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Private Equity puzzles, solved step by step

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  1. 011Diligence flags two independent risks in a target: a 20% chance its revenue will need to be restated, and a 10% chance its largest customer leaves. What is the chance at least one of them happens?Probability and expected value in dealsWarm upMid-market buyout fund

    Try it first

    Fast answer?

    Show the worked solution

    28%. The easy route is through the opposite event. The chance there is no restatement is 80% and the chance the customer stays is 90%; because the risks are independent, the chance of neither is 0.8 x 0.9, which is 72%. At least one problem is everything else, 100% less 72%, or 28%. Adding 20% and 10% gives 30% and double counts the 2% chance of both.

    Why not just add the two chances?

    Picture two friends who each might be late for dinner. If you add their chances of being late, the evening where both are late gets counted once for each of them. Adding probabilities works only when the events cannot happen together; when they can, the overlap is counted twice. Here both problems happen together 0.2 x 0.1, or 2%, of the time, so 20 plus 10 overshoots by exactly that: 30 less 2 is 28.

    Every outcome in one square: at least one problem is everything except the big cell2%customer only 8%restateonly18%neither problem0.8 x 0.9 = 72%restated 20%not restated 80%customer leaves 10%customer stays 90%At least one problem2 + 18 + 8 = 28%or 100 - 72 = 28%28%Adding 20 + 10 = 30%counts the red 2% celltwice, once in eachproblem's slice
    Splitting all outcomes 20 to 80 for the restatement and 10 to 90 for the customer gives four cells, 2%, 18%, 8% and 72%, so at least one problem is 28%, and adding 20% and 10% counts the 2% overlap twice.

    Why is one minus none the safest route?

    Because the opposite of at least one is a single clean case: nothing goes wrong. At least one problem is everything except the case where neither happens, so you multiply the two chances of no problem and subtract from one. It scales without effort. With five independent risks of 10% each, the chance none happens is 0.9 to the fifth, about 59%, so at least one is about 41%, a number that adding would put at 50%.

    The relationship
    P(at least one)=1−(1−0.2)(1−0.1)=1−0.72=0.28P(\text{at least one}) = 1 - (1 - 0.2)(1 - 0.1) = 1 - 0.72 = 0.28
    0.2chance of a revenue restatement
    0.1chance the largest customer leaves
    0.72chance neither happens, if the two are independent
    What it says in wordsThe chance of at least one problem is one less the chance of no problem at all.

    Is independence a fair assumption in diligence?

    Usually not, and saying so earns credit. A company that needs a revenue restatement may have weak controls or stretched customer relationships, so the two risks tend to move together, which raises the chance of both and lowers the chance of at least one below 28%. If the risks were perfectly linked, so the customer leaves only when revenue is also restated, the answer would fall to 20%. The 28% is the answer the question asks for; the correlation point is the judgement the interviewer is listening for.

    Where candidates lose it

    Saying 30% is the whole trap. It is quick, sounds right and is off by the overlap, which the interviewer chose small so that only careful candidates notice.

    The second miss is treating independence as a given. Answer 28%, then add one sentence on why diligence risks are rarely independent.

    What the interviewer asks next

    • What is the chance both happen?
    • With four independent 10% risks, what is the chance of at least one?
    • If the two risks are positively correlated, does the chance of at least one rise or fall?
  2. 019Five bidders each estimate an asset's value. Each estimate is the true value of 1,000 plus an error spread evenly between minus 200 and plus 200, and each bids its estimate. If you win the auction, what is your estimate on average, and what does that tell you about bidding?Probability and expected value in dealsHardLarge-cap buyout fund

    Try it first

    Given that you won, your estimate is on average:

    Show the worked solution

    About 1,133, so the winner overpays by about 133 on average. Each estimate is right on average, but the auction picks the highest of five. Five draws spread evenly between 800 and 1,200 sit on average at the sixths of the range, and the top one averages 800 plus five sixths of 400, about 1,133. To avoid overpaying, each bidder should bid below its own estimate, and by more as the number of bidders grows.

    If every estimate is unbiased, how can the winner be wrong?

    Picture five friends guessing the number of sweets in a jar. On average they are right, but the one who guesses highest is almost certainly too high. Each estimate is unbiased on its own, but the auction does not pick a random estimate; it picks the highest, and the highest of several noisy guesses is biased upwards. That is the {term('winner’s curse', 'The tendency for the winner of an auction, chosen because its estimate was highest, to have overestimated the value of what it bought.')}: winning is itself evidence that you overestimated.

    The auction picks the bidder who overestimated most8009001,0001,1001,200true value 1,0008679331,0001,0671,133winner overpays 133Five bidders: expected sorted estimatesTen bidders: top estimate averages 1,164More bidders push the winning estimate further from the truth.
    Five estimates spread evenly from 800 to 1,200 sit on average at 867, 933, 1,000, 1,067 and 1,133, so the winning estimate averages about 133 above the true value of 1,000, and with ten bidders it averages about 1,164.

    Why does the top estimate average five sixths of the range?

    Five points dropped at random on a line split it, on average, into six equal gaps. So the expected sorted estimates sit at one sixth, two sixths and so on up to five sixths of the way from 800 to 1,200: 867, 933, 1,000, 1,067 and 1,133. The top one is 400 x 5/6, or 333, above 800, which is 1,133. With n bidders the top estimate averages n over n plus 1 of the range, so ten bidders push it to about 1,164.

    The relationship
    E[max⁡]=L+(H−L)nn+1=800+400×56≈1,133E[\max] = L + (H - L)\frac{n}{n+1} = 800 + 400 \times \frac{5}{6} \approx 1{,}133
    L, Hthe lowest and highest possible estimates, 800 and 1,200
    nthe number of bidders, here 5
    What it says in wordsThe highest of n evenly spread estimates sits, on average, n parts out of n plus 1 up the range.

    What does a disciplined bidder do with this?

    Shade the bid. A bidder that wants to break even when it wins must bid as though its estimate is the highest of five, which in this setup means bidding about 133 below its estimate, and more in a crowded auction. That is the case for walking away from processes with many bidders and for building value on what the buyer can change rather than on a higher estimate of the same cash flows. Say the limits: real bidders have different information and different synergies, so not all of the gap is error, and a bidder with genuine private information is less exposed.

    Where candidates lose it

    The common answer is 1,000 because errors average out. They do across all bidders, but the question conditions on winning, and conditioning on being highest is the whole point.

    The second loss is giving 1,133 and no implication. Close with what it means for behaviour: shade the bid, and shade it more as the field gets bigger.

    What the interviewer asks next

    • With two bidders, what does the winning estimate average?
    • How much should each of five bidders shade its bid to break even on average when it wins?
    • Why are sponsors with an operating plan less exposed to the winner's curse?
  3. 045A seller wants 100 upfront plus an earnout of 50 if year-2 EBITDA hits a target. You think the chance of hitting it is 40%. At a 12% discount rate, what is the earnout worth to you today, and what is the total price in value terms?Probability and expected value in dealsHardMid-market buyout fund

    Try it first

    What is the earnout worth to you today?

    Show the worked solution

    The earnout is worth about 15.9 to you, so the price in value terms is about 115.9. A 40% chance of 50 is 20 on average, payable in two years, and 20 / 1.12^2 is 15.9. The headline price is 150, but you are paying about 116 in value. A seller who thinks the chance is 80% values the same earnout at 31.9, which is why earnouts close price gaps.

    How do you value a payment that may not happen?

    A shopkeeper who offers a Rs 500 voucher to anyone who spends Rs 5,000 next month books its cost by how many customers she expects to claim it, not by the face value. An earnout is a contingent payment, so you value it as chance times amount, discounted for the wait: 0.4 x 50 / 1.12^2 is about 15.9. That number, not 50, is what the earnout adds to your price.

    The relationship
    V=p×EO(1+r)t=0.4×501.122≈15.9V = \frac{p \times EO}{(1+r)^t} = \frac{0.4 \times 50}{1.12^2} \approx 15.9
    pyour estimate of the chance the target is hit, 40%
    EOthe earnout payment, 50
    rthe discount rate, 12%
    tyears until payment, 2
    What it says in wordsAn earnout is worth the chance of paying it, times the amount, discounted to today.
    One earnout, two values: that difference is what closes the dealHeadline price100 upfront150.0face value, if paidBuyer's value, 40%100 upfront115.90.4 x 50 / 1.12^2 = 15.9Seller's value, 80%100 upfront131.90.8 x 50 / 1.12^2 = 31.9050100150Gap between the two views: 15.9
    The same 50 earnout is worth 15.9 today to a buyer who puts the chance at 40% and 31.9 to a seller who puts it at 80%, so the buyer feels it is paying 115.9 while the seller feels it is receiving 131.9.

    Why does an earnout make a deal possible?

    Because both sides can be right in their own terms. The seller, confident in the plan, values the package at about 132; the buyer, more cautious, values it at about 116; and the contract lets each side bet on its own view. If the target is hit, the buyer pays more but has a business that performed. If not, the buyer has paid 100 for a business that did not.

    Say the risks. Earnouts are a common source of disputes: how EBITDA is defined, which costs the buyer loads onto the business after closing, and whether the seller's management stays to run it. A buyer controls the business that decides the payout, so the contract needs a tight EBITDA definition and agreed accounting policies.

    Where candidates lose it

    The common loss is counting the earnout at its face value of 50, which makes the price look like 150 and either overpays or kills the deal. The other is applying the probability but forgetting two years of waiting.

    The second loss is treating the 40% as a fact. It is your estimate; the seller's is higher. Say that the gap between the two estimates is exactly what the earnout is for.

    What the interviewer asks next

    • What chance of hitting the target makes the earnout worth 25 to you?
    • Would you rather the earnout be all-or-nothing or paid in proportion to EBITDA achieved, and why?
    • How would you protect the seller from the buyer managing EBITDA down after closing?
  4. 053A commercial due diligence study costs Rs 2 crore. There is a 25% chance it uncovers a deal-breaker that would otherwise cost the fund Rs 30 crore. Is the study worth buying?Probability and expected value in dealsCoreMid-market buyout fund

    Try it first

    What is the most the fund should be willing to pay for this study?

    Show the worked solution

    Yes: the study is worth Rs 7.5 crore in expectation and costs Rs 2 crore, a net gain of Rs 5.5 crore. Without it, the fund carries a 25% chance of losing Rs 30 crore, an expected loss of Rs 7.5 crore. With it, the fund walks away in the bad case and pays only the fee. The study stays worth buying as long as the chance of a problem is above 2 over 30, about 6.7%.

    What exactly is the fund buying?

    Think of paying a mechanic to inspect a second-hand car before you buy it. The inspection is worth nothing if the car is sound and a great deal if the gearbox is about to fail. A diligence study is worth the loss it can prevent, multiplied by the chance that the loss is really there. It is not worth the loss itself, and it is not worth zero because the problem is unlikely. Draw both choices as branches and the answer is visible.

    Diligence is worth what it can change, times the chance it changes it (Rs crore)Buy thestudy?NoYes, pay 225%: problem, lose 3075%: fine, lose 0Expected: 0.25 x -30= -7.525%: found, walk away, -275%: clean, proceed, -2Expected: the fee only= -2.0Saves 7.5, costs 2Worth +5.5 net
    Proceeding blind carries a 25% chance of a Rs 30 crore loss, an expected loss of Rs 7.5 crore; buying the study caps the cost at its Rs 2 crore fee, so the study is worth Rs 5.5 crore more than it costs.
    The relationship
    V=p×L−c=0.25×30−2=5.5V = p \times L - c = 0.25 \times 30 - 2 = 5.5
    pthe chance the deal-breaker exists and the study finds it, 25%
    Lthe loss avoided by walking away, Rs 30 crore
    cthe cost of the study, Rs 2 crore
    What it says in wordsThe net value of a test is the loss it prevents times the chance it prevents it, less what the test costs.

    What assumptions is that answer resting on?

    Two, and you should say both. First, the study is perfect: it always finds the problem when it is there and never raises a false alarm. If the study catches the problem only 60% of the time, its value falls to 0.25 x 0.6 x 30, Rs 4.5 crore, still above the fee. Second, walking away costs nothing beyond the fee. In a live auction, pausing for a study can lose the deal to a faster bidder, and that cost belongs on the yes branch.

    Where candidates lose it

    Candidates compare the Rs 2 crore fee with the Rs 30 crore loss and say yes because 30 is bigger, which would also say yes at a fee of Rs 20 crore. The comparison that decides it is the fee against the expected saving of Rs 7.5 crore.

    The opposite slip is dismissing the study because the problem probably is not there. A 75% chance of a clean result is exactly why the study is cheap insurance, not why it is wasted.

    What the interviewer asks next

    • What if the study also raises a false alarm on 10% of clean deals, and you would walk away from a good deal worth Rs 12 crore?
    • At what fee would you be indifferent?
    • How would you put a value on the time the study takes in a competitive auction?
  5. 069About 10% of acquisition targets have a real accounting problem. A quality-of-earnings review flags 90% of the problem cases, but it also flags 15% of clean ones. The review flags your target. What is the chance it really has a problem?Probability and expected value in dealsHardMid-market buyout fundPortfolio operations team

    Try it first

    Given a flag, how likely is a real problem?

    Show the worked solution

    About 40%. Picture 1,000 targets: 100 have a problem and the review flags 90 of them. Of the 900 clean targets, it wrongly flags 15%, which is 135. So 225 targets are flagged and only 90 of those are real problems, 90 divided by 225. A good test on a rare problem still throws up more false alarms than true ones.

    Why is the answer not 90%?

    Think of a smoke alarm that goes off for almost every real fire, but also for burnt toast. In a house where fires are rare and toast is daily, most alarms are toast. The 90% is the chance of a flag when there is a problem; the question asks the reverse, the chance of a problem when there is a flag, and the two differ because clean targets are far more common. Counting people instead of using percentages makes the reversal visible.

    1,000 targets: the review flags 225, and only 90 of them are real problemsProblem, flagged: 90Problem, missed: 10Clean, flagged anyway: 135Clean, cleared: 765Flagged: 90 + 135 = 225Real: 90 / 225= 40%Why so low: the problem is rare, so 15% of the many clean targets outnumber 90% of the few bad ones90 real135 false alarms= the 225 flagsEach square is one target; the colours are the four ways a review can turn out
    Of 1,000 targets, the review flags 90 of the 100 real problems and 135 of the 900 clean ones, so only 90 of the 225 flags, 40%, are real problems.
    The relationship
    P(problem∣flag)=0.10×0.900.10×0.90+0.90×0.15=0.090.225=40%P(\text{problem} \mid \text{flag}) = \frac{0.10 \times 0.90}{0.10 \times 0.90 + 0.90 \times 0.15} = \frac{0.09}{0.225} = 40\%
    0.10the share of targets with a real problem
    0.90the chance the review flags a real problem
    0.15the chance the review flags a clean target
    What it says in wordsThe chance a flag is real is the true flags divided by all flags, true and false.

    What should a deal team do with a 40% flag?

    Treat the flag as a reason to dig, not a reason to walk away. A flag lifts the chance of a problem from 10% to 40%, four times the starting level, but it still leaves the target more likely clean than not. A second, independent check changes the picture: if a forensic review with the same hit and false alarm rates also flags it, the chance rises to about 80%. The limit to state: that assumes the two reviews make independent mistakes, which two teams looking at the same ledgers may not.

    Where candidates lose it

    The common answer is 90%, mixing up the chance of a flag given a problem with the chance of a problem given a flag. Interviewers ask this precisely because the confusion is so natural.

    The second slip is forgetting the false alarms entirely and answering 100% or near it. Write the four groups of 1,000 down, 90, 10, 135 and 765, before you compute anything.

    What the interviewer asks next

    • A second independent review also flags it. What is the chance now?
    • How would the answer change if only 2% of targets had problems?
    • Which matters more to a fund, the false alarm rate or the miss rate, and why?
  6. 097Each deal in a fund has a 20% chance of returning 0x, a 50% chance of 2x and a 30% chance of 4x, independently. What is the expected money multiple per deal, and what is the chance that at least one of three deals is a zero?Probability and expected value in dealsCoreLarge-cap buyout fundSecondaries and fund of funds

    Try it first

    Chance that at least one of three deals returns zero?

    Show the worked solution

    The expected multiple is 2.2x, and the chance of at least one zero in three deals is 48.8%. Expected value is 20% x 0 plus 50% x 2 plus 30% x 4, which is 2.2. For the zero, take the complement: each deal avoids a zero 80% of the time, so all three do 0.8 cubed, 51.2% of the time. A good average hides a near coin-flip chance of a loss.

    How do you get the expected multiple?

    Weight each outcome by its chance and add. It is the same as asking what a hundred identical deals would return on average: twenty return nothing, fifty return 2x and thirty return 4x, which is 0 plus 100 plus 120, or 220 on 100 put in. The expected multiple is 2.2x, but no single deal ever returns 2.2x: each one returns 0, 2 or 4.

    A 2.2x average hides a near coin-flip chance of at least one zero20%0x50%2x30%4xmean 2.2xOne deal: chance of each multiple51.2%12.8%12.8%3.2%12.8%3.2%3.2%0.8%Three deals: green = no zero, red = a zeroNo zero: 51.2% At least one zero: 48.8%
    One deal returns 0x with 20% chance, 2x with 50% and 4x with 30%, an average of 2.2x; across three independent deals only the path with no zeros, 51.2%, avoids a loss, so the chance of at least one zero is 48.8%.
    The relationship
    E[M]=0.2(0)+0.5(2)+0.3(4)=2.2P(≥1 zero)=1−0.83=0.488E[M] = 0.2(0) + 0.5(2) + 0.3(4) = 2.2 \qquad P(\geq 1 \text{ zero}) = 1 - 0.8^3 = 0.488
    E[M]expected money multiple of one deal
    0.8the chance one deal is not a zero
    0.8^3the chance none of three deals is a zero
    What it says in wordsAverage the outcomes by their chances; for at least one, take one minus the chance of none.

    Why does at least one zero use the complement?

    There are many ways to get at least one zero: the first deal, the second, the third, or any two, or all three. There is only one way to get no zero, so count that and subtract it from one. Adding 20% three times gives 60% because it counts the two-zero and three-zero cases more than once. The chance all three are zeros is 0.2 cubed, 0.8%.

    The fund-level point is the one to close on: a manager with a 2.2x average still writes off a deal in about half of all three-deal stretches. That is why investors judge a manager over many deals, and why a single write-off early in a fund says little on its own.

    Where candidates lose it

    The fast wrong answer to the second half is 60%, adding the probabilities. Probabilities of overlapping events cannot simply be added; the complement avoids the trap.

    The other slip is treating the expected 2.2x as what each deal returns. Say plainly that the average is a property of many deals, not of one.

    What the interviewer asks next

    • What is the chance that exactly one of the three deals is a zero?
    • With ten deals, what is the chance of at least one zero?
    • If outcomes are not independent, for example all deals in one sector, what changes?
  7. 099A fund screens 40 deals a year. 25% reach investment committee, 30% of those are signed and 60% of signed deals close. How many deals close? How many must be screened to expect 5 closes?Probability and expected value in dealsCoreMid-market buyout fundIndian mid-market PE

    Try it first

    How many deals close from 40 screened?

    Show the worked solution

    About 1.8 deals close, and about 111 must be screened to expect 5. Forty screened becomes 10 at investment committee, 3 signed and 1.8 closed. The stage rates multiply to 4.5%, so expecting 5 closes takes 5 divided by 0.045, about 111 deals screened. Conversion rates multiply, which is why sourcing volume matters so much.

    Why do the stage rates multiply?

    Each rate applies only to what survived the stage before, like a cricket trial where a quarter of players make the camp, a third of those make the squad and most of the squad play. A funnel's overall conversion is the product of its stage rates, so three reasonable-looking rates combine into a small number: 25% x 30% x 60% is 4.5%.

    Conversion rates multiply: 25% x 30% x 60% = 4.5% of screened deals close40Screenedx 25%10Investment committeex 30%3Signedx 60%1.8ClosedWork it backwards25% x 30% x 60% = 4.5%of screened deals closeFor 5 closes:5 / 0.045 = 111deals screenedabout 2.8 times today's 40
    Forty screened deals narrow to 10 at investment committee, 3 signed and 1.8 closed, an overall conversion of 4.5%, so expecting 5 closes needs about 111 deals screened.
    The relationship
    40×0.25×0.30×0.60=1.850.045≈11140 \times 0.25 \times 0.30 \times 0.60 = 1.8 \qquad \frac{5}{0.045} \approx 111
    0.25, 0.30, 0.60the conversion rate at each stage
    0.045the overall share of screened deals that close
    What it says in wordsMultiply the stage rates to get the overall rate; divide the target by it to size the top of the funnel.

    What would you do with this as a deal team?

    You can lift closes by screening more deals or by improving any one stage, and improving a stage is often cheaper. Raising the committee rate from 25% to 35%, by screening sharper, takes closes from 1.8 to 2.5 without a single extra deal. One honest caveat: 1.8 is an expected number. In a year with 40 screens the fund could close zero or four, so a target of 5 closes should be planned with a margin above 111.

    Interviewers in Indian mid-market funds often ask this to see whether you understand that origination is a numbers game. A candidate who says a team needs to see more than a hundred opportunities to close five has understood why associates spend so much time on screening.

    Where candidates lose it

    The common slip is averaging or adding the rates, or applying each one to the original 40. Every rate applies only to the deals that survived the stage before.

    The second is answering 111 and calling it certain. It is the screening volume for an expected 5 closes; to be confident of 5, you need more.

    What the interviewer asks next

    • Which stage would you try to improve first, and why?
    • If closing takes six months, how many deals must be in the funnel at any time?
    • How would you estimate these conversion rates for a new fund with no history?
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