Case 075Market-making gamesHard
A contract settles at the sum of three cards drawn without replacement from ten cards numbered 1 to 10, at Rs 100 a point. Quote a two-way market before any card, after the first card shows 9, and after the second shows 2, keeping pace with the dealer.
1The situation
Kestrelgate Trading's superday game uses ten cards numbered 1 to 10. The dealer will draw three without replacement, and a contract settles at their sum, Rs 100 a point. You must show a bid and an offer before the first card, then update within a few seconds after each card is turned, while the other candidates trade against your quotes.
The first card is a 9. The second is a 2. The dealer asks for a market at each step and will not wait for long division.
2Your task
Give the fair value and a market at each of the three stages, with the shortcut that makes each repricing fast, and explain how the width should change as cards come out.
Quick check
The first card is a 9, above the pack's average of 5.5. By how much does the fair value of the three-card sum rise?
Worked solution
Try it on paper, then open one step at a time.
30-second answerThe answer to give first
Fair value is 16.5 before any card, 19.22 after the 9 and back to 16.5 after the 2; quote about 15 / 18, then 18 / 20.5, then 15.5 / 17.5. The shortcut is cards shown plus cards to come times the average of the unseen pack: 3 x 5.5; 9 + 2 x 46/9; 9 + 2 + 44/8. The 9 and the 2 average 5.5 between them, so the fair value returns to its start, but the spread of outcomes has shrunk from 4.4 to 2.7, so each market is tighter than the last.
Step 1What is the contract worth before the first card?
Three cards from a pack whose average is 5.5 are worth 3 x 5.5 = 16.5 on average. The spread is wide: the sum runs from 6 to 27, and its standard deviation is 4.39, a little less than three independent draws would give because drawing without replacementEach card drawn is removed from the pack, so the cards that remain are no longer an unbiased sample of the original ten. pulls the cards apart. A market of 15 bid, 18 offered puts fair value just inside the middle with 1.5 points of edge each side, about a third of a standard deviation, which is tight enough to attract trades and wide enough to survive the first card. Say it in one breath, because the dealer is already reaching for the pack.
Step 2How do you reprice in seconds after the 9?
Use one rule at every stage: fair value equals the cards already shown plus the number still to come times the average of the cards still in the pack. The pack summed to 55; take out the 9 and the nine cards left sum to 46, an average of 5.11. Fair value is 9 + 2 x 5.11 = 19.22, not 20: the high card lifted the sum but also removed itself from what is left, so the two cards to come are worth less than they were. The uncertainty has fallen as well, to a standard deviation of 3.66, so quote a little tighter: 18 bid, 20.5 offered, which keeps about a third of a standard deviation of edge each side. A candidate who quotes 19 / 21 has priced with replacement and will be sold to by anyone who did the subtraction.
| \sum \text{shown} | sum of the cards already on the table |
| \sum \text{unseen} | sum of the cards still in the pack: 55 minus what has been shown |
| \#\text{unseen} | number of cards still in the pack |
Step 3Why does the 2 bring the fair value back to where it started?
After the 2, the cards shown sum to 11 and the eight left sum to 44, an average of exactly 5.5 again. Fair value is 11 + 5.5 = 16.5, the same as before any card, because the two cards drawn average 5.5 between them, so the pack that remains looks, on average, like the one you started with. That is the lesson of drawing without replacement: the fair value is not a running total that only climbs, it is a recomputation from the pack, and a high card followed by a low one leaves the pack unchanged. The outcomes are now eight equally likely sums, 12, 14, 15, 16, 17, 18, 19 and 21, with a standard deviation of 2.69, so quote 15.5 bid, 17.5 offered: a point of edge each side, 0.37 of a standard deviation, the same proportion as before.
Step 4How should the width change as the cards come out?
Scale it with the uncertainty. The standard deviation goes 4.39, 3.66, 2.69, so a width of 3 points, then 2.5, then 2 keeps the edge at about a third of a standard deviation each time. Tightening as information arrives is how you keep the flow: a quote that stays 3 wide when only one card is left will be undercut, and one that was 2 wide before any card would have been run over by the first 9 or 10. Watch the other side too. If a candidate lifts your 17.5 offer the moment the 2 appears, they may simply have done the arithmetic faster; if the same candidate keeps lifting, start asking what they see that you do not. The limitation of the whole method is that it prices the mean and the spread and nothing else: in a live game your inventory matters as much, and after selling three lots at 17.5 you should move the market down to buy them back rather than keep selling.
Where candidates lose it
The common error is pricing with replacement, 9 + 2 x 5.5 = 20 after the first card. Each card removed changes the average of the pack, and a candidate who forgets that is a point too high and gets sold to.
The second miss is quoting the same width throughout. Each card cuts the standard deviation, and a width that does not shrink with it either leaks edge to faster quoters or, early on, leaves the quote exposed to the first big card.
What the interviewer asks next
- The first card is a 10 instead of a 9. Quote your market and explain the change from 16.5.
- A candidate lifts your 20.5 offer for five lots straight after the 9. What do you quote next, and why?
- How would your three markets differ if the cards were drawn with replacement?
Asked at Optiver, Prop Trading, Chicago, 2026 (Wall Street Oasis): Market making game full simulation including fast mental math and quick ev/fair value calculation
Company names and figures are illustrative.
