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Replication vs Hedging: An Argument and an Activity

Replication is an argument. A payoff can be built exactly out of things that already have prices, so it cannot cost anything other than what building it costs. Hedging is an activity. Somebody holds positions meant to offset a risk they already carry. One is a step in a proof, the other is something a person does, and a result about the first says less about the second than its name suggests.

One observation carries the whole comparison. Replication is used to establish a price, and then it is put away. Nobody has to carry the bundle out for the price to be right, and the price does not become less right if nobody ever does. Every convenience the argument grants itself is a convenience it can afford precisely because the thing it describes never has to happen. The comparison starts there, and the convenience is why the two words are not two settings of one dial.

What is replication, defined from scratch?

ReplicationBuilding a payoff exactly out of things that already have prices, as a step in an argument rather than as something anybody performs. starts with a payoff handed over as a set of numbers, one number for each way the world is allowed to turn out. Whatever produced those numbers does not matter. The question is narrow and mechanical: is there some combination of things that already carry prices which delivers exactly those numbers, in every one of the stated outcomes? If such a combination exists, then the payoff has a price, and that price is the cost of putting the combination together today.

The step that converts a matching combination into a price is set out under the law of one price: two things that deliver identical numbers in every outcome cannot carry two different prices. So once the match is exact, the price is forced. Not estimated, not approximated, not fitted. Forced, by the fact that anything else would let somebody take one price and give the other and finish with more than they started with in every outcome at once.

A balance makes the same point in everyday terms. An object of unknown weight sits on one pan. Beside it stands a box of calibrated standard weights. Weights go onto the other pan until the beam sits level. The beam sits level rather than nearly level, so the weight of the object is then known exactly rather than roughly. Then the weights come off the pan and go back in the box. The weights were never the answer. They were how the answer was reached, so the reading survives their removal.

The matching conditions, and the unique pair that meets them
$$ h\,S_0 u - Be^{rT} \;=\; \Pi_u, \qquad h\,S_0 d - Be^{rT} \;=\; \Pi_d $$ $$ h \;=\; \frac{\Pi_u-\Pi_d}{S_0u-S_0d}, \qquad B \;=\; \frac{h\,S_0 d-\Pi_d}{e^{rT}} $$
\(h\)the number of units of the standard process held in the bundle, allowed to be any number at all
\(S_0\)the value of the standard process at time zero, which is Rs 100/- throughout this reading
\(u,\ d\)the two stated multipliers that carry the process to its up value and its down value over the horizon
\(B\)the amount borrowed at time zero, repaid with interest at the horizon
\(r\)the one borrowing rate, continuously compounded, taken as 5 per cent a year here
\(T\)the horizon, one year throughout
\(\Pi_u,\ \Pi_d\)the two numbers of the payoff, one for each stated outcome, handed over without explanation
What it says in wordsThere are two outcomes to match and two things to choose, so at most one pair of numbers can satisfy both conditions at once. When that pair exists, the bundle does not approximate the payoff or track it on average; it delivers the same number in every outcome, which is what allows the price to be forced rather than argued.

Two shapes of the same argument get separate names, and both are arguments. Static replicationBuilding the payoff once at the start and never touching the holding again until the horizon. builds the bundle once and never touches it. Dynamic replicationBuilding the payoff in a way that requires the holding to be changed as the process moves, up to changing it at every instant. builds it in a way that requires the holding to be adjusted as the process moves. The dynamic shape is taken up below, and the adjustment is part of the argument rather than part of anybody's day.

The argument in four moves, and the fourth one is the whole point. 1 A payoff arrives as numbers Rs 22.140276/- in one outcome and nothing in the other, with no account of what produced them. 2 A bundle of already priced things is found 0.549834 units of the standard process, and borrowing of Rs 42.821115/- at the one rate. 3 The bundle is checked in every stated outcome It delivers both numbers exactly rather than closely, which is what forces the price. 4 The price is read off and the bundle is put away Rs 12.162285/-, and the bundle is never mentioned again anywhere in the argument.
The replication argument ends by discarding the bundle it built, which is why the holding inside it was never an instruction to anybody.

So the last move deserves its own name. The bundle is scaffoldingSomething put up in order to establish a result and then taken down, with the result standing on its own afterwards.. Scaffolding goes up so that the price can be established, and it comes down as soon as the price is written. A reader who finishes the argument holding nothing but the number has taken away exactly what the argument was built to give them.

Try it out

What happens to the replicating bundle once the price has been established?

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What is hedging, defined from scratch?

HedgingHolding positions intended to offset a risk somebody already carries, as an activity performed through time by a person with an account. starts somewhere else entirely. Hedging starts with somebody who already carries an exposure they would rather not carry. The person takes on a further position whose value tends to move the other way, and the combination is then less sensitive to whatever they were exposed to. Notice what the definition contains and how little it is: a person, an exposure that already exists, and a purpose expressed as less rather than as none.

Three things belong to that activity and are not optional parts of it. The offset has to be corrected as things move, so there is a frequency, and somebody has to decide how often. Putting the offset on and changing it is paid for every time, so there is a cost. What is left over after the offset is never nothing, so there is a residual, and it has to be judged against a standard that somebody chose. Hedging is scored on a matter of degree. A matter of degree has no exact answer and never claimed one.

The everyday version is a tally rather than a balance. Somebody stands at the door of a hall keeping a running count of how many people are inside. Every time a person enters or leaves, the count has to be corrected. Between corrections the count is wrong by however many people moved in the meantime. Correcting more often keeps the count wrong for shorter stretches and takes more of the counter's attention; correcting less often is easier and lets the count drift further. There is no setting of that dial at which the tally is simply right and stays right, and none of that is a defect in the idea of counting. Drift between corrections is what counting a moving thing is.

The correction has a name of its own. RebalancingChanging a holding as conditions move, so that the offset keeps doing what it was put on to do. is the act of changing the offsetting holding after the thing being offset has moved. Every rebalancing is a decision, it happens at a moment somebody chose, and it costs something. A description of hedging that leaves out the frequency and the cost has left out most of the activity.

What is left over after an offset, over one interval
$$ \varepsilon \;=\; \Delta V \;-\; h\,\Delta S \;-\; c(h) $$
\(\varepsilon\)the residual, being whatever the offset failed to cancel over the interval
\(\Delta V\)the change over the interval in the value of the exposure being offset
\(\Delta S\)the change over the same interval in the standard process, written S with a time subscript
\(h\)the units of the process held against the exposure over that interval
\(c(h)\)what it cost to put that holding on and to change it, which the argument never carries and the activity always does
What it says in wordsThe activity is judged by how small the leftover is, by a standard somebody has to choose, and at what cost it was made that small. There is no arrangement of the holding that makes the leftover identically zero over a real interval, so success here is a question of degree and of taste about which standard to use.
Three things every offset has, and the argument never mentions any of them. A FREQUENCY Somebody chooses how often the holding is corrected. A COST Paid to begin, and paid again at every single correction. A RESIDUAL What is left over, judged against a chosen standard. how far off the offset has drifted correct correct correct The offset drifts between corrections and is reset at each one, and each reset is paid for.
An offset drifts between corrections and is reset at each one, so what is left over is a matter of degree rather than an identity that either holds or does not.
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Where do the two part company, and is the gap one of degree?

Both descriptions contain a holding. Both name units of the standard process. Both put a number on how much of it there is. The surface similarity is the entire trap. The difference is one of kind rather than of degree: one is a sentence inside a proof and the other is a thing done in the world, and no amount of adjusting either turns it into the other.

Take the balance and the tally back out. The standard weights on the pan and a bag of sand carried in a small boat to keep it steady are both weights. Both are chosen, both are measured, both are put somewhere. But the standard weights exist to produce a reading and then leave the pan, and the reading does not care whether they are still there. The bag of sand has to stay in the boat, has to be shifted when the boat is loaded differently, and stops working the moment nobody attends to it. Nobody would confuse the two, and the only reason the confusion arises in pricing is that both are written down as a number of units.

What is being askedReplicationHedging
Its purposeEstablish a priceReduce an exposure already carried
Its test of successDelivers every stated number exactlyWhat is left over is small enough by a chosen standard
How long it livesEnds the moment the price is writtenRuns as long as the exposure runs
What it costs to doNothing, by assumptionPaid at the start and at every change
Who carries it outNobody, and nobody needs toSomebody with an account and a decision to make
If nobody ever does itThe price still standsNothing is offset at all
Two things that both contain a holding, and are not the same kind of thing. REPLICATION Purpose: establish a price Test: delivers every number exactly Life: ends when the price is written Cost: none, by assumption Carried out by: nobody at all If skipped: the price still stands A step inside a proof. HEDGING Purpose: reduce an exposure Test: the leftover is small enough Life: runs while the exposure runs Cost: paid at every change Carried out by: a person, with an account If skipped: nothing is offset Something a person does.
Replication establishes a price and is then discarded, while hedging is something somebody carries out on a Tuesday, so a result about the first is not a result about the second.
Try it out

Is replication something somebody does?

The Greeks, Practically teaches you to read a derivatives risk report and say what each number on it is telling you about the position in front of you.

What does the argument look like on one payoff?

The whole argument fits on one set of numbers. The standard process starts at Rs 100/-. Over the one year horizon it is allowed exactly two destinations, Rs 122.140276/- or Rs 81.873075/-. A payoff is handed over as two numbers and nothing else is said about it: Rs 22.140276/- if the process finishes at the higher value, and nothing if it finishes at the lower one. Nothing is said about what produced that pair, and the argument does not need to know.

The holding follows from dividing the spread of the payoff by the spread of the process. The payoff spread is Rs 22.140276/- and the process spread is Rs 40.267201/-, being the difference between Rs 122.140276/- and Rs 81.873075/-. Dividing one by the other gives 0.549834 units. The borrowing follows from the lower outcome: 0.549834 units are worth Rs 45.016600/- there, and the payoff needs nothing there, so the borrowing has to grow to exactly Rs 45.016600/- by the horizon. At a rate of 5 per cent continuously compounded that means borrowing Rs 42.821115/- today.

The checkUp outcomeDown outcome
Value of the standard processRs 122.140276/-Rs 81.873075/-
0.549834 units are worthRs 67.156876/-Rs 45.016600/-
Less the borrowing, grown at the one rateRs 45.016600/-Rs 45.016600/-
What the bundle deliversRs 22.140276/-Rs 0.000000/-
What the payoff needsRs 22.140276/-Rs 0.000000/-
DifferenceRs 0.000000/-Rs 0.000000/-

Assembling that bundle today costs 0.549834 times Rs 100/-, or Rs 54.983400/-, less the Rs 42.821115/- that was borrowed rather than paid, leaving Rs 12.162285/-. Rs 12.162285/- is the price of the payoff. Read the other way, by weighting the up outcome at 0.577493 and discounting at 0.951229, the same price comes to Rs 12.162285/- again, agreeing to six decimal places. Two routes to the same number, and neither of them requires anybody to hold anything. The bundle has now done its work and does not appear again in the argument.

The bundle multiplied out, outcome by outcome, in rupees. THE CHECK UP OUTCOME DOWN OUTCOME Value of the process 122.140276 81.873075 0.549834 units are worth 67.156876 45.016600 Less the grown borrowing 45.016600 45.016600 The bundle delivers 22.140276 0.000000 The payoff needs 22.140276 0.000000 Difference 0.000000 0.000000 Cost today: 0.549834 times Rs 100/- is Rs 54.983400/-, less Rs 42.821115/- borrowed, leaving Rs 12.162285/-.
Holding 0.549834 units and borrowing Rs 42.821115/- delivers Rs 22.140276/- in one outcome and nothing in the other, which can be verified by multiplying out.
Try it out

At a holding of 0.4 units the up outcome falls short by Rs 2.549151/- and the down outcome overshoots by Rs 3.484245/-. What does that pattern indicate?

The pattern in that question is what makes the whole argument work, so take it apart. Hold the cost of the bundle fixed at Rs 12.162285/- and let the holding vary. Every rupee of extra holding has to be paid for with extra borrowing, and the borrowing costs the same in both outcomes while the extra units are worth much more in the up outcome than in the down one. So raising the holding lifts what the bundle delivers in the up outcome and lowers what it delivers in the down one. The two gaps move in opposite directions, and that is exactly why one and only one value can close both at once.

What the bundle delivers at a general holding, with the cost held fixed
$$ D_u(h) \;=\; \Pi_u + (h-h^{*})\bigl(S_0u - S_0e^{rT}\bigr), \qquad D_d(h) \;=\; \Pi_d + (h-h^{*})\bigl(S_0d - S_0e^{rT}\bigr) $$
\(D_u,\ D_d\)what the bundle delivers in the up outcome and in the down outcome
\(h\)whatever holding is chosen, with the borrowing adjusted so the bundle still costs Rs 12.162285/-
\(h^{*}\)the one holding that matches both outcomes, being 0.549834 here
\(S_0u-S_0e^{rT}\)Rs 17.013166/-, the gain per extra unit in the up outcome after paying for the extra borrowing
\(S_0d-S_0e^{rT}\)minus Rs 23.254034/-, the loss per extra unit in the down outcome after the same
What it says in wordsMoving the holding away from 0.549834 changes what the bundle delivers in the two outcomes by amounts of opposite sign, so a change that helps one outcome always hurts the other by a fixed amount per unit. Both gaps can only be zero at the same holding, and that is the holding at which the payoff is matched.
Two gaps, opposite slopes, one crossing point. 0.549834, the only holding that closes both 0 +11 -11 up outcome gap down outcome gap 0.0 0.4 0.7 1.0 units of the standard process held At 0.4 the up outcome falls short by Rs 2.549151/- and the down outcome overshoots by Rs 3.484245/-. At 0.7 the up outcome overshoots by Rs 2.554799/- and the down outcome falls short by Rs 3.491965/-.
The two gaps run in opposite directions as the holding changes, so only one holding puts both of them at zero and only that holding fixes a price.
Try it out

How many holdings of the standard process deliver the payoff exactly in both outcomes?

Play with it

Move the holding and watch the match break

The control sets the units of the standard process held in the bundle, from 0 to 1. The borrowing moves with it so that the bundle always costs the same Rs 12.162285/-. Each panel compares what the bundle delivers against what the payoff needs in that outcome. At 0.549834 both gaps are zero. Moving in either direction opens a gap upward in one panel and downward in the other, and no setting closes both again.

0 units0.549834 units1 unit
UP OUTCOME, process at Rs 122.140276/- DOWN OUTCOME, process at Rs 81.873075/- 22.140276 22.140276 0.000000 0.000000 bundle delivers payoff needs bundle delivers payoff needs gap 0.000000 gap 0.000000 Bars are in rupees and are measured from the zero line. One step, two outcomes, and every figure is an invented illustration.
Units held
0.549834
Borrowed today
42.821115
Up outcome gap
0.000000
Down outcome gap
0.000000

At a holding of 0.549834 units the bundle delivers Rs 22.140276/- in the up outcome and Rs 0.000000/- in the down one, so both gaps are zero and the payoff is matched exactly.

Educational illustration. The bundle always costs Rs 12.162285/-. Only one holding, 0.549834, closes both gaps: at 0.4 the up outcome falls short by Rs 2.549151/- and the down overshoots by Rs 3.484245/-, and at 0.7 the up overshoots by Rs 2.554799/- and the down falls short by Rs 3.491965/-. One step, two outcomes, free trading, fractional units and one borrowing rate are assumptions of the argument rather than facts about anything. Every reading is computed from the formula above and never sampled. Figures in rupees.
Try it out

How many of the argument's five assumptions would somebody hedging in practice be expected to have?

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What is the argument allowed to assume?

Five things carried that worked instance, and each one is something the activity does not get. The argument assumes that the process moves to exactly one of two stated values. The argument assumes the bundle can be held in fractional unitsHolding any amount of something at all, including 0.549834 of a unit, with no smallest tradeable size., including 0.549834 of a unit. A single rate is assumed for both borrowing and lending. Trading is assumed frictionlessCosting nothing at all to trade, which the argument assumes and which the activity never gets., so nothing at all is paid to put the bundle on. And it assumes the holding never has to change once it is set.

What the argument assumesWhat the argument getsWhat somebody doing it has instead
The process moves to exactly one of two stated valuesGrantedAn unbounded set of outcomes, none of them stated in advance
The bundle can be held in fractional unitsGrantedA smallest size, below which nothing can be held
Borrowing and lending happen at one rateGrantedTwo different rates, and neither is the same for everybody
Nothing at all is paid to tradeGrantedA cost every time, paid whether or not anything works
The holding never has to changeGrantedA holding that has to be corrected, at a frequency somebody chooses

Five for five, and none of the five is a small idealisation of something a person nearly has. Each one is the difference between a sentence that can be written down and a thing that can be done. None of that is a criticism of the argument. An argument that had to pay to trade and could only hold whole units would not establish anything cleanly, and the price it produced would be a range rather than a number. The assumptions are load bearing, and the load they bear is the exactness of the conclusion.

Five assumptions. The argument gets all of them, the activity gets none. WHAT IS ASSUMED THE ARGUMENT THE ACTIVITY The process moves to one of two stated values GRANTED NOT GIVEN The bundle can be held in fractional units GRANTED NOT GIVEN Borrowing and lending happen at one rate GRANTED NOT GIVEN Nothing at all is paid to trade GRANTED NOT GIVEN The holding never has to change GRANTED NOT GIVEN And the last one gets harder in the continuous version rather than easier.
Two stated outcomes, fractional holdings, one borrowing rate, free trading and a holding that never changes are what the argument assumes, and the activity has none of the five.
Try it out

Does the continuous version of the argument make the assumption about rebalancing easier or harder?

What does a replication result promise, and what does it not?

A replication result promises a price, and promises that the price is the only one consistent with the assumptions it stated. The promise is a strong one and worth having. The result does not promise that the holding inside it can be achieved. Nothing in the result promises that a nearby holding would deliver anything near the payoff. Nothing in the result promises that the holding is stable if the argument is changed. And the result never considered whether holding it would be a sensible thing for anybody to do, so it very definitely does not promise that either.

The last point is easy to miss, so take it head on. Refine the same construction and the price improves while the demand on the holder gets steadily worse. At one step there is one moment at which a holding has to be chosen, and the price comes out at Rs 12.16/-. At two steps there are three such moments and the price falls to Rs 9.54/-. At four steps there are ten moments and Rs 9.97/-. At twelve steps there are seventy eight moments and Rs 10.29/-, against the value the construction is converging to, Rs 10.45/-. The lattice construction here is the one associated with Cox, Ross and Rubinstein, 1979, and the limiting value is the one associated with Black, Scholes and Merton, 1973. The approach is not a straight line: it overshoots high, comes back too far, and then closes in from below.

The price gets better and the demand on the holder gets worse. the limit, Rs 10.45/- one step, 1 decision Rs 12.16/- two steps, 3 decisions Rs 9.54/- four steps, 10 decisions Rs 9.97/- twelve steps, 78 decisions Rs 10.29/- continuous, unbounded Rs 10.45/- 9.50 10.00 10.50 11.00 11.50 12.00 It overshoots high, comes back too far, and then closes in from below. Invented illustration, rupees.
The continuous argument needs the holding to change at every instant, which is further from anything doable than the one step version, and the price it produces is exactly as valid.
The continuous statement, and what it asks for
$$ V_T \;=\; V_0 \;+\; \int_0^T h_t\,dS_t \;+\; \int_0^T r\bigl(V_t - h_tS_t\bigr)\,dt $$
\(V_t\)the value of the bundle at time t, which has to equal the payoff at the horizon in every outcome
\(h_t\)the units of the standard process held at time t, a whole function of time rather than one number
\(S_t\)the standard process, written S with a time subscript, starting at Rs 100/-
\(r\)the one borrowing rate, applied to whatever part of the bundle is borrowed or lent at each moment
\(T\)the horizon, one year
What it says in wordsThe continuous version does not settle for one holding. It asks for a holding at every instant of the year, changing as the process moves, with no money added or taken out along the way. That is a heavier demand than the single choice the one step version makes, and the price it produces is no less correct for asking it.

There is one more reason not to read the holding as an instruction, and it is the sharpest one available. The same payoff rule, priced by the one step argument, carries a holding of 0.549834 units. Priced by the continuous argument, it carries a holding of 0.636831 units at time zero. Same process, same rule for the payoff, two correct arguments, two different numbers. A quantity that changes when the argument changes is a feature of the argument rather than a property of the world, and nobody should be told to hold it.

The error that gets made, and what it costs

Somebody reads the working, arrives at 0.549834 units, and carries that number away as a thing to hold. A holding of the standard process is exactly what a position looks like written down, and the six decimal places make it look settled rather than provisional, so the step is an easy one to take. But the number was scaffolding for a price, and lifting it out is converting a step in a proof into a position.

Lifting the number carries the number and nothing else. Every one of the five conditions that made the step valid stays behind. There are more than two outcomes. Trading is not free. Units come in sizes. Borrowing and lending are not the same rate. And the holding cannot be left alone. The moment there are more than two outcomes it has to be corrected as things move, and correcting it is a separate activity kept separate throughout.

The cost is a position taken on the authority of an argument that was never about positions. The argument cannot be blamed for it, having never claimed otherwise. The argument concluded with Rs 12.162285/- and then stopped.

What travelled with the number, and what did not. LIFTED OUT OF THE WORKING 0.549834 units of the standard process read as an instruction to hold, and it never was one. WHAT DID NOT COME WITH IT exactly two stated outcomes fractional units of any size one borrowing rate for everything nothing at all paid to trade a holding that never has to change A position taken on the authority of an argument that was never about positions.
The 0.549834 units are scaffolding for a price, and holding them as a position means acting on an argument that assumed two outcomes, free trading and no rebalancing.
Try it out

Somebody takes the 0.549834 units out of the working and holds them as a position. What have they imported, and what have they not?

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Why does the distinction decide how a result should be read?

Because the distinction changes which claims the result has to defend. Ask one question of any passage that contains a holding: what did it conclude with? If it concluded with a price, then whatever holding appears inside it is a means, and the assumptions around it were chosen for the convenience of reaching that price. Nothing in it is addressed to anybody, and nothing in it is a suggestion. If it concluded with an instruction, then it is a claim about action, and it needs assumptions that survive contact with action. The assumptions that survive contact with action are different ones, and somebody else usually has to state them.

There is a second test and it is quicker. Would the result still be true if nobody ever carried it out? For a replication result the answer is yes, unambiguously, and that is precisely why the bundle can be discarded at the end. A hedge that nobody puts on offsets nothing at all, so for any claim about hedging the answer is no. A result that survives nobody doing it was never an instruction, whatever it looks like written down.

One question settles how any passage containing a holding should be read. What did the result conclude with? A PRICE The holding inside it is a means. It tells nobody to hold anything. Its assumptions suited the proof. AN INSTRUCTION Then it is a claim about action. It needs assumptions that survive action, and those are different ones. Everything in this guide concluded with Rs 12.162285/-, so it sits on the left.
Ask whether the result concluded with a price or with an instruction, because a result concluding with a price is not telling anybody to hold anything.
Try it out

A result concludes with a price. Is it telling anybody to hold anything?

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How does somebody reading a result actually use this?

The reader this matters most to is not the person writing the argument. The reader who matters is the person on the receiving end of working somebody else produced, whether a preprint from a repository, a model note handed across a desk, or a stretch of derivation in a set of course materials. Such a reader has to decide which claims the passage must defend before deciding whether to believe it, and the two questions above do that job in about fifteen seconds.

  1. Find the last line and see what kind of thing it isA number with a currency on it is a price. A sentence with a holding as its object is an instruction. Almost every replication passage ends in the first kind, however much holding language appears in the middle of it.
    Here the last line of the argument is Rs 12.162285/-.
  2. Ask whether the result survives nobody doing itIf the conclusion would still be true in a world where nobody carried out a single trade, the passage was establishing something rather than proposing something. If it would not, it was proposing something and needs the assumptions that go with proposing.
    The price stands whether or not the bundle is ever assembled.
  3. List the conditions and ask which of them holdTwo outcomes, fractional units, one rate, free trading, a fixed holding. The situation at hand scores against each. Where the score is zero out of five, nothing in the passage was addressed to that situation, and that is a statement about the passage rather than about the reader.
    Nobody scores above zero on the second, fourth or fifth.
  4. Check whether the number moves when the argument doesPrice the same payoff rule a second way and see whether the holding changes. If it does, the holding belonged to the method rather than to the payoff, and it was never a candidate for anybody to carry.
    0.549834 at one step against 0.636831 in the continuous version.

The same discipline runs the other way, and it is worth saying so. A genuine claim about hedging, one that really is about what somebody should hold and how often they should correct it, is not evidenced by a replication result. The frequency, the cost of the corrections, and the standard the leftover is being judged against are the three things to ask for. The frequency, the cost and the standard are the whole of the activity, and a replication result answers none of the three because it was never asked.

Carrying out a hedge, and choosing how often to correct it, is covered separately. Whether a hedging schedule exists at all is set out under complete market vs incomplete market. What any contract pays is covered separately. No jurisdiction sets the definition of a price, so no rule, threshold or period anywhere is engaged, and every figure follows by computation from the four stated parameters of the standard process.

References

SourceDocumentWhere
arXiv Quantitative FinancePreprint repository for work on replication arguments and no-arbitrage pricingarxiv.org
Social Science Research NetworkWorking paper repository for the same materialssrn.com
Hull, Shreve and WilmottStandard textbook treatments of replication, hedging and no-arbitrage pricingPublished books
Cox, Ross and Rubinstein, 1979Option Pricing: A Simplified Approach, the lattice construction the refinements above useJournal of Financial Economics
Black, Scholes and Merton, 1973The two papers behind the limiting price the lattice converges toJournal of Political Economy; Bell Journal of Economics and Management Science

The standard process and its four parameters are invented.
Educational material. Not advice on any investment, tax, budget or market position.

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