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Stochastic Calculus & Derivative Pricing Theory
1Probability Foundations
The Probability SpaceRandom VectorsSigma-AlgebraExpectationSample Space and EventsDensity and Distribution FunctionsRisk-Neutral ProbabilityState Price Density vs…
2Stochastic Processes and Jumps
Properties of a Stochastic ProcessMartingaleBrownian Motion and Its PropertiesBrownian Motion vs Geometric…Stopping TimeThe Markov PropertyState VariablesTransition ProbabilityQuadratic VariationQuadratic Variation vs Ordinary…Submartingale and SupermartingaleMartingale RepresentationMarkov Process vs MartingaleOptional StoppingFiltrationJump ProcessesThe Poisson ProcessLevy ProcessesJump Diffusion
3Ito Calculus
The Ito IntegralThe Ito Integral vs the Riemann IntegralInfinitesimals in Stochastic CalculusQuadratic CovariationIto's LemmaHow to Apply Ito's…The Infinitesimal GeneratorIto Calculus vs Ordinary Calculus
4Stochastic Differential Equations
Stochastic Differential EquationsStochastic Differential Equation vs…Drift and DiffusionStrong and Weak Solutions ComparedDiscretisationGeometric Brownian Motion
5Pricing Theory and No-Arbitrage
No-ArbitrageGirsanov, Radon-Nikodym and Change…Physical and Risk-Neutral Measures…The Fundamental Theorems of…The Law of One PriceThe Pricing KernelDiscount Factors and Zero-Coupon PricesReplication vs HedgingComplete Market vs Incomplete MarketClearing Margin Architecture
6Option Pricing Theory
European and American OptionsMonte Carlo European OptionThe Black-Scholes PDEBlack Scholes and the GreeksThe Payoff FunctionThe Binomial ModelBinomial Option PricingDelta Hedging in TheoryBoundary, Initial and Terminal ConditionsThe Exercise BoundaryHow to Check Put-Call…
7Volatility Models
Constant, Local and Stochastic…Vasicek Model vs CIR ModelThe Heston ModelThe SABR ModelThe Volatility ProcessImplied VolatilityVolatility Smile vs Skew vs Surface
8Interest Rate Models
Interest-Rate DerivativesMean ReversionThe Zero-Coupon BondThe Ornstein-Uhlenbeck ProcessThe Discount CurveZero RatesShort-Rate Model vs Market Model
9Numerical Pricing
Closed Form and Numerical…Monte Carlo PricingEuler and Milstein Schemes ComparedTree MethodsFinite Difference MethodsNumerical Error and StabilityVariance Reduction
10Calibration and Model Risk
Model OverrideMarket Price and Model PriceCalibrationHow to Document a Pricing ModelThe Educational Illustration LabelMarket ConventionsModel Uncertainty and LimitationsBacktesting a Pricing ModelIdentifiabilityCalibrated ParametersThe Calibration Loss Function

Complete Market vs Incomplete Market: One Price or a Range

A complete market is one in which every payoff can be assembled out of things already carrying a price, so each payoff has exactly one price. An incomplete market is one in which some payoffs cannot be assembled, and those carry a range instead. Completeness is a counting condition, its absence costs a computable interval, and the incomplete case is the ordinary one.

The whole comparison turns on one question that can be settled before any pricing is attempted: are there enough independent things to trade to reach every way the horizon can turn out? Counting is the whole of it. The count returns a yes or a no, the check takes a minute, and everything else in this guide follows from which answer comes back.

Here is the everyday version, and it uses nothing but a balance and a box of weights. Suppose the box holds a one kilogram weight and a two kilogram weight. One kilogram can be made. So can two, and so can three. One and a half cannot. There is no arrangement of those two weights that lands on it, and the honest answer stops being a number: the amount asked for sits somewhere between one kilogram and two, and the box cannot narrow it further. Nothing about the request was unreasonable and nothing about the balance was faulty; the box simply did not contain enough distinct weights to reach the amount asked for.

A market is that box. The weights are the things whose prices are already known. The amounts that might be asked for are payoffs. When the box can make the amount exactly, the cost of making it is the price, and there is nothing to argue about. When it cannot, what comes back is a bracket, and no amount of care in the arithmetic turns a bracket into a number.

Everything below is that picture written carefully enough to check, on the standard process: a single traded quantity starting at Rs 100/-, carrying a volatility of 20 per cent a year and a drift of 8 per cent a year, watched for one year, with cash growing at 5 per cent a year continuously compounded. The four parameters are assumed rather than measured, and every figure computed from them follows by arithmetic rather than from any observation.

What is a complete market, defined from scratch?

A complete marketOne where every payoff can be built out of the things that are already priced, so nothing that can be asked for falls outside what the available holdings can produce. is a setting in which, for every payoff that could be handed over, there exists a holding of the available things that delivers exactly that payoff in every outcome. Not approximately. Not on average. In every outcome, to the last paisa.

Because the rest depends on it, a payoff needs saying precisely here. A payoff is a list of amounts, one entry for each way the horizon can turn out. The list is not a contract, and where the list came from does not matter here. Somebody hands over the list and asks what it costs to arrange for exactly those amounts to arrive. Completeness is the property that this question always has an answer, whatever list is handed over.

The available things here are two. The first is the standard process itself, starting at Rs 100/- and finishing at whatever value the outcome delivers. The second is cash, starting at one rupee and finishing at e to the rate times the horizon, or 1.051271 rupees over the year. A holding is a pair: how many units of the standard process, and how many rupees of cash. Both may be negative. A negative entry means the holding was sold or the cash was borrowed.

What building a payoff asks for, written out
$$ \Delta\, S_T(\omega_i) \;+\; b\,e^{rT} \;=\; V_T(\omega_i) \qquad \text{for every } i = 1,\dots,n $$
\(\omega_i\)the \(i\)-th outcome, one of the \(n\) ways the horizon can turn out
\(S_T(\omega_i)\)the value of the standard process at the horizon in that outcome
\(V_T(\omega_i)\)the amount the payoff delivers in that outcome, handed over as a number
\(\Delta\)units of the standard process held, positive or negative
\(b\)rupees of cash held at time zero, negative where it is borrowed
\(r,\ T\)the rate, 0.05 a year continuously compounded, and the horizon, one year
What it says in wordsA payoff can be built exactly when one single pair of numbers, a holding of the standard process and an amount of cash, reproduces the payoff at every outcome at once, which is a system of as many equations as there are outcomes in only two unknowns.

The last clause of that statement is the whole of this guide. As many equations as there are outcomes. Two unknowns. A system like that has a solution for every right hand side only when the equations are not more numerous than the unknowns can handle, and that is arithmetic rather than finance.

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What is an incomplete market, defined from scratch?

An incomplete marketOne where at least one payoff cannot be built out of the things already priced, so that payoff carries an interval of permitted prices rather than a single one. is a setting in which at least one payoff that could be handed over has no holding that delivers it in every outcome. The system above has more equations than the two unknowns can satisfy, so for some right hand sides there is simply no pair that works.

Notice what has and has not happened. The assumption underneath everything is untouched: no position costing nothing may deliver something for certain while never delivering a loss. The no-arbitrage assumption still rules out a great deal. The assumption has merely stopped picking one figure. Instead of a price it returns a price rangeThe interval of figures the no-arbitrage assumption permits when a payoff cannot be built, with everything outside it ruled out and nothing inside it preferred., and the assumption gives no reason to prefer any figure inside that interval over any other.

The temptation is to read incompleteness as a defect, either of the market or of the mathematics. Incompleteness is neither. Go back to the box of weights. Being unable to make one and a half kilograms is not a fault in the balance and not a fault in arithmetic; it is a true report about how many distinct weights are in the box. An incomplete market is not a market that has gone wrong, it is a description that has reported honestly how much it can and cannot pin down.

The honesty is uncomfortable to live with. A range is harder to put in a report than a number, and the pressure to produce a number does not go away because the mathematics stopped supplying one. The pressure, and what people do under it, is taken up below, where a single number is needed and the mathematics supplies a range.

How is completeness checked by counting, before pricing anything?

Here the comparison becomes checkable rather than atmospheric. Completeness is a counting conditionA check that compares the number of independent things available to trade with the number of outcomes that can occur, settled before any pricing is attempted.: line up the horizon values of everything available to trade as the columns of a table, put one row for each outcome, and ask how many independent columns there are against how many rows.

The counting condition, as a rank
$$ A \;=\; \begin{pmatrix} S_T(\omega_1) & e^{rT} \\ \vdots & \vdots \\ S_T(\omega_n) & e^{rT} \end{pmatrix}, \qquad \text{complete} \iff \operatorname{rank} A = n \;\Longrightarrow\; n \le 2 $$
\(A\)the payoff table, one row per outcome and one column per available thing
\(n\)the number of outcomes admitted by the description
\(\operatorname{rank} A\)the number of independent columns, which can never exceed the number of columns
What it says in wordsThe setting is complete exactly when the table of horizon values has as many independent columns as there are outcomes, and since the table here has only two columns, that can happen only when the outcomes number two or fewer.

Two columns. Rank at most two. So with the standard process and cash as the only things available, completeness survives up to two outcomes and fails from three onward, and no amount of skill in the pricing changes that. The check is finished before any pricing begins. A count of the independent things available to hold, set against a count of the outcomes the description admits, has already decided whether a single price is available at all.

The word doing the work is independent. Adding a third thing to hold that is itself a fixed combination of the first two adds a column but no rank, and buys nothing. Adding it is the same trap as putting a second one kilogram weight in the box: the box now has three weights and still cannot make one and a half. SpanningReaching every possible outcome pattern using combinations of what is available, which is what the independent columns of the payoff table can and cannot do. is about independent directions, never about how many items are on the shelf.

Count the rows. Count the independent columns. Everything else follows from that one comparison. TWO OUTCOMES, TWO INSTRUMENTS OUTCOMES Rs 122.140276/- Rs 81.873075/- INSTRUMENTS the standard process cash at the rate 2 rows, 2 columns THE COUNTING BALANCES every payoff builds, one price each THREE OUTCOMES, TWO INSTRUMENTS OUTCOMES Rs 122.140276/- Rs 100/- Rs 81.873075/- INSTRUMENTS the standard process cash at the rate nothing here 3 rows, 2 columns SHORT BY ONE ROW some payoffs do not build, and those carry a range
Two outcomes against two instruments leaves the counting balanced and every payoff buildable at one price each, while three outcomes against the same two instruments leaves the table one row short, so some payoffs cannot be built and carry an interval instead.
Try it out

A description admits four outcomes at the horizon, and there are still exactly two independent things available to hold. Complete or incomplete?

The check runs before any pricing. It is two counts and one comparison. COUNT BOTH, THEN COMPARE independent instruments against outcomes admitted INSTRUMENTS REACH EVERY OUTCOME independent columns equal the rows FEWER COLUMNS THAN ROWS at least one direction is out of reach ONE PRICE the cost of building it, and nothing else Rs 12.162285/- AN INTERVAL ends ruled in, nothing inside preferred Rs 4.877058/- to Rs 12.162285/-
Counting the independent instruments against the outcomes admitted answers whether a single price exists at all, and on the standard process that comparison leads either to Rs 12.162285/- or to the interval running from Rs 4.877058/- to Rs 12.162285/-.

What does completeness actually buy?

Uniqueness. Uniqueness is the entire purchase, and it is worth being blunt about how narrow it is. Completeness does not make a price accurate. Completeness does not make a description true. Completeness does not reduce anybody's exposure to anything. Completeness buys one thing, that the argument returns a point rather than an interval, and it buys nothing else at all.

The mechanism behind that purchase is the same counting again in a different costume, and it is worth seeing directly. Instead of asking which payoffs can be built, ask which sets of weights on the outcomes are admissible: strictly positive, adding to one, and repricing the standard process itself. The admissible weight sets form a set of their own, and the size of that set decides whether the price is a point.

The admissible weights, and how many free directions they have
$$ \mathcal{M} \;=\; \Bigl\{\, \mathbb{Q}=(q_1,\dots,q_n) \;:\; q_i \gt 0,\ \ \textstyle\sum_i q_i = 1,\ \ \textstyle\sum_i q_i\, S_T(\omega_i) = S_0\, e^{rT} \,\Bigr\}, \qquad \dim \mathcal{M} \;=\; n-2 $$
\(\mathbb{Q}\)a risk-neutral measure, here one weight per outcome
\(\mathcal{M}\)the set of every measure the assumption admits
\(q_i\)the weight the measure places on outcome \(i\), strictly above zero
\(S_0\)the starting value of the standard process, Rs 100/-
\(n-2\)the free directions left after the two conditions have been imposed
What it says in wordsThe admissible measures are the strictly positive weight sets that add to one and reprice the standard process, and because those are two conditions on however many outcomes there are, the set of them has exactly two fewer free directions than there are outcomes.

Now read the dimension. At two outcomes it is nought, so the set is a single point and the measure is the only one there is. At three it is one, so the set is a segment and there are infinitely many admissible measures. At four it is two, at five it is three, and the set only grows. The counting of instruments against outcomes and the counting of free directions in the measure set are the same statement written twice.

The counting is why the phrase that completeness makes a model better is worth resisting. Look at what actually moved. The description of how the standard process can behave did not become more faithful when the third outcome was struck out; it became narrower. A complete description is a description that has been made small enough that two instruments can reach all of it, and smallness is not the same as truth.

Try it out

A setting is described as complete. What exactly has that established about the prices in it?

What does its absence cost, as a number rather than as a worry?

Here is the worked instance, small enough to check by hand. One step, one year. The standard process finishes at Rs 122.140276/- in the up outcome and Rs 81.873075/- in the down outcome, those being Rs 100/- multiplied by e to plus and minus the volatility times the square root of the horizon. Cash grows by 1.051271. The payoff handed over is Rs 22.140276/- in the up outcome and nothing in the down one, and its origin does not matter here.

With two outcomes the two equations in two unknowns solve once. The holding is Rs 22.140276/- divided by Rs 40.267201/-, or 0.549834 units of the standard process, and the cash is minus Rs 42.821115/-, meaning that much is borrowed. Building the payoff therefore costs 0.549834 times Rs 100/- less Rs 42.821115/-, or Rs 12.162285/-. Rs 12.162285/- is the price, it is the only price, and the counting is why.

Now admit a third outcome at Rs 100/-, and change nothing else. The two instruments are the same two. The new outcome sits at the level where the handed-over list already returns nothing, so the payoff there is nothing. Three equations, two unknowns, and the system has no solution: the payoff cannot be built. No-arbitrage now returns an interval, and both of its ends can be derived rather than asserted.

The top of the interval, as a bundle rather than as a weight
$$ \overline{V}_0 \;=\; \min_{\Delta,\,b}\;\Bigl\{\, \Delta S_0 + b \;:\; \Delta\, S_T(\omega_i) + b\,e^{rT} \;\ge\; V_T(\omega_i) \ \text{ for every } i \,\Bigr\} $$
\(\overline{V}_0\)the highest price the assumption permits, at time zero
\(\Delta,\ b\)the holding of the standard process and the cash, as before
\(\ge\)never worth less than the payoff, in every outcome without exception
What it says in wordsThe top of the permitted interval is the cost of the cheapest holding of the standard process and cash whose value at the horizon is never below the payoff in any outcome, which is why it is called a superreplicating bundle rather than a replicating one.

On the three outcome case that cheapest bundle is the same 0.549834 units and the same borrowing of Rs 42.821115/-, costing Rs 12.162285/-. The bundle matches the payoff exactly at the two extreme outcomes and overshoots at the middle one, where it is worth Rs 9.966799/- against a payoff of nothing. SuperreplicationBuilding a holding that is never worth less than the payoff in any outcome, whose cost gives the top of the permitted interval. is exactly that overshoot, and the overshoot is what is paid for at the top of the interval.

The bottom of the interval, and its closed form
$$ \underline{V}_0 \;=\; \max_{\Delta,\,b}\;\Bigl\{\, \Delta S_0 + b \;:\; \Delta\, S_T(\omega_i) + b\,e^{rT} \;\le\; V_T(\omega_i) \ \text{ for every } i \,\Bigr\} \;=\; S_0\bigl(1 - e^{-rT}\bigr) $$
\(\underline{V}_0\)the lowest price the assumption permits, at time zero
\(\le\)never worth more than the payoff, in every outcome without exception
\(e^{-rT}\)the discount factor over the horizon, 0.951229
What it says in wordsThe bottom of the permitted interval is the cost of the dearest holding that is never worth more than the payoff, which on this payoff is one whole unit of the standard process financed by borrowing the discounted Rs 100/-, so the bottom comes out at the starting value less its own discounted amount.

Working that closed form through lands on Rs 100/- less Rs 95.122942/-, or Rs 4.877058/-. The holding that achieves it is one whole unit of the standard process, with Rs 95.122942/- borrowed, and it checks outcome by outcome: at Rs 122.140276/- it is worth Rs 22.140276/- against a payoff of the same, at Rs 100/- it is worth nothing against a payoff of nothing, and at Rs 81.873075/- it is worth minus Rs 18.126925/- against a payoff of nothing, a value below the payoff and therefore permitted.

OutcomeStandard process at the horizonPayoff handed overWeight at the low endWeight at the high end
UpRs 122.140276/-Rs 22.140276/-0.2315740.577493
MiddleRs 100/-nothing0.7684260
DownRs 81.873075/-nothing00.422507
Discounted weighted averageboth reprice Rs 100/-Rs 4.877058/-Rs 12.162285/-

The interval is Rs 7.285227/- wide and its top is 2.493775 times its bottom. The width is the cost of incompleteness on this payoff, and it is not a rounding at the edge of an answer, it is most of the answer. One precision point belongs here and it is easy to check on the table: both of the weight sets at the ends place nothing on one outcome, and admissible weights have to be strictly positive. So the ends themselves are ruled out along with everything outside them, and what the assumption permits is every figure strictly between. Selling at exactly Rs 12.162285/- and holding the superreplicating bundle would cost nothing to set up, lose in no outcome, and gain Rs 9.966799/- at the middle one. Such an arrangement is precisely what the assumption exists to forbid.

Two straight lines trap a bent payoff. The trapping is the interval. -20 -10 0 10 20 81.87 90 100 110 122.14 value of the standard process at the horizon, in rupees Rs 9.966799/- overshoot at the middle outcome never worth less, cost Rs 12.162285/- never worth more, cost Rs 4.877058/-
The cheapest bundle never worth less than the payoff costs Rs 12.162285/- and overshoots by Rs 9.966799/- at the middle outcome, while the dearest bundle never worth more costs Rs 4.877058/-, and those two costs are the ends of the permitted interval.
Try it out

The permitted interval on this payoff runs from Rs 4.877058/- to Rs 12.162285/-. How wide is that, relative to the numbers involved?

One outcome added. The top does not move. The bottom opens away from it. TWO OUTCOMES Rs 12.162285/- THREE OUTCOMES the bottom opens away by Rs 7.285227/- Rs 4.877058/- Rs 12.162285/- 0 4 8 12 price at time zero, in rupees
Adding one outcome turns the single price of Rs 12.162285/- into an interval running from Rs 4.877058/- to Rs 12.162285/-, so the top holds exactly where it was and the whole of the Rs 7.285227/- opens downward.
Try it out

Outcomes are about to be added beyond the third, still with no new instrument. What happens to the top of the interval?

Play with it

Add an outcome and watch the price open

One control: how many outcomes the description admits, from two up to five, with the extra ones placed between the two extremes. Two instruments throughout, the standard process and cash, and the payoff never changes. Every figure below is computed from the bundle conditions rather than sampled, so the reading at any setting is the same on every reload.

More rows on the left. The same two columns. Watch the right hand side. OUTCOMES ADMITTED Rs 81.87/- Rs 90.48/- Rs 100/- Rs 110.52/- Rs 122.14/- value of the standard process at the horizon PRICE THE ARGUMENT PERMITS the top, fixed Rs 12.162285/- Rs 4.877058/- 0 4 8 12 price at time zero, in rupees Directions no combination of the two instruments can reach: none 2 outcomes, 2 instruments: the counting balances and the price is a single number.
2 outcomes2 outcomes5 outcomes
Free directions in the weight set
0
Lowest price permitted
Rs 12.162285/-
Highest price permitted
Rs 12.162285/-
Width of the interval
Rs 0.000000/-
Educational illustration. One step over one year. Two instruments throughout, the standard process and cash at 5 per cent a year continuously compounded. The payoff is Rs 22.140276/- at the up outcome and nothing elsewhere. At two outcomes the price is the single figure Rs 12.162285/-. From three outcomes onward the permitted interval runs from Rs 4.877058/- to Rs 12.162285/-, and every reading here is computed from the bundle conditions rather than drawn at random, so the same setting always gives the same figures.
Try it out

A third outcome has just opened the price into an interval. What did that establish about the two outcome case that came before it?

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Why is the incomplete case ordinary and the complete case special?

Because every honest addition to a description adds outcomes, and almost none of them adds an instrument. One sentence carries the whole argument, and it is worth walking through the additions one at a time to feel how one sided the traffic is.

Admitting that the process can finish somewhere between the two extremes rather than only at them is the mildest thing anybody could ask for, and it moves the count from two outcomes to three. Admitting that it moves at more than one date multiplies the outcomes with the dates. Admitting jumps, in the sense of Merton, 1976, adds outcomes that differ by how many arrivals occurred and how large each was, none of which is reachable by holding the process and cash. Admitting that the volatility itself moves, in the sense of Heston, 1993, adds something worse than an outcome: a second source of movement with nothing traded against it, and that is unhedgeable riskA source of movement that no combination of the traded things can offset, so exposure to it survives every holding available. in the plain sense of the phrase.

Now count what went the other way. To restore the balance, each of those additions would need a matching independent thing to hold, with a price already known, whose horizon value moves with exactly the new source and not with the old ones. Sometimes such a thing exists. Usually it does not, and where it does, its price came from somewhere and that somewhere has to be accounted for too.

Completeness is therefore not a property that descriptions tend to have, it is a property that descriptions are built to have, by keeping the outcome count down to what the available instruments can reach. The two outcome case survives in teaching, this guide included, for one reason: it is the only setting where the argument produces a single number cleanly enough to check by hand. Being checkable by hand is a good reason to keep the case and a bad reason to believe it.

Here is the counting example again, from the balance and the box. Every extra amount somebody might ask to have weighed out is another row. Weights are what would have to be added to keep up, and nothing about being asked for a new amount puts a new weight in the box. The requests grow on their own; the box only grows when somebody buys a weight.

Each step toward realism lengthens the left bar. The right bar never moves. WHAT THE DESCRIPTION ADMITS OUTCOMES INSTRUMENTS two values, one step the constructed teaching case 2 2 a value between the two extremes the mildest addition anyone could ask for 3 2 jumps, after Merton, 1976 how many arrived, and how large each was many 2 volatility that moves, after Heston, 1993 a second source, with nothing traded against it a continuum 2 The traffic runs one way. Only the first row is complete, and it was constructed to be.
Adding a middle value, then jumps, then a volatility that moves lengthens the outcome count at every step while the instrument count stays at two, so each move toward realism carries the description further from completeness.
Try it out

Between completeness and incompleteness, which is the special case that has to be arranged rather than the ordinary one that shows up on its own?

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What is done when a single number is needed and the model gives a range?

Three responses are in common use, and they are honest in different ways. None of them recovers a single number from the mathematics, and the reason to name all three is so that a reader can tell which one they are looking at when a report hands them a figure.

  1. Quote two prices rather than one The interval is reported as an interval. A figure at which the payoff would be taken on and a higher figure at which it would be passed on, sitting at or inside the two ends. Reporting the interval hides nothing, and the report says on its face that the argument returned a bracket. The cost is that a bracket cannot be added up, averaged or put in a single cell.
  2. Take one end of the interval and say which end The top, Rs 12.162285/- on the worked payoff, is the cost of a bundle that is never worth less in any outcome, so taking it is a conservative choice with a clear meaning. The bottom, Rs 4.877058/- here, has the mirror meaning. Neither end was selected by the assumption. Both were selected by somebody deciding which way to lean.
  3. Add an assumption that picks a point inside the interval Choose one measure out of the many admissible ones, on some ground the assumption did not supply: a preference, a penalty for how far the chosen measure sits from the physical measure P, a fitted parameter, a convention. The output is a single number again. The number is single because of the added assumption, and the number moves when the assumption does.

The one thing that must survive from this section is that all three are choices, and a report that presents any of them as a result of the argument has mislabelled its own output. Naming which response was used costs one sentence and tells the reader everything about how much weight the figure carries.

A bid and offerTwo prices rather than one, which is one honest way to report a payoff whose price the argument returns as an interval. pair is the first response wearing its everyday clothes, and the balance makes the same point one last time. Asked for one and a half kilograms, a person can say between one and two, can hand over two and say it is at least what was asked for, or can decide on some other ground to call it one and a half. All three are usable. Only the first is a statement about the box.

Three responses to one interval. Read the bottom strip on each. QUOTE TWO PRICES both ends reported nothing chosen inside the argument supplied both of these TAKE ONE END Rs 12.162285/- taken a lean, stated as one the argument supplied the end, not the choosing ADD AN ASSUMPTION one measure selected a point comes back the argument supplied neither the point nor the ground All three are usable. Only the first is entirely a statement about the mathematics.
Quoting two prices, taking one end of the interval and adding an assumption that picks a point are three responses to the same interval, and only the first reports something the no-arbitrage argument by itself supplied.
Try it out

A report takes the top of the interval, Rs 12.162285/-, and presents it as the price. Has a single price been recovered from the mathematics?

The failure: reading a single price as news about the market

The mistake is short and it is made in good faith. A model is run, it returns one number, and the single number is read as evidence that everything a person might be handed can be built and priced. The single number is not evidence of that. The single number is evidence that the model was written with as many outcomes as it had instruments, and that is a fact about the writing.

Watch how it compounds. Somebody who has read the single number that way meets a richer model later, one that admits a middle outcome or a moving volatility, and that model reports an interval. The earlier model gave a clean figure and the richer one will not, so the interval looks like a regression. So the richer model gets set aside and the cleaner one is kept. The cost is preferring the description that hides the uncertainty to the description that reports it, and that is exactly the wrong way round.

The tell is available in one line and takes no expertise to read. Any model can be asked how many outcomes it admits at the horizon and how many independent things it allows to be held. If the first number exceeds the second and a single price came out anyway, then something outside no-arbitrage picked that price, and the report should say what.

The number people quote sits above the two lines that produced it. MODEL OUTPUT Price of the payoff Rs 12.162285/- outcomes admitted at the horizon 2 independent instruments available 2 THESE TWO LINES ARE THE ANSWER WHAT THE SINGLE PRICE IS EVIDENCE OF The outcome count was set equal to the instrument count by whoever wrote the model. It is evidence about nothing outside the model at all. Change the second line to 3 and the big number becomes an interval, with nothing else touched.
A model reporting Rs 12.162285/- with two outcomes and two instruments has reported something about its own settings, and changing the outcome count to three turns that same single number into an interval with nothing else altered.
Try it out

An unfamiliar model returns a single price for a payoff. What has that established?

An incomplete market returns a range, not a number. See how one gets chosen.

How does somebody reading a model output actually use this?

Concretely, and it takes about two minutes. Someone handed a valuation, a risk figure or a reserve number that came out of a model does the counting themselves, on the model's own description rather than on its results.

First, find the outcome count. The count is rarely called that. The count appears as the number of states in a lattice, the number of factors driving a diffusion, whether jumps are admitted, whether the volatility is a constant or a process of its own. Second, find the instruments the model treats as already priced and independent: the underlying quantity, cash, and whatever else the model is told the price of. Third, compare the two numbers.

Where the first exceeds the second and one number came out anyway, ask the only question that matters: which assumption picked that number, and how far does the answer move when it changes? A model whose author can name the selecting assumption in one sentence is being read correctly, and a model whose author cannot has produced a figure nobody can attribute.

The same counting works in reverse as a design check. A clean answer arriving early is usually the shape of the description talking rather than the mathematics, so somebody building a model who finds that a single price falls out should look at the outcome count before feeling pleased.

None of this asks for market access, data or software. The check is two counts and a subtraction, done on the document the model is described in. Stating completeness as a counting condition rather than as a property that a setting either has or lacks by nature is what makes the check that cheap.

Covered elsewhere. The two results that link no-arbitrage to the existence of a pricing measure and completeness to its uniqueness are set out separately, and the equivalence itself is stated there. Choosing among the admissible measures when the price is a range needs a ground that no-arbitrage does not supply, and no such ground exists anywhere in this subject area: the three responses named above are descriptions rather than recommendations. The payoff arrived as a list of amounts and stayed one, so what any contract pays is a separate subject.

On jurisdiction. There is no India-specific rule bearing on the counting condition, and no threshold, rate or period arises. The counting condition, the interval and both of its ends are mathematics and hold wherever the assumption is made. Where a conduct duty attaches to how a valuation is reported, that duty sits with the regulator concerned and should be confirmed at source rather than taken from here.

References

SourceDocumentWhere
arXiv Quantitative FinancePreprint repository for statements of completeness, the set of admissible pricing measures and the superreplication intervalarxiv.org
Social Science Research NetworkWorking paper repository for the same material, including treatments of pricing under incompletenessssrn.com
Harrison and Pliska, 1981The link between completeness and uniqueness of the pricing measure, which is the result the counting condition rests onStochastic Processes and their Applications, 1981
Cox, Ross and Rubinstein, 1979The lattice construction whose one step case is worked here and then given a third outcomeJournal of Financial Economics, 1979
Merton, 1976Jump diffusion, a description that adds outcomes without adding instrumentsJournal of Financial Economics, 1976
Heston, 1993Stochastic volatility, a second source of movement with nothing traded against itThe Review of Financial Studies, 1993
Hull, Shreve and WilmottStandard texts covering replication, the pricing measure and superreplicationPearson, Springer and Wiley respectively

The standard process, its four parameters and the payoff worked here are invented.
Educational material. Not advice on any investment, tax, budget or market position.

Comparison

Other comparisons in Pricing Theory and No-Arbitrage

Comparison

Replication vs Hedging: An Argument and an Activity

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