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Portfolio Management puzzles, solved step by step

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Showing 61–69 of 69 · filtered from 100Clear filters
  1. 089A 10-year bond has a modified duration of 7 and convexity of 60. Estimate its price change for a 100 basis point fall in yield, and for a 100 basis point rise.Bond mathsCoreFixed income

    Try it first

    Which pair of estimates is right?

    Show the worked solution

    About +7.3% if yields fall 100 basis points and -6.7% if they rise 100. Duration alone gives 7% either way. Convexity adds half of 60 times 0.01 squared, which is 0.3%, in both directions, because the yield change is squared. So the gain is bigger than the loss for the same size of move.

    Why does convexity help in both directions?

    A ball rolling in a bowl rises the same way whichever side you push it. The convexity term depends on the yield change squared, so it is positive whether yields rise or fall: it adds to the price gain when yields drop and cushions the loss when they climb. Duration is the straight tangent to the price curve; convexity measures how far the real curve bends above it.

    Convexity lifts the curve above the tangent on both sides-4-3-2-1+1+2+3+4-20%-10%+10%+20%+30%At -4 points:curve +32.8%, tangent +28%At +4 points:curve -23.2%, tangent -28%shaded gap = convexityduration + convexityduration onlyyield change, pointsAt 100 bpYield falls+7.0 duration+0.3 convexity+7.3%Yield rises-7.0 duration+0.3 convexity-6.7%gain beats loss
    The duration-only tangent predicts a 7% move each way, but the curved estimate that adds convexity sits above it on both sides, giving +7.3% for a 100 basis point fall and -6.7% for a 100 basis point rise, with the gap widening for bigger moves.
    The relationship
    ΔPP≈−Dmod Δy+12 C (Δy)2=−7(±0.01)+30(0.0001)\frac{\Delta P}{P} \approx -D_{mod}\,\Delta y + \tfrac12\,C\,(\Delta y)^2 = -7(\pm 0.01) + 30(0.0001)
    D_modmodified duration, 7
    Cconvexity, 60
    Delta ychange in yield, plus or minus 0.01
    What it says in wordsThe price change is the duration effect plus a small positive bend that grows with the square of the move.

    How big does convexity get, and what does it cost?

    At 100 basis points the bend is only 0.3%, but it grows with the square: at 400 basis points it is 4.8%, a large share of the move. That asymmetry is valuable in volatile markets, so bonds with more convexity usually trade at a slightly lower yield: you pay for it through carry. Callable bonds and many mortgage securities have negative convexity, and for them the sign flips: losses outrun gains.

    Say the limit too. This is a second-order estimate. For very large moves the true price differs again, and an interviewer may ask you to reprice the bond from its cash flows instead.

    Where candidates lose it

    The common slip is attaching the convexity term with the sign of the yield move, giving +6.7% and -7.3%. That shows the candidate memorised a formula without seeing that the squared term cannot be negative.

    The other loss is saying the answer is symmetric at 7% each way. Duration alone is a straight line; naming convexity is the point of the question.

    What the interviewer asks next

    • Why does a callable bond have negative convexity at low yields?
    • Two bonds have the same duration; one has higher convexity. Which would you rather own, and what does it cost?
    • Estimate the price change for a 250 basis point rise.
  2. 090Two retirees each start with Rs 1 crore and withdraw Rs 10 lakh at the end of every year. One earns minus 20%, plus 10% and plus 30% over three years; the other earns the same returns in reverse order. Who ends with more, and by how much?Compounding and fee dragCoreRetirement and pensionsWealth management

    Try it first

    Who ends with more?

    Show the worked solution

    The retiree with the good year first ends with Rs 87.6 lakh, against Rs 77.1 lakh, a gap of Rs 10.5 lakh. Without withdrawals both would end at Rs 114.4 lakh, because the order of multiplication does not matter. Withdrawals break that: in the bad-first order, the money taken out early misses the strong returns that come later.

    Why does the order suddenly matter?

    A shop owner who must pay a fixed rent every month is hurt more by a bad first quarter than a bad last one: an early slump forces them to dip into stock just when prices are low. Without withdrawals, 0.8 x 1.1 x 1.3 gives the same answer in any order; with fixed withdrawals, each rupee taken out misses every return after it, so losses early in retirement do lasting damage.

    Same three returns, opposite order: withdrawals lock in an early loss6080100120140Year 0Year 1Year 2Year 3+30%, then -10 lakh-20%, then -10 lakh87.677.1Order: +30, +10, -20Order: -20, +10, +30Gap: 10.5 lakhRs lakhNo withdrawals:both end at 114.4
    Starting from Rs 1 crore with Rs 10 lakh withdrawn each year, the bad-year-first path ends at Rs 77.1 lakh and the good-year-first path at Rs 87.6 lakh, although both would reach Rs 114.4 lakh with no withdrawals.

    Where exactly does the Rs 10.5 lakh go?

    Think of each withdrawal as money that would otherwise have kept compounding. The ending balance equals the no-withdrawal result less each withdrawal grown at the returns it missed. In the bad-first order the first Rs 10 lakh misses a 10% and a 30% year, so it costs 14.3 lakh of ending wealth; in the good-first order it misses a 10% gain and a 20% fall, so it costs only 8.8.

    WithdrawalBad year first: cost at the endGood year first: cost at the end
    End of year 114.38.8
    End of year 213.08.0
    End of year 310.010.0
    Total taken from the no-withdrawal Rs 114.4 lakh37.326.8
    Each Rs 10 lakh withdrawal costs the ending balance its own value grown at the returns it missed, which totals Rs 37.3 lakh in the bad-first order and Rs 26.8 lakh in the good-first order.

    This is sequence-of-returns risk, and it is why retirement planners hold a cash or short-bond buffer for the first few years of withdrawals, or vary withdrawals with markets. The same logic runs in reverse for someone still saving: early losses hurt a saver less, because little money is invested yet.

    Where candidates lose it

    The trap is answering that order cannot matter because multiplication commutes. That is true for a lump sum left alone and exactly wrong once money moves.

    The second loss is getting the two balances without explaining why. Give the one-line mechanism: each withdrawal misses the returns that follow it.

    What the interviewer asks next

    • What happens to the gap if the withdrawal doubles to Rs 20 lakh?
    • Does the order matter for someone making equal yearly contributions instead?
    • How would you protect a new retiree against a bad first year?
  3. 091A trader bets on a fair coin, starting at Rs 1,000 and doubling the stake after every loss until a win, then starting again. The trader has Rs 63,000. What does each cycle win, how often does it wipe out, and what is the expected value?Behavioural and decision trapsCoreHedge fundsRisk management

    Try it first

    What is the expected value of one cycle?

    Show the worked solution

    Each cycle wins Rs 1,000 with probability 63 in 64 and loses Rs 63,000 with probability 1 in 64, so the expected value is exactly zero. The capital covers six stakes, Rs 1,000 up to Rs 32,000, so six straight losses, a 1 in 64 chance, wipe it out. Doubling down turns many small wins into one rare, large loss without creating any edge.

    Why does it feel like a sure thing?

    A driver who never buys insurance saves the premium every month and feels clever for years, until the one accident. Doubling after each loss produces a long run of small wins because the one outcome that loses, six tails in a row, is rare, but when it comes it is sixty three times the usual win. Short track records of such strategies look excellent, which is exactly the danger.

    Each loss doubles the next stake until the capital runs outLoss 1stake 1kLoss 2stake 2kLoss 3stake 4kLoss 4stake 8kLoss 5stake 16kLoss 6stake 32kRs 63,000 gone64k?No moneyfor 64kbars: stake on that tossline: total lost so farOne cycleWin Rs 1,000chance 63 in 64Lose Rs 63,000chance 1 in 64Expected value0Over 50 cycles, chanceof at least one wipe-out54%
    Six straight losses with doubling stakes of Rs 1,000 to Rs 32,000 use up the whole Rs 63,000, and the seventh stake cannot be placed; the cycle wins Rs 1,000 sixty three times in sixty four and loses Rs 63,000 once, for an expected value of zero.
    The relationship
    E=6364(1,000)−164(63,000)=984.4−984.4=0E = \tfrac{63}{64}(1{,}000) - \tfrac{1}{64}(63{,}000) = 984.4 - 984.4 = 0
    63/64chance of at least one head in six tosses
    1/64chance of six tails in a row
    What it says in wordsFrequent small wins and a rare large loss cancel exactly on a fair coin.

    What does this teach about judging a strategy?

    Run it 50 times and the chance of at least one wipe-out is about 54%, yet most individual traders running it for a few weeks will show a smooth profit. A win rate says nothing on its own; what matters is the size of the losses relative to the wins, and whether the worst case can end the game. Selling far out-of-the-money options has the same shape: steady premium income, and occasionally a loss that erases years of it.

    Say the limitation of the fix people suggest. More capital only pushes the wipe-out further out and makes it bigger: with infinite money and no stake limit the strategy would work, and nobody has either.

    Where candidates lose it

    The trap is being impressed by the 98.4% win rate. The interviewer is checking whether you weigh outcomes by size as well as frequency.

    The second loss is saying the strategy is negative in expectation. On a fair coin it is exactly zero; the harm is in the shape, a small chance of ruin, not in the average. Say both halves.

    What the interviewer asks next

    • The coin pays slightly less than even money. What happens to the expected value?
    • Where do you see this payoff shape in real portfolios?
    • How would you size risk so that no single loss can end the strategy?
  4. 092The dollar-rupee spot rate is 84, one-year rupee interest rates are 6.5% and one-year dollar rates are 4.5%. What is the one-year forward rate, and what does hedging the currency do to an Indian investor's return on a dollar deposit?Currency and global returnsCoreGlobal investingFixed income

    Try it first

    For the Indian investor holding dollars, is the hedge a cost or a gain?

    Show the worked solution

    The forward is about 85.61, a 1.9% premium to spot, and hedging lifts the dollar deposit's return to about 6.5% in rupees. Converting, earning 4.5% and selling forward must give the same rupees as simply earning 6.5% at home. For an Indian investor holding dollars the hedge earns the 1.9% premium; it is a cost only for someone on the other side.

    Why is the forward rate set by interest rates rather than forecasts?

    If two shops sell the same phone at different prices with free delivery between them, someone will buy in one and sell in the other until the gap closes. Investing rupees at home and converting to dollars, investing and selling forward are both riskless routes from the same starting sum, so they must end at the same number of rupees; the forward rate is whatever makes that true. This is covered interest parity.

    Two riskless routes to the same place must pay the sameTodayRs 84In one yearRs 89.46Route 1: keep rupees, earn 6.5%84 x 1.065 = Rs 89.46Convert at 84$1.000Earn 4.5%$1.045Sell forward at FRs 89.46F = 89.46 / 1.045 = 85.61, a 1.9% premium
    Rs 84 invested at 6.5% grows to Rs 89.46, and converting to one dollar, earning 4.5% and selling the $1.045 forward must reach the same Rs 89.46, which fixes the forward at 85.61, a 1.9% premium to spot.
    The relationship
    F=S×1+rRs1+r$=84×1.0651.045≈85.61F = S \times \frac{1 + r_{Rs}}{1 + r_{\$}} = 84 \times \frac{1.065}{1.045} \approx 85.61
    Sspot rupees per dollar, 84
    r_Rsone-year rupee rate, 6.5%
    r_$one-year dollar rate, 4.5%
    What it says in wordsThe forward premium on the dollar equals, roughly, the gap between rupee and dollar interest rates.

    So who pays for hedging, and what does it tell the investor?

    The hedged dollar deposit earns 1.045 dollars sold at 85.61, which is 6.5% in rupees: exactly the rupee rate. A fully hedged foreign bond earns roughly the home interest rate plus its own spread, so hedging removes the currency bet but cannot manufacture a higher rate. The same 1.9% is a genuine cost for a dollar investor hedging rupee bonds, which is why hedged returns on Indian debt look lower to foreign funds.

    One honest limit: the forward is not a forecast. It builds in a 1.9% rupee depreciation only because of the rate gap. The unhedged investor earns 4.5% plus whatever the rupee actually does, which may be more or less than the forward implied.

    Where candidates lose it

    The common slip is calling the 1.9% a cost for the Indian investor. The sign depends on which currency you are selling forward, and the interviewer asks this way round precisely to catch it.

    The second slip is treating the forward as the market's forecast of the rupee. It is an arbitrage price set by interest rates, and saying so separates you from candidates who memorised the formula.

    What the interviewer asks next

    • Rupee rates rise to 7.5%. What happens to the forward, and to the hedged return?
    • Why do foreign investors in Indian bonds often leave the currency unhedged?
    • What would you do if the quoted forward were 86.5?
  5. 093Trading 10% of a stock's daily volume costs 20 basis points in market impact. If impact follows a square-root law, what does trading 40% of daily volume cost per rupee traded, and how does the total cost compare?Funds, ETFs and implementationHardPortfolio implementationQuantitative asset management

    Try it first

    How much larger is the total impact cost of the 40% order?

    Show the worked solution

    About 40 basis points per rupee, and 8 times the total cost. Under a square-root law, cost per rupee rises with the square root of size: four times the size is twice the cost per rupee, 40 basis points. Total cost is size times cost per rupee, so it rises four times two, or eight times. On Rs 50 crore of daily volume, Rs 1 lakh becomes Rs 8 lakh.

    Why does a bigger order cost more per rupee?

    Selling one flat in a building is easy at the going price; selling ten at once means working down to buyers who would only pay less. A large order uses up the willing counterparties near the current price and has to reach further, so each extra rupee traded moves the price more than the one before. Empirical studies of trading costs across markets find that the cost per rupee grows roughly with the square root of the order's share of volume, a rule practitioners use widely as a first estimate.

    Four times the size, twice the cost per rupee, eight times the total10%20%30%40%50%20 bp40 bp60 bp80 bpif cost rose in line with size20 bp40 bpOrder size, share of daily volumeDaily volume Rs 50 crore10%: Rs 5 crore x 20 bpRs 1 lakh40%: Rs 20 crore x 40 bpRs 8 lakhSplit over 4 days at 10%about Rs 4 lakhif impact fades overnight
    Cost per rupee rises along a square-root curve from 20 basis points at 10% of daily volume to 40 at 40%, so the total cost on a Rs 50 crore volume stock rises from Rs 1 lakh to Rs 8 lakh, eight times, while spreading the order over four days would cost about Rs 4 lakh.
    The relationship
    c(q)=20q10% bp,total∝q⋅c(q)∝q3/2c(q) = 20\sqrt{\frac{q}{10\%}}\ \text{bp}, \qquad \text{total} \propto q \cdot c(q) \propto q^{3/2}
    qorder size as a share of daily volume
    c(q)impact cost per rupee traded
    What it says in wordsCost per rupee grows with the square root of size, so total cost grows with size to the power one and a half.

    What does the portfolio manager do with this?

    Two things. Because total cost grows faster than size, spreading a large order over several days is usually cheaper: four days at 10% each costs about Rs 4 lakh against Rs 8 lakh in one go, provided the price impact of one day's trading has largely faded by the next and the price does not drift away meanwhile. And a strategy's capacity is limited: a fund that doubles in size pays about 2.8 times the rupee impact on each rebalance, which eats into returns quickly.

    Say the limits. The square-root law is an empirical average, with a coefficient that differs by stock and market conditions, and splitting an order adds timing risk: if the information behind the trade leaks or the price moves, waiting costs more than impact would have.

    Where candidates lose it

    The common slip is answering two times, applying the square root to the total cost. The law describes cost per rupee; the total picks up the size again.

    The second loss is stopping at the number. Say what follows from it: large orders get split, and strategy capacity falls as assets grow.

    What the interviewer asks next

    • At what share of daily volume does cost per rupee reach 60 basis points?
    • Why might splitting the order over four days cost more, not less?
    • How would you estimate the capacity of a small-cap strategy from this rule?
  6. 094A strategy stakes Rs 1 lakh per bet and wins each bet with probability 55%, winning or losing the stake. Starting with Rs 5 lakh, what is the chance of reaching Rs 10 lakh before losing everything?Probability and expected valueHardHedge fundsRisk management

    Try it first

    Roughly what is the chance of reaching Rs 10 lakh?

    Show the worked solution

    About 73%, against 50% for a fair bet. This is the gambler's ruin problem. With the ratio of loss to win odds r = 0.45 / 0.55, the chance of reaching 10 units from 5 is (1 minus r to the 5) over (1 minus r to the 10), about 73.2%. Smaller bets make it higher still: with Rs 50,000 bets it is about 88%.

    Why is the answer so much higher than 55%?

    A slightly better tennis player might win 55% of points, yet win most matches, because a match needs many points and the small edge keeps adding up. Reaching Rs 10 lakh before zero needs a net five wins, which takes many bets, and every bet tilts the race a little in your favour, so the edge compounds into a much bigger survival advantage.

    A 55% edge bows the curve up: from the middle, 73% instead of 50%01234567891025%50%75%100%55% win rate: 73.2%fair coin: 50%Starting capital, Rs lakh (target 10, bet 1)Start 5, target 10at 55%, by bet sizeRs 5 lakh bets55%Rs 2.5 lakh bets60%Rs 1 lakh bets73%Rs 0.5 lakh bets88%smaller bets, surer edge
    With Rs 1 lakh bets and a Rs 10 lakh target, a fair coin gives a straight line and a 50% chance from Rs 5 lakh, while a 55% win rate bows the curve up to 73.2%; shrinking the bet to Rs 50,000 lifts it to about 88%.
    The relationship
    P(reach N from i)=1−r i1−r N,r=qp=0.450.55P(\text{reach } N \text{ from } i) = \frac{1 - r^{\,i}}{1 - r^{\,N}}, \quad r = \frac{q}{p} = \frac{0.45}{0.55}
    istarting capital in bets, 5
    Ntarget in bets, 10
    p, qchance of winning and losing each bet, 0.55 and 0.45
    What it says in wordsThe chance of hitting the target first depends on the edge through r, and on how many bets away each barrier is.

    Why does bet size matter so much?

    Keep the edge and the rupee distances fixed and change only the stake. With Rs 5 lakh bets the whole outcome rides on one toss, 55%; with Rs 1 lakh bets it is 73%; with Rs 50,000 bets it is 88%, because more bets give the law of large numbers room to work. That is the portfolio lesson: a real edge is only worth something if position sizes are small enough that an unlucky run cannot end the game first.

    Bet sizeBets to ruinBets to targetChance of reaching Rs 10 lakh
    Rs 5 lakh1155.0%
    Rs 2.5 lakh2259.9%
    Rs 1 lakh5573.2%
    Rs 0.5 lakh101088.1%
    Holding the 55% edge and the Rs 5 lakh start fixed, smaller bets raise the chance of reaching Rs 10 lakh from 55% to about 88%, because each barrier is more bets away.

    Where candidates lose it

    The common slip is answering 55%, the per-bet win rate, which treats a long race as a single toss. The interviewer wants to see that you recognise the gambler's ruin structure.

    The second loss is missing the sizing point. The follow-up is almost always what happens with bigger or smaller bets, so volunteer it.

    What the interviewer asks next

    • With a fair coin, what is the chance of reaching Rs 10 lakh from Rs 3 lakh?
    • What if the target were unlimited? What is the chance of never going broke?
    • How does this connect to the Kelly criterion for sizing bets?
  7. 097A stock trades at 25 times trailing earnings, pays out 40% of earnings, earns a 20% return on equity, and has a 12% cost of equity. What growth rate does the price imply, and how does it compare with the growth its reinvestment could support?Valuation riddlesHardFundamental asset managementIndian equity research

    Try it first

    What perpetual growth does the 25x multiple imply?

    Show the worked solution

    The price implies about 10.2% growth for ever, below the 12% that reinvestment could support today. Setting 25 equal to 0.4 x (1 + g) / (0.12 - g) gives g of 2.6 / 25.4. Retaining 60% at a 20% return supports 12%, but 12% for ever equals the cost of equity and would make the stock infinitely valuable, so the market is pricing in returns fading to about 17%.

    What does it mean to work backwards from a multiple?

    If a flat rents for Rs 30,000 a month and sells for Rs 1.2 crore, the price tells you what buyers assume about future rents, whether or not anyone says it. A P/E is the same kind of compressed forecast: fix the payout and the cost of equity, and the multiple pins down the one perpetual growth rate the price assumes. Reverse engineering the price like this is safer than forecasting growth and seeing what multiple falls out.

    The relationship
    25=0.4 (1+g)0.12−g  ⇒  3−25g=0.4+0.4g  ⇒  g=2.625.4≈10.2%25 = \frac{0.4\,(1+g)}{0.12 - g} \;\Rightarrow\; 3 - 25g = 0.4 + 0.4g \;\Rightarrow\; g = \frac{2.6}{25.4} \approx 10.2\%
    0.4payout ratio
    0.12cost of equity
    gthe perpetual growth the price implies
    What it says in wordsThe multiple equals the payout grown one year, divided by the gap between the cost of equity and growth; solve for growth.
    Working backwards from 25x: the market assumes growth fades below 12%Implied by 25x P/E10.2%ROE 20% x retention 60%12.0%cost of equity 12%:growth here meansan infinite P/EPrice implies ROE fading to about 17.1% at the same 60% retentionJustified P/E by growth8%10.8x10%22.0x10.2%25.0x11%44.4x11.5%89.2xpayout 40%, cost of equity 12%
    The 25 times multiple implies 10.2% perpetual growth, below the 12% that 60% retention at a 20% return supports, and the justified P/E rises from 22 times at 10% growth to 89 times at 11.5%, which is why growth near the cost of equity cannot last for ever.

    Is the stock cheap because it can grow faster than the price assumes?

    Not so fast. Sustainable growth is return on equity times retention, 20% x 60% = 12%. But 12% growth for ever equals the cost of equity, which would make the stock worth an infinite multiple, so no price could reflect it; the gap tells you the market expects the 20% return on new investment to fade. At the same 60% retention, the price is consistent with a long-run return on equity of about 17.1%.

    That turns the question into a sharper one: will this business keep earning well above 17% on new money for a long time? That is a question about competition and moats, and it is the right place to spend the next five minutes of the interview. Say also that one-stage models are crude; a two-stage model with high growth fading to a lower rate is the usual next step.

    Where candidates lose it

    The common slip is declaring the stock undervalued because 12% beats 10.2%. Plugging 12% into the model gives division by zero, and a candidate who does not notice has not understood the formula.

    The second slip is using the earnings yield shortcut, 12% minus 4%, which ignores the payout ratio and lands near 8%. Set up the equation and solve it.

    What the interviewer asks next

    • What P/E would be justified if long-run growth were 9%?
    • Rebuild this with a two-stage model: 12% for five years, then 6%.
    • How would a lower payout ratio change the implied growth at the same 25x?
  8. 098A portfolio holds 60% equities returning 10% and 40% bonds returning 6%. Its benchmark holds 50% equities returning 12% and 50% bonds returning 5%. Split the 0.1 point shortfall into allocation, selection and interaction effects.Performance measurementHardPerformance analysisMulti-asset

    Try it first

    Was the decision to overweight equities a good one?

    Show the worked solution

    Allocation added 0.70 points, selection cost 0.50 and interaction cost 0.30, netting to the -0.1 shortfall. Allocation prices the weight bets at benchmark returns: +10% x 12 and -10% x 5. Selection prices the return gaps at benchmark weights: 50% x (10 - 12) and 50% x (6 - 5). Interaction is the weight bets times the return gaps.

    Why split the result at all, if it only lagged by 0.1?

    A team can lose a match by one run after a brilliant bowling spell and a dismal batting collapse; the scoreline hides both. Attribution separates the decision of how much to hold in each asset class from the decision of what to hold within it, so each can be judged on its own. Here the allocation call was right and the equity picking was poor, which is a very different story from a flat 0.1 point miss.

    The allocation call added value; the stock and bond picking gave it back8.50Benchmark+0.70Allocation-0.50Selection-0.30Interaction8.40Portfolio7.5%8.0%8.5%9.0%9.5%axis starts at 7.5%Net-0.10points0.7 - 0.5 - 0.3
    From the benchmark's 8.5%, the equity overweight adds 0.70 points, weak equity selection takes 0.50 and the interaction takes 0.30, arriving at the portfolio's 8.4%.
    SegmentAllocationSelectionInteractionTotal
    Equities+1.20-1.00-0.20-0.00
    Bonds-0.50+0.50-0.10-0.10
    Total+0.70-0.50-0.30-0.10
    Equities carry the story: the overweight earned +1.20 while picking cost -1.00 and the interaction -0.20; bonds lost -0.50 on the underweight but picked well.

    What is the interaction term, and why does it bite here?

    Interaction is the weight bet times the return gap. The manager overweighted equities by 10 points and underperformed within them by 2 points, so the extra equity weight magnified the poor picking by 0.2; underweighting bonds, where the picking was good, gave up another 0.1. Some firms fold interaction into selection, since the weights are the manager's choice; say which convention you are using.

    One more check an interviewer may ask for. The Brinson-Fachler version measures allocation against the total benchmark return, (weight bet) x (segment return minus 8.5). It gives the same total, 0.70, here, because the weight bets sum to zero, but it splits the credit between segments differently.

    The relationship
    A=∑(wp−wb)Rb,S=∑wb(Rp−Rb),I=∑(wp−wb)(Rp−Rb)A = \sum (w_p - w_b) R_b, \quad S = \sum w_b (R_p - R_b), \quad I = \sum (w_p - w_b)(R_p - R_b)
    w_p, w_bportfolio and benchmark weights
    R_p, R_bportfolio and benchmark returns within each segment
    What it says in wordsAllocation prices the weight bets, selection prices the return gaps, interaction prices the two together.

    Where candidates lose it

    The common slip is judging the allocation by the portfolio's own equity return, 10%, instead of the benchmark's 12%. That mixes the picking into the allocation and understates a good decision.

    The second slip is losing track of signs on the underweight. Ten fewer points of bonds at 5% is minus 0.5, and in selection the bonds' 1 point outperformance at 50% weight is plus 0.5. Write the table before speaking.

    What the interviewer asks next

    • If the manager had held benchmark weights, what would the portfolio have returned?
    • Why do some firms fold interaction into selection?
    • How does attribution work for a portfolio that holds a segment the benchmark does not?
  9. 100You can hold a 7-year bullet yielding 7.0%, or a barbell of 2-year bonds at 6.5% and 12-year bonds at 7.2% with the same duration. Which does better if yields shift 100 basis points in parallel, either way? What does the barbell give up?Bond mathsHardFixed incomeInstitutional asset management

    Try it first

    On an immediate 100 basis point parallel move, up or down, which wins?

    Show the worked solution

    The barbell wins both ways on an immediate parallel move, by about 0.12 points if yields fall and 0.10 if they rise, but it yields about 0.15 points less a year. With duration matched, convexity is the only difference: 71 for the barbell against 49 for the bullet. Over a year the barbell needs a move of roughly 113 to 123 basis points to earn back its lower yield, and it loses if the curve steepens.

    Why does spreading money to the two ends add convexity?

    Balancing a plank on a see-saw with one heavy child in the middle is steady; balancing it with a child at each end makes it swing more for the same push. Price sensitivity grows faster than linearly with maturity, so a mix of short and long bonds with the same average duration as a middle bond has more curvature than the middle bond: here about 71 against 49. More convexity means gaining a little more when yields fall and losing a little less when they rise.

    The barbell's convexity edge is real, small, and paid for in yield-300 bp+300 bpprice change, %Bullet (solid) and barbell (dashed):almost the same line-300-100+100+3000.51.0yield given up:0.15 a year+0.12+0.10Barbell minus bullet,points of priceparallel shift, basis points
    The bullet and barbell price changes almost coincide across parallel shifts, but the barbell's advantage grows with the square of the move, from about 0.10 to 0.12 points at 100 basis points to over 0.7 at 300; it only clears the 0.15 points of yield it gives up each year beyond moves of roughly 113 to 123 basis points.

    What does the barbell give up, and when does it lose?

    First, yield. Weighting the 2-year at about 50% to match duration gives a blended yield near 6.85%, about 0.15 points below the bullet's 7.0%. That is the price of convexity: if yields sit still, the bullet simply earns more, and over a year the barbell's edge only pays for itself on a parallel move of more than about 1.2 points. Second, curve shape. If the curve steepens, with short yields falling and long yields rising, the barbell's long leg loses and the bullet wins; if the 7-year sector rallies against the two ends, the bullet wins too.

    BulletBarbell
    Yield, blended7.00%6.85%
    Modified duration6.546.54
    Convexity48.970.6
    Yields fall 100 bp+6.79%+6.91%
    Yields rise 100 bp-6.30%-6.20%
    Priced as zero-coupon bonds with modified duration matched at 6.54, the barbell gains 6.91% against 6.79% on a 100 basis point fall and loses 6.20% against 6.30% on a rise, while yielding 0.15 points less.

    State the assumptions: zero-coupon bonds, a blended yield taken as a weighted average, which is an approximation, and an instantaneous shift. The conclusion survives all three: the barbell buys protection against large parallel moves with yield, and takes on curve-shape risk.

    Where candidates lose it

    The common slip is saying same duration, same result. Duration matching removes only the first-order difference, and the question is about what is left over.

    The second loss is praising the barbell without the cost. It gives up yield and carries curve risk, and a candidate who names both sounds like someone who has run a bond book.

    What the interviewer asks next

    • How would you build the barbell to match both duration and yield? What would you give up?
    • Which does better if the curve flattens with no change in the 7-year yield?
    • Why do liability-driven investors often prefer bullets matched to their payment dates?
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