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Debt Capital Markets puzzles, solved step by step

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All topicsLeverage, coverage and cash flow9Mental maths and numeracy8Estimation and market sizing7Logic and brainteasers8Cost of capital and valuation riddles7Bond pricing and yield7Compounding, PIK and fees6Issuance and refinancing arithmetic8Credit spreads and default probability8Duration and convexity8Capital structure and recovery8Probability and expected value10Yield curve and forward rates6
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Showing 41–50 of 100
  1. 041K investors each send a sorted list of n orders by limit yield. You need one sorted order book. How many comparisons does a naive merge take against a min-heap merge, and why is the heap the right tool as K grows?Logic and brainteasersCoreCitadelNew York · 2026CSCitadel SecuritiesNew York · 2026

    Try it first

    Merging 64 lists of 1,000 orders: roughly how many comparisons does scanning every list's front order each time take, against a heap?

    Show the worked solution

    A naive scan takes about n K (K minus 1) comparisons; a min-heap takes about n K log2 K. For 64 investors with 1,000 orders each, that is about 4.03 million against 0.384 million, roughly 10 times fewer. The heap holds only each list's current best order, so finding the next order costs a few steps down one branch rather than a look at every list.

    What is the naive way, and where does it waste effort?

    Imagine 64 queues at a bank, each already in order of arrival, and you must call people one at a time in overall order. The naive clerk walks along all 64 queue fronts every time to find the earliest. Every time one order leaves the book, the naive merge re-compares all K front orders, even though only one of them changed. That is K minus 1 comparisons for each of n K orders: 64,000 orders times 63 is 4,032,000 comparisons.

    The other naive route is to merge lists one at a time: merge list 1 and 2, then merge in list 3, and so on. Each merge re-reads everything merged so far, which costs about n times K squared over 2, here about 2.08 million. Better than scanning, but it still grows with the square of K.

    Keep only the K front runners in order, and the merge stays cheap7.42%7.45%7.48%7.50%7.51%7.55%7.60%7.62%next order out:lowest yieldPop the top, push that investor's next order,and re-sort one path: about log2 K = 3 steps here1m2m3m4m216324864K, number of investor lists (n = 1,000 each)scan all heads: 4.03mmin-heap: 0.384m
    A min-heap keeps each investor's best remaining order, with the lowest yield at the top, so each step costs about log2 K comparisons; merging 64 lists of 1,000 orders then takes about 0.384 million comparisons against 4.03 million for scanning every front order.

    Why does a heap fix it?

    A min-heapA tree in which every parent is smaller than its children, so the smallest item is always at the top and can be removed and replaced in a number of steps equal to the tree height. keeps the K front orders only partly sorted: the best is always at the top, and the rest are arranged so that fixing the tree after a change touches one path from top to bottom. Taking the best order and inserting that investor's next one costs about log2 K comparisons instead of K, which is 6 instead of 63 at K of 64. Total work becomes n K log2 K, about 384,000 comparisons.

    The relationship
    scan: nK(K−1)≈4.03mheap: nKlog⁡2K=64,000×6=384,000\text{scan: } nK(K-1) \approx 4.03\text{m} \qquad \text{heap: } nK\log_2 K = 64{,}000 \times 6 = 384{,}000
    norders per investor list, 1,000
    Knumber of investor lists, 64
    \log_2 Kheight of the heap, 6 for 64 lists
    What it says in wordsBoth methods output every order once; the heap makes each output cost the height of a small tree instead of a scan of every list.

    Say where the heap does not matter. With four or five lists, scanning is about as fast and simpler to code, and the orders arrive as fast as a person can read them anyway. The heap earns its place when K is large or the lists do not fit in memory, which is the version in the reported question: arrays read from disk, where only the front of each list is held at once. A careful heap counts about two comparisons per level on the way down, so treat log2 K as the order of the cost, not an exact count.

    Where candidates lose it

    The common miss is proposing to concatenate all the lists and sort them. It works, but costs about n K log2 of n K and throws away the fact that each list is already sorted, which is the whole hint in the question.

    The second loss is naming a heap without saying what sits in it. Say clearly: one entry per list, the current front order, plus which list it came from so you know where to fetch the next one.

    What the interviewer asks next

    • What else does each heap entry need to store besides the yield?
    • How would you merge the lists if they were too large to fit in memory at once?
    • Two orders have the same yield. How do you keep allocation fair in the merged book?

    Asked at Citadel, Equity Capital Markets, New York, 2026 (Wall Street Oasis): I was asked to implement K-way merge of K sorted arrays
    Asked at Citadel Securities, Equity Capital Markets, New York, 2026 (Wall Street Oasis): and the cadidate was expected to use a min heap

  2. 042A trader starts with 3 units of capital and stops at 0 or 6. Each trade wins or loses 1 unit. What is the probability of reaching 6 if each trade is a fair coin, and if the win probability is 55%?Probability and expected valueHardRisk managementFixed income asset management

    Try it first

    With a 55% edge on each trade, the chance of reaching 6 before 0 is closest to:

    Show the worked solution

    50% with a fair coin, and about 64.6% with a 55% win rate. With a fair coin, your capital is a fair bet, so the chance of reaching 6 from 3 is 3 over 6. With an edge, the chance is 1 over 1 plus (q over p) cubed, where q over p is 0.45 over 0.55. That gives 1 over 1.548, or 64.6%. Spread the same edge over walls ten times further away and it rises to about 99.8%.

    Why is the fair-coin answer simply 3 over 6?

    Picture a game where you and a friend toss a coin for Rs 1 until one of you is broke; you start with Rs 3, the friend with Rs 3. Every toss is fair, so on average nobody gains, and your expected wealth at the end must still be Rs 3. If the game ends at 0 or 6 and your expected ending wealth is 3, you must reach 6 exactly half the time. In general the fair-coin chance of reaching N from i is i over N.

    How does a 55% edge change it?

    The relationship
    P(reach N from i)=1−(q/p)i1−(q/p)N1−0.818231−0.81826=11+0.81823≈64.6%P(\text{reach } N \text{ from } i) = \frac{1 - (q/p)^i}{1 - (q/p)^N} \qquad \frac{1 - 0.8182^3}{1 - 0.8182^6} = \frac{1}{1 + 0.8182^3} \approx 64.6\%
    p, qchance of winning and losing each trade, 0.55 and 0.45
    q/p0.45 over 0.55, about 0.818
    i, Nstarting capital 3 and target 6
    What it says in wordsThe ratio of losing to winning odds, raised to the distance from each wall, sets how strongly the edge tilts the outcome.

    This is the classic gambler's ruinA random walk that stops at two walls, used to find the chance of hitting one wall before the other. set-up. A 55% edge on each trade turns into a 64.6% chance of doubling before going broke, a modest lift because the walls are only three steps away. The fair game takes 9 trades on average to finish, so the edge only gets a handful of chances to work.

    A small edge per trade becomes a big edge over many trades0%25%50%75%100%40%45%50%55%60%Chance of winning each tradefair coin: 50%start 3, target 6: 64.6%start 30, target 60: 99.8%
    Starting with 3 units and a target of 6, a 55% win rate gives a 64.6% chance of reaching the target, but with 30 units and a target of 60, still in steps of 1, the same edge gives 99.8%, because the edge has many more trades over which to work.

    That is the lesson a desk wants. The same edge, bet in smaller pieces relative to capital, almost removes the risk of ruin: starting at 30 with a target of 60 and 1-unit trades, the chance of success is 99.8%. Betting a large share of capital on each trade throws the edge away, because variance gets to end the game before the edge shows. The limit is the model itself: real trades do not win or lose exactly one unit, and edges are estimated, not known.

    Where candidates lose it

    The common wrong answer to the second part is 55%: candidates assume the per-trade edge equals the edge on the whole game. The game is many trades long, so the edge compounds, and the answer must be higher.

    The opposite error is guessing something near certainty. With walls only three steps away, variance still dominates; say {P42['prob']*100:.1f}% and then explain why position size, not the edge alone, drives the chance of ruin.

    What the interviewer asks next

    • What is the expected number of trades before the game ends with a fair coin?
    • With a 45% win rate, what is the chance of reaching 6?
    • How does this connect to the Kelly criterion for sizing a bet?
  3. 043An issuer raises Rs 1,000 crore at 8.2% twelve months before its old bond matures and parks the cash at 6.9% until then. What does the pre-funding cost, and what risk does it remove?Compounding, PIK and feesCoreSyndicate desksCorporate banking

    Try it first

    What is the cost of carrying the cash for a year?

    Show the worked solution

    Pre-funding costs about Rs 13 crore of negative carry, before tax. The issuer pays 8.2% on the new bond while earning 6.9% on the parked cash, a 1.3% gap on Rs 1,000 crore for twelve months. In return it removes refinancing risk: it no longer needs the market to be open, spreads to hold and its rating to survive the final year. On a five-year deal, waiting would have to cost more than about 26 basis points a year for pre-funding to lose.

    What exactly does pre-funding cost?

    A family renting a flat signs a new lease a year before the old one ends because rents are rising and good flats are scarce. For twelve months they pay a little extra holding the new flat, but they are not searching in a panic the week the old lease ends. Pre-funding costs the gap between what the new money costs and what the parked cash earns, for as long as both exist: the negative carryThe cost of holding a position whose income is lower than its funding cost, here cash earning less than the bond that raised it.. Here 8.2% less 6.9% is 1.3%, on Rs 1,000 crore for a year, Rs 13 crore, about Rs 1.08 crore a month.

    The relationship
    Carry=1,000×(8.2%−6.9%)×1212=13 crore\text{Carry} = 1{,}000 \times (8.2\% - 6.9\%) \times \tfrac{12}{12} = 13 \text{ crore}
    1,000amount raised early, Rs crore
    8.2%coupon on the new bond
    6.9%yield earned on the parked cash
    12/12the fraction of a year the two overlap
    What it says in wordsThe cost is the rate gap on the amount raised, for the time both the new bond and the parked cash exist.
    Twelve months of negative carry buys certainty on refinancing day123456789101112Months until the old bond maturesRs 13 croreCumulative cost: raise at 8.2%, park at 6.9%1.3% x Rs 1,000 crore = Rs 1.08 crore a monthWhat the premium buysNo need for the market tobe open on one fixed dayNo exposure to spreadswidening in the last yearNo risk a downgrade landsjust before maturityBreakeven: about 26 bp a year on a 5-year deal (33 bp discounted). After 25% tax: Rs 9.75 crore.
    Raising Rs 1,000 crore at 8.2% and parking it at 6.9% costs about Rs 1.08 crore a month, Rs 13 crore by the old bond's maturity, in exchange for removing the need to find a market on one fixed day.

    What does that Rs 13 crore buy?

    Certainty. Without pre-funding, the issuer must refinance in a narrow window before maturity, and if markets are shut, spreads have widened or its rating has slipped in that window, it either pays far more or cannot repay. Pre-funding is insurance with a known premium. A useful breakeven: spread over a five-year replacement bond, Rs 13 crore is about 26 basis points a year before discounting and about 33 after. If waiting risked a rise larger than that, or a missed maturity, the premium was cheap.

    Say the refinements. Interest paid is usually tax deductible and interest earned is taxable, so at an assumed 25% rate on both the after-tax carry is about Rs 9.75 crore. The issuer also carries a bigger balance sheet for a year, gross debt rises before the old bond goes, which can briefly worsen reported leverage. And the parked cash must be invested safely and kept liquid; reaching for yield on it defeats the purpose of paying for certainty.

    Where candidates lose it

    The common miss is quoting the full coupon, Rs 82 crore, as the cost. The cash is not idle; it earns 6.9%, and only the gap is the price of pre-funding.

    The second is stopping at Rs 13 crore and calling it a waste. The interviewer wants the other side of the trade named: refinancing risk, which is exactly what issuers with a large maturity and a shaky market fear most.

    What the interviewer asks next

    • The issuer could instead buy back the old bond early. How would you compare the two?
    • The parked cash earns 7.5% instead. What is the carry, and does the answer change?
    • Why do rating agencies look favourably on issuers who pre-fund large maturities?
  4. 044A distressed bond trades at 55. It will either be repaid at 100 or restructured with a recovery of 30. Ignoring discounting, what probability of full repayment is the market pricing?Capital structure and recoveryCoreRestructuringCredit research

    Try it first

    The implied chance of full repayment is:

    Show the worked solution

    About 35.7%. Set the price equal to the probability-weighted payoff: p times 100 plus 1 minus p times 30 equals 55. The 30 is paid either way, so the price only has to cover 25 of the 70-point gap between recovery and par, and 25 over 70 is 35.7%. The market thinks restructuring is nearly twice as likely as repayment.

    How do you turn a price into a probability?

    Suppose a raffle ticket pays Rs 100 if you win and Rs 30 as a consolation prize if you lose, and it sells for Rs 55. Everyone gets the Rs 30, so you are really paying Rs 25 for a shot at an extra Rs 70. A price between two outcomes is a probability-weighted average of them, so you can solve for the weight. The consolation prize matters: ignore it and you would read the Rs 55 as a 55% chance.

    The relationship
    p⋅100+(1−p)⋅30=55  ⇒  p=55−30100−30=2570≈35.7%p \cdot 100 + (1 - p) \cdot 30 = 55 \;\Rightarrow\; p = \frac{55 - 30}{100 - 30} = \frac{25}{70} \approx 35.7\%
    pmarket-implied chance of full repayment
    100payoff if repaid in full
    30recovery if restructured
    55today's price
    What it says in wordsThe implied probability is how far the price sits above the recovery, as a share of the distance from recovery to par.
    The price tells you how far along the road from 30 to 100 the market sitsBond todayprice 55p = 35.7%1 - p = 64.3%Repaid in full100Restructuredrecovery 30305510025 of the 70 gapp x 100 + (1 - p) x 30 = 55 gives p = (55 - 30) / (100 - 30) = 25 / 70 = 35.7%
    A bond at 55 that pays either 100 or a recovery of 30 sits 25 points up a 70-point range, which implies a 35.7% chance of full repayment and a 64.3% chance of restructuring.

    What does ignoring discounting hide?

    Both payoffs arrive in the future, often a year or more away, and a distressed investor wants a high return for waiting. If the payoffs arrive in a year and the buyer demands 12%, the price must equal the expected payoff divided by 1.12, which lifts the implied repayment probability to about 45.1%. So the 35.7% is a floor: part of the discount to par is a charge for time and risk, not only for default. That is why desks quote these as risk-neutral probabilities, not forecasts.

    The other soft spot is the recovery of 30. It is an estimate, and the implied probability is sensitive to it: at a recovery of 40, p is 15 over 60, 25%. Before trading on the number, a credit analyst would test the recovery from the balance sheet and the claims ranking ahead of this bond.

    Where candidates lose it

    The instant wrong answer is 55%, reading the price as a probability. That would only be right if the bad outcome paid nothing. Here it pays 30, and the answer drops to 35.7%.

    The second miss is forgetting to say the assumption. Ignoring discounting makes the probability look low; one sentence noting that a required return would raise it shows you know the difference between a market price and a forecast.

    What the interviewer asks next

    • What price would imply a 50% chance of repayment?
    • If the recovery estimate falls to 20, what probability is implied at 55?
    • How would you set up the same calculation for a credit default swap spread?
  5. 045A barbell of equal market values in 2-year and 10-year zeros and a bullet 6-year zero both yield 7% and have the same duration of 6. Rates move 100 basis points up, then separately 100 down. Which position does better in each case, and by how much?Duration and convexityHardFixed income asset managementSyndicate desks

    Try it first

    Rates jump 100 basis points in parallel. Which does better?

    Show the worked solution

    The barbell does better both ways, by about 0.065 per Rs 100 when rates rise and 0.075 when they fall. Up 100: the bullet loses 5.43, the barbell 5.36. Down 100: the bullet gains 5.80, the barbell 5.87. Duration is matched, so the difference is convexity, which the barbell has more of because its cash flows sit further apart.

    If the durations match, why do the results differ?

    Balance a see-saw with one child sitting in the middle, or with two children at the far ends. Both are balanced, but push the ends and the version with weight at the tips swings further. Duration measures where the weight of the cash flows sits on average; convexity measures how spread out it is, and the barbell's cash at years 2 and 10 is spread much wider than the bullet's single payment at year 6. For a zero, convexity grows roughly with maturity squared, so the 10-year leg adds far more than the 2-year leg takes away.

    The relationship
    Cbullet=6×71.072≈36.7Cbarbell=12⋅2×3+10×111.072≈50.7C_{\text{bullet}} = \frac{6 \times 7}{1.07^2} \approx 36.7 \qquad C_{\text{barbell}} = \tfrac{1}{2} \cdot \frac{2 \times 3 + 10 \times 11}{1.07^2} \approx 50.7
    T(T+1)/(1+y)^2convexity of a zero-coupon bond maturing in T years at yield y
    1/2each leg is half the barbell's market value
    What it says in wordsThe barbell averages a small and a very large convexity, which beats the single middle one.
    Same duration, but the barbell comes out ahead whichever way rates jumpValue change per Rs 100, 100 bp moves+5.80bullet+5.87barbellRates -100 bpbarbell ahead by 0.075-5.43bullet-5.36barbellRates +100 bpbarbell ahead by 0.0650.20.40.60.8-300-1000+100+300Parallel move, basis pointsBarbell minus bullet, per Rs 1000.770.52
    For a 100 basis point rise the barbell loses 5.36 per Rs 100 against 5.43 for the bullet, and for a 100 basis point fall it gains 5.87 against 5.80; the barbell's advantage grows with the size of the move, to about 0.52 at plus 300.

    How big is the advantage, and what does it cost in a real market?

    Small on a 100 basis point move: under a tenth of a rupee per Rs 100, about 6.5 paise on a rise and 7.5 on a fall. The advantage grows with roughly the square of the move, so at 300 basis points it is 0.52 to 0.77 per Rs 100, which is why convexity matters most in volatile markets. Price the positions by discounting each cash flow at the new flat yield, which is what the figures above do exactly rather than by the duration and convexity approximation.

    Now the honest limit. A flat curve where both positions yield 7% and convexity is free cannot last: buyers would all pick the barbell. In real markets the barbell usually yields a little less than the bullet, and that lower yield is the price of its convexity; whether it pays depends on how much rates actually move. The barbell also loses if the curve twists, for example if 2-year and 10-year yields rise while 6-year yields do not, a non-parallel move that duration and convexity for a single yield do not capture.

    Where candidates lose it

    The common wrong answer is that matched duration means matched results. It does to first order, for small moves, and the interviewer picked 100 basis points to push past that.

    The second trap is saying the barbell wins and stopping. Add the two caveats: in a real curve you pay for convexity through a lower yield, and a non-parallel move can hurt the barbell. Those two sentences separate a memorised answer from an understood one.

    What the interviewer asks next

    • What yield give-up on the barbell would make the two break even for a 100 basis point move either way?
    • The curve steepens: 2-year yields fall 50 and 10-year yields rise 50. Which position wins now?
    • Why do liability-matching investors often prefer bullets?
  6. 046A company has 50 of debt and 50 of equity at market value, trades at 10x earnings and pays 6% on its debt. What is its WACC before and after a 25% tax rate on interest?Cost of capital and valuation riddlesWarm upCitiNew York · 2026

    Try it first

    What cost of equity does a P/E of 10 suggest, as a quick proxy?

    Show the worked solution

    WACC is 8.0% before tax and 7.25% after. Read the cost of equity as the earnings yield, 1 over a P/E of 10, which is 10%. Half the capital costs 10% and half costs 6%, so the blend is 8.0%. The tax shield cuts debt to 6% x 0.75 = 4.5%, and the blend falls to 7.25%. The P/E shortcut assumes no growth; with growth the true cost of equity is higher.

    Where does the cost of equity come from when you are not given a beta?

    If a shop earns Rs 10,000 a year and sells for Rs 1 lakh, a buyer earns 10% on the price. Nobody would pay more unless they expected growth, so 10% is roughly what buyers of such a shop demand. A P/E of 10 means earnings are a tenth of the price, an earnings yield of 10%, and with no growth that is a quick proxy for the cost of equity. Say out loud that it is a proxy: it is the fastest honest route when the interviewer gives you only a multiple.

    The relationship
    WACC=EVke+DVkd(1−t)=0.5×10%+0.5×6%×0.75=7.25%WACC = \tfrac{E}{V}k_e + \tfrac{D}{V}k_d(1-t) = 0.5 \times 10\% + 0.5 \times 6\% \times 0.75 = 7.25\%
    E/V, D/Vequity and debt as shares of total capital at market value, 0.5 each
    k_ecost of equity, here the earnings yield 1 / 10 = 10%
    k_dcost of debt, 6%
    ttax rate on interest, 25%
    What it says in wordsWeight each funder's required return by its share of the capital, and cut the debt cost by the tax it saves.
    Weight each funder's cost by its share of the capitalEquity 50cost 10% = 1 / P/EDebt 50cost 6%, 4.5% after taxMarket valuesBefore tax: 0.5 x 10% + 0.5 x 6%equity 5.0debt 3.0= 8.00%After tax: 0.5 x 10% + 0.5 x 4.5%equity 5.0debt 2.25= 7.25%0%5%10%The tax shield on interest takes 0.75 points off the blend
    Equity of 50 costing 10% and debt of 50 costing 6% blend to 8.0% before tax, and to 7.25% once interest is deducted at 25%, because the debt's after-tax cost falls to 4.5%.

    Why does tax only touch the debt half?

    Interest is paid before tax and dividends after it. Every rupee of interest reduces taxable profit, so the government in effect pays a quarter of the interest bill at a 25% tax rate, and debt that costs 6% on paper costs 4.5% to the company. Equity gets no such relief. That is why the after-tax WACC is 0.75 points lower: half the capital times the 1.5 point shield. The difference compounds into valuation, since a lower discount rate raises the value of every future cash flow.

    State the limit of the shortcut before the interviewer does. The earnings yield equals the cost of equity only for a company that does not grow and pays out all its earnings. If earnings grow at 3% a year, investors paying 10x are expecting roughly 10% plus 3%, about 13%, and the WACC rises with it. For a real company you would build the cost of equity from a risk-free rate, a beta and a market premium instead.

    Where candidates lose it

    The common error is using 10 as a percentage or treating the P/E itself as a cost. Invert it: a multiple becomes a yield only when you flip it.

    The second loss is giving one WACC and not saying whether it is before or after tax. The question asked for both on purpose; give 8.0% and 7.25% and say where the 0.75 points went.

    What the interviewer asks next

    • The company re-levers to 70% debt at a 7% cost. What happens to WACC, and what should happen to the cost of equity?
    • If earnings grow at 4% a year, what cost of equity does a P/E of 10 imply?
    • Why do you use market values rather than book values for the weights?

    Asked at Citi, Capital Markets, New York, 2026 (Wall Street Oasis): $50 debt, $50 equity, P/E 10x, Cost of Debt 6%, what is WACC

  7. 047EBITDA is Rs 150 crore, capex Rs 40 crore, cash taxes Rs 20 crore, interest Rs 30 crore and scheduled principal Rs 20 crore. Compute the fixed charge cover and the interest cover, and say which one a lender trusts more.Leverage, coverage and cash flowWarm upCorporate bankingLeveraged finance

    Try it first

    What is the fixed charge cover?

    Show the worked solution

    Interest cover is 5.0x and fixed charge cover is 1.8x; a lender trusts the fixed charge cover more. Interest cover is EBITDA of 150 over interest of 30. Fixed charge cover takes off capex of 40 and tax of 20, leaving 90, and sets it against interest plus the principal that must be repaid this year, 50. It counts the cash that really has to go out, so it shows how thin the cushion is.

    Why can a company look five times covered and still be tight?

    A salaried person earning Rs 1.5 lakh a month with a Rs 30,000 loan interest bill looks comfortable. But rent and school fees of Rs 60,000 come out first, and the loan also needs Rs 20,000 of principal each month. What is left, Rs 90,000, against Rs 50,000 owed, is the true cushion. Interest cover ignores the cash a business must spend before lenders are paid and ignores the principal it owes, so it flatters the picture. Fixed charge coverCash flow after capex and tax, divided by all the debt payments due in the period, interest and scheduled principal together. fixes both.

    The relationship
    ICR=15030=5.0×FCCR=150−40−2030+20=9050=1.8×\text{ICR} = \frac{150}{30} = 5.0\times \qquad \text{FCCR} = \frac{150 - 40 - 20}{30 + 20} = \frac{90}{50} = 1.8\times
    150EBITDA, Rs crore
    40, 20capex and cash taxes, which must be paid before lenders
    30, 20interest and scheduled principal due this year
    What it says in wordsInterest cover divides earnings by interest; fixed charge cover divides cash left after essential spending by everything owed to lenders this year.
    Same company: 5.0x covered on one test, 1.8x on the one lenders trustInterest coverEBITDA 150Interest 30150 / 30 = 5.0xFixed charge coverCash left 90capex 40tax 20Interest 30Principal 2090 / 50 = 1.8x
    The same company covers its Rs 30 crore of interest 5.0 times from EBITDA of Rs 150 crore, but after Rs 40 crore of capex and Rs 20 crore of tax it covers its Rs 50 crore of interest and principal only 1.8 times.

    Which ratio would you put in a covenant?

    The fixed charge ratio, for a lender who cares about being repaid on schedule. At 1.8x the company has Rs 40 crore of spare cash a year after paying lenders, and a 44% fall in that cash would leave it unable to meet its schedule; at 5.0x interest cover the same fall would still look safe. Interest cover is still useful: it is quick, comparable across companies, and a lender pricing a bullet bond with no amortisation cares less about principal. But for an amortising term loan, fixed charge cover is the test that fails first.

    Say the limits. Definitions vary by document: some deduct only maintenance capex, some add lease payments to the fixed charges, some take tax paid rather than tax charged. Always read the covenant's own definition before comparing a borrower's ratio with a peer's; two companies at 1.8x on different definitions are not equally safe.

    Where candidates lose it

    The common slip is stopping at 5.0x and calling the credit comfortable. The question gave capex, tax and principal because they are the numbers interest cover leaves out.

    The second is putting principal on the wrong side, subtracting it from EBITDA rather than adding it to the charges. Principal is owed to lenders, so it belongs in the denominator with interest.

    What the interviewer asks next

    • Capex rises to Rs 60 crore. What is the fixed charge cover now?
    • Why might a lender deduct only maintenance capex rather than total capex?
    • The company adds a Rs 15 crore lease payment. Where does it go in each ratio?
  8. 048A plane has 100 seats and 100 passengers with assigned seats. The first passenger is drunk and sits in a random seat; every later passenger takes their own seat if it is free, otherwise a random free seat. What is the probability the last passenger gets their own seat, and the probability for the Nth passenger?Probability and expected valueCoreBelvedere TradingChicago · 2022

    Try it first

    The chance that passenger 100 gets their own seat is:

    Show the worked solution

    The last passenger gets their own seat with probability exactly 1/2. Every random choice picks seat 1, seat 100, or another seat that just passes the problem on. Seat 1 and seat 100 are always equally likely, and whichever goes first decides it. For passenger k, the same argument over the seats that still matter gives (n minus k plus 1) over (n minus k plus 2): 99 in 100 for passenger 2, falling to 1/2 for the last.

    Which seats actually matter to the last passenger?

    Think of a game of musical chairs where every displaced person grabs a random empty chair. It looks like a mess, but most grabs only move the mess along to someone else. For the last passenger, only two seats matter: seat 1, the drunk's own, and seat 100, their own. If a displaced passenger takes seat 1, the chain stops and everyone after sits correctly. If someone takes seat 100, the last passenger loses. Any other seat hands the same situation to a later passenger.

    Only seats 1 and 100 decide the last passenger's fateA displaced passengerpicks a free seatSeat 1 (the drunk's own)Everyone after sits correctlySome other seat jPassenger j repeats the choiceSeat 100 (the last one's)Last passenger is displacedThe middle branch loopsuntil seat 1 or seat 100is finally chosenSeats 1 and 100 are always equally likely: 1/2Passenger k of 100P = (n - k + 1) / (n - k + 2)k = 299/10099.0%k = 5051/5298.1%k = 9011/1291.7%k = 992/366.7%k = 1001/250.0%
    Every random pick lands on seat 1, which ends the chain and saves the last passenger, on seat 100, which dooms them, or on another seat, which just passes the choice along, and since seats 1 and 100 are always equally likely the last passenger's chance is exactly one half.

    How do you get the answer for any passenger?

    Apply the same logic to passenger k. For them, the deciding seats are seat 1 and the seats of passengers k to n, which are still unclaimed by their owners when the chain reaches them. Passenger k loses only if their own seat is picked before seat 1, and among the n minus k plus 2 seats that matter, only one of them is theirs. The chance of the chain ending well for them is therefore n minus k plus 1 over n minus k plus 2.

    The relationship
    P(k gets own seat)=n−k+1n−k+2k=100:12k=2:99100P(k \text{ gets own seat}) = \frac{n - k + 1}{n - k + 2} \qquad k = 100: \frac{1}{2} \qquad k = 2: \frac{99}{100}
    nnumber of seats and passengers, 100
    kthe passenger's boarding position, from 2 to n
    What it says in wordsPassenger k is safe unless their own seat is the one picked first among the seats that still matter to them.

    Check the ends of the formula, which is what an interviewer will do. Passenger 2 loses only if the drunk sits in seat 2, a 1 in 100 chance, so 99 in 100 is right. Passenger 99 has a 2 in 3 chance, and passenger 100 has 1 in 2. The answer does not depend on the size of the plane for the last passenger: with 10 seats or 1,000 it is still one half, which is the fact worth saying out loud.

    Where candidates lose it

    Candidates try to track the chain of displaced passengers and drown in cases. The interviewer is waiting to see if you spot that only two seats matter; say that first and the answer follows in one line.

    The second loss is answering 1/2 for the last passenger and then guessing 1/2 for everyone. The reported question asked for the Nth passenger, so have the general formula and its two sanity checks ready.

    What the interviewer asks next

    • What is the expected number of passengers who end up in the wrong seat?
    • What if the first two passengers are both drunk?
    • Why is the answer for the last passenger independent of the number of seats?

    Asked at Belvedere Trading, Equity Capital Markets, Chicago, 2022 (Wall Street Oasis): Drunk passenger on a plane, what's the probability the Nth passenger gets his assigned seat

  9. 049You buy a 6% annual coupon bond at 100. A year later, just after the coupon is paid, it trades at 95. What total return did you earn over the year, and why is the answer not minus 5%?Bond pricing and yieldWarm upFixed income asset management

    Try it first

    Your total return for the year is:

    Show the worked solution

    A total return of +1%. You paid 100. During the year you received a coupon of 6, and the bond is now worth 95, so you hold 101 of value against 100 paid. Total return is income plus price change, 6 minus 5, divided by the price you paid. Quoting minus 5% counts only the price and forgets the coupon, which for a bond is most of the return.

    What counts as return on a bond?

    If you buy a flat for Rs 1 crore, collect Rs 6 lakh of rent over the year and the flat's market value slips to Rs 95 lakh, you are not down 5%. You have Rs 95 lakh of flat and Rs 6 lakh of cash: Rs 1.01 crore. Total return is everything the investment paid you plus the change in what it is worth, divided by what you paid. For a bond, the coupon is the rent.

    The relationship
    TR=C+(P1−P0)P0=6+(95−100)100=+1%TR = \frac{C + (P_1 - P_0)}{P_0} = \frac{6 + (95 - 100)}{100} = +1\%
    Ccoupon received during the year, 6
    P_0price paid, 100
    P_1price a year later, just after the coupon, 95
    What it says in wordsAdd the income received to the change in price, then divide by what you paid.
    Total return = income + price change: 6 - 5 = +1100Price paid+6Coupon received-5Price change101Ending value80bond 95+ cash 6Total return+1.0%Axis starts at 80 so the small moves are visible
    The investor paid 100, received a 6 coupon and saw the price fall 5 to 95, so ends the year with 101 of value, a total return of +1% rather than the -5% the price alone suggests.

    Why would the price have fallen, and what does it mean for next year?

    A fixed coupon bond falls in price when market yields rise. If the bond had four years left after the coupon, a price of 95 means new buyers earn about 7.49% a year to maturity, so the loss this year is partly paid back as extra yield in later years if the bond is held. That is the other reason not to fixate on the minus 5: a holder to maturity still gets 100 at the end, and the price fall is a mark-to-market loss, not money gone for good.

    Two limits worth saying. This assumes the coupon is simply held as cash; reinvesting it would add a little more. And it assumes the issuer is still sound: if the price fell because default risk rose, the loss may not come back. A desk reports both numbers, the price change and the total return, because they answer different questions.

    Where candidates lose it

    The instant wrong answer is minus 5%, because the price is the only number on the screen. For a bond, the coupon is usually the larger part of the return, and ignoring it gets the sign wrong here.

    The other slip is adding the coupon to the new price and dividing by the new price: 101 over 95. Returns are measured on what you paid, so divide by 100.

    What the interviewer asks next

    • What price a year later would have given a total return of zero?
    • If the coupon were reinvested at 7% for half a year before you measure, what changes?
    • Why do index providers publish total return rather than price return for bond indices?
  10. 050An unlevered firm is worth Rs 2,000 crore. It adds Rs 800 crore of permanent debt at a 25% tax rate. Distress would cost 30% of firm value and the extra debt creates a 10% probability of distress. Is the firm worth more or less after the debt?Cost of capital and valuation riddlesHardCorporate bankingLeveraged finance

    Try it first

    Is the firm worth more or less with the debt?

    Show the worked solution

    Worth more: about Rs 2,134 crore, Rs 134 crore above the unlevered value. Permanent debt of Rs 800 crore at a 25% tax rate creates a tax shield worth 0.25 x 800, Rs 200 crore, lifting value to Rs 2,200 crore. Distress would destroy 30% of that, Rs 660 crore, but with a 10% chance the expected cost is Rs 66 crore. The shield wins unless the distress probability passes about 30%.

    Where does debt add value, and where does it take it away?

    A family that takes a home loan gets a tax deduction on the interest every year, a steady saving. But if the loan is too big and a job is lost, they may have to sell the house in a hurry at a poor price. Debt adds value through the tax saved on interest and subtracts value through the expected cost of financial distress; the net of the two decides whether borrowing helps. That balance is the {term('trade-off theory', 'The idea that a company chooses its debt level by weighing the tax benefit of interest against the expected costs of financial distress.')} of capital structure.

    The relationship
    VL=VU+tD−p⋅c⋅(VU+tD)=2,000+200−0.10×0.30×2,200=2,134V_L = V_U + tD - p \cdot c \cdot (V_U + tD) = 2{,}000 + 200 - 0.10 \times 0.30 \times 2{,}200 = 2{,}134
    V_Uvalue of the firm with no debt, Rs 2,000 crore
    tDpresent value of the tax shield on permanent debt, 0.25 x 800 = 200
    pprobability of distress, 10%
    cshare of firm value lost in distress, 30%
    What it says in wordsLevered value is unlevered value plus the tax shield, less the probability-weighted cost of distress.
    Debt adds value through the tax shield until expected distress costs catch up2,000Unlevered firm+200Tax shield-66Expected distress2,134Levered firm1,800Axis starts at Rs 1,800 crore so the moves are visibleNet gain+134BreakevenPD 30.3%not 10%
    The firm's Rs 2,000 crore unlevered value rises to Rs 2,200 crore with the Rs 200 crore tax shield, and a 10% chance of losing 30% in distress takes off Rs 66 crore, leaving Rs 2,134 crore, a net gain of Rs 134 crore.

    Why is the tax shield worth t times D?

    For permanent debt, the company pays interest of r times D every year forever and saves t times that in tax. Discounting a perpetual saving of t r D at the debt's own rate r gives t D. So Rs 800 crore of permanent debt at a 25% tax rate is worth Rs 200 crore in tax savings, whatever the interest rate, as long as the debt is truly permanent and the company always has profits to deduct against. Both conditions are generous, which is why real tax shields are usually worth less than t D.

    Now find where the answer flips. The shield is 200; the distress cost is the probability times 660. The firm is worse off once the distress probability passes 200 over 660, about 30.3%, so debt at this level is value-adding only while distress stays well below a one-in-three chance. Adding more debt raises both lines, the shield in a straight line and the distress probability faster, which is why an optimal level exists. The limits: the 30% cost and the 10% probability are estimates, and indirect distress costs, lost customers and staff, are the hardest part to measure.

    Where candidates lose it

    One common error is to compare the full Rs 660 crore distress cost with the Rs 200 crore shield and conclude the debt destroys value. The distress cost only happens 10% of the time; it has to be weighted by its probability.

    The opposite error is adding the Rs 200 crore shield and stopping, which is the textbook answer with taxes and no distress. The question gave you the distress numbers so you would net them off.

    What the interviewer asks next

    • At what distress probability does the firm become worth less than Rs 2,000 crore?
    • The debt is only outstanding for five years, not forever. How does that change the value of the tax shield?
    • Why might a stable utility carry more debt than a young technology company with the same value?
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