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Risk Management puzzles, solved step by step

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All topicsCapital and leverage6Compounding and drawdowns8Correlation and diversification8Counterparty exposure and collateral7Credit risk arithmetic10Duration and rates7Liquidity and balance sheet7Logic, estimation and brainteasers7Operational loss and fraud7Options and Greeks7Probability and base rates8Statistics and estimation10VaR and expected shortfall8
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  1. 078Each of 25 stocks has 20% volatility. What is the volatility of an equal-weighted portfolio if they are uncorrelated, and what floor does a pairwise correlation of 0.3 put under it?Correlation and diversificationCoreAsset manager riskQuant risk

    Try it first

    With a correlation of 0.3, roughly where does portfolio volatility settle however many stocks you add?

    Show the worked solution

    Uncorrelated, the portfolio's volatility is 4%; with a correlation of 0.3 it is 11.45%, above a floor of 10.95%. Uncorrelated risk shrinks with the square root of the count, 20% over 5. With correlation, the shared risk stays: variance is 20% squared times (1/25 plus 24/25 times 0.3). As the count grows the floor is 20% times the square root of 0.3.

    Why does adding stocks stop helping?

    Picture 25 shops in one town. Each has its own bad luck, a broken freezer or a rude cashier, and across 25 shops those mishaps average out. But if the town's main factory closes, every shop loses customers on the same day, and owning more shops in the same town does not help. Diversification removes each stock's own risk but cannot touch the risk the stocks share, and correlation is the measure of that shared part.

    The relationship
    σp2=σ2(1n+(1−1n)ρ)=0.04×(0.04+0.96×0.3)=0.01312\sigma_p^2 = \sigma^2\left(\frac{1}{n} + \left(1 - \frac{1}{n}\right)\rho\right) = 0.04 \times (0.04 + 0.96 \times 0.3) = 0.01312
    sigmaeach stock's volatility, 20%
    nnumber of stocks, 25
    rhopairwise correlation, 0.3
    What it says in wordsPortfolio variance is a shrinking own-risk term plus a shared term that stays; the square root of 0.01312 is 11.45%.
    More stocks cut risk only down to the floor that correlation sets5%10%15%20%025 stocks, correlation 0.3: 11.45%25 stocks, uncorrelated: 4.0%110254050Number of stocks, equal weights, each 20% volatilityPortfolio volatilityThe floor20% x sqrt(0.3)= 10.95%at any count
    With no correlation, 25 stocks at 20% volatility give a 4.0% portfolio and the line keeps falling; with a correlation of 0.3 the same 25 stocks give 11.45%, and no number of stocks takes the portfolio below 10.95%.

    How do you reach the numbers in your head?

    Uncorrelated first: variance divides by n, so volatility divides by the square root of n, 20% over 5 is 4%. For the floor, let n run to infinity and the 1/n term vanishes, leaving variance of sigma squared times rho. The square root of 0.3 is about 0.55, so the floor is about 11%, and 25 stocks already capture almost all the diversification available. The 25-stock figure of 11.45% is only half a point above the 10.95% floor.

    Then say the limitation. Correlations are estimated in normal markets and tend to rise in a sell-off, exactly when diversification is wanted. A portfolio sized at 11% volatility on a correlation of 0.3 can behave like one at 15% or more if the correlation jumps to 0.6.

    Where candidates lose it

    Candidates get the 4% and then apply the same square-root rule to the correlated case, which gives 4% again. The square-root rule is a special case that holds only when correlation is zero.

    The second loss is saying diversification removes all risk given enough stocks. Name the floor, give the number, and say that correlation rises in a crisis.

    What the interviewer asks next

    • How many stocks do you need to be within one point of the floor?
    • What happens to the floor if correlations jump to 0.6 in a crisis?
    • Why does a portfolio of index funds across countries not diversify as much as the correlation tables suggest?
  2. 081A bond has a modified duration of 7 and convexity of 60. Yields rise 100 basis points. Estimate the price change with and without convexity.Duration and ratesCoreTreasury and ALMBank market risk

    Try it first

    Does convexity make the loss bigger or smaller than the duration estimate?

    Show the worked solution

    Duration alone gives a -7.00% fall; adding convexity gives -6.70%. Duration is the straight-line estimate: minus 7 times 1%. Convexity adds half of 60 times 1% squared, which is 0.30%. So the bond falls about 6.7%, not 7%. The gap looks small at 100 basis points, but it grows with the square of the move.

    What does each number measure?

    Think of a car's speedometer and its acceleration. Speed tells you how far you will go in the next minute if nothing changes; acceleration tells you how the speed itself is changing. Duration is the speedometer of a bond: the percentage price change for a small yield move. Convexity is the acceleration: how duration itself shifts as yields move. A modified duration of 7 means about 7% of price per 1% of yield, and a convexityThe second-order sensitivity of a bond price to yield; it measures how much the price curve bends away from the duration line. of 60 says the price curve bends away from that straight line.

    The relationship
    ΔPP≈−D Δy+12C(Δy)2=−7(0.01)+12(60)(0.01)2=−7.00%+0.30%\frac{\Delta P}{P} \approx -D\,\Delta y + \tfrac{1}{2} C (\Delta y)^2 = -7(0.01) + \tfrac{1}{2}(60)(0.01)^2 = -7.00\% + 0.30\%
    Dmodified duration, 7
    Cconvexity, 60
    Delta ychange in yield, 0.01
    What it says in wordsThe price change is the straight-line duration estimate plus a convexity term that grows with the square of the yield move.
    Duration draws a straight line; the bond's price curve bows above it-4%-2%0+2%+4%80100120Change in yieldPrice, from 100bond price curve:bows above the lineduration line:straight, too pessimistic+100 bpAt +100 bp, zoomed (axis starts at -5%)Duration only-7.00%Convexity adds+0.30%Estimate-6.70%-5%-7 x 1% + 0.5 x 60 x (1%) squared= -7.00% + 0.30% = -6.70%
    The bond's price curve bows above the straight duration line whichever way yields move; at plus 100 basis points, duration predicts -7.00% and convexity adds back 0.30%, an estimated fall of -6.70%.

    When does the convexity term stop being a rounding error?

    Square the move and see. At 100 basis points convexity is worth 0.30%; at 300 basis points it is nine times that, 2.70%, against a duration effect of 21%. Because the convexity term grows with the square of the move, it is small for daily risk and large in a stress scenario. A treasury stress test that uses duration alone will overstate losses on a large rate rise for a plain bond and understate them for a callable bond or a mortgage book, where convexity is negative.

    Close with the sign. Positive convexity is something a bond holder pays for through a slightly lower yield, and negative convexity, from options sold to borrowers, is what makes prepayable loans harder to hedge.

    Where candidates lose it

    The usual slip is forgetting the half in the convexity term and adding 0.60%, which gives minus 6.4%. Write the formula before the numbers so the half is on the page.

    The second is subtracting convexity because yields rose. The convexity term is a square, so it is positive for a rise and a fall alike.

    What the interviewer asks next

    • What is the price change if yields fall 100 basis points instead?
    • Why does a callable bond have negative convexity at low yields?
    • How would you hedge the convexity of a mortgage book?
  3. 082A Rs 200 crore bond position has a one-day 99% VaR of Rs 3 crore. The bid-ask spread on the bond is 40 basis points. What is the liquidity-adjusted VaR?Liquidity and balance sheetCoreBank market riskTreasury and ALM

    Try it first

    How much does the spread add to the Rs 3 crore VaR?

    Show the worked solution

    About Rs 3.4 crore: the Rs 3 crore VaR plus Rs 0.4 crore to get out. The position is marked at mid, but selling means taking the bid, half the spread below mid. Half of 40 basis points is 0.20%, and 0.20% of Rs 200 crore is Rs 0.4 crore. The exit cost adds 13% to the risk number, and more if spreads widen in a stress.

    Why is ordinary VaR missing a cost?

    A second-hand car dealer will quote you two prices for the same car: what he pays and what he sells for. Your car is worth the middle on paper, but if you need cash today you get the lower one. VaR is computed on mid prices, so it measures how far the value might move, not what it costs to actually leave the position. For a liquid government bond the difference is small; for a corporate bond the spread can be a meaningful share of the risk.

    Getting out costs half the spread, even on a day prices do not moveask 100.20mid 100.00bid 99.80you sell hereOne bond quote, price per 100Half spread = 0.40% / 2 = 0.20%0.20% x Rs 200 cr = Rs 0.4 cr3.03.0Market VaR3.03.4Normal spread3.0+1.24.2Stressed spread+0.4Rs crore, one day, 99%
    Selling at the bid costs half the 40 basis point spread, 0.20% of Rs 200 crore or Rs 0.4 crore, which lifts a Rs 3.0 crore market VaR to a liquidity-adjusted Rs 3.4 crore, and to Rs 4.2 crore if the spread widens to 120 basis points.
    The relationship
    LVaR=VaR+12×s×P=3.0+0.5×0.0040×200=3.4\text{LVaR} = \text{VaR} + \tfrac{1}{2} \times s \times P = 3.0 + 0.5 \times 0.0040 \times 200 = 3.4
    VaRmarket VaR on mid prices, Rs 3 crore
    sbid-ask spread as a fraction of price, 0.40%
    Pposition value, Rs 200 crore
    What it says in wordsAdd the cost of crossing half the spread to the market VaR, because that cost is paid even if prices do not move.

    What makes the adjustment larger than it looks?

    Two things, and both arrive in a stress. Spreads widen exactly when you need to sell, and a large position moves the price against you as you sell it. If the spread triples to 120 basis points, the exit cost is Rs 1.2 crore and the adjusted figure is Rs 4.2 crore, 40% above plain VaR. A risk team would also ask how many days it takes to exit Rs 200 crore without moving the market; if the answer is five days rather than one, the market VaR itself should be scaled to that horizon.

    Say the limit of the simple version: it treats the spread as a fixed number. A fuller treatment uses the spread's own volatility, adding a multiple of its standard deviation, so the adjustment reflects how bad the spread gets in a bad week, not how it looks on an average one.

    Where candidates lose it

    The common mistake is adding the full 40 basis points, Rs 0.8 crore. Positions are marked at mid, so selling costs only the distance from mid to bid, half the spread.

    The second is saying VaR already includes liquidity because it uses market prices. It uses mid prices and a one-day horizon, and assumes you could exit at mid; the question is testing whether you see that gap.

    What the interviewer asks next

    • The bond takes five days to sell without moving the price. How would you change the VaR?
    • Why might a desk argue against a liquidity add-on for government bonds?
    • How would you estimate a bid-ask spread for a bond that rarely trades?
  4. 083You have eight identical-looking balls, one of them slightly heavier, and a two-pan balance. What is the fewest number of weighings that guarantees you find the heavy ball?Logic, estimation and brainteasersCoreBank market riskRisk GCC

    Try it first

    What is the minimum number of weighings that always works?

    Show the worked solution

    Two weighings. Put three balls on each pan and leave two aside. If one pan drops, the heavy ball is among its three: weigh one against another, and a balance points to the third. If the pans balance, weigh the two set aside against each other. A balance has three outcomes, so two weighings separate up to nine balls.

    Why is halving the wrong instinct?

    A guessing game where someone answers only yes or no halves the possibilities with each question. A balance answers in three ways: left heavier, right heavier or level. Each weighing has three outcomes, so the best split is into three groups, and the balanced outcome is information, not a wasted turn. Four against four uses only two of the three outcomes, because the pans can never balance, and so it wastes a third of what the scale can tell you.

    Three outcomes per weighing, so split into three groupsWeighing 1: 1 2 3 against 4 5 67 and 8 wait on the tableleft dropsWeigh 1 against 2heavy in 1, 2, 3ball 1left dropsball 3balanceball 2right dropsbalanceWeigh 7 against 8heavy is 7 or 8ball 7left dropsball 8right dropsright dropsWeigh 4 against 5heavy in 4, 5, 6ball 4left dropsball 6balanceball 5right drops8 balls, 9 possible endings after two weighings: 3 x 3 = 9, which is at least 8
    Weighing 1, 2 and 3 against 4, 5 and 6 sends every case down one of three branches, and a second weighing within each branch names the heavy ball, so eight balls are always solved in two weighings.

    How do you prove two is the minimum and find the limit?

    One weighing has three outcomes, and eight balls need eight different answers, so one weighing cannot be enough. Two weighings have 3 times 3, nine outcomes. With w weighings you can separate at most 3 to the power w balls, so nine balls also need only two, and a tenth ball needs a third weighing. Saying the bound, not only the procedure, is what turns a trick into reasoning.

    The relationship
    3w≥n⇒w=⌈log⁡38⌉=23^{w} \ge n \quad\Rightarrow\quad w = \lceil \log_3 8 \rceil = 2
    wnumber of weighings
    nnumber of balls, 8
    3outcomes of one weighing
    What it says in wordsYou need enough weighings that three to the power of that number covers every ball.

    Why would a risk interviewer ask this?

    It tests whether you count what a test can tell you before you run it. The same habit applies to a control check: a review that can only return pass or fail tells you less than one that also flags items for a closer look. Name the three outcomes first and the answer follows.

    Where candidates lose it

    Most candidates split four against four, then two against two, then one against one, and answer three. It works, but it is not the minimum, because a balance never happens in the first two steps.

    The other loss is finding two weighings without saying why one is impossible. Give the counting bound: one weighing, three outcomes, fewer than eight balls.

    What the interviewer asks next

    • What is the most balls you can handle in three weighings?
    • Now you do not know whether the odd ball is heavier or lighter. How many weighings for twelve balls?
    • What if the scale shows the weight difference rather than just which side drops?
  5. 084An erroneous payment must pass three independent checkers, each of whom catches 80% of errors. What share of errors gets through, and why is the real figure likely to be higher?Operational loss and fraudCoreOperational risk

    Try it first

    Out of 100 errors, how many get past all three checkers if they really are independent?

    Show the worked solution

    About 0.8% get through if the checkers are truly independent. Each misses 20% of what reaches them, so 100 errors become 20, then 4, then 0.8. The real figure is likely higher because the checkers are not independent: later checkers relax because someone already looked. If checkers two and three catch only 40%, 7.2% get through, nine times as many.

    Why do independent checks multiply?

    Think of three sieves stacked on top of each other. If each lets one grain in five through, the first passes 20 of 100 grains, the second 4 of those 20, and the third 0.8 of the 4. When checks are independent, the chance of an error getting past all of them is the product of each one's miss rate. That is why a three-check process looks almost watertight on paper: 0.2 cubed is 0.008.

    Independent checks multiply; checkers who lean on each other do notIndependent: each catches 80%1002040.8Checkers 2 and 3 lean on checker 1: they catch 40%100Errors made20After checker 112After checker 27.2After checker 30.2 x 0.2 x 0.2= 0.8%get through0.2 x 0.6 x 0.6= 7.2%get through
    Independent checkers catching 80% each let 100 errors shrink to 20, 4 and then 0.8, but if the second and third checkers lean on the first and catch only 40%, 100 errors shrink to 20, 12 and 7.2, nine times as many.

    Why is the real leakage higher than 0.8%?

    Because people who know others are checking check less carefully. The second checker assumes the first caught the obvious problems, and the third signs off because two colleagues already did. Checks that rely on each other are not independent, and once they are correlated the multiplication rule overstates how much they catch. There is also a common cause: an error that looks like a normal payment, a correct-looking amount to a familiar name, fools all three checkers for the same reason.

    The relationship
    P(leak)=∏i(1−ci)=0.2×0.6×0.6=0.072P(\text{leak}) = \prod_i (1 - c_i) = 0.2 \times 0.6 \times 0.6 = 0.072
    c_ithe catch rate of checker i
    0.2the first checker's miss rate
    0.6the miss rate of a checker who leans on the one before
    What it says in wordsThe share of errors that gets through is the product of the miss rates, so a drop in the later checkers' care multiplies straight into the leak.

    What would an operational risk team do about it?

    Measure each check on its own, not the chain. Seed known errors into the flow and count what each checker catches; rotate who checks first; give each checker a different thing to look for rather than the same whole payment. The goal is to make the checks genuinely independent, because three checks that behave like one are more dangerous than one check everyone knows is the only one.

    Where candidates lose it

    The first slip is adding: three checks at 80% sound like 240% coverage, or candidates subtract 3 times 20% and get a negative. Multiply the miss rates, not the catch rates.

    The bigger miss is stopping at 0.8%. The interviewer asked why the real figure is higher; name reliance between checkers and a common cause, and give a number for how much it matters.

    What the interviewer asks next

    • How would you test whether your checkers really are independent?
    • Would you rather have three checkers at 80% or one automated check at 99%?
    • An error gets through all three checks. How do you run the review?
  6. 086Ten fund managers each have a 50% chance of beating the index in any year, with no skill at all. What is the probability that at least one of them beats it five years running?Probability and base ratesCoreAsset manager risk

    Try it first

    Roughly how likely is it that at least one of ten coin-flipping managers has a five-year streak?

    Show the worked solution

    About 27.2%. One manager beats the index five years running with probability one half to the fifth, 1 in 32. The chance that none of the ten does it is 31/32 to the power 10, about 0.728. So at least one streak appears 27.2% of the time with no skill anywhere. With 100 managers it is 95.8%.

    Why is a streak among many managers weak evidence?

    Ask a hall of 300 people to toss a coin five times, and about nine will throw five heads. Nobody would call them skilled tossers. The chance that one named person has a streak is small, but the chance that someone in a crowd has one is large, and a fund manager with a five-year record is usually picked from a crowd. Which question you are answering decides everything: the probability for manager G, or the probability for whoever turned out to have the streak.

    With enough managers, a five-year streak is what luck looks likeY1Y2Y3Y4Y5ABCDEFGfive in a rowHIJbeat indexdid notChance of a five-year streak by luck aloneOne manager1 in 32 = 3.1%At least one of 1027.2%At least one of 10095.8%1 - (31/32) to the power 10= 1 - 0.728 = 27.2%
    Among ten coin-flipping managers, one happens to beat the index all five years; the chance for any single manager is only 1 in 32, but at least one of ten does it 27.2% of the time and at least one of 100 does it 95.8% of the time.
    The relationship
    P(at least one)=1−(1−132)10=1−0.728=0.272P(\text{at least one}) = 1 - \left(1 - \tfrac{1}{32}\right)^{10} = 1 - 0.728 = 0.272
    1/32one manager beating the index five years in a row by chance
    10the number of managers
    What it says in wordsWork out the chance that nobody has a streak, then take it away from one.

    How do you get there fast without a calculator?

    Use the expected count first: ten managers times 1 in 32 is about 0.31 streaks. When the expected count is small, the chance of at least one is a little below it, so 31% is an upper bound and the exact answer is about 27%. The gap comes from the chance of two or more streaks, which the simple sum counts twice. Saying the bound and then the exact figure shows the interviewer you can check your own work.

    What does an asset manager's risk team do with this?

    It sets the bar for evidence. A five-year record of beating the index is common among hundreds of funds even if none has skill, so the team looks at how the returns were earned: the size of the edge against its volatility, whether it comes from one bet or many, and whether the process explains the outcome. Survivorship matters too: the managers whose streaks broke often closed their funds, so the crowd you see is already filtered toward winners.

    Where candidates lose it

    The fast wrong answer is 3.1%, the chance for one named manager. The question asks about any of ten, and the interviewer is testing whether you notice the difference.

    The other miss is adding ten times 3.1% and calling it 31%. That overcounts the cases with two streaks; give it as a bound and then the exact figure.

    What the interviewer asks next

    • How many managers would you need before a ten-year streak by luck is more likely than not?
    • A fund's marketing shows five straight years of beating the index. What questions do you ask?
    • How does survivorship bias change these numbers?
  7. 087A desk's daily returns have a volatility of 1%. Over 250 days its average daily return is 0.05%. How precisely is that mean estimated, and can you say the desk has skill?Statistics and estimationCoreAsset manager riskQuant risk

    Try it first

    Is 0.05% a day, measured over one year, clearly different from zero?

    Show the worked solution

    Not precisely enough to claim skill. The standard error of the mean is the daily volatility over the square root of the number of days: 1% over the square root of 250, about 0.063%. The estimate of 0.05% is only 0.79 standard errors from zero, and a two standard error band runs from -0.076% to 0.176%. You would need about 1,600 days, 6.4 years, to clear zero.

    Why is a year of daily data not enough?

    Weigh yourself on a bathroom scale that jumps by two kilos each time you step on it. If you lost 100 grams last month, a week of readings will not show it; the jumps drown the signal. The precision of an average improves only with the square root of the number of observations, so a small edge buried in large daily noise takes years to show. Here the daily noise is 1% and the edge is 0.05%, twenty times smaller.

    The relationship
    SE=σn=1%250=0.063%t=0.050.063=0.79SE = \frac{\sigma}{\sqrt{n}} = \frac{1\%}{\sqrt{250}} = 0.063\% \qquad t = \frac{0.05}{0.063} = 0.79
    sigmadaily return volatility, 1%
    nnumber of daily observations, 250
    thow many standard errors the mean is from zero
    What it says in wordsThe mean's uncertainty is the daily volatility divided by the square root of the number of days, and the edge is less than one of those units from zero.
    One year of data cannot tell a 0.05% edge from zerozero: no skill250 daysone year-0.076%+0.176%1,600 daysabout 6.4 years0.000%+0.100%estimate 0.05%-0.10%0+0.10%+0.20%Average daily return, with a two standard error band
    After 250 days the two standard error band around the 0.05% daily mean runs from -0.076% to 0.176% and straddles zero; after about 1,600 days, 6.4 years, the band narrows to 0.000% to 0.100% and only just clears zero.

    How long would it take, and what does that mean for judging desks?

    Set the t-statistic to 2 and solve for n: n equals (2 times 1% over 0.05%) squared, which is 1,600 days. An annual Sharpe ratio of about 0.79 needs more than six years of data before it is statistically distinguishable from zero. That is longer than most desks keep the same strategy, so a risk team cannot rely on the P&L record alone; it looks at whether the edge has a reason, whether it survives out of sample, and how much the result depends on a few days.

    State the assumptions. The calculation treats daily returns as independent with constant volatility. Fat tails and volatility clustering make the true uncertainty larger, so six years is a floor, not a promise.

    Where candidates lose it

    The common error is annualising the mean to 12.5% and declaring skill, as if a big annual number were proof. The annual volatility grows too, to about 16%, and the ratio of the two is what matters.

    The other slip is dividing by 250 instead of its square root, which makes the mean look fifty times more precise than it is.

    What the interviewer asks next

    • The desk's volatility is 0.5% instead. How many days now?
    • Why is the mean so much harder to estimate than the volatility?
    • How would you judge a new desk that has only six months of history?
  8. 088A treasury holds Rs 500 crore of government bonds with a modified duration of 6. Daily changes in yield have a standard deviation of 6 basis points. What is the one-day 99% VaR?VaR and expected shortfallCoreUBSAnonymous employee in · 2020

    Try it first

    What is the position's DV01, the loss for a one basis point rise in yield?

    Show the worked solution

    About Rs 4.19 crore. The position loses Rs 500 crore times 6 times 0.0001, Rs 30 lakh, for each basis point rise in yield. A 99% one-day rise is 2.33 times 6 basis points, about 14 basis points. Rs 30 lakh times 13.96 is Rs 4.19 crore. It assumes normal yield changes and a linear price response.

    Why start from DV01 instead of a price volatility?

    A taxi fare is a rate per kilometre times the distance. You would not guess the fare directly; you would multiply. For a bond, DV01 is the rupee rate per basis point and the yield move is the distance, so VaR is DV01 times the yield move at the chosen confidence. Yield volatility is what the market data gives you, and duration converts it to rupees. Guessing a price volatility for the bond skips the step the interviewer wants to see.

    Bond VaR = rupees per basis point x the 99% yield movePositionRs 500 cr, duration 6DV01Rs 30 lakh per bp99% yield move2.33 x 6 bp = 14.0 bpOne-day 99% VaRRs 4.19 crore500 x 6 x 0.0001 = 0.30 crore = Rs 30 lakh a bp0.30 x 13.96 = 4.19+14.0 bpworst 1% of days-18-12-60+6+12+18Daily change in yield, bp (standard deviation 6)yields up = bond price down,so the right tail is the loss
    A Rs 500 crore position with duration 6 loses Rs 30 lakh per basis point; a 99% daily yield rise is 2.33 times 6 basis points, 14.0 basis points, so the one-day 99% VaR is Rs 4.19 crore, the loss on the worst 1% of days.
    The relationship
    VaR99=P⋅D⋅0.0001⋅z99⋅σbp=500×6×0.0001×2.33×6=4.19\text{VaR}_{99} = P \cdot D \cdot 0.0001 \cdot z_{99} \cdot \sigma_{bp} = 500 \times 6 \times 0.0001 \times 2.33 \times 6 = 4.19
    Pposition value, Rs 500 crore
    Dmodified duration, 6
    z2.33, the one-sided 99% point
    sigma_bpdaily standard deviation of yield, 6 bp
    What it says in wordsMultiply rupees lost per basis point by the yield rise that is exceeded only one day in a hundred.

    What does this number leave out?

    Three things, and a treasury risk manager names them unprompted. The estimate assumes yield changes are normal, that the price responds in a straight line, and that every bond in the book moves with the same yield. Fat tails make a 14 basis point day more common than the normal says. Convexity makes the true loss slightly smaller than the linear figure. And a book spread along the curve has curve risk: if short yields rise and long yields do not, one DV01 figure misses it. Over ten days, the square-root rule would scale this to about Rs 13.2 crore, if daily moves are independent.

    Also say which way hurts. A holder of bonds loses when yields rise, so the one-sided 99% point on the upside of yields is the one that matters, which is why the figure uses 2.33 and not the two-sided 2.58.

    Where candidates lose it

    The usual slip is a units error: forgetting that a basis point is 0.0001 and producing a VaR a hundred times too large or too small. Say DV01 out loud first, Rs 30 lakh a basis point, and the rest follows.

    The other is using 2.58 because 99% sounds like a two-sided number. VaR is a one-sided loss measure, so the multiplier is 2.33.

    What the interviewer asks next

    • What is the 99% expected shortfall under the same normal assumption?
    • The book holds 2-year and 10-year bonds with the same total DV01. What risk does one number hide?
    • How would convexity change the VaR for a 300 basis point stress?

    Asked at UBS, Risk Management, Anonymous employee in, 2020 (Wall Street Oasis): Calculate VAR

  9. 093A company's depreciation rises by Rs 10 crore and the tax rate is 25%. Walk the change through the income statement, the cash flow statement and the balance sheet.Credit risk arithmeticCoreMoody'sNew York · 2022

    Try it first

    What happens to the company's cash?

    Show the worked solution

    Net income falls Rs 7.5 crore, cash rises Rs 2.5 crore, and both sides of the balance sheet fall Rs 7.5 crore. Pre-tax profit drops 10, tax drops 2.5, so net income drops 7.5. The cash flow statement adds back the non-cash 10, leaving cash up 2.5. On the balance sheet, cash is up 2.5 and fixed assets down 10, total assets down 7.5, matched by retained earnings down 7.5.

    How does a non-cash charge put cash in the bank?

    Think of a shopkeeper who can deduct the wear on his delivery van from his taxable income. Writing the van down costs him nothing today, since he paid for it years ago, but it lowers the tax bill he pays this year. Depreciation moves no cash itself; the only cash effect is the tax it saves, 25% of Rs 10 crore, Rs 2.5 crore. That tax shield is the whole answer on cash, and the three statements are the bookkeeping that proves it.

    A Rs 10 crore non-cash charge leaves the company Rs 2.5 crore richer in cashIncome statementDepreciation+10.0Pre-tax profit-10.0Tax at 25%-2.5Net income-7.5Cash flow statementNet income-7.5Add back depreciation+10.0(non-cash charge)Cash from operations+2.5Balance sheetCash+2.5Fixed assets-10.0Total assets-7.5Retained earnings-7.5Both sides-7.5Net income flows to the cash flow statement and to retained earnings; the cash change flows to the balance sheet.The cash gain is the tax saved: 25% x 10 = 2.5.
    Extra depreciation of Rs 10 crore cuts net income by Rs 7.5 crore after a Rs 2.5 crore tax saving, the add-back leaves cash from operations up Rs 2.5 crore, and the balance sheet shows cash up 2.5 and fixed assets down 10, total assets down 7.5, matched by retained earnings down 7.5.

    What order do you walk it in?

    Income statement first, because everything starts from net income. Then the cash flow statement: net income down 7.5, add back the 10 of depreciation because no cash left, and cash from operations is up 2.5. Finish on the balance sheet and prove it balances: assets fall by 10 of fixed assets less 2.5 of extra cash, 7.5, and equity falls by the 7.5 of lower retained earnings. Stating that both sides moved by the same 7.5 is the check the interviewer is waiting for.

    The relationship
    ΔNI=−10(1−0.25)=−7.5ΔCash=−7.5+10=+2.5\Delta NI = -10(1 - 0.25) = -7.5 \qquad \Delta \text{Cash} = -7.5 + 10 = +2.5
    Delta NIchange in net income
    0.25tax rate
    +10the depreciation added back because no cash was spent
    What it says in wordsNet income falls by the after-tax charge, and cash rises by the tax the charge saved.

    Why does a credit analyst care?

    Because a lender is repaid in cash, not in profit. A company whose earnings fall because of higher depreciation may be generating slightly more cash, so interest cover measured on net income and on cash flow can move in opposite directions. The limit: the tax saving is real only if the company is paying tax; a loss-making company gets no cash benefit this year, and a higher depreciation charge often reflects heavy past capital spending that the analyst should look at directly.

    Where candidates lose it

    The usual slip is saying cash is unchanged because depreciation is non-cash, which forgets the tax line. The second most common is cash down 7.5, following net income and forgetting the add-back.

    The other loss is not closing the balance sheet. Say the two sides out loud, assets down 7.5 and equity down 7.5, so the interviewer hears that it balances.

    What the interviewer asks next

    • Walk through the same change if the company is loss-making and pays no tax.
    • Now the company buys Rs 50 crore of equipment with cash. Walk the three statements.
    • Why might a rating agency look at EBITDA rather than net income for this company?

    Asked at Moody's, Generalist, New York, 2022 (Wall Street Oasis): how the 3 statements are related / connected.

  10. 095A trader hiding a Rs 1 crore loss doubles the position each month to win it back, and loses six months running, starting with the Rs 1 crore. What is the hidden loss now, and what does the pattern tell a control function?Operational loss and fraudCoreOperational riskBank market risk

    Try it first

    After six losing months, how big is the hidden loss?

    Show the worked solution

    Rs 63 crore. The monthly losses double: 1, 2, 4, 8, 16 and 32 crore, and they add to 2 to the power 6, less 1, which is 63. Each month's loss is one more than everything before it combined, so the hole grows as fast as the bets. For a control function, the pattern is the signal: position size growing geometrically with no matching approved limit.

    Why does doubling down grow the hole so fast?

    A gambler at a roulette table who doubles his bet after every loss plans to recover everything with one win. After six losses in a row he has lost 63 times his first stake and must bet 64 times it to break even, if the table allows it. Doubling means each new bet equals all past losses plus one, so the cumulative loss is always just under the next bet, and a short losing run produces an enormous number. The strategy fails when the losing run is longer than the capital or the limit.

    Doubling down turns a Rs 1 crore hole into Rs 63 crore in six months102030405060700Month 1lost 1Month 2lost 2Month 3lost 4Month 4lost 8Month 5lost 16Month 6lost 3237153163Rs 63 crore hiddenloss that month, Rs crorecumulative hidden lossNext month's bet would need Rs 64 crore of risk to win it all back
    Monthly losses of Rs 1, 2, 4, 8, 16 and 32 crore take the hidden loss from Rs 1 crore to Rs 63 crore in six months, and winning it back in month seven would need Rs 64 crore of risk.
    The relationship
    ∑k=052k=26−1=63\sum_{k=0}^{5} 2^k = 2^6 - 1 = 63
    2^kthe loss in month k+1, in Rs crore
    2^6 - 1the total after six months
    What it says in wordsA run of doubling losses sums to one less than the next doubling.

    What should a control function see before month six?

    Several things, and none needs the trader's honesty. A position growing geometrically, a P&L that is flat or smooth while the gross position explodes, and large trades that are cancelled, amended or booked to unusual accounts are the classic signs of concealed losses. Gross notional limits catch the growth even when net risk looks small. Reconciling traded volumes with confirmations from counterparties catches fictitious offsetting trades. A mandatory two-week leave rule catches positions that need the trader to keep rolling them.

    The operational risk lesson is that the fraud is the smaller part of the loss. A Rs 1 crore trading loss, reported on day one, is a normal cost of business; the controls failed on the other Rs 62 crore. That is why control reviews measure time to detection, not only whether a loss was eventually found.

    Where candidates lose it

    The fast wrong answer is Rs 32 crore, the last month's loss, or Rs 64 crore, the next bet. The total is the sum, 63, and saying 2 to the power 6 less 1 shows the pattern.

    The larger miss is stopping at the arithmetic. The question asks what the pattern tells a control function: name gross position growth, smooth reported P&L and cancelled or amended trades as the signals.

    What the interviewer asks next

    • Which single control would have caught this earliest, and why?
    • Why do concealed trading losses often come with unusually smooth reported P&L?
    • How would you design a key risk indicator for this pattern?
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