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Portfolio Management puzzles, solved step by step

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  1. 013A foreign equity index has 16% volatility in its local currency, and that currency has 8% volatility against the rupee. What is the volatility of an unhedged position if the two correlate at plus 0.3, and if they correlate at minus 0.3?Currency and global returnsHardGlobal investingMulti-asset

    Try it first

    With a correlation of minus 0.3, is the unhedged position riskier than the hedged one?

    Show the worked solution

    About 19.9% at plus 0.3 and 15.6% at minus 0.3. The unhedged return is roughly the local return plus the currency return, so the variances add with a correlation term: 16 squared plus 8 squared, plus or minus 2 x 0.3 x 16 x 8. That is 396.8 or 243.2, with square roots of 19.9% and 15.6%. With negative correlation the unhedged position is less volatile than the hedged one at 16%.

    How can adding a second risk reduce the total?

    Think of a shop that sells umbrellas and sunglasses. Each product's sales swing a lot with the weather, but in opposite directions, so the till is steadier than either product alone. When two sources of return tend to move against each other, combining them lowers risk even though each one is volatile on its own. For an Indian investor holding foreign shares, the currency is the second source. If the foreign currency tends to strengthen against the rupee when that market falls, it cushions the loss, and the unhedged position is steadier: 15.6% instead of 16%.

    Currency adds to or offsets local risk, depending on the sign of the correlationCorrelation +0.3local market 16currency 8unhedged: 19.916 x 16 + 8 x 8 + 2 x 0.3 x 16 x 8 = 396.8square root: 19.9% against 16.0% hedgedCorrelation -0.3local market 16currency 8unhedged: 15.616 x 16 + 8 x 8 - 2 x 0.3 x 16 x 8 = 243.2square root: 15.6% against 16.0% hedged
    Drawn as vectors, local risk of 16 and currency risk of 8 combine to 19.9 when they correlate at plus 0.3, but to only 15.6 at minus 0.3, which is below the 16 of a fully hedged position.
    The relationship
    σunhedged=σL2+σX2+2ρ σLσX=256+64±76.8\sigma_{unhedged}=\sqrt{\sigma_L^2+\sigma_X^2+2\rho\,\sigma_L\sigma_X}=\sqrt{256+64\pm 76.8}
    \sigma_Lthe index's volatility in local currency, 16%
    \sigma_Xthe currency's volatility against the rupee, 8%
    \rhothe correlation between the two, plus or minus 0.3
    What it says in wordsThe unhedged variance is the two variances plus twice the covariance, and the covariance changes sign with the correlation.

    So should a global portfolio hedge its currency?

    The puzzle gives the risk side of the answer, not the whole decision. A hedge removes the currency's volatility, but it also removes the currency's correlation with the market, and when that correlation is negative the hedge adds risk rather than cutting it. The rest of the decision is cost, which depends on the interest rate gap between the two currencies, and the investor's own liabilities in rupees. Say the limitation: correlations are measured on history and tend to shift in a crisis, so the minus 0.3 that makes the unhedged position look safer is the number least likely to hold when it matters. The formula also ignores the small cross term from multiplying the two returns.

    Where candidates lose it

    Most candidates say hedging always lowers risk, because the hedge removes a volatile exposure. That is true only when the currency correlates positively with the local market. With a negative correlation the currency is itself a hedge.

    The arithmetic trap is adding 16 and 8 to get 24, which assumes perfect correlation. Add variances, include the covariance term with its sign, then take the root.

    What the interviewer asks next

    • At what correlation is the unhedged volatility exactly 16%?
    • What does it cost to hedge, and what drives that cost?
    • Why do some investors hedge their foreign bonds but not their foreign equities?
  2. 017A coin-flip bet wins Rs 1.5 lakh or loses Rs 1 lakh. Many people refuse to play it once. Why, and what is the chance of ending with an overall loss if you play it ten times?Behavioural and decision trapsHardWealth managementAsset management

    Try it first

    Over ten independent plays, how often does the total end in a loss?

    Show the worked solution

    People refuse because a loss hurts more than an equal gain pleases, but ten plays lose money only about 17% of the time. Each play is worth plus Rs 25,000 on average. Over ten plays, four wins and six losses break even, so only three or fewer wins lose: 176 of 1,024 sequences, 17.2%. Judging each bet alone makes a good repeated bet feel bad.

    Why does a bet with a positive expected value get refused?

    Ask someone whether they would bet their weekend on a coin flip to win a second weekend, and most say no, because losing the one they have feels worse than gaining a new one feels good. This is loss aversionThe tendency, documented by Kahneman and Tversky in prospect theory, to feel a loss more strongly than a gain of the same size.. If a loss feels twice as bad as an equal gain feels good, this bet's felt value is 0.5 x 1.5 minus 0.5 x 2 x 1, which is minus 0.25 lakh, so refusing it once is consistent with how the person feels, even though its expected value is plus Rs 25,000. The factor of two is an assumption for the arithmetic, not a measured constant.

    How do you get the chance of a loss over ten plays?

    Count wins. With k wins and 10 minus k losses the total is 1.5k minus (10 minus k), which is 2.5k minus 10 lakh. That is negative only when k is three or less. Because each win outweighs each loss, you can lose six flips out of ten and still break even, which is why pooling the bets makes a loss so much rarer than a single flip suggests. The number of ways to get 0, 1, 2 or 3 wins is 1 plus 10 plus 45 plus 120, which is 176, out of 1,024 equally likely sequences: 17.2%.

    Ten plays of a +1.5 / -1 lakh coin flip: how often the total ends in a loss0.1%-10.01.0%-7.54.4%-5.011.7%-2.520.5%024.6%+2.520.5%+5.011.7%+7.54.4%+10.01.0%+12.50.1%+15.0Total after ten plays, Rs lakhLoss, 3 wins or fewer: 17.2%Break even, 4 wins: 20.5%Ahead, 5 or more wins: 62.3%Average: +2.5 lakh10 plays x Rs 25,000
    Over ten plays the total ends in a loss only with three or fewer wins, a chance of 17.2%, breaks even at four wins with 20.5%, and ends ahead 62.3% of the time, with an average gain of Rs 2.5 lakh.
    The relationship
    P(loss)=∑k=03(10k)(12)10=1+10+45+1201024≈17.2%P(\text{loss})=\sum_{k=0}^{3}\binom{10}{k}\left(\tfrac12\right)^{10}=\frac{1+10+45+120}{1024}\approx 17.2\%
    kthe number of winning flips out of ten
    \binom{10}{k}the number of sequences with exactly k wins
    What it says in wordsAdd up the sequences with three or fewer wins and divide by all 1,024 possible sequences.

    What does this mean for how clients see a portfolio?

    A client who checks a portfolio every day sees each day as a separate bet and feels every loss. Looking at the same holdings less often pools the bets, and the pooled result loses far less often than any single period does. The economist Paul Samuelson told the story of a colleague who refused one such bet but would take a hundred; the lesson for a wealth desk is to frame decisions at the horizon the money actually has. State the limitation: pooling helps only when the bets are independent and the investor can survive the bad runs, and ten plays still lose 17% of the time.

    Where candidates lose it

    Candidates call refusing the single bet irrational and move on. The interviewer wants the mechanism, loss aversion, and then the arithmetic that shows why the same person might accept the bet repeated.

    On the numbers, the slip is setting the loss threshold at fewer than five wins, as if wins and losses were the same size. Write the total as 2.5k minus 10 before you count anything.

    What the interviewer asks next

    • How many plays until the chance of an overall loss falls below 5%?
    • What if the loss were Rs 1.4 lakh instead of Rs 1 lakh?
    • Why might a client rationally refuse even the ten-play version?
  3. 018You must interview 10 fund managers one at a time, in random order, and hire or reject each on the spot, with no going back. What rule gives you the best chance of hiring the single best manager, and what is that chance?Probability and expected valueHardMulti-manager allocationFund selection

    Try it first

    How many managers should you see and pass on before you are willing to hire?

    Show the worked solution

    Interview and pass on the first 3, then hire the first manager better than all of them. You get the best one about 40% of the time. The first three set the bar at no cost but the chance the best is among them. Passing on 4 gives almost the same, 39.8%. As the number of candidates grows, the rule becomes: pass on about 37%, one over e, and the chance of success tends to 37% too.

    Why pass on anyone at all?

    Think of house hunting in a fast market where every flat is gone the moment you walk away. If you sign the first one, you have no idea whether it was good. If you look at every flat before deciding, the best has already been taken. A short look-only phase buys you a benchmark; after that, the first candidate who beats the benchmark is likely to be the best overall. The cost is that the best might be inside the look-only phase, which happens with chance r in 10 if you pass on r. Hiring the first manager blindly succeeds only 10% of the time.

    Chance of hiring the best of 10, by how many you pass on first10.0%028.3%136.6%239.9%339.8%437.3%532.7%626.5%718.9%810.0%9Managers interviewed and passed on before you are willing to hirePass on 3, then hire the firstwho beats all of them
    With 10 managers, the chance of hiring the best rises from 10% if you pass on none to a peak of 39.9% if you pass on 3, then falls back to 10% if you pass on 9, because waiting too long is as costly as not waiting.

    How do you compute the chance for a given rule?

    Suppose you pass on r and the best manager sits at position i, after r. You hire them only if nobody between r and i beat the first r, which happens when the best of the first i minus 1 candidates is among the first r: a chance of r over i minus 1. Averaging over where the best one sits gives r over 10 times the sum of 1 over (i minus 1), for i from r plus 1 to 10. For r equals 3 that is 0.3 times (1/3 + 1/4 + ... + 1/9), which is 0.3987. The curve is flat near the top: 3 and 4 differ by less than half a point.

    The relationship
    P(r)=rn∑i=r+1n1i−1P(3)=0.3(13+14+⋯+19)≈0.399P(r)=\frac{r}{n}\sum_{i=r+1}^{n}\frac{1}{i-1} \qquad P(3)=0.3\left(\tfrac13+\tfrac14+\dots+\tfrac19\right)\approx 0.399
    nthe number of candidates, 10
    rhow many you interview and pass on first
    ithe position of the best candidate
    What it says in wordsThe chance of success is the share you skip times the sum, over later positions, of the chance that no one between beats your benchmark.

    Say the limitation, because allocators hear this puzzle and then ask about real selection. The rule maximises the chance of the single best and scores a second-best hire as a total failure. Real allocators care about hiring someone good, can often revisit a manager, and rarely see candidates in random order, and each of those changes the rule.

    Where candidates lose it

    Candidates either hire early because a manager looks strong, or propose looking at half the field before deciding. Both lose most of the value. The interviewer wants the look-then-leap structure and a number.

    The other lost point is stopping at 3 without the general rule. Offer the one-over-e result for large fields: pass on about 37% and win about 37% of the time.

    What the interviewer asks next

    • What changes if you only need a manager in the top three?
    • With 100 candidates, how many should you pass on?
    • How would you adapt the rule if you could call back a rejected manager with some probability?
  4. 020A stock trades at 60 times earnings and pays no dividend, and its investors require 12% a year. If it should trade at 20 times earnings in ten years, what annual earnings growth does today's price require?Valuation riddlesHardFundamental asset managementAsset management

    Try it first

    Which growth rate does the 60x multiple imply?

    Show the worked solution

    About 25% a year for ten years. With no dividend, all of the 12% return must come from price, so the price in ten years must be 60 x 1.12 to the tenth, about 186 times today's earnings. If the stock then trades at 20 times, earnings must be 186 divided by 20, or 9.32 times today's. That is growth of 25.0% a year. At 15% growth the investor would earn only about 3% a year.

    How do you turn a multiple into a growth forecast?

    Think of paying 60 years of a shop's current profit for the shop. That only makes sense if the profit is going to be far bigger soon. A high multiple is a forecast you can read: work forward from the return investors want, and back from the multiple the stock should end at, and the growth in between is what the price assumes. Here the investor wants 12% a year with no dividend, so the price must grow 3.11 times in ten years, to about 186 times today's earnings. At a mature 20 times, earnings must reach 9.32 times today's level.

    What a 60x multiple needs: earnings growth of 25% a year for a decade2468100246810YearsEarnings, today = 1needed: 9.32at 15%: 4.05gapPrice in 10 years60 x 1.12^10 = 186.4At 20x, earningsmust be 9.32Growth needed25.0% a yearAt 15%: returnonly 3.0% a year
    To justify 60 times earnings today and 20 times in ten years at a 12% return, earnings must grow 25% a year to 9.32 times today's level, while a 15% path reaches only 4.05 and would leave the investor with about 3% a year.
    The relationship
    g=(PE0(1+r)10PE10)1/10−1=(60×3.10620)1/10−1≈25%g=\left(\frac{PE_0(1+r)^{10}}{PE_{10}}\right)^{1/10}-1=\left(\frac{60\times 3.106}{20}\right)^{1/10}-1\approx 25\%
    PE_0, PE_{10}the multiple today, 60, and in ten years, 20
    rthe required return, 12%, all from price since there is no dividend
    gthe annual earnings growth the price requires
    What it says in wordsThe earnings growth needed is the required price growth, adjusted for the multiple shrinking from 60 to 20.

    What do you do with the number once you have it?

    You ask how often a company sustains that growth for a decade, which is rarely, and you say so. The question the interviewer wants answered is not whether the company is good but whether the price has already paid for more than the company is likely to deliver. At a still strong 15% a year, earnings reach 4.05 times today's, the price at 20 times is about 81, and the investor earns about 3.0% a year rather than 12%. Say the limitations: the exit multiple of 20 is an assumption, and buybacks, dividends or a higher exit multiple would lower the growth needed.

    Where candidates lose it

    The common error is saying the stock needs to grow earnings at 12%, the required return. That ignores the multiple falling from 60 to 20, which on its own costs about 10% a year of price.

    The other trap is stopping at the arithmetic. On a fundamental desk the interviewer wants the judgement: 25% for a decade is a demanding assumption, and a reverse calculation like this is how you show a price is stretched without claiming to know the future.

    What the interviewer asks next

    • What growth is needed if the stock still trades at 40 times in ten years?
    • How does paying a 2% dividend change the answer?
    • What required return does today's price imply if earnings grow at 15%?
  5. 021Analyst A has an information coefficient of 0.10 on 25 independent bets a year. Analyst B has an information coefficient of 0.03 on 400 independent bets a year. Whose information ratio is higher?Performance measurementHardQuantitative asset managementSystematic investing

    Try it first

    Which analyst has the higher information ratio?

    Show the worked solution

    Analyst B, with 0.6 against 0.5. By the fundamental law of active management, the information ratio is roughly the information coefficient times the square root of the number of independent bets. A gets 0.10 times the root of 25, which is 5, for 0.5. B gets 0.03 times the root of 400, which is 20, for 0.6. Breadth beats accuracy here, but only if B's bets really are independent.

    How can a less accurate analyst add more value?

    Think of two shopkeepers. One makes a large margin on a few sales a day; the other makes a thin margin on hundreds. The second can earn more, and with less swing day to day, because many small edges average into a steadier total. Active return grows with the number of bets while its noise grows only with the square root, so the ratio of the two rises with the square root of breadth. This is Grinold's fundamental lawRichard Grinold's result that a strategy's information ratio is approximately its information coefficient times the square root of its breadth. of active management. B's skill is under a third of A's, but B's root breadth is four times A's.

    Information ratio = skill x square root of independent betsAnalyst A: accurate, few betsSkill (IC)0.10Root of betsroot 25 = 5Information ratio0.5bars scaled to the larger of the twoAnalyst B: thin edge, many betsSkill (IC)0.03Root of betsroot 400 = 20Information ratio0.6bars scaled to the larger of the twoB's edge rests on breadth. If B's 400 bets move together like 100 independent ones:0.03 x root 100 = 0.3, and A's 0.5 is ahead again.
    Analyst A's skill of 0.10 on a root breadth of 5 gives an information ratio of 0.5, while analyst B's skill of 0.03 on a root breadth of 20 gives 0.6, unless B's bets are correlated enough to count as only 100, which cuts B to 0.3.
    The relationship
    IR≈IC×BRA:0.1025=0.5B:0.03400=0.6IR\approx IC\times\sqrt{BR} \qquad A: 0.10\sqrt{25}=0.5 \qquad B: 0.03\sqrt{400}=0.6
    ICthe information coefficient: the correlation between forecasts and outcomes
    BRbreadth: the number of independent bets a year
    IRthe information ratio: active return per unit of tracking error
    What it says in wordsSkill times the square root of independent bets gives the information ratio.

    Where does the argument break?

    At the word independent. Four hundred bets that all lean on the same factor, say cheap stocks, behave like far fewer independent bets, and breadth has to be counted in independent bets, not trades. If B's 400 positions carry the information of only 100 independent ones, B's ratio is 0.03 times 10, which is 0.3, and A is ahead again. The law also ignores costs: 400 bets a year means more turnover, and a thin edge of 0.03 is the first thing trading costs eat. A portfolio manager hiring between the two would ask B how correlated the signals are before believing the 0.6.

    Where candidates lose it

    The instinctive answer is A, because a coefficient of 0.10 sounds far better than 0.03. The interviewer is testing whether you know breadth enters the formula at all.

    The second trap is taking B's 400 at face value. The follow-up is almost always what if the bets are correlated, and the answer is that breadth shrinks and B's advantage can vanish.

    What the interviewer asks next

    • How many independent bets would A need to match B?
    • How would you estimate the effective number of independent bets in a portfolio?
    • Why do trading costs hit analyst B harder than analyst A?
  6. 022A private fund calls Rs 100 crore from an investor today and returns Rs 200 crore in five years, an IRR of about 14.9%. If the fund instead uses a credit line to delay the call by one year, at a borrowing cost of Rs 8 crore paid out of the final distribution, what happens to the IRR and to the multiple of money?Private and real asset mathsHardPrivate markets

    Try it first

    With the credit line, what happens?

    Show the worked solution

    The IRR rises to about 17.7% while the multiple falls from 2.00x to 1.92x. With the line, the investor pays Rs 100 crore at year 1 instead of year 0 and receives Rs 192 crore at year 5 after the borrowing cost. That is 1.92 times the money over four years, 17.7% a year, against 2.00 times over five years, 14.9%. The investor ends with Rs 8 crore less, and the reported IRR looks better.

    How can the return rise when the investor gets less money?

    Imagine lending a friend money: getting back Rs 192 after four years can be a better annual rate than Rs 200 after five, even though Rs 200 is more money. IRR measures speed, not size, so anything that shortens the time the investor's money is out raises it, even at a cost. A subscription lineA short-term loan to a private fund, secured on investors' commitments, used to delay capital calls. does exactly that. The fund's deal is identical; only the investor's clock starts a year later.

    A later call lifts the IRR while the investor ends with lessWithout credit linemultiple 2.00xIRR 14.9%Y0Y1Y2Y3Y4Y5-100 called+200With credit linemultiple 1.92xIRR 17.7%Y0Y1Y2Y3Y4Y5-100 called+192line funds year 1after -8 interest
    Without the credit line the investor pays 100 at year 0 and gets 200 at year 5, an IRR of 14.9% and 2.00x; with it the investor pays 100 at year 1 and gets 192 at year 5, an IRR of 17.7% but only 1.92x.
    The relationship
    (200100)1/5−1≈14.9%(192100)1/4−1≈17.7%\left(\frac{200}{100}\right)^{1/5}-1\approx 14.9\% \qquad \left(\frac{192}{100}\right)^{1/4}-1\approx 17.7\%
    200, 192the distribution at year 5 without and with the line, Rs crore
    1/5, 1/4one over the years the investor's money is at work
    What it says in wordsWith a single call and a single distribution, the IRR is the multiple raised to one over the years, minus one.

    Is the investor better or worse off?

    It depends on what the investor does with the Rs 100 crore during the extra year. If the idle money earns less than the Rs 8 crore the line costs, the investor is worse off even though the fund reports a higher IRR. That is why allocators look at the multiple and the IRR together, and increasingly ask for IRRs calculated both with and without the effect of credit lines. Say the limitation: this example uses one call and one distribution; real funds call and return money in many pieces, and the line's effect on IRR is largest in the early years of a fund.

    Where candidates lose it

    Candidates say both numbers fall, because the line costs money. They miss that IRR is time-weighted and rewards a later call.

    The deeper trap is stopping at the arithmetic. The interviewer on a private markets desk wants to hear that a higher IRR here does not mean a better result for the investor, and that the multiple exposes it.

    What the interviewer asks next

    • What if the line delays the call by two years at a cost of Rs 16 crore?
    • What return must the investor earn on the idle Rs 100 crore to break even?
    • Why do some investors prefer to see a fund's multiple before its IRR?
  7. 023A portfolio manager decides to buy 10,000 shares when the price is Rs 100. The trading desk fills 60% of the order at an average of Rs 101.2, and the rest goes unfilled as the price closes the day at Rs 104. What is the implementation shortfall?Funds, ETFs and implementationHardPortfolio implementationInstitutional asset management

    Try it first

    Which part of the shortfall is larger?

    Show the worked solution

    Rs 23,200, or 2.32% of the Rs 10 lakh intended trade. Against a paper portfolio that bought all 10,000 shares at the decision price of Rs 100, the 6,000 filled at Rs 101.2 cost Rs 7,200 in execution. The 4,000 unfilled shares missed a rise to Rs 104, an opportunity cost of Rs 16,000. The order you did not fill cost more than the one you did.

    What is the shortfall measured against?

    Think of deciding to buy a train ticket at the counter price, then finding the queue slow: you pay a bit more for some of the group's tickets, and the rest miss the train and take a dearer taxi. The cost of the trip is measured against the plan, not against what you ended up doing. Implementation shortfall compares the real portfolio with a paper portfolio that traded everything instantly at the decision price, so both the extra paid and the move missed count as cost. The idea is due to Andre Perold, and the benchmark here is Rs 100, the price when the decision was made.

    Implementation shortfall: the order you did not fill cost more than the one you didExecution cost6,000 filled x (101.2 - 100)Rs 7,200 (0.72%)Opportunity cost4,000 unfilled x (104 - 100)Rs 16,000 (1.60%)Total shortfallof the Rs 10 lakh intendedRs 23,200 (2.32%)Benchmark: the decision price of Rs 100. Both costs are measured against it,so an unfilled order is charged for the move it missed.
    Against a decision price of Rs 100, the 6,000 shares filled at Rs 101.2 cost Rs 7,200 and the 4,000 unfilled shares cost Rs 16,000 as the price rose to Rs 104, a total shortfall of Rs 23,200, or 2.32% of the intended trade.
    ComponentSharesPer share, RsCost, RsShare of Rs 10 lakh
    Execution cost6,0001.27,2000.72%
    Opportunity cost4,0004.016,0001.60%
    Total10,00023,2002.32%
    The execution and opportunity costs add to a shortfall of Rs 23,200, 2.32% of the intended Rs 10 lakh purchase.

    What should the manager take from the split?

    That trading patiently is not free. A desk that works an order slowly to keep execution cost down can lose more to the price running away, so the right trading speed depends on how fast the manager's idea is likely to be priced in. Here the price moved 4% in a day, a sign the idea was urgent, or that the buying itself pushed the price. Say the limitations: explicit costs such as commission and taxes should be added on top, and the unfilled shares are charged at the closing price by convention; had the order been cancelled deliberately, a different end point might be fairer.

    Where candidates lose it

    Most candidates measure only the execution cost, 1.2% on the filled shares, and forget that shares never bought still cost the fund. The unfilled 40% is the bigger number here.

    The second slip is the base. Express the shortfall against the whole intended trade, Rs 10 lakh, not against the Rs 6 lakh filled, or the number cannot be compared across orders.

    What the interviewer asks next

    • What if the price had closed at Rs 99 instead?
    • How would you decide how fast to trade the order?
    • Why might a VWAP benchmark make the same desk look good?
  8. 024A fund's measured alpha is 4% a year, with a standard error of 3%. Across all funds, true alphas average zero with a spread (standard deviation) of 1.5%. What is your best estimate of this fund's true alpha?Statistics and forecastingHardFund selectionQuantitative asset management

    Try it first

    Best estimate of the true alpha?

    Show the worked solution

    About 0.8% a year. Combine the fund's noisy measurement with what you know about funds in general, weighting each by its precision. The measurement's variance is 3 squared, 9; the spread of true alphas has variance 1.5 squared, 2.25. The measurement gets 2.25 / 11.25, a weight of 0.2, so the estimate is 0.2 x 4% + 0.8 x 0%, which is 0.8%. A noisy 4% deserves heavy shrinkage toward zero.

    Why not take the 4% at face value?

    A new restaurant with two five-star reviews is probably good, but you would not bet it beats every restaurant in town with thousands of reviews. When a measurement is noisy compared with how much things really differ, most of an extreme reading is luck, so the best estimate sits much closer to the average. Here true alphas across funds rarely stray far from zero, a spread of 1.5, while one fund's measured alpha can miss the truth by 3. A reading of 4% is far more likely to be a modest fund that got lucky than a fund with a true 4%.

    A noisy 4% alpha, pulled toward the zero average of all funds-6%-4%-2%0%2%4%6%8%10%12%True alpha, per cent a yearbest estimate: 0.8%all funds: 0%, spread 1.5measured: 4%, spread 34% pulled 80% of the way back toward 0%
    The prior for all funds is centred on zero with a spread of 1.5 and the fund's measurement on 4% with a spread of 3, so the combined estimate lands at 0.8%, with a spread of 1.34, pulled 80% of the way back to zero.
    The relationship
    α^=τ2τ2+s2 αobs=2.252.25+9×4%=0.8%\hat\alpha=\frac{\tau^2}{\tau^2+s^2}\,\alpha_{obs}=\frac{2.25}{2.25+9}\times 4\%=0.8\%
    \tauthe spread of true alphas across funds, 1.5%
    sthe standard error of this fund's measured alpha, 3%
    \alpha_{obs}the measured alpha, 4%
    What it says in wordsThe estimate is the measured alpha scaled by how much of the total variance comes from real differences between funds.

    How does a fund selector use this?

    By refusing to rank funds on raw past alpha. Shrinkage keeps the ranking but compresses it, so a fund with a long, steady record keeps more of its measured alpha than one with a short, volatile record showing the same number. A fund whose standard error was 1% instead of 3% would keep 2.25 / 3.25, about 69% of its 4%. Say the limitations: the result depends on the assumed spread of true alphas, which itself is estimated, and on the average being zero; if the fund belongs to a peer group with a known positive or negative average, shrink toward that instead.

    Where candidates lose it

    Most candidates either take the 4% as measured, ignoring the noise, or answer zero, ignoring the evidence. The interviewer wants the weighted middle and the reason for the weights.

    The arithmetic slip is weighting by standard deviations, 1.5 and 3, instead of variances, which gives one third and 1.3%. Precision is one over the variance, so square before you weight.

    What the interviewer asks next

    • What if the fund had 20 years of data and a standard error of 1%?
    • How would you estimate the spread of true alphas across funds?
    • Why does this argument make top-quartile rankings unstable from one year to the next?
  9. 039A 60/40 portfolio holds equities with 18% volatility and bonds with 6% volatility, and the two correlate at 0.1. What is the portfolio's volatility, and what share of its risk comes from equities?Portfolio risk mathsHardMulti-assetAsset allocation

    Try it first

    Roughly what share of the portfolio's risk comes from the 60% in equities?

    Show the worked solution

    Volatility is about 11.3%, and equities contribute about 93% of the risk. The variance is 0.36 x 324 plus 0.16 x 36 plus 2 x 0.6 x 0.4 x 0.1 x 18 x 6, which is 116.64 plus 5.76 plus 5.18, or 127.58. The square root is 11.3%. Equities' own term plus half the cross term is 119.2, which is 93% of the total.

    Why does 60% of the money carry more than 90% of the risk?

    Picture a household with two earners, one a salaried clerk and one a commission-only salesperson. The salesperson may bring in 60% of the money but almost all of the month-to-month swings. Risk contribution depends on weight times volatility, and variance squares it, so a sleeve three times as volatile with more capital swamps the other. Equities' variance term is 0.36 times 324, or 116.6; bonds' is 0.16 times 36, or 5.76. Twenty to one before the cross term.

    Capital split 60/40, risk split about 93/760%40%Capital93.5%6.5% bondsRiskEquitiesBondsBonds: 40% of capital,only 6.5% of the riskVariance, % squaredEquities 0.6² x 18² = 116.64Bonds 0.4² x 6² = 5.76Cross term = 5.18Total = 127.58Volatility = 11.30%
    Capital is split 60/40, but equities supply 93.5% of the portfolio's variance and bonds only 6.5%. The portfolio's volatility is 11.30%, so a 60/40 portfolio behaves almost entirely like an equity portfolio with the volume turned down.

    How do you split the risk between the two sleeves?

    Give each asset its own variance term plus half of the cross term. An asset's risk contribution is its weight times its covariance with the whole portfolio, and the contributions add to the total variance. For equities that is 0.6 x (0.6 x 324 + 0.4 x 10.8), which is 0.6 x 198.72, or 119.23. Divided by 127.58, that is 93.5%. Bonds take the remaining 6.5%.

    The relationship
    σp2=we2σe2+wb2σb2+2wewbρ σeσbRCe=we (weσe2+wb ρ σeσb)σp2\sigma_p^2 = w_e^2\sigma_e^2 + w_b^2\sigma_b^2 + 2 w_e w_b \rho\,\sigma_e\sigma_b \qquad RC_e = \frac{w_e\,(w_e\sigma_e^2 + w_b\,\rho\,\sigma_e\sigma_b)}{\sigma_p^2}
    w_e, w_bthe capital weights, 60% and 40%
    \sigma_e, \sigma_bthe volatilities, 18% and 6%
    \rhothe correlation, 0.1
    RC_ethe equity share of portfolio variance
    What it says in wordsPortfolio variance is each asset's own variance plus the cross term, and each asset's share is its weight times its covariance with the portfolio.

    This is the arithmetic behind risk parity, which sizes each sleeve so that the risk contributions are equal rather than the capital. To give bonds half the risk here, the portfolio would hold roughly three times as much bond capital as equity, and often borrow to lift the return. The limitation: correlation is not stable. In some years stocks and bonds fall together, and the 7% can grow quickly.

    Where candidates lose it

    The first slip is saying the portfolio volatility is 0.6 x 18 plus 0.4 x 6, which is 13.2%. That ignores diversification and would be right only at a correlation of one. The second is reporting 60% as the equity risk share because that is the capital share.

    Write the three variance terms, take the square root, then split. The whole point of the question is the gap between 60 and 93, so say it in a sentence.

    What the interviewer asks next

    • What equity weight gives equal risk contributions from the two sleeves?
    • How does the equity risk share change if the correlation rises to 0.5?
    • Why might a pension fund still describe itself as 60/40 despite this?
  10. 049Fund rankings persist from one year to the next with a correlation of 0.2. A fund was in the top decile of its category last year. Where do you expect it to rank this year?Behavioural and decision trapsHardFund selectionPerformance analysis

    Try it first

    Where should you expect last year's top-decile fund to land this year?

    Show the worked solution

    Around the 64th percentile, still above average but most of the way back to the middle. On a normal scale, the top decile averages about 1.75 standard deviations above the median. With a correlation of 0.2, the expected position this year is a fifth of that, 0.35, which is about the 64th percentile. The quick linear version, 50 plus 0.2 x 45, gives the 59th.

    Why should a top-decile fund be expected to fall back?

    Think of a student who topped one exam. Part of that was knowing the subject and part was that the questions happened to suit them. Next time, the knowledge carries over and the luck does not. An extreme result is usually a mix of skill and a large dose of luck, and only the skill is expected to repeat, so the best forecast moves back towards the average by however much luck there was. A correlation of 0.2 says four fifths of last year's spread in rankings was the non-repeating kind.

    With persistence of 0.2, next year's expected rank hugs the middle00252550507575100100Percentile rank last yearExpected rank this yearperfect persistencepure luck: 50top decile: 96thTop-decile fundaverage z last year 1.75x 0.2 = 0.35about 64th pctexpected this year(shortcut: 59th)
    With a year-to-year correlation of 0.2, the expected rank this year is a flat curve close to the 50th percentile. A top-decile fund, averaging about the 96th percentile last year, is expected around the 64th this year, far below the diagonal that perfect persistence would give.

    How do you turn a rank correlation into an expected rank?

    Work on a normal-score scale, where the regression is a straight line through the middle. The expected score this year is the correlation times last year's score, so a correlation of 0.2 keeps one fifth of the distance from average. The top decile's average score is the normal density at its cut-off, 1.28, divided by 0.1, which is about 1.75. A fifth of that is 0.35, and the normal table turns it into the 64th percentile. If you skip the normal scale and pull the 95th percentile a fifth of the way from 50, you get about the 59th, a fair first answer.

    The relationship
    E[zt+1∣zt]=ρ ztzˉtop 10%=φ(1.28)0.10≈1.75Φ(0.2×1.75)≈0.64E[z_{t+1} \mid z_t] = \rho\, z_t \qquad \bar{z}_{top\,10\%} = \frac{\varphi(1.28)}{0.10} \approx 1.75 \qquad \Phi(0.2 \times 1.75) \approx 0.64
    \rhothe year-to-year correlation of rankings, 0.2
    z_tlast year's normal score
    \varphi, \Phithe standard normal density and cumulative probability
    What it says in wordsNext year's expected score keeps only the correlation's share of this year's distance from the middle.

    Then say what a fund selector does with it. Chasing last year's top decile buys mostly luck at a high price, often just as new money floods in. The answer is not to ignore performance but to weight longer records, look for a process that explains the result, and set expectations that even a genuinely good fund will usually rank well below where it did in its best year.

    Where candidates lose it

    The two extreme answers both lose the point. Expecting the fund to stay in the top decile ignores that a correlation of 0.2 is weak. Expecting it to fall below average overshoots: regression pulls results back towards the middle, not past it.

    Say one fifth of the distance, give the 64th percentile on the normal scale or the 59th with the quick version, and explain that the difference comes from how extreme the top decile really is. Then draw the selection lesson.

    What the interviewer asks next

    • What persistence correlation would keep a top-decile fund in the top quartile on average?
    • How does the answer change if you look at five-year rankings instead of one?
    • Why do flows into last year's best funds tend to make this problem worse?
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