Case 095Regression and model reviewWarm up
Read a regression output: Kalindor Motors' monthly returns on the market over 60 months give beta 1.35 (standard error 0.15), alpha 0.2% a month (standard error 0.4%) and R-squared 0.58. Does beta differ from 1, what is its 95% interval, and what do you make of alpha?
1The situation
The interviewer hands you a printed regression output for Kalindor Motors, an invented auto maker: 60 monthly excess returns regressed on the market's excess return. The beta is 1.35 with a standard error of 0.15; the intercept, the alpha, is 0.2% a month with a standard error of 0.4%; R-squared is 0.58. The printout shows a t-statistic of 9.00 beside the beta.
The question: is Kalindor more volatile than the market in the sense that matters, what range is its beta likely in, and does it show alpha?
2Your task
Test whether beta differs from 1, give a 95% interval for it, interpret alpha and R-squared, and check that the output hangs together.
Quick check
The printout shows t = 9.0 for beta. What does that number test?
Worked solution
Try it on paper, then open one step at a time.
30-second answerThe answer to give first
Beta is significantly above 1: t = (1.35 - 1) / 0.15 = 2.33, beyond the 5% critical value of 2.00, and the 95% interval is 1.05 to 1.65. The printed t of 9.0 only says beta is not zero. Alpha of 0.2% a month has t = 0.5 and an interval of -0.6% to 1.0% a month: indistinguishable from zero. R-squared of 0.58 leaves 42% of the variance stock-specific.
Step 1Which hypothesis should you test?
If a friend claims his car does better than 15 km a litre, you check his mileage against 15, not against zero; nobody doubts the car moves. Software tests every coefficient against zero by default, so the printed t of 9.0 answers a question nobody asked: whether Kalindor moves with the market at all. The useful question is whether it moves more than the market, a test against 1. That t-statistic is (1.35 - 1) / 0.15 = 2.33. With 58 degrees of freedom, the 5% two-sided critical value is 2.00, so beta is above 1 at the 5% level, with a p-value of about 0.023.
| beta hat | estimated beta, 1.35 |
| se | its standard error, 0.15 |
| t 0.975, 58 | the 5% two-sided critical value with 58 degrees of freedom, about 2.00 |
Step 2What do alpha and R-squared say?
Alpha is 0.2% a month, which sounds like 2.4% a year. Its t-statistic is 0.2 / 0.4 = 0.5 and its 95% interval runs from -0.6% to 1.0% a month, roughly -7% to +12% a year, so the data cannot tell Kalindor's alpha from zero. That is typical: five years of monthly data almost never pin down a single stock's alpha. R-squared of 0.58 means the market explains 58% of the variance of Kalindor's returns and 42% is company-specific, the part a market hedge cannot remove. For a hedger that matters as much as the beta: a perfect beta hedge would still leave most of the stock's month-to-month swings.
Step 3Does the output hang together?
A quick consistency check catches typos and misread columns. The alpha's standard error is roughly the residual volatility over the square root of 60, which implies a residual standard deviation of about 3.1% a month. The beta's standard error is roughly residual volatility over the square root of 60 times market volatility, which implies market volatility of about 2.67% a month. Those two imply an R-squared of 0.57, matching the printed 0.58, so the output is internally consistent. The market volatility it implies, about 9% a year, describes a fairly calm five years.
Close with how you would use the beta. For hedging, 1.35 is the best single estimate, but the interval from 1.05 to 1.65 is wide, and betas estimated this way tend to drift towards 1 in later periods. A common adjustment weights the estimate two-thirds and 1 one-third, giving 1.23. The limitation: the test assumes the residuals are independent with constant variance; with autocorrelated or volatile-clustered residuals, use robust standard errors before leaning on the 2.33.
Where candidates lose it
The common loss is quoting the printed t of 9.0 as proof that Kalindor is riskier than the market. It proves only that beta is not zero; the test against 1 gives 2.33, a much closer call.
The second is annualising the 0.2% alpha to 2.4% and calling it outperformance. With a standard error twice its size, the alpha is noise until a much longer record says otherwise.
What the interviewer asks next
- How many months of data would you need for an alpha of 0.2% a month to reach t = 2?
- What would an R-squared of 0.15 change about how you use this beta?
- How would you test whether Kalindor's beta changed after a merger halfway through the sample?
- Why do betas estimated on daily data often differ from monthly ones for less liquid stocks?
Asked at Wolverine Trading, Prop Trading, Chicago, 2016 (Wall Street Oasis): There was also a I believe minitab output, but could've been another statistical software output
Company names and figures are illustrative.
