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Risk Management puzzles, solved step by step

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All topicsCapital and leverage6Compounding and drawdowns8Correlation and diversification8Counterparty exposure and collateral7Credit risk arithmetic10Duration and rates7Liquidity and balance sheet7Logic, estimation and brainteasers7Operational loss and fraud7Options and Greeks7Probability and base rates8Statistics and estimation10VaR and expected shortfall8
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Showing 71–80 of 83 · filtered from 100Clear filters
  1. 084An erroneous payment must pass three independent checkers, each of whom catches 80% of errors. What share of errors gets through, and why is the real figure likely to be higher?Operational loss and fraudCoreOperational risk

    Try it first

    Out of 100 errors, how many get past all three checkers if they really are independent?

    Show the worked solution

    About 0.8% get through if the checkers are truly independent. Each misses 20% of what reaches them, so 100 errors become 20, then 4, then 0.8. The real figure is likely higher because the checkers are not independent: later checkers relax because someone already looked. If checkers two and three catch only 40%, 7.2% get through, nine times as many.

    Why do independent checks multiply?

    Think of three sieves stacked on top of each other. If each lets one grain in five through, the first passes 20 of 100 grains, the second 4 of those 20, and the third 0.8 of the 4. When checks are independent, the chance of an error getting past all of them is the product of each one's miss rate. That is why a three-check process looks almost watertight on paper: 0.2 cubed is 0.008.

    Independent checks multiply; checkers who lean on each other do notIndependent: each catches 80%1002040.8Checkers 2 and 3 lean on checker 1: they catch 40%100Errors made20After checker 112After checker 27.2After checker 30.2 x 0.2 x 0.2= 0.8%get through0.2 x 0.6 x 0.6= 7.2%get through
    Independent checkers catching 80% each let 100 errors shrink to 20, 4 and then 0.8, but if the second and third checkers lean on the first and catch only 40%, 100 errors shrink to 20, 12 and 7.2, nine times as many.

    Why is the real leakage higher than 0.8%?

    Because people who know others are checking check less carefully. The second checker assumes the first caught the obvious problems, and the third signs off because two colleagues already did. Checks that rely on each other are not independent, and once they are correlated the multiplication rule overstates how much they catch. There is also a common cause: an error that looks like a normal payment, a correct-looking amount to a familiar name, fools all three checkers for the same reason.

    The relationship
    P(leak)=∏i(1−ci)=0.2×0.6×0.6=0.072P(\text{leak}) = \prod_i (1 - c_i) = 0.2 \times 0.6 \times 0.6 = 0.072
    c_ithe catch rate of checker i
    0.2the first checker's miss rate
    0.6the miss rate of a checker who leans on the one before
    What it says in wordsThe share of errors that gets through is the product of the miss rates, so a drop in the later checkers' care multiplies straight into the leak.

    What would an operational risk team do about it?

    Measure each check on its own, not the chain. Seed known errors into the flow and count what each checker catches; rotate who checks first; give each checker a different thing to look for rather than the same whole payment. The goal is to make the checks genuinely independent, because three checks that behave like one are more dangerous than one check everyone knows is the only one.

    Where candidates lose it

    The first slip is adding: three checks at 80% sound like 240% coverage, or candidates subtract 3 times 20% and get a negative. Multiply the miss rates, not the catch rates.

    The bigger miss is stopping at 0.8%. The interviewer asked why the real figure is higher; name reliance between checkers and a common cause, and give a number for how much it matters.

    What the interviewer asks next

    • How would you test whether your checkers really are independent?
    • Would you rather have three checkers at 80% or one automated check at 99%?
    • An error gets through all three checks. How do you run the review?
  2. 085A rule of thumb says an at-the-money option is worth about 0.4 times volatility times the square root of time times the price. What is a three-month at-the-money call on a Rs 1,000 stock with 20% volatility worth?Options and GreeksWarm upBank market riskQuant risk

    Try it first

    Roughly what is the premium?

    Show the worked solution

    About Rs 40. The typical one-year move is 20% of Rs 1,000, Rs 200. Over three months it is Rs 200 times the square root of 0.25, Rs 100. The call is worth about 0.4 of that typical move, Rs 40. A full Black-Scholes calculation at zero rates gives Rs 39.88, so the rule is within a rupee.

    Why is the premium a slice of the typical move?

    Imagine insuring a shop's daily takings against a bad day. The premium depends on how much the takings usually swing, not on how large the takings are. An at-the-money option pays out on the upside half of the stock's moves, so its value is proportional to the size of a typical move over the option's life, not to the stock price itself. The price enters only through converting volatility into rupees.

    An at-the-money premium is a slice of the typical move, not of the priceShare priceRs 1,000x volatility 20%Rs 200a typical move over one yearx sqrt(0.25) = 0.5Rs 100a typical move over three monthsx 0.4Rs 40the at-the-money call premiumWhy 0.4? The average payoff of the upside half of a normal move is 1 / sqrt(2 x pi) = 0.399 of one standard deviation.Black-Scholes at zero rates: Rs 39.88. The rule is within 0.3%.
    Rs 1,000 times 20% volatility is a Rs 200 one-year move, times the square root of 0.25 is a Rs 100 three-month move, and 0.4 of that is a Rs 40 premium, within 0.12 of the Black-Scholes value of Rs 39.88.
    The relationship
    CATM≈0.4 σT S=0.4×0.20×0.25×1000=40C_{ATM} \approx 0.4\, \sigma \sqrt{T}\, S = 0.4 \times 0.20 \times \sqrt{0.25} \times 1000 = 40
    sigmaannual volatility, 20%
    Ttime to expiry in years, 0.25
    Sshare price, Rs 1,000
    0.4about 1 over the square root of 2 pi
    What it says in wordsMultiply the price by volatility and the square root of time to get a typical move, then take 0.4 of it.

    Where does 0.4 come from, and when does the rule fail?

    If the stock's move is roughly normal with standard deviation of one typical move, the average payoff from the upside half is that deviation divided by the square root of 2 pi, 0.399. The 0.4 is not a fudge factor; it is the average size of the positive half of a normal move. The rule is built for at-the-money options with short expiries and low rates. It fails for options far in or out of the money, where the payoff is mostly intrinsic value or mostly zero, and over long horizons, where interest rates and the skew of returns start to matter.

    A risk manager uses this to sanity-check a trader's mark in ten seconds. If a three-month at-the-money call on a Rs 1,000 stock is marked at Rs 70, the mark implies volatility of about 35%, which is a question worth asking.

    Where candidates lose it

    The common error is scaling time linearly: a quarter of a year, so a quarter of Rs 200, then 0.4 of Rs 50 gives Rs 20. Volatility scales with the square root of time, so three months is half a year's move.

    The other slip is applying the rule to a deep out-of-the-money option. Say it is an at-the-money shortcut and name where it breaks.

    What the interviewer asks next

    • What is the matching at-the-money put worth at zero rates?
    • How much does the premium rise if volatility doubles, and if time to expiry doubles?
    • A trader marks the call at Rs 70. What implied volatility is that?
  3. 086Ten fund managers each have a 50% chance of beating the index in any year, with no skill at all. What is the probability that at least one of them beats it five years running?Probability and base ratesCoreAsset manager risk

    Try it first

    Roughly how likely is it that at least one of ten coin-flipping managers has a five-year streak?

    Show the worked solution

    About 27.2%. One manager beats the index five years running with probability one half to the fifth, 1 in 32. The chance that none of the ten does it is 31/32 to the power 10, about 0.728. So at least one streak appears 27.2% of the time with no skill anywhere. With 100 managers it is 95.8%.

    Why is a streak among many managers weak evidence?

    Ask a hall of 300 people to toss a coin five times, and about nine will throw five heads. Nobody would call them skilled tossers. The chance that one named person has a streak is small, but the chance that someone in a crowd has one is large, and a fund manager with a five-year record is usually picked from a crowd. Which question you are answering decides everything: the probability for manager G, or the probability for whoever turned out to have the streak.

    With enough managers, a five-year streak is what luck looks likeY1Y2Y3Y4Y5ABCDEFGfive in a rowHIJbeat indexdid notChance of a five-year streak by luck aloneOne manager1 in 32 = 3.1%At least one of 1027.2%At least one of 10095.8%1 - (31/32) to the power 10= 1 - 0.728 = 27.2%
    Among ten coin-flipping managers, one happens to beat the index all five years; the chance for any single manager is only 1 in 32, but at least one of ten does it 27.2% of the time and at least one of 100 does it 95.8% of the time.
    The relationship
    P(at least one)=1−(1−132)10=1−0.728=0.272P(\text{at least one}) = 1 - \left(1 - \tfrac{1}{32}\right)^{10} = 1 - 0.728 = 0.272
    1/32one manager beating the index five years in a row by chance
    10the number of managers
    What it says in wordsWork out the chance that nobody has a streak, then take it away from one.

    How do you get there fast without a calculator?

    Use the expected count first: ten managers times 1 in 32 is about 0.31 streaks. When the expected count is small, the chance of at least one is a little below it, so 31% is an upper bound and the exact answer is about 27%. The gap comes from the chance of two or more streaks, which the simple sum counts twice. Saying the bound and then the exact figure shows the interviewer you can check your own work.

    What does an asset manager's risk team do with this?

    It sets the bar for evidence. A five-year record of beating the index is common among hundreds of funds even if none has skill, so the team looks at how the returns were earned: the size of the edge against its volatility, whether it comes from one bet or many, and whether the process explains the outcome. Survivorship matters too: the managers whose streaks broke often closed their funds, so the crowd you see is already filtered toward winners.

    Where candidates lose it

    The fast wrong answer is 3.1%, the chance for one named manager. The question asks about any of ten, and the interviewer is testing whether you notice the difference.

    The other miss is adding ten times 3.1% and calling it 31%. That overcounts the cases with two streaks; give it as a bound and then the exact figure.

    What the interviewer asks next

    • How many managers would you need before a ten-year streak by luck is more likely than not?
    • A fund's marketing shows five straight years of beating the index. What questions do you ask?
    • How does survivorship bias change these numbers?
  4. 087A desk's daily returns have a volatility of 1%. Over 250 days its average daily return is 0.05%. How precisely is that mean estimated, and can you say the desk has skill?Statistics and estimationCoreAsset manager riskQuant risk

    Try it first

    Is 0.05% a day, measured over one year, clearly different from zero?

    Show the worked solution

    Not precisely enough to claim skill. The standard error of the mean is the daily volatility over the square root of the number of days: 1% over the square root of 250, about 0.063%. The estimate of 0.05% is only 0.79 standard errors from zero, and a two standard error band runs from -0.076% to 0.176%. You would need about 1,600 days, 6.4 years, to clear zero.

    Why is a year of daily data not enough?

    Weigh yourself on a bathroom scale that jumps by two kilos each time you step on it. If you lost 100 grams last month, a week of readings will not show it; the jumps drown the signal. The precision of an average improves only with the square root of the number of observations, so a small edge buried in large daily noise takes years to show. Here the daily noise is 1% and the edge is 0.05%, twenty times smaller.

    The relationship
    SE=σn=1%250=0.063%t=0.050.063=0.79SE = \frac{\sigma}{\sqrt{n}} = \frac{1\%}{\sqrt{250}} = 0.063\% \qquad t = \frac{0.05}{0.063} = 0.79
    sigmadaily return volatility, 1%
    nnumber of daily observations, 250
    thow many standard errors the mean is from zero
    What it says in wordsThe mean's uncertainty is the daily volatility divided by the square root of the number of days, and the edge is less than one of those units from zero.
    One year of data cannot tell a 0.05% edge from zerozero: no skill250 daysone year-0.076%+0.176%1,600 daysabout 6.4 years0.000%+0.100%estimate 0.05%-0.10%0+0.10%+0.20%Average daily return, with a two standard error band
    After 250 days the two standard error band around the 0.05% daily mean runs from -0.076% to 0.176% and straddles zero; after about 1,600 days, 6.4 years, the band narrows to 0.000% to 0.100% and only just clears zero.

    How long would it take, and what does that mean for judging desks?

    Set the t-statistic to 2 and solve for n: n equals (2 times 1% over 0.05%) squared, which is 1,600 days. An annual Sharpe ratio of about 0.79 needs more than six years of data before it is statistically distinguishable from zero. That is longer than most desks keep the same strategy, so a risk team cannot rely on the P&L record alone; it looks at whether the edge has a reason, whether it survives out of sample, and how much the result depends on a few days.

    State the assumptions. The calculation treats daily returns as independent with constant volatility. Fat tails and volatility clustering make the true uncertainty larger, so six years is a floor, not a promise.

    Where candidates lose it

    The common error is annualising the mean to 12.5% and declaring skill, as if a big annual number were proof. The annual volatility grows too, to about 16%, and the ratio of the two is what matters.

    The other slip is dividing by 250 instead of its square root, which makes the mean look fifty times more precise than it is.

    What the interviewer asks next

    • The desk's volatility is 0.5% instead. How many days now?
    • Why is the mean so much harder to estimate than the volatility?
    • How would you judge a new desk that has only six months of history?
  5. 089Bank A reports a CET1 ratio of 14%, with risk-weighted assets equal to 25% of its total assets. Bank B reports 11%, with risk-weighted assets at 55% of total assets. Which bank has more equity per rupee of assets?Capital and leverageHardBank credit riskRating agency

    Try it first

    Which bank holds more equity for every rupee of assets?

    Show the worked solution

    Bank B, with about 6.05% of assets in equity against 3.5% for bank A. Equity to assets is the CET1 ratio times the share of assets that count as risk-weighted: 14% times 25% for A, 11% times 55% for B. A's higher ratio rests on low risk weights, so it is levered about 29 times against B's 16.5 times.

    Why can a higher capital ratio mean less capital?

    Two people each say they save 20% of their income. One counts only the salary left after rent; the other counts the whole salary. The first sounds equally thrifty but saves far fewer rupees. A CET1 ratio divides equity by risk-weighted assets, not total assets, so a bank that assigns low risk weights to its loans can show a high ratio on a thin equity base. The share of assets that ends up risk-weighted is called {term('RWA density', 'Risk-weighted assets divided by total assets; a low figure means the bank judges most of its assets to be low risk.')}, and it is the number that reconciles the two views.

    The relationship
    EA=ERWA×RWAAA:14%×25%=3.5%B:11%×55%=6.05%\frac{E}{A} = \frac{E}{RWA} \times \frac{RWA}{A} \qquad A: 14\% \times 25\% = 3.5\% \qquad B: 11\% \times 55\% = 6.05\%
    ECET1 equity
    RWArisk-weighted assets
    Atotal assets
    What it says in wordsEquity per rupee of assets is the CET1 ratio multiplied by the RWA density.
    Divide by assets instead of risk-weighted assets and the ranking flips14.00%Bank Ahigher11%Bank BCET1 ratio (equity / RWA)3.50%Bank A6.05%Bank BhigherEquity / total assetsRisk weightsA: RWA = 25% of assetsB: RWA = 55% of assets14% x 25% = 3.5%
    Bank A's CET1 ratio of 14% beats bank B's 11%, but because A's risk-weighted assets are only 25% of its assets against B's 55%, A holds 3.5% of assets in equity and B holds 6.05%, and the ranking flips.

    Which number should a credit analyst trust?

    Both, because they answer different questions. The CET1 ratio is right if the risk weights are right. Equity to assets makes no judgement about risk, so it is the check on whether the risk weights are doing too much of the work. Test A's number: if its true risk density were 40% rather than 25%, perhaps because its internal models are optimistic, its CET1 ratio would be 3.5% over 40%, only 8.75%. That is why regulators set a leverage ratio floor alongside risk-based ratios; the current minimum is set by the regulator, so confirm it before quoting it.

    What would make bank A's low density legitimate?

    A book of home loans with low loan-to-value ratios, or large holdings of government bonds, genuinely carries low risk weights, and a 25% density can be honest. The question is whether the weights are earned. An analyst asks what the assets are, whether the density has fallen while the book stayed the same, and how the bank's model-based weights compare with the standardised ones.

    Where candidates lose it

    Most candidates answer bank A, reading the higher ratio as more capital. The question is built to see whether you ask what the denominator is.

    The second miss is getting B and then calling A unsafe. A low density can be legitimate; say what you would check before concluding the weights are too low.

    What the interviewer asks next

    • What happens to bank A's CET1 ratio if its risk weights rise to the level of bank B's?
    • Why do regulators set a leverage ratio at all if risk-weighted ratios exist?
    • Which kinds of assets carry low risk weights, and which of them surprised people in past crises?
  6. 090A fund's NAV over six observations is 100, 120, 90, 130, 100 and 140. What is its maximum drawdown?Compounding and drawdownsWarm upAsset manager risk

    Try it first

    What is the maximum drawdown?

    Show the worked solution

    25%. Drawdown is measured from the highest value reached so far. The fund peaks at 120 and falls to 90, a 25% drop. It then peaks at 130 and falls to 100, a 23.1% drop. The larger of the two, 25%, is the maximum drawdown. Measured from the start the worst point looks like only 10%, which understates the pain.

    Why measure from the running peak?

    If your savings climbed to Rs 1.2 lakh and then fell to Rs 90,000, you would not console yourself that you started with Rs 1 lakh. You lost Rs 30,000 of money you had. Drawdown measures the fall from the highest value an investor has held so far, because that is the loss an investor who bought at the top actually suffers. The running peak resets upward each time the fund makes a new high, and each drawdown is measured against it.

    Drawdown is measured from the running peak, not from the start8010012014010012090130100140120 to 90-25.0%130 to 100-23.1%from the start: only -10%running peak (dashed)t0t1t2t3t4t5ObservationNAV
    The fund's NAV falls 25.0% from its peak of 120 to 90 and 23.1% from its later peak of 130 to 100, so the maximum drawdown is 25%, although the worst point measured from the start of 100 is only 10% down.
    The relationship
    DDt=Vtmax⁡s≤tVs−1MDD=min⁡tDDt=90120−1=−25%DD_t = \frac{V_t}{\max_{s \le t} V_s} - 1 \qquad MDD = \min_t DD_t = \frac{90}{120} - 1 = -25\%
    V_tNAV at time t
    max V_sthe running peak up to time t
    MDDmaximum drawdown, the deepest fall from a running peak
    What it says in wordsEach point's drawdown is how far it sits below the best value seen so far; the maximum drawdown is the deepest of them.

    What does the number not tell you?

    Two things worth saying. Maximum drawdown is a single worst episode, so it depends heavily on the sample: a longer history can only make it larger, never smaller. It also ignores time. The fall from 120 to 90 took one period and the recovery took one more; a fund that takes three years to climb out of a 25% hole is a different experience from one that recovers in a quarter. A risk team reports duration of the drawdown and time to recovery alongside the depth, and remembers that a 25% fall needs a 33.3% gain to get back.

    Where candidates lose it

    The fast wrong answer is 10%, measuring the lowest point, 90, against the start, 100. It ignores that investors held the fund at 120.

    The other slip is picking the most recent fall, 23.1%, because it is fresh, or measuring 130 to 90, which mixes a later peak with an earlier trough. The peak must come before the trough.

    What the interviewer asks next

    • What gain does the fund need to recover from its maximum drawdown?
    • Why is maximum drawdown hard to compare across funds with different track record lengths?
    • How would you combine drawdown with volatility in one risk-adjusted measure?
  7. 091Asset A has 10% volatility. Asset B has 30% volatility and a correlation of minus 0.2 with A. What weight in B minimises the portfolio's volatility, and what is that minimum?Correlation and diversificationHardAsset manager riskQuant risk

    Try it first

    Can adding some of the 30% volatility asset make the portfolio less risky than A alone?

    Show the worked solution

    About 14.3% in B, giving a minimum volatility of about 8.78%. The minimum variance weight in B is A's variance less the covariance, over the sum of the variances less twice the covariance: 160 over 1,120. The portfolio is less risky than A alone for any weight in B up to 28.6%, even though B is three times as volatile.

    How can a riskier asset lower total risk?

    An umbrella seller and an ice cream seller at the same beach each have bad days, but rarely the same bad days. A shopkeeper who sells mostly ice cream and a few umbrellas has steadier takings than one who sells only ice cream, even if umbrella sales swing wildly. For a small weight, the risk an asset adds depends on how it moves with what you already hold, and a negatively correlated asset offsets part of the existing risk. B's own variance enters with the square of its weight, so at small weights it barely registers, while the offset enters in proportion to the weight.

    The relationship
    wB∗=σA2−ρσAσBσA2+σB2−2ρσAσB=100+60100+900+120=14.3%w_B^* = \frac{\sigma_A^2 - \rho\sigma_A\sigma_B}{\sigma_A^2 + \sigma_B^2 - 2\rho\sigma_A\sigma_B} = \frac{100 + 60}{100 + 900 + 120} = 14.3\%
    sigma_A, sigma_Bvolatilities 10% and 30%, so variances 100 and 900 in per cent squared
    rhocorrelation, minus 0.2
    rho sigma_A sigma_Bthe covariance, minus 60
    What it says in wordsThe minimum-risk weight in B is A's variance less the covariance, divided by the variance of the difference between the two assets.
    Adding the riskier asset first lowers total risk6%8%10%12%14%16%18%asset A alone: 10%minimum 8.78% at 14.3% in Bback to 10% at 28.6% in B0%10%20%30%40%50%60%Weight in asset B (30% volatility, correlation -0.2 with A)Portfolio volatilityw(B) =(100 + 60) /(100 + 900 + 120)= 14.3%variances in % squared
    Portfolio volatility falls from A's 10% to a minimum of 8.78% at a 14.3% weight in the 30% volatility asset, stays below 10% until B's weight reaches 28.6%, and only then climbs toward B's own 30%.

    How do you check the minimum volatility?

    Plug the weight back in: 0.857 squared times 100, plus 0.143 squared times 900, plus twice 0.857 times 0.143 times minus 60. That is 73.5 plus 18.4 less 14.7, about 77.1, whose square root is 8.78%. A shortcut confirms it: the minimum variance for two assets is the product of the variances times one minus rho squared, over the same denominator, 90,000 times 0.96 over 1,120, which is 77.1. Two routes agreeing is the check the interviewer is listening for.

    Then give the limit. The answer rests on a correlation estimate, and correlations drift. If the correlation moved to zero, the best weight would fall to 10% and the minimum would rise to about 9.5%; if it turned positive in a stress, the benefit would shrink further. A risk manager treats the minimum variance weight as a range, not a point.

    Where candidates lose it

    The instinct that a 30% volatility asset must add risk is the trap. For small weights, correlation dominates and B's own volatility barely enters.

    The mechanical slip is the sign of the covariance: with a negative correlation, minus rho sigma sigma becomes plus 60 in the numerator and minus two rho sigma sigma becomes plus 120 in the denominator. Write the covariance as a number, minus 60, before substituting.

    What the interviewer asks next

    • What is the minimum-variance weight if the correlation is zero?
    • At what correlation does adding any B increase risk from the start?
    • Why might a risk manager distrust a correlation estimated from calm years?
  8. 092A counterparty has a 2% probability of default. Your exposure to it is Rs 10 crore in normal states, but in the states where it defaults the exposure is Rs 40 crore. With 60% loss given default, compare the expected loss with and without that link.Counterparty exposure and collateralHardCounterparty riskQuant risk

    Try it first

    How much larger is the expected loss once exposure and default are linked?

    Show the worked solution

    Rs 12 lakh if independent, Rs 48 lakh when linked: four times as much. Independent: 2% times 60% times Rs 10 crore. Linked: the defaults happen exactly when exposure is Rs 40 crore, so 2% times 60% times Rs 40 crore. That link is wrong-way risk. Averaging exposure first gives only about Rs 12.7 lakh and misses it.

    Why does the link between exposure and default matter so much?

    Insuring a house against fire with an insurer whose only office is in the same building is poor protection: the insurer is least able to pay in exactly the event you insured against. Expected loss is probability of default times loss given default times the exposure at the moment of default, and wrong-way risk is when that exposure is largest in the states where the counterparty fails. Here the default probability and the recovery are unchanged; only the exposure in the bad states moved, and the expected loss quadrupled.

    Wrong-way risk: the exposure is biggest in the states where default happensIndependentexposure is 10 whatever happensCounterparty98%2%survivesexposure 10, loss 0defaultsexposure 10 x 60% = 6EL = 2% x 60% x 10 = Rs 12 lakhLinked (wrong-way)exposure jumps to 40 in defaultCounterparty98%2%survivesexposure 10, loss 0defaultsexposure 40 x 60% = 24EL = 2% x 60% x 40 = Rs 48 lakhSame default probability, same LGD: Rs 12 lakh against Rs 48 lakh, 4 times the loss
    With the same 2% default probability and 60% loss given default, exposure of Rs 10 crore in every state gives an expected loss of Rs 12 lakh, but exposure that jumps to Rs 40 crore in the default states gives Rs 48 lakh, four times as much.
    The relationship
    EL=PD×LGD×E[exposure∣default]0.02×0.6×40=0.48EL = PD \times LGD \times E[\text{exposure} \mid \text{default}] \qquad 0.02 \times 0.6 \times 40 = 0.48
    PDprobability of default, 2%
    LGDloss given default, 60%
    E[exposure | default]the expected exposure in the states where default happens, Rs 40 crore
    What it says in wordsUse the exposure conditional on default, not the average exposure, because only the default states produce a loss.

    Where does this happen in practice?

    Whenever the trade and the counterparty share a driver. A bank that sells a put on a country's currency to a bank in that country gains exposure just as that bank weakens. A lender taking a company's own shares as collateral sees the collateral fall as the company fails. The general signal is a trade whose value to you rises in the same scenario that damages the counterparty. A limit system that measures average exposure, about Rs 10.6 crore here, reports the position as a Rs 10 crore line and misses where the loss sits.

    Say how desks handle it. Specific wrong-way trades are flagged and either priced with the conditional exposure, collateralised more heavily or refused. General wrong-way risk, from shared exposure to a market factor, is harder to see and needs a stress scenario in which the counterparty and the market move together.

    Where candidates lose it

    The common error is averaging first: 98% of 10 plus 2% of 40 is Rs 10.6 crore, and 2% times 60% of that is about Rs 12.7 lakh, barely above the independent case. It treats the link as a small adjustment when it is the whole story.

    The other miss is changing the default probability instead of the exposure. The link is in the exposure; the default rate is the same in both trees.

    What the interviewer asks next

    • Give an example of right-way risk, where exposure falls as the counterparty weakens.
    • How would collateral posted by the counterparty change the Rs 48 lakh?
    • How do banks reflect wrong-way risk in CVA?
  9. 094A bank has assets of Rs 1,000 crore with a duration of 4 and liabilities of Rs 900 crore with a duration of 1. What is the duration of its equity, and what happens to its equity if rates rise 1%?Liquidity and balance sheetHardTreasury and ALMBank market risk

    Try it first

    If rates rise 1%, roughly how much of the bank's Rs 100 crore of equity is lost?

    Show the worked solution

    The duration of equity is about 31, so a 1% rate rise costs about Rs 31 crore, 31% of equity. Assets fall 4% of Rs 1,000 crore, Rs 40 crore. Liabilities fall 1% of Rs 900 crore, Rs 9 crore. Equity absorbs the difference, Rs 31 crore on a base of Rs 100 crore. Leverage of ten to one turns a modest duration gap into a large equity sensitivity.

    Why is equity so much more sensitive than either side?

    A family buys a Rs 1 crore flat with Rs 10 lakh down and a Rs 90 lakh loan. If the flat's value falls 4%, they lose Rs 4 lakh, 40% of their stake, even though the flat barely moved. Equity is the thin difference between two large numbers, so any gap in how assets and liabilities respond to rates is magnified by the leverage. A bank that funds four-year assets with one-year deposits has that gap built in.

    A thin slice of equity absorbs the whole duration gapBeforeAssets1,000Equity 100Liabilities900After rates rise 1%Assets960Equity 69Liabilities891duration 4duration 1Assets: -4% x 1,000-40Liabilities: -1% x 900-9Equity-31, or -31%Duration of equity(4,000 - 900) / 100 = 31
    A 1% rate rise cuts assets of Rs 1,000 crore by Rs 40 crore and liabilities of Rs 900 crore by Rs 9 crore, so the Rs 100 crore equity slice falls Rs 31 crore to Rs 69 crore, a duration of equity of 31.
    The relationship
    DE=A⋅DA−L⋅DLE=1000×4−900×1100=31D_E = \frac{A \cdot D_A - L \cdot D_L}{E} = \frac{1000 \times 4 - 900 \times 1}{100} = 31
    A, L, Eassets 1,000, liabilities 900, equity 100, in Rs crore
    D_A, D_Lasset duration 4 and liability duration 1
    D_Eduration of equity
    What it says in wordsEquity's duration is the rupee duration of assets less that of liabilities, spread over the small equity base.

    How do you say this in the language a treasury uses?

    Two equivalent ways. The leverage-adjusted duration gap is 4 less 0.9 times 1, which is 3.1; multiply by the 1% move and by total assets, Rs 1,000 crore, and you get the same Rs 31 crore. Either way the answer is an economic value of equity loss, the number supervisors ask banks to measure for interest rate risk in the banking book. Say too that the income view is different: in the first year, deposits reprice faster than loans, so net interest income is squeezed as well.

    Name the assumptions. The calculation treats the rate rise as a parallel shift, uses first-order duration without convexity, and takes the deposit duration of 1 at face value. Deposits that customers leave in place for years behave as longer-dated funding; deposits that can leave overnight behave as shorter. That behavioural assumption can move the answer more than the arithmetic.

    Where candidates lose it

    The common error is answering 3%, the simple gap between 4 and 1, and applying it to equity. The gap has to be weighted by the balance sheet sizes and then divided by equity, which multiplies it roughly ten times.

    The second is forgetting that liabilities fall in value too. Subtract the Rs 9 crore gain on liabilities, or the answer comes out at 40% instead of 31%.

    What the interviewer asks next

    • What liability duration would make the equity immune to a parallel rate move?
    • How would you use interest rate swaps to shorten the asset duration?
    • Why might the economic value of equity fall while net interest income rises?
  10. 095A trader hiding a Rs 1 crore loss doubles the position each month to win it back, and loses six months running, starting with the Rs 1 crore. What is the hidden loss now, and what does the pattern tell a control function?Operational loss and fraudCoreOperational riskBank market risk

    Try it first

    After six losing months, how big is the hidden loss?

    Show the worked solution

    Rs 63 crore. The monthly losses double: 1, 2, 4, 8, 16 and 32 crore, and they add to 2 to the power 6, less 1, which is 63. Each month's loss is one more than everything before it combined, so the hole grows as fast as the bets. For a control function, the pattern is the signal: position size growing geometrically with no matching approved limit.

    Why does doubling down grow the hole so fast?

    A gambler at a roulette table who doubles his bet after every loss plans to recover everything with one win. After six losses in a row he has lost 63 times his first stake and must bet 64 times it to break even, if the table allows it. Doubling means each new bet equals all past losses plus one, so the cumulative loss is always just under the next bet, and a short losing run produces an enormous number. The strategy fails when the losing run is longer than the capital or the limit.

    Doubling down turns a Rs 1 crore hole into Rs 63 crore in six months102030405060700Month 1lost 1Month 2lost 2Month 3lost 4Month 4lost 8Month 5lost 16Month 6lost 3237153163Rs 63 crore hiddenloss that month, Rs crorecumulative hidden lossNext month's bet would need Rs 64 crore of risk to win it all back
    Monthly losses of Rs 1, 2, 4, 8, 16 and 32 crore take the hidden loss from Rs 1 crore to Rs 63 crore in six months, and winning it back in month seven would need Rs 64 crore of risk.
    The relationship
    ∑k=052k=26−1=63\sum_{k=0}^{5} 2^k = 2^6 - 1 = 63
    2^kthe loss in month k+1, in Rs crore
    2^6 - 1the total after six months
    What it says in wordsA run of doubling losses sums to one less than the next doubling.

    What should a control function see before month six?

    Several things, and none needs the trader's honesty. A position growing geometrically, a P&L that is flat or smooth while the gross position explodes, and large trades that are cancelled, amended or booked to unusual accounts are the classic signs of concealed losses. Gross notional limits catch the growth even when net risk looks small. Reconciling traded volumes with confirmations from counterparties catches fictitious offsetting trades. A mandatory two-week leave rule catches positions that need the trader to keep rolling them.

    The operational risk lesson is that the fraud is the smaller part of the loss. A Rs 1 crore trading loss, reported on day one, is a normal cost of business; the controls failed on the other Rs 62 crore. That is why control reviews measure time to detection, not only whether a loss was eventually found.

    Where candidates lose it

    The fast wrong answer is Rs 32 crore, the last month's loss, or Rs 64 crore, the next bet. The total is the sum, 63, and saying 2 to the power 6 less 1 shows the pattern.

    The larger miss is stopping at the arithmetic. The question asks what the pattern tells a control function: name gross position growth, smooth reported P&L and cancelled or amended trades as the signals.

    What the interviewer asks next

    • Which single control would have caught this earliest, and why?
    • Why do concealed trading losses often come with unusually smooth reported P&L?
    • How would you design a key risk indicator for this pattern?
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