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  1. 066On an island everyone either always tells the truth or always lies. A says: "At least one of the two of us is a liar." B says nothing. What are A and B?Logic and brainteasersCoreConsulting style brainteasersSales and trading

    Try it first

    Before you work it: what can you say about B, who said nothing?

    Show the worked solution

    A always tells the truth and B always lies. Suppose A is a liar. Then A's statement is false, so neither of them is a liar, which means A tells the truth: a contradiction. So A is truthful, the statement is true, at least one of the two is a liar, and since A is not, B is. B never needed to speak.

    Why does assuming A is a liar fall apart?

    Picture someone who says, with a straight face, "I am lying right now." If that is a lie, they are telling the truth, and if it is the truth, they are lying; the sentence eats itself. A's statement is a milder cousin. A liar can never truthfully announce that there is a liar among us, because the announcement would then be true. So test the liar case first: if A lies, the statement is false, which means neither person is a liar, which means A is truthful. The assumption contradicts itself and is thrown out.

    Assume each type for A in turn and look for the contradictionA says: "At least one of the two of us is a liar"B says nothingsuppose A liessuppose A tells the truthThen the statement is falseSo neither of them is a liarSo A tells the truthContradiction: a liar cannotbe telling the truth. A is not a liar.Then the statement is trueSo at least one of them is a liarA is truthful, so it must be BA tells the truth. B is a liar.B's silence does not save B
    Supposing A lies makes A's statement false, which would mean neither is a liar and so A is truthful, a contradiction, while supposing A is truthful makes the statement true and points at B, so A tells the truth and silent B is the liar.

    How does B get classified without saying a word?

    Once A is truthful, A's sentence becomes a fact about the pair: at least one of them lies. A has been cleared, so the only person left who can be the liar is B, and B's silence changes nothing because the information came from A. The question is built this way to see whether you notice that evidence about a person can come from someone else. Say the two steps in order, A first and then B, and name the contradiction out loud rather than skipping to the answer.

    Assumption about AIs the statement true?What followsVerdict
    A liesNoNeither is a liar, so A is truthfulContradiction, rejected
    A tells the truthYesAt least one lies, and A does notB is the liar
    Only the second row survives the test, so A is truthful and B, who said nothing, is the liar, because the statement A made is about both of them.

    Why do interviewers like this shape of puzzle?

    It rewards the method you need for any logic test: assume a case, chase it to a contradiction, and move on. The same discipline is how you check a model: assume the circular reference resolves, trace it, and if it cannot, the assumption was wrong. Candidates who fail it usually try to argue from B's silence, which carries no information, instead of from A's sentence, which carries all of it.

    Where candidates lose it

    The common loss is saying that nothing can be known about B, because B gave no statement. The statement that convicts B is A's, and it only works because a liar cannot utter it.

    The second loss is reversing the pair and calling A the liar, from the feeling that whoever accuses must be the guilty one. Test the case rather than trusting the feeling: the liar assumption breaks in two steps.

    What the interviewer asks next

    • A instead says: "Both of us are liars." What are A and B now?
    • A says: "B would say I am a liar." What can you conclude?
    • What if A says: "At least one of us tells the truth"?
  2. 068How many zeros are at the end of 100 factorial, written out in full?Mental maths and countingCoreBulge bracket IBMiddle market IB

    Try it first

    Before you count: how many trailing zeros?

    Show the worked solution

    24 trailing zeros. Each zero at the end is a factor of 10, which is a 2 paired with a 5. Among the numbers 1 to 100 there are 97 factors of 2 but far fewer 5s, so the 5s decide it. The 20 multiples of 5 contribute one 5 each, and the four multiples of 25 contribute a second, giving 20 + 4 = 24. There is no multiple of 125 below 100, so there is no third layer.

    Why is the answer about fives and not about tens?

    Think of making pairs of shoes from a pile of lefts and rights. If you have 97 left shoes and 24 right shoes, you can make 24 pairs; the extra lefts do not help. A trailing zero is a pair of one 2 and one 5 multiplied together, and in 1 to 100 the 2s vastly outnumber the 5s, so the number of 5s sets the number of zeros. Counting multiples of 10 misses the zeros built from a 5 in one number and a 2 in another, such as 5 x 2 = 10 or 15 x 4 = 60.

    Count the fives: every multiple of 5 gives one, every multiple of 25 gives a second510152025525 x3035404550525 x5560657075525 x80859095100525 xone factor of 5 from each multiple of 5: 20a second factor of 5 from each multiple of 25: 4 more125 is above 100, so no third layerFives in 100! = 20 + 4= 24 trailing zerosTwos in 100! = 97: plenty to pairEach trailing zero is one factor of 10,which is one 2 paired with one 5.Twos are everywhere; fives are the scarce part,so count the fives.the four multiples of 25 are the step people miss
    The 20 multiples of 5 from 5 to 100 each contribute one factor of 5, and the four multiples of 25 contribute a second one, so 100 factorial contains 24 fives, each paired with one of its 97 twos to make 24 trailing zeros.

    Where do the extra four come from?

    A number like 50 is 2 x 5 x 5: it carries two fives, not one. Every multiple of 25 hides a second five, and 25, 50, 75 and 100 are the four of them below 100, so the count is 20 from the multiples of 5 plus 4 from the multiples of 25. The next layer would be multiples of 125, which carry a third five, but 125 is beyond 100, so the count stops at 24. The pattern continues for larger factorials: divide by 5, then 25, then 125, and add the whole-number parts.

    The relationship
    Z=⌊1005⌋+⌊10025⌋+⌊100125⌋=20+4+0=24Z = \left\lfloor \tfrac{100}{5} \right\rfloor + \left\lfloor \tfrac{100}{25} \right\rfloor + \left\lfloor \tfrac{100}{125} \right\rfloor = 20 + 4 + 0 = 24
    Zthe number of trailing zeros
    floorthe whole-number part of the division
    5, 25, 125each power of 5 adds a layer of fives
    What it says in wordsAdd up the whole-number parts of 100 divided by 5, by 25 and by 125, because each layer counts one more five per number.

    How do you check it without writing out 100 factorial?

    Test the method on a factorial you can write. 10 factorial is 3,628,800, with two trailing zeros, and the rule gives 10 over 5 = 2, plus 10 over 25 = 0, which matches. Showing the rule on a small case you can verify is the fastest way to earn trust for the big case you cannot. Then say the general version: the number of trailing zeros of n factorial is the whole-number sum of n over 5, n over 25, n over 125 and so on, and for 1,000 factorial that is 200 + 40 + 8 + 1 = 249.

    Where candidates lose it

    The fast wrong answers are 10, from counting multiples of 10, and 20, from counting multiples of 5 once. The second is close enough that candidates say it with confidence and lose the point on the four multiples of 25.

    The other loss is explaining it as a memorised formula. Say why fives are the scarce factor first; the formula then sounds like reasoning rather than recall.

    What the interviewer asks next

    • How many trailing zeros does 1,000 factorial have?
    • How many factors of 2 are in 100 factorial, and why does that number not matter here?
    • What is the smallest n for which n factorial ends in exactly 30 zeros, and is every count reachable?
  3. 069Two companies both trade at 8x EV/EBITDA. One spends 20% of its EBITDA on capex each year and the other spends 60%. Which is cheaper, and which multiple shows it?Valuation riddlesCoreElite boutique IBBulge bracket IB

    Try it first

    Before you work it: which company is cheaper?

    Show the worked solution

    The company spending 20% is cheaper, and EV over EBITDA less capex shows it. Give both Rs 100 crore of EBITDA, so each is worth Rs 800 crore. The first keeps Rs 80 crore after capex and trades at 10x that cash figure; the second keeps Rs 40 crore and trades at 20x. EV/EBITDA cannot see capital intensity, so when capex differs this much, compare value against cash earnings instead.

    Why does the same 8x mean different things?

    Two taxi drivers each earn Rs 1 lakh a month before costs. One drives a new car that needs a service a year; the other drives an old one that eats Rs 60,000 a month in repairs. You would not pay the same for both businesses. EBITDA is earnings before the spending needed to keep the assets working, so two companies with equal EBITDA can hand their owners very different amounts of cash. At 8x, both are valued at Rs 800 crore on Rs 100 crore of EBITDA. The first spends Rs 20 crore of that on capex, the second Rs 60 crore, and that difference never appears in the headline multiple.

    Same 8x on EBITDA; take capex off and the two companies are nothing alikeCompany A: capex 20% of EBITDAEBITDA 10080 leftcapex 20Rs crore a yearEVRs 800 croreEV / EBITDA8.0xsameEV / (EBITDA - capex)800 / 80 = 10xcheaper on cash earningsCompany B: capex 60% of EBITDAEBITDA 10040 leftcapex 60Rs crore a yearEVRs 800 croreEV / EBITDA8.0xsameEV / (EBITDA - capex)800 / 40 = 20xtwice as expensive,same headline
    Both companies carry Rs 100 crore of EBITDA and an Rs 800 crore enterprise value, but after capex the first keeps Rs 80 crore and the second Rs 40 crore, so on EV over EBITDA less capex they trade at 10x and 20x and the first is the cheaper company.

    Which multiple fixes it?

    Take the capex off before dividing. EV over EBITDA less capex puts the two companies on cash they can actually keep, and the gap opens up to 10x against 20x. EV over EBIT does a rougher version of the same job, because depreciation is yesterday's capex spread over time, but it lags when a company is spending more than it depreciates. The cleanest version is EV over unlevered free cash flow, which also takes tax and working capital off. Name the limitation too: capex can be lumpy, so use a normal year or an average, and growth capex that adds capacity deserves a different reading from maintenance capex that merely keeps the lights on.

    Rs crore a yearCompany ACompany B
    EBITDA100100
    Capex2060
    EBITDA less capex8040
    Enterprise value800800
    EV / EBITDA8.0x8.0x
    EV / (EBITDA less capex)10.0x20.0x
    On identical EBITDA and value, company A keeps Rs 80 crore after capex and company B Rs 40 crore, so company B costs twice as much per rupee of cash earnings.
    The relationship
    EVEBITDA−capex=800100−20=10x800100−60=20x\frac{EV}{EBITDA - capex} = \frac{800}{100 - 20} = 10x \qquad \frac{800}{100 - 60} = 20x
    EVenterprise value, Rs 800 crore for both
    EBITDARs 100 crore for both
    capexcapital spending, Rs 20 crore and Rs 60 crore
    What it says in wordsDivide value by the cash left after capex, and the capital-hungry company looks twice as expensive.

    When would the market be right to pay 8x for both?

    Say the case against your own answer. If company B's Rs 60 crore of capex is building capacity that will lift EBITDA sharply, the market may be paying for growth that company A will never deliver. The question has no growth figures, so the honest answer is that on today's cash the 20% company is cheaper, and that the interviewer would need to tell you about growth and the split between maintenance and growth capex before you could defend an equal multiple.

    Where candidates lose it

    The common loss is answering that neither is cheaper because the multiples match. The interviewer has deliberately picked a multiple that is blind to capex to see whether you know what EBITDA leaves out.

    The second loss is naming the fix without the limitation. Capex is lumpy and some of it is growth, so say which capex you would use and why.

    What the interviewer asks next

    • Both companies also have the same EV/EBIT. What would that tell you about their depreciation?
    • How would you separate maintenance capex from growth capex if the company does not disclose the split?
    • Which industries tend to show the biggest gap between EV/EBITDA and EV/(EBITDA less capex)?
  4. 070A fund earns 10% a year before fees and charges 2% a year. Over 30 years, what share of the gross ending wealth does the fee consume?Growth and compoundingCoreMiddle market IBPrivate equity

    Try it first

    Before you compute: roughly what share of the final gross pot goes to fees?

    Show the worked solution

    About 42% of the gross ending wealth. Rs 1 compounding at 10% for 30 years becomes Rs 17.45. With a 2% fee the money compounds at 8% and becomes Rs 10.06. The gap is Rs 7.39, and 7.39 over 17.45 is 42%. A fee that sounds like a fifth of the return takes more than two fifths of the final pot, because every rupee of fee also forfeits the growth it would have earned.

    Why does a 2% fee take far more than 2%?

    Imagine a farmer who hands over two in every hundred sacks of grain each harvest. The loss is not two sacks; it is two sacks plus everything those sacks would have grown into had they been sown. A fee is taken from a growing pot, and each slice removed stops compounding, so the cost builds year on year. After one year the fee has cost about 2% of the pot. After 10 years it has cost 17%, after 20 years 31%, and after 30 years 42%. The number is still climbing at year 30; it only stops when the money is withdrawn.

    A 2% fee takes 2% of the pot each year, and the pot it takes from keeps growingYear 0Year 10Year 20Year 305x10x15x17.4x at 10%10.1x at 8% netgap 7.4x= 42% of the gross potfee has taken 17%fee has taken 31%Not 2% x 30 years = 60% of the gain,but 42% of everything you would have had
    Rs 1 compounding at 10% reaches Rs 17.45 in 30 years while at 8% after fees it reaches Rs 10.06, and the shaded gap of Rs 7.39 is 42% of the gross ending wealth, having been 17% at year 10 and 31% at year 20.

    How do you get the number in your head?

    Use the rule of 72 for the two growth rates. At 10% money doubles roughly every 7.2 years, so in 30 years it doubles a little over four times, about 17x. At 8% it doubles every 9 years, so just over three times, about 10x. The ratio of the two end points, 10 over 17, is roughly 0.58, so the fee has taken about 42% of the gross pot. The exact figures are 17.45x and 10.06x, and the exact share is 42.3%, but the rule of 72 gets you within a point in ten seconds.

    The relationship
    fee share=1−(1.08)30(1.10)30=1−10.0617.45=42.3%\text{fee share} = 1 - \frac{(1.08)^{30}}{(1.10)^{30}} = 1 - \frac{10.06}{17.45} = 42.3\%
    1.10gross growth of Rs 1 each year at 10%
    1.08net growth each year after a 2% fee
    30years the money compounds
    What it says in wordsCompare the net end point with the gross end point; the shortfall is the share the fee consumed.

    What does an interviewer want after the number?

    The link to the desk. Carried interest, management fees and transaction costs all work the same way: a small annual drag compounds into a large share of the terminal value, which is why net-of-fee returns, not gross, are what an investor should compare. Say the limitation too. The 10% gross return is an illustration, not a forecast, and a fee is worth paying if the manager's gross return beats the alternative by more than the fee. The question is about arithmetic, not about whether any fund is worth its fee.

    Where candidates lose it

    The fast wrong answer is 60%, from multiplying 2% by 30 years, or 20%, from saying the fee is a fifth of the return. Both treat the fee as a flat deduction rather than a slice of a compounding pot.

    The other loss is a number without a check. The rule of 72 gives roughly 17x against 10x in seconds, and saying it shows you can sanity check compounding without a calculator.

    What the interviewer asks next

    • What share of the gross pot does a 1% fee take over 30 years?
    • If the fee is charged on gains only, like a 20% carry, how does the arithmetic change?
    • Over how many years would the 2% fee consume half of the gross pot?
  5. 071Final-year free cash flow is Rs 100 crore, long-run growth is 4% and WACC is 10%. By what percentage does the terminal value fall if WACC rises to 11%?DCF and cost of capitalCoreBulge bracket IBMiddle market IB

    Try it first

    Before you compute: how much does the terminal value fall?

    Show the worked solution

    It falls by about 14.3%, one seventh. Terminal value is next year's cash flow over the spread between WACC and growth. At 10% the spread is 6 points, so the value is Rs 104 crore over 0.06, about Rs 1,733 crore. At 11% the spread is 7 points, giving Rs 1,486 crore. The new value is 6 over 7 of the old, a fall of 14.3%. The spread, not the WACC, is what the value is sensitive to.

    Why does a one point move in WACC cost a seventh of the value?

    Think of a shop whose rent is Rs 10 a month and whose takings are Rs 16: the owner keeps Rs 6. If rent goes up by one rupee the owner's margin shrinks by a sixth, far more than the rent went up in percentage terms. The terminal value divides by the gap between WACC and growth, and when that gap is thin, a small move in either rate is a large move in the gap. Here the gap goes from 6 points to 7, so the value falls to six sevenths of itself.

    One point of WACC on a six point spread: the terminal value loses a seventh8%9%10%11%12%1,5002,0002,500WACC, with growth fixed at 4%Terminal value, Rs crore10%: Rs 1,733 crore11%: Rs 1,486 crore-14.3%TV = 104 / (WACC - 4%)spread 6 points becomes 7 pointsnew / old = 6 / 7, a fall of 14.3%
    With growth fixed at 4%, the terminal value of Rs 100 crore of final-year cash flow falls from Rs 1,733 crore at a 10% WACC to Rs 1,486 crore at 11%, a drop of 14.3%, because the spread in the denominator grows from 6 points to 7.

    What is the shortcut, and when does it break?

    You do not need either terminal value to answer. The ratio of new to old value is the ratio of the old spread to the new spread, 6 over 7, so the percentage change is the spread change divided by the new spread. The same shortcut runs the other way: a fall in WACC to 9% narrows the spread to 5 points, and the value rises by 6 over 5 minus 1, 20%. Notice the asymmetry. A one point fall lifts value 20% while a one point rise cuts it 14.3%, which is why DCF sensitivity tables look lopsided.

    The relationship
    TV=FCF×(1+g)WACC−gTV11%TV10%=0.10−0.040.11−0.04=67⇒−14.3%TV = \frac{FCF \times (1+g)}{WACC - g} \qquad \frac{TV_{11\%}}{TV_{10\%}} = \frac{0.10 - 0.04}{0.11 - 0.04} = \frac{6}{7} \Rightarrow -14.3\%
    FCFfinal-year free cash flow, Rs 100 crore
    glong-run growth, 4%
    WACCthe discount rate, 10% rising to 11%
    What it says in wordsThe cash flow cancels; the terminal value changes by the ratio of the old spread to the new spread.
    WACCSpread over 4% growthTerminal value, Rs croreChange from the 10% case
    8%4 points2,600+50.0%
    9%5 points2,080+20.0%
    10%6 points1,733+0.0%
    11%7 points1,486-14.3%
    12%8 points1,300-25.0%
    Each one point step in WACC moves the terminal value by a different percentage, larger on the way down in WACC than on the way up, because the value is a cash flow divided by a thin and changing spread.

    Why does this matter beyond the arithmetic?

    The terminal value is usually most of a DCF, often two thirds or more of the enterprise value. If a one point move in WACC moves the terminal value by a seventh, the whole valuation is a judgement about two inputs that nobody knows to within a point. That is why a banker shows a sensitivity table rather than a single number, and why a growth assumption of 4% against a WACC of 10% should be cross-checked against the implied exit multiple before anyone trusts it.

    Where candidates lose it

    The common loss is answering 10%, from the WACC moving from 10 to 11, or 1%, from the one point move itself. Both forget that the value divides by the spread, not by the WACC.

    The other loss is computing both terminal values with the Rs 104 crore numerator and losing a minute. Say the spreads, 6 and 7, and the answer is one division.

    What the interviewer asks next

    • What happens to the terminal value if growth rises from 4% to 5% with WACC fixed at 10%?
    • What exit EV/EBITDA multiple does a Rs 1,733 crore terminal value imply if final-year EBITDA is Rs 150 crore?
    • Why would a WACC of 10% with 4% growth be hard to defend for a mature company?
  6. 072A property is bought at a 7% cap rate with a 60% loan-to-value loan at 9% interest-only. What is the cash-on-cash return on the equity?Rates, risk and optionsCoreWells Fargo SecuritiesNew York · 2026

    Try it first

    Before you work it: does borrowing raise or lower the equity return here?

    Show the worked solution

    About 4%, below the unlevered 7%. Per Rs 100 of property, a 7% cap rate means Rs 7 of net operating income. A 60% loan is Rs 60, and at 9% interest-only it costs Rs 5.4 a year. That leaves Rs 1.6 of cash for the Rs 40 of equity, which is 4%. Because the loan costs more than the property yields, this is negative leverage: borrowing lowers the equity return rather than raising it.

    Why is the cash-on-cash below the cap rate?

    Suppose you borrow money at 9% to put in a deposit paying 7%. Every rupee borrowed loses you 2 paise a year, and the more you borrow the worse it gets. Leverage lifts the equity return only when the asset yields more than the debt costs; when the cap rate sits below the interest rate, every rupee of debt subtracts from the equity's return. Here the Rs 60 of debt earns 7% inside the property, Rs 4.2, but costs 9%, Rs 5.4, so it drags Rs 1.2 off the Rs 7 that the equity would otherwise keep on Rs 100 unlevered.

    Borrow at 9% to buy a 7% yield and the leverage works against the equity7.0NOI-5.4Interest1.6To equityPer Rs 100 of property60 x 9%1.6 on 40 of equity = 4.0% cash-on-cashCash-on-cash if the loan costs...5%10%7%7%9%4%unlevered 7%Loan rate below the cap rate: leverage adds to the return.Equal: no effect. Above, as here at 9%: leverage subtracts.Interest-only loan, so no principal repayment in the cash figure.
    Per Rs 100 of property, Rs 7 of net operating income less Rs 5.4 of interest on Rs 60 of debt at 9% leaves Rs 1.6 for Rs 40 of equity, a 4% cash-on-cash return, and the same loan at 5% would give 10% while at 7% it would leave the return unchanged at 7%.

    How do you say the answer in a way the interviewer can follow?

    Fix the value at Rs 100 so every input becomes a rupee figure. Cap rate times value is the income; loan-to-value times value is the debt; debt times the rate is the interest; the rest is cash on the equity, and the equity is value minus debt. That is four multiplications and two subtractions, and saying each one aloud keeps you honest. Then say the comparison that matters: 4% levered against 7% unlevered, so the loan has cost the equity 3 points of yield.

    The relationship
    CoC=NOI−interestequity=7−60×9%100−60=1.640=4%\text{CoC} = \frac{\text{NOI} - \text{interest}}{\text{equity}} = \frac{7 - 60 \times 9\%}{100 - 60} = \frac{1.6}{40} = 4\%
    NOInet operating income, the cap rate times the value
    interestthe loan times its rate, interest-only so no principal
    equityvalue less the loan, here Rs 40 per Rs 100
    What it says in wordsCash-on-cash is the income left after interest, divided by the cash the equity put in.
    Loan rateInterest on Rs 60Cash to Rs 40 of equityCash-on-cash
    5%3.04.010%
    7%4.22.87%
    9%5.41.64%
    The cash-on-cash return crosses the unlevered 7% exactly when the loan rate equals the cap rate, rising above it at cheaper rates and falling below it, to 4%, at the 9% in the question.

    Why would anyone buy with negative leverage?

    Because cash-on-cash is a snapshot of year one. A buyer accepting 4% today is betting on rent growth lifting the income, on refinancing when rates fall, or on selling at a lower cap rate, none of which is in this calculation. Say that the figure ignores principal repayment, because the loan is interest-only, and ignores any appreciation. A total return would add both, and a lender would also look at the debt service coverage, which here is 7 over 5.4, about 1.3x, thin for most lenders.

    Where candidates lose it

    The common loss is assuming leverage must raise the return and answering something above 7%. The interviewer has set the loan rate above the cap rate on purpose to see whether you check the sign before you multiply.

    The second loss is dividing the cash by the whole Rs 100 of value instead of the Rs 40 of equity, which gives 1.6% and a confused look. Cash-on-cash is measured on the cash the equity actually put in.

    What the interviewer asks next

    • At what loan rate does the cash-on-cash equal the cap rate, and why?
    • Now the loan amortises over 25 years. Does the cash-on-cash rise or fall, and what does it leave out?
    • If rents grow 3% a year, what is the cash-on-cash in year 3?

    Asked at Wells Fargo Securities, Real Estate, New York, 2026 (Wall Street Oasis): What is the CoC when you have _ Interest Rate, _ LTV, and _ Cap rate?

  7. 074A corridor has 100 closed lockers. Student 1 opens every locker. Student 2 toggles every second locker, student 3 every third, and so on up to student 100, who toggles only locker 100. Which lockers end up open?Logic and brainteasersCoreConsulting style brainteasersSales and trading

    Try it first

    Before you reason it out: how many lockers end up open?

    Show the worked solution

    The 10 perfect squares: lockers 1, 4, 9, 16, 25, 36, 49, 64, 81 and 100. Locker n is toggled once by every student whose number divides n, so it ends open if n has an odd number of divisors. Divisors come in pairs, d and n over d, so the count is even unless one divisor pairs with itself, which happens only when n is a perfect square. Those ten lockers are open; the other 90 are shut.

    What decides whether a locker ends open or closed?

    Think of a light switch flicked by a series of people walking past. Only the number of flicks matters: an odd count leaves the light on, an even count leaves it off. Locker n is flicked by student d exactly when d divides n, so its final state depends only on how many divisors n has. Locker 12 is touched by students 1, 2, 3, 4, 6 and 12, six flicks, and ends closed. Locker 16 is touched by 1, 2, 4, 8 and 16, five flicks, and ends open.

    A locker is toggled once per divisor; only perfect squares have an odd number123456789101112131415161718192021222324252627282930313233343536373839404142434445464748495051525354555657585960616263646566676869707172737475767778798081828384858687888990919293949596979899100lime: the 10 lockers left open, all perfect squaresLocker 12: touched by students 1, 2, 3, 4, 6, 121open2shut3open4shut6open12shut6 divisors, even: ends closed (1x12, 2x6, 3x4: all in pairs)Locker 16: touched by students 1, 2, 4, 8, 161open2shut4open8shut16open5 divisors, odd: ends open (4 x 4 pairs 4 with itself)Divisors come in pairs, d and n/d, except when d = n/d: a square root.
    Of the 100 lockers only the ten perfect squares stay open, because locker 12 is toggled by its six divisors and ends closed while locker 16 is toggled by its five divisors, 4 pairing with itself, and ends open.

    Why do only perfect squares have an odd number of divisors?

    Divisors arrive in pairs. If d divides n then so does n over d: for 12 the pairs are 1 and 12, 2 and 6, 3 and 4. Pairs give an even count, and the only way to break a pair is for a divisor to be its own partner, d equal to n over d, which means n is d squared. So 16 has the pairs 1 and 16, 2 and 8, and then 4 standing alone. Every perfect square has exactly one such unpaired divisor, and no other number has any, which is why the open lockers are exactly the squares.

    The relationship
    toggles(n)=#{d:d∣n}odd  ⟺  n=m2\text{toggles}(n) = \#\{d : d \mid n\} \qquad \text{odd} \iff n = m^2
    toggles(n)the number of times locker n changes state
    d | nd divides n, so student d touches locker n
    m^2a perfect square, the only case where a divisor pairs with itself
    What it says in wordsA locker is toggled once per divisor, and the count is odd only for perfect squares.

    How should you present it in the room?

    Do not simulate 100 students. Work one small locker aloud, say the pairing rule, name the exception, and list the ten squares: that is a ninety second answer that shows structure rather than stamina. Then offer the check: the number of open lockers is the whole-number part of the square root of 100, which is 10, and for 1,000 lockers it would be 31. Interviewers use this puzzle to see whether you look for the rule behind a process instead of running the process, which is the same instinct a model builder needs when a spreadsheet has a thousand rows and one formula.

    Where candidates lose it

    The usual loss is trying to simulate the first twenty lockers by hand under time pressure and never reaching the rule. The puzzle rewards stepping back and asking what one locker's fate depends on.

    The other loss is spotting that the squares stay open and being unable to say why. Have the pairing argument ready: divisors pair up, and only a square root pairs with itself.

    What the interviewer asks next

    • How many lockers end open if there are 1,000 lockers and 1,000 students?
    • Which lockers are toggled exactly twice, and what kind of numbers are they?
    • Student 1 now skips the corridor entirely. Which lockers end open?
  8. 075A tech company is worth 10x EBITDA and carries net debt of 7x EBITDA. If its enterprise value falls 10%, what happens to its equity value?Enterprise value and dilutionCoreMoelis & CompanyNew York · 2026

    Try it first

    Before you work it: how far does the equity fall?

    Show the worked solution

    The equity falls by about 33%, a third. Equity value is enterprise value less net debt: 10 minus 7, so 3 turns of EBITDA. A 10% fall takes enterprise value to 9 turns, and the lenders are still owed 7, so equity is 2 turns. From 3 to 2 is a one third fall. At 7 turns of debt on a 10 turn valuation the equity is a thin slice, and every move in the business's value is magnified 3.33 times on it.

    Why does the equity fall more than the business?

    Picture a flat bought for Rs 1 crore with a Rs 70 lakh loan. If the flat's price falls 10% to Rs 90 lakh, the bank is still owed Rs 70 lakh, so the owner's stake falls from Rs 30 lakh to Rs 20 lakh, a third. Net debt is fixed in rupees, so the whole of any fall in enterprise value comes out of the equity, and the thinner the equity slice, the larger the percentage hit. Here the equity is 3 turns of EBITDA under 7 turns of debt, so a 1 turn fall in value is a third of it.

    Debt does not move with the business, so the whole fall lands on the thin equity slicenet debt 7xequity 3xEV 10xBefore: EV 10xnet debt 7xequity 2xEV 9xAfter EV falls 10%: 9x10x7xEV -10%= -1 turndebt unchangedEquity: 3x to 2x-33%on a 10% fall in EVEV / equity = 10 / 3 = 3.33every 1% in EV is 3.33% in equity,in both directionsEV +10% would take equity to 4x: +33%EV -30% would wipe the equity outand start cutting into the debt
    With net debt fixed at 7 turns of EBITDA, a fall in enterprise value from 10 turns to 9 takes the equity from 3 turns to 2, a 33% fall, and the multiplier of 3.33 works the same way upwards, where a 10% rise in EV would lift the equity 33%.

    What is the general rule, and what does 7x tell you about sensitivity?

    The percentage move in equity is the percentage move in EV times EV over equity. At 10x EV and 7x debt that multiplier is 10 over 3, 3.33, so each 1% in enterprise value is 3.33% on the equity, up or down. That is what an interviewer means by sensitivity: 7 turns of leverage on a 10 turn valuation makes the equity a geared bet on the business. If EBITDA or the multiple slips 30%, the equity is worth nothing and the lenders start taking losses, which is why debt at that level prices as if it carried some of the equity risk.

    The relationship
    ΔEE=ΔEVEV×EVE=−10%×103=−33.3%\frac{\Delta E}{E} = \frac{\Delta EV}{EV} \times \frac{EV}{E} = -10\% \times \frac{10}{3} = -33.3\%
    Eequity value, EV less net debt, 3 turns of EBITDA
    EVenterprise value, 10 turns of EBITDA
    Delta EV / EVthe 10% fall in enterprise value
    What it says in wordsThe equity moves by the EV move scaled up by how many times EV covers the equity.
    Move in EVEV, x EBITDANet debt, x EBITDAEquity, x EBITDAMove in equity
    +10%11.07.04.0+33%
    +0%10.07.03.0+0%
    -10%9.07.02.0-33%
    -20%8.07.01.0-67%
    -30%7.07.00.0-100%
    With net debt fixed at 7 turns, each 10% step in enterprise value is a one third step in the equity, and a 30% fall in enterprise value leaves the equity worth nothing.

    Why does a banker ask a tech company this?

    Because 7 turns is a lot of debt for a business valued on growth rather than assets. If the valuation multiple compresses, as growth multiples do when rates rise or growth slows, the enterprise value can fall 10% with no change in EBITDA at all, and the equity takes a third of that on the chin. Say the assumption you leaned on: net debt stays fixed, which holds over a short window but not if the company is burning or generating cash. The question tests whether you can see leverage as a magnifier before you build a single model.

    Where candidates lose it

    The common loss is answering 10%, as if equity and enterprise value moved together. The debt sits between them and does not move, so the equity absorbs the whole fall.

    The second loss is giving 33% and stopping. The interviewer asked what 7x tells you about sensitivity, so name the multiplier, 10 over 3, and say that it works both ways.

    What the interviewer asks next

    • EBITDA falls 10% and the multiple stays at 10x. What happens to the equity, and is it the same answer?
    • At what fall in enterprise value is the equity worth nothing?
    • How does this magnifier relate to the beta of a levered company?

    Asked at Moelis & Company, Generalist, New York, 2026 (Wall Street Oasis): A tech company has leverage rate of 7X. What does it tell you about the about the impact on sensitivity?

  9. 076An office building earns net operating income of Rs 10 crore a year and trades at an 8% cap rate. If cap rates fall to 7%, what happens to its value?Valuation riddlesCoreElite boutique IBBulge bracket IB

    Try it first

    Before you compute: how much does the value move?

    Show the worked solution

    The value rises about 14%, from Rs 125 crore to Rs 142.9 crore. A cap rate is the income yield a buyer demands, so value is net operating income divided by the cap rate. Rs 10 crore over 8% is Rs 125 crore; the same Rs 10 crore over 7% is Rs 142.9 crore. The ratio of the two values is 8 over 7, a rise of 14.3%. Nothing happened to the building; the market now pays more for each rupee of its rent.

    Why does a lower cap rate mean a higher value?

    A fixed deposit paying Rs 10,000 a year is worth Rs 1.25 lakh if savers demand 8%, and Rs 1.43 lakh if they will accept 7%. The cheque has not changed; the price people pay for it has. A cap rate is the yield a buyer requires on a building's income, so value is income divided by the cap rate, and a fall in the required yield raises the price of the same income. Rs 10 crore over 0.08 is Rs 125 crore; over 0.07 it is Rs 142.9 crore. The cap rateCapitalisation rate: net operating income divided by the property value, the income yield a buyer requires. works exactly like a bond yield, and value moves the other way.

    Same Rs 10 crore of income, priced at 8 over 7: value rises one seventh6%7%8%9%10%100125150Cap rateValue, Rs crore, on Rs 10 crore of NOI8%: Rs 125 crore7%: Rs 142.9 crore+14.3%Value = NOI / cap ratenew / old = 8% / 7% = 1.143one point of cap rate, one seventh of value
    With net operating income fixed at Rs 10 crore, a fall in the cap rate from 8% to 7% lifts the building's value from Rs 125 crore to Rs 142.9 crore, a rise of 14.3%, because value is income divided by the cap rate and 8 over 7 is 1.143.

    How do you get the percentage without computing either value?

    The income cancels. The ratio of new to old value is the old cap rate over the new cap rate, 8 over 7, so the rise is one seventh, 14.3%. The move is not symmetric: the same one point rise, from 8% to 9%, would cut value by 8 over 9 minus 1, about 11.1%. Small cap rates make the swings bigger: from 5% to 4% is a 25% jump in value, from 10% to 9% only 11.1%. Say that pattern after the number, because the follow-up is usually about a different starting rate.

    The relationship
    V=NOIcV7%V8%=0.080.07=1.143⇒+14.3%V = \frac{NOI}{c} \qquad \frac{V_{7\%}}{V_{8\%}} = \frac{0.08}{0.07} = 1.143 \Rightarrow +14.3\%
    Vthe building's value
    NOInet operating income, Rs 10 crore a year
    cthe cap rate, 8% falling to 7%
    What it says in wordsValue is income over the cap rate, so the value changes by the ratio of the old cap rate to the new one.
    Cap rateValue of Rs 10 crore of NOI, Rs croreChange from the 8% case
    6%166.7+33.3%
    7%142.9+14.3%
    8%125.0+0.0%
    9%111.1-11.1%
    10%100.0-20.0%
    Each one point step in the cap rate moves the value by a different percentage, larger as the cap rate gets lower, because the value is a fixed income divided by a shrinking rate.

    What would a banker add about why cap rates move?

    Cap rates track the cost of money and the perceived risk of the rent. A fall from 8% to 7% usually means lower interest rates, more buyers chasing the asset, or more confidence in the tenant, and none of those is something the owner did. That is why a real estate team separates value created by raising income from value handed over by the market, and why an owner who bought at 8% and sells at 7% has earned a 14% gain on cap rate compression alone. Mention the limit: the formula assumes a stable income, so a building with leases about to expire does not deserve the same cap rate as one with ten years of rent locked in.

    Where candidates lose it

    The common loss is reading a falling cap rate as bad news for the value, because falling sounds like a fall. A cap rate is a yield, and a lower required yield means a higher price for the same income.

    The second loss is saying 12.5%, from 1 over 8, or 1%, from the one point move. The value scales by the ratio of the rates, 8 over 7, and saying that ratio aloud is the answer.

    What the interviewer asks next

    • NOI also rises 5% as the cap rate falls to 7%. What is the value now?
    • Why is a one point move in the cap rate a bigger deal at 5% than at 10%?
    • If the building was bought with 60% debt at the 8% cap rate, what did the cap rate move do to the equity?
  10. 078Estimate how many ATMs India needs. Walk me through the logic, then tell me whether your number is sensible.Estimation and market sizingCoreBulge bracket IBConsulting style brainteasers

    Try it first

    Which input turns a count of cash users into a count of machines?

    Show the worked solution

    About 2.7 lakh ATMs, on these assumptions. Take 100 crore adults, 80% with a bank account and half of those using ATMs: 40 crore users. Two withdrawals a month each is 80 crore a month, or 2.67 crore a day. If one machine handles about 100 withdrawals a day, you need roughly 2.67 lakh machines. Every input is an assumption to say out loud, not a fact.

    Where does population stop being the useful number?

    Think of a petrol pump. Nobody decides how many pumps a town needs by counting residents; they count cars, how often each one fills up, and how many fills one nozzle can manage in a day. ATMs work the same way. Population only tells you demand; capacity per machine is what turns demand into a number of machines. So the estimate has two halves: build daily withdrawals from people, then divide by what one machine does.

    The demand half, with round numbers. Start with about 100 crore adults, rounded so the arithmetic stays easy. Say 80% hold a bank account with a debit card, and half of those actually take cash from a machine in a typical month: 40 crore users. Two withdrawals a month each gives 80 crore withdrawals, which over 30 days is about 2.67 crore a day.

    Demand comes from people; the machine count comes from capacityAdults100 crorex 80% banked80 crorex 50% use ATMs40 crore usersx 2 a month80 crore a monthdivide by 30 days2.67 crore a daydivide by capacity100 per machine a daymachines neededabout 2.67 lakhOne machine, 24 hours100 uses x 2 min = 3.3 h00:0006:0012:0018:0024:00idleidleTheoretical maximum: 720 uses a day. Using it would cut the answer about seven times.
    Starting from 100 crore adults, the banked and ATM-using shares and two withdrawals a month give 2.67 crore withdrawals a day, and dividing by 100 uses per machine gives about 2.67 lakh ATMs, because one machine is busy only about 3.3 hours of its day.

    How many withdrawals can one machine really handle?

    A withdrawal takes about two minutes from card in to cash out, so a machine busy all 24 hours could do 720 a day. It never is. Demand bunches around mornings, lunch, evenings and salary days, and sits near zero at three in the morning. Size the machine for its realistic daily use, not its theoretical maximum, because idle night hours are capacity nobody can use. About 100 a day, a little over three hours of real use, is a fair working figure, and the one you should defend if pushed.

    The relationship
    N=A×b×u×w30×c=100 cr×0.8×0.5×230×100≈2.67 lakhN = \frac{A \times b \times u \times w}{30 \times c} = \frac{100\text{ cr} \times 0.8 \times 0.5 \times 2}{30 \times 100} \approx 2.67\text{ lakh}
    Aadults, 100 crore
    bshare with a bank account, 80%
    ushare of those who use ATMs, 50%
    wwithdrawals a month per user, 2
    cwithdrawals one machine handles a day, 100
    What it says in wordsMachines needed equal daily withdrawals divided by what one machine serves in a day.

    How do you sense-check 2.7 lakh?

    Turn the answer into a ratio a person can judge. 2.67 lakh machines for 100 crore adults is about 27 ATMs per lakh adults, or one machine for every 3,750 adults. In a city that feels like a machine every few streets; in a village it feels sparse, which matches deployment leaning toward cities. RBI publishes the actual installed count, so say you would check your figure against the latest data. The second check is direction: digital payments cut cash withdrawals, so the honest answer drifts down over time, not up. If withdrawals fall from two a month to 1.5, the requirement falls to about 2.0 lakh.

    Where candidates lose it

    The common failure is starting from population and multiplying by an ATMs-per-person figure pulled from the air. That is a guess with arithmetic around it, and the interviewer has no step to follow or challenge.

    The second loss is using a machine's theoretical capacity. Seven hundred and twenty uses a day assumes a queue at three in the morning, and it cuts the answer roughly seven times. Say why you picked 100 before anyone asks.

    What the interviewer asks next

    • How would wider UPI use change your estimate over five years?
    • How would you size the cash a bank must load into these machines each week?
    • Which single assumption would you research first, and why?
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