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060

Case 060Risk limits and drawdownsCore

Ashvel Capital's 99% one-day VaR model was breached on 7 of the last 250 days, against 2.5 expected. How unlikely is that if the model is right, and what do you change?

1The situation

Ashvel Capital runs a multi-strategy book. Its risk team reports a 99% one-day value at risk every morning. Over the last 250 trading days, the day's loss exceeded that morning's VaR seven times. Four of the seven came within three weeks of each other during a sharp sell-off; the other three were spread across the year.

The model uses two years of daily history and assumes returns are normally distributed.

2Your task

If the model were right, how likely is seven or more breaches? Is the model broken, and what would you change?

Quick check

If the model is right, roughly what is the chance of 7 or more breaches in 250 days?

Worked solution

Try it on paper, then open one step at a time.

30-second answerThe answer to give first

A correct 99% model would produce seven or more breaches only about 1.4% of the time, so the model understates Ashvel's tail risk. The expected count is 2.5. A likelihood-ratio test gives 5.5, above the 3.84 needed to reject at 5%. Four breaches in three weeks also says the model reacts too slowly to volatility. Change the volatility estimate to weight recent days, drop the normal assumption and add expected shortfall and a stressed window.

Step 1How unlikely is seven breaches if the model is right?

Treat each day as an independent 1% event, like a die with a hundred faces rolled 250 times, counting the ones. Two or three is normal; seven or more happens with a chance of about 1.4%. The count follows a binomial distributionThe number of successes in a fixed number of independent tries, each with the same chance. Here, the number of breach days in 250 days at 1% a day., with 2.5 expected. Five or more already happens only 10.8% of the time; ten or more is about 0.03%.

If the 99% model is right: how many breaches in 250 days?8.1020.5125.7221.5313.446.752.761.070.380.191011Breaches in 250 trading days (bar labels: chance, %)expected 2.5Seven or more breaches1.4% chance
If Ashvel's 99% VaR model were correct, two or three breaches in 250 days would be most likely and seven or more would have only a 1.4% chance, so seven breaches is strong evidence the model understates tail losses.
The relationship
P(X≥7)=1−∑k=06(250k)(0.01)k(0.99)250−k≈0.0137P(X \ge 7) = 1 - \sum_{k=0}^{6} \binom{250}{k} (0.01)^k (0.99)^{250-k} \approx 0.0137
Xnumber of breach days in 250
0.01chance of a breach on any day if the 99% model is right
250trading days in the test window
What it says in wordsAdd up the chances of 0 to 6 breaches and subtract from one: about 1.4% is left for 7 or more.
Step 2Is the count the only thing wrong?

No, and the clustering is the more useful clue. Four breaches inside three weeks means the model's volatility estimate lagged the market: it was still using calm history when the market had already turned. A correct model's breaches should arrive scattered, not in bunches. Formal tests check both: the Kupiec test on the count, where 5.5 against a threshold of 3.84 rejects the model, and an independence test, such as Christoffersen's, on whether one breach makes the next more likely. Regulatory frameworks for banks also grade backtests by breach count, for example a traffic-light scheme where a handful of breaches in a year calls for review; confirm the current thresholds before quoting them.

Step 3What would you change?

Fix the two faults the evidence points to. First, the lag: weight recent days more heavily in the volatility estimate, so the model widens within days of a regime change rather than months. Second, the shape: replace the normal assumption with historical or fat-tailed returns, because a normal curve puts too little weight on large losses. Then add what VaR does not say: expected shortfall, the average loss on the days beyond VaR, and a stressed VaR computed on the worst year in the history, and set limits on those too.

Before any of that, check the plumbing. Breaches can come from comparing VaR with P&L that includes fees, new trades made during the day or a pricing error. Backtest against the P&L the positions held that morning would have made, and only then conclude the model is wrong. Seven real breaches still mean the book took more risk than the limits assumed, and the PMs' limits were set on a number that was too small.

Where candidates lose it

The common loss is saying seven against 2.5 is a bit high and moving on, or the reverse, calling the model broken without saying how unlikely the count is. The interviewer wants the probability, about 1.4%, and the test it fails.

The second is missing the clustering. Four breaches in three weeks tells you what is wrong, a slow volatility estimate, which is more useful than knowing that something is.

What the interviewer asks next

  • How many breaches would you need before you are 95% sure the model is wrong, and why is that one-sided?
  • What does expected shortfall tell you that VaR cannot?
  • Ashvel switches to a faster volatility estimate and breaches fall to three. What might it have made worse?
← Case 059Vetrin Partners starts a quarter with Rs 100 crore long and Rs 100 crore short on Rs 100 crore of capital. Longs rise 20% and shorts rise 30%. What are the new gross and net exposures, and what must the PM do to get back to target?Case 061 →Vornix EdTech spends Rs 12,000 to acquire a customer paying Rs 500 a month at a 30% gross margin, with 4% monthly churn, and trades at 8x sales. Build the unit economics and make the short case.

Company names and figures are illustrative.

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