    What happens to the portfolio's volatility when correlation rises from 0.2 to 0.8?

    Show the worked solution

    About 11.6% in normal markets and 14.2% in a crisis. With equal weights and equal volatilities, portfolio variance is 15% squared times (1 + rho)/2. At a correlation of 0.2 that is 225 x 0.6 = 135, a volatility of 11.6%; at 0.8 it is 225 x 0.9 = 202.5, a volatility of 14.2%. About 77% of the diversification benefit disappears just when it is needed.

    Where does correlation enter the arithmetic?

    Picture an umbrella shop and an ice-cream stall owned by one family. On ordinary days one does well when the other is quiet, and the family income is smoother than either shop's. A city-wide power cut shuts both at once. Portfolio variance is each asset's own variance, weighted, plus a co-movement term that carries the correlation, so when correlation jumps the co-movement term grows and the smoothing shrinks. Here the own terms are 56.25 each and the co-movement term is 2 x 0.5 x 0.5 x rho x 225.

    The relationship
    σp2=w12σ12+w22σ22+2w1w2ρ σ1σ2=225×1+ρ2\sigma_p^2 = w_1^2\sigma_1^2 + w_2^2\sigma_2^2 + 2w_1w_2\rho\,\sigma_1\sigma_2 = 225 \times \frac{1+\rho}{2}
    w1, w2the weights, 0.5 each
    sigma1, sigma2the volatilities, 15% each
    rhothe correlation between the two assets
    What it says in wordsPortfolio variance is the weighted own variances plus a cross term that grows with correlation.
    Diversification shrinks exactly when correlations jumpNormal markets: correlation 0.2Portfolio variance, % squared112.5 own+22.5co-movement term: 2 x 0.5 x 0.5 x 0.2 x 225Volatility, %15.0either asset alone11.6the 50/50 portfolioBenefit of holding both: 3.4 pointsCrisis: correlation 0.8Portfolio variance, % squared112.5 own+90.0co-movement term: 2 x 0.5 x 0.5 x 0.8 x 225Volatility, %15.0either asset alone14.2the 50/50 portfolioBenefit of holding both: 0.8 points
    At a correlation of 0.2 the co-movement term adds 22.5 to a variance of 112.5, giving 11.6% volatility; at 0.8 it adds 90.0, giving 14.2%, so the benefit of holding both assets falls from 3.4 points to 0.8.

    What are the two numbers?

    Normal markets: 112.5 plus 2 x 0.25 x 0.2 x 225 = 22.5 gives 135, and the square root is 11.6%. Crisis: the co-movement term rises to 90, variance to 202.5, and volatility to 14.2%, a 22.5% jump in risk with no change in either asset's own volatility. The benefit of holding two assets instead of one falls from 3.4 points to 0.8. In a real crisis each asset's volatility usually rises too, so this is the milder case.

    What would a risk manager do with this?

    Stop sizing positions on correlations measured in calm markets. A risk limit set on a normal-market correlation understates crisis risk by about 22% here, before any rise in the assets' own volatility. Platforms that run many books run stressed-correlation scenarios for this reason, and ask each manager what the book looks like if everything moves together. The honest limitation: nobody knows the crisis correlation in advance; 0.8 is an assumption, and the answer should say so.

    Where candidates lose it

    The common loss is treating correlation as if it scaled volatility directly, or quoting 15% in both regimes because each asset's volatility has not changed. Correlation enters only through the cross term in the variance.

    The second is computing both numbers and missing the point of the question: the benefit you were counting on shrinks exactly in the regime where you need it. Say that sentence.

    What the interviewer asks next

    • At what correlation does the portfolio's volatility reach 13%?
    • With three equally weighted assets, what is the volatility at a correlation of 0.8?
    • Why might correlations between assets rise in a sell-off?
  7. 072An investment earns 10% a year before fees and charges a 2% annual fee. Over 20 years, what share of the investor's ending wealth does the fee consume?Returns, compounding and feesCoreFund of funds and allocatorsMulti-manager platforms

    Try it first

    Over 20 years, what share of the ending wealth does the 2% fee take?

    Show the worked solution

    About 31% of the ending wealth. Rs 1 lakh growing at 10% a year becomes Rs 6.73 lakh in 20 years; at 8% after the fee it becomes Rs 4.66 lakh. The fee takes Rs 2.07 lakh, about 31% of what the investor would otherwise have had, although each year it looks like only a fifth of the return.

    Why does a fifth of each year's return become almost a third of the wealth?

    Think of a mango tree whose fruit you replant. If a neighbour takes one mango in every five each year, you lose those mangoes and every tree they would have grown. A fee taken every year removes money that would itself have compounded for the remaining years, so its cost grows faster than the fee rate suggests. The share lost is 1 minus (1.08/1.10) to the 20th: each year the investor keeps 98.2% of what the gross path would have held, and 0.982 to the 20th is about 0.69.

    The relationship
    share lost=1−(1.081.10)20=1−4.666.73≈30.7%\text{share lost} = 1 - \left(\frac{1.08}{1.10}\right)^{20} = 1 - \frac{4.66}{6.73} \approx 30.7\%
    1.10the gross growth factor each year
    1.08the growth factor after the 2% fee
    20the number of years
    What it says in wordsThe fraction of wealth the fee takes is one minus the ratio of the two growth paths after 20 years.
    A fee of a fifth of the return takes almost a third of the wealth1234567Rs lakhyr 0yr 5yr 10yr 15yr 206.73 at 10%4.66 at 8%fee: 2.07yr 10: 2.59 vs 2.16Fee = 2 of the 10 points each yearTakes 30.7% of ending wealth
    Rs 1 lakh grows to Rs 6.73 lakh in 20 years at 10% but only Rs 4.66 lakh at 8% after the fee, a gap of Rs 2.07 lakh that widens every year and ends at about 31% of the gross wealth.

    How do you estimate it without a calculator?

    Use the rule of 72. At 10% money doubles about every 7.2 years, so 20 years is about 2.8 doublings, near 7 times; at 8% it doubles every 9 years, about 2.2 doublings, near 4.6 times. The exact numbers are 6.73 and 4.66, so the estimate lands within a few per cent, and 4.6 over 6.9 already tells you roughly a third is gone. Say the estimate first, then the exact figure.

    What does an allocator take from this?

    That fees should be judged against the return they leave, over the holding period, not as a percentage in a single year. A manager charging 2% needs to beat a cheaper alternative by about 2 points a year, every year, just to leave the investor level; over 20 years the difference is 31% of the pot. Hedge fund fees often add a share of profits on top, which widens the gap further. The illustration assumes a steady 10%; real returns vary, but the compounding of the fee does not depend on that.

    Where candidates lose it

    The two fast answers are 2% and 20%: the fee rate, or the fee as a share of one year's return. Both treat the fee as a one-year cost and ignore that every rupee taken would have compounded for the years that follow.

    The second loss is working out 4.66 and 6.73 and then reporting the gap as a share of the smaller number, 44%. The question asks what share of the investor's potential wealth the fee consumed, so divide by the gross figure.

    What the interviewer asks next

    • The fee is 1% instead of 2%. What share of ending wealth does it take over 20 years?
    • Add a 20% share of profits on top of the 2% fee. Roughly what does the investor keep?
    • Why do fees matter more for a 30-year retirement saver than for a 3-year investor?
  8. 073A thousand fund managers have no skill at all: each has a 50% chance of beating the market in any year, independently. How many will beat it five years running, and what does that say about track records?Statistics and estimationCoreQuant and systematic funds

    Try it first

    How many of the 1,000 unskilled managers beat the market five years in a row?

    Show the worked solution

    About 31 managers, 1,000 halved five times. Each year roughly half the unbeaten managers beat the market by luck, so 500 survive year one, 250 year two, then 125, 62.5 and 31.25. A perfect five-year record is something luck hands to about 3 managers in every 100, so in a large crowd it cannot on its own separate skill from chance.

    Why does a crowd produce streaks even without skill?

    Fill a stadium with a thousand people and ask each to toss a coin five times. Someone will throw five heads, and about 31 will. A result that is rare for one person is almost certain somewhere in a large group, so the question is never whether a flawless record exists but how many you would expect by chance. Each manager's chance is 1 in 32; across 1,000 managers that is 31.25 expected perfect records.

    Halve it five times: flawless records that luck alone produces1,000start500after yr 1250after yr 2125after yr 362.5after yr 431.25after yr 5dashed: the half that drop out each year1,000 x (1/2) to the 5th = 31.253.1% of a skill-free crowdpost five perfect years
    Starting from 1,000 unskilled managers, half fall away each year, leaving 500, 250, 125, 62.5 and finally about 31 with a flawless five-year record produced by chance alone.
    The relationship
    E[perfect records]=1,000×(12)5=31.25E[\text{perfect records}] = 1{,}000 \times \left(\tfrac12\right)^5 = 31.25
    1,000the number of managers
    1/2each manager's chance of beating the market in a year
    5the number of years
    What it says in wordsMultiply the crowd by the chance that one member gets the streak.

    If some managers really are skilled, how much does a perfect record tell you?

    Suppose 5% of the thousand are skilled and beat the market 60% of the time. They produce about 3.9 perfect records, while the 950 unskilled produce about 29.7, so a manager with five perfect years is skilled only about 12% of the time. A 60% manager has only a 8% chance of five perfect years, so most skilled managers do not have flawless records either. The record is weak evidence in both directions.

    What should you look at instead?

    Longer records, more decisions per year and a reason. Skill shows up more reliably in many independent decisions than in a handful of annual outcomes, and in a process that explains where the edge comes from. Allocators also check how many managers were in the starting pool, because the funds still reporting are the ones that survived; the ones that were closed after bad years have dropped out of the data. That is survivorship biasThe distortion that comes from studying only the survivors of a process, whose results look better than those of the whole starting group., and it makes every surviving record look stronger than it is.

    Where candidates lose it

    The first loss is saying none, or very few, because five in a row sounds impressive. The interviewer wants the crowd arithmetic: rare for one, expected for many.

    The second is stopping at 31 without the conclusion. The number is only half the answer; say what it means for reading a track record, and name survivorship bias.

    What the interviewer asks next

    • How many of the 1,000 beat the market in at least four of the five years?
    • How many years of beating the market would one unskilled manager in 1,000 be expected to reach?
    • How would you design a test that separates a 60% manager from a 50% one?
  9. 074A company has a market value of Rs 1,000 crore, earnings of Rs 100 crore, and Rs 300 crore of net cash that earns 6% after tax. What is the P/E of the operating business on its own?Valuation, accounting and macro riddlesCoreLong-short equity fundsGlobal macro funds

    Try it first

    What is the P/E of the operating business alone?

    Show the worked solution

    About 8.5x, not 10x. Rs 300 crore of the Rs 1,000 crore market value is cash, so the operating business is valued at Rs 700 crore. The cash earns 6% after tax, Rs 18 crore, so the operating business earns Rs 82 crore. Rs 700 crore over Rs 82 crore is about 8.5 times earnings. The headline 10x blends a cheaper business with cash priced at about 16.7 times its income.

    Why is the headline P/E misleading here?

    Imagine buying a shop for Rs 10 lakh that has Rs 3 lakh sitting in its till. You are really paying Rs 7 lakh for the shop itself. A company's price and earnings both include its cash, and cash is valued very differently from a business: here it earns 6% after tax, so it is worth about 16.7 times its income. Blending the two gives the headline 10x, which is neither the price of the cash nor the price of the business.

    Take the cash out of both the price and the earningsMarket value, Rs crore1,000-300700totalnet cashoperating businessEarnings, Rs crore100-1882totalinterest on cashoperating earningsHeadline P/E 10x. Operating business 700 / 82 = 8.5x. Cash 300 / 18 = 16.7x.
    Removing Rs 300 crore of cash from the Rs 1,000 crore market value leaves Rs 700 crore for the operating business, and removing the Rs 18 crore it earns leaves Rs 82 crore of operating earnings, a multiple of about 8.5x against the headline 10x.

    How do you work it?

    Strip the cash out of both the numerator and the denominator. The price of the operating business is 1,000 minus 300, Rs 700 crore; its earnings are 100 minus 6% of 300, Rs 82 crore; and 700 over 82 is 8.54x. Taking the cash out of only the price gives 7.0x, which is too low because the Rs 100 crore still contains the cash's interest. The check: 700 plus 300 is 1,000 and 82 plus 18 is 100.

    The relationship
    P/Eops=1,000−300100−0.06×300=70082≈8.5×\text{P/E}_{\text{ops}} = \frac{1{,}000 - 300}{100 - 0.06 \times 300} = \frac{700}{82} \approx 8.5\times
    1,000market value, Rs crore
    300net cash, Rs crore
    0.06 x 300the after-tax income the cash earns, Rs 18 crore
    What it says in wordsTake the cash out of the price and its income out of the earnings, then divide.

    When would you not strip out all the cash?

    When the cash is not really free. Cash needed to run the business, cash trapped abroad that would be taxed on the way home, or cash a management team is likely to spend badly may deserve less than full value. A long-short analyst uses the ex-cash multiple to compare this business with peers that hold no cash, and then asks how much of the Rs 300 crore shareholders will actually see. That judgement moves the answer between about 8.5x and the headline 10x.

    Where candidates lose it

    The first slip is quoting 10x and moving on, which treats the cash as if it were part of the operating business. The interviewer put Rs 300 crore of cash in precisely so that the headline multiple would mislead.

    The second is subtracting the cash from the price but leaving its interest in the earnings, which gives 7.0x. Cash must come out of both sides.

    What the interviewer asks next

    • The cash earns only 3% after tax. What is the operating P/E now?
    • The company holds Rs 300 crore of net debt instead, at 6% after tax. What is the operating P/E?
    • Why might the market value the company's cash at less than Rs 300 crore?
  10. 077In a Monty Hall game you pick door 1. This host does not know where the car is: he opens one of the other two doors at random, and it happens to show a goat. Should you switch, and why does the usual two-thirds answer no longer hold?Conditional probability and BayesCoreSCSquarepoint CapitalLondon · 2026

    Try it first

    The host opened a door at random and it happened to show a goat. What is your chance of winning if you switch?

    Show the worked solution

    It makes no difference: switching and sticking each win half the time. List the six equally likely cases of car position and the host's random pick. Two of them reveal the car, and you have seen that they did not happen. The four that remain split two and two. The knowing host gives two thirds only because he never risks the car, which pushes those two cases into the switch column.

    Where does the usual two-thirds answer come from?

    In the standard game the host knows where the car is and always opens a goat door. Your first pick is right one time in three, and nothing the knowing host does can change that, so the other two thirds sit on the remaining closed door. His choice carries information because it is forced: when the car is behind door 2, he must open door 3, and when it is behind door 3, he must open door 2.

    What changes when the host picks at random?

    Picture a friend who does not know the answer to a quiz question and strikes out one option on a whim. If that option happens to be wrong, you have learned less than if someone who knew had struck it. The random host is that friend. Write out six cases: the car behind door 1, 2 or 3, each with the host's coin choosing door 2 or door 3. In two of the six the random host opens the car door, and the goat you saw rules those two out, which removes switch wins rather than stick wins.

    Same six cases: the knowing host moves two of them, the random host loses themHost knows where the car isCarCoinOpensResult122stick wins133stick wins223 insteadswitch wins233switch wins322switch wins332 insteadswitch winsSwitch wins 4 of 6 = 2/3Host opens a door at randomCarCoinOpensResult122stick wins133stick wins222car shown: ruled out233switch wins322switch wins333car shown: ruled outSwitch wins 2 of the 4 left = 1/2
    In the same six equally likely cases, a knowing host redirects the two where his coin points at the car, so switching wins 4 of 6; a random host shows the car in those two, they are ruled out, and switching wins 2 of the 4 that remain, one half.

    Count what is left. The car behind door 1 survives both host choices: two cases where sticking wins. The car behind door 2 survives only when the host opened door 3, and the car behind door 3 only when he opened door 2: two cases where switching wins. Two against two.

    The relationship
    P(switch wins∣goat shown)=2/64/6=12P(\text{switch wins} \mid \text{goat shown}) = \frac{2/6}{4/6} = \frac{1}{2}
    2/6cases where the car is behind the other closed door and the host showed a goat
    4/6all cases where the host showed a goat, which is what you observed
    What it says in wordsCondition on what you saw: of the cases where a goat appears, half have the car behind the door you would switch to.

    Why would an interviewer want the intuitive answer broken rather than recited?

    Because the lesson travels to every desk. The same observation carries different information depending on the process that produced it. A strong track record shown by a manager who launched ten funds and closed the nine that did badly is a host choosing which door to open for you. Before you update on evidence, ask whether the source could have shown you something else, and whether it chose what to show.

    Where candidates lose it

    Candidates who know the classic puzzle answer two thirds on reflex. The interviewer changed one fact, that the host knows, and is checking whether you notice that the host's knowledge is exactly what made switching better.

    The other loss is saying one half without a reason, which sounds like the naive answer to the classic game. Name the two ruled-out cases, where the car would have been shown, and show that both come out of the switch column.

    What the interviewer asks next

    • With 100 doors and a knowing host who opens 98 goat doors, what is your chance if you switch?
    • With 100 doors and a random host who happens to open 98 goat doors, what is it now?
    • Where does the same logic show up when you read a fund family's track record?

    Asked at Squarepoint Capital, Quant Research Intern Interview, London, 2026 (Wall Street Oasis): notably I was asked why the 'intuitive answer' was not true rather than just what the correct answer was, related to the Monty Hall problem

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