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Mutual Fund Mastery puzzles, solved step by step

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Showing 51–60 of 71 · filtered from 100Clear filters
  1. 074A gold fund's vault holds nine coins that look identical, but one is slightly lighter than the others. Using a balance scale only twice, how do you find the light coin?Logic and numeracy brainteasersCoreIndian AMCsGlobal asset managers

    Try it first

    What should the first weighing be?

    Show the worked solution

    Weigh three coins against three. The pan that rises holds the light coin; if they balance, it is among the three left aside. Then weigh two of those three suspects against each other: the rising pan holds it, and a balance means it is the third. Each weighing has three possible outcomes, so two weighings can separate 3 x 3 = 9 coins.

    Why split into three groups rather than two?

    A shopkeeper asking a customer "yes, no, or not sure?" learns more from one answer than one asking only "yes or no?". A balance scale gives three answers, left pan rises, right pan rises, or the pans balance, so the best weighing splits the suspects into three equal groups and lets the scale tell you which group holds the light coin. Put coins 1 to 3 on the left and 4 to 6 on the right. If the left pan rises, the light coin is 1, 2 or 3. If the right pan rises, it is 4, 5 or 6. If they balance, it is 7, 8 or 9.

    Each weighing has three outcomes, so it splits the suspects into thirdsWeighing 1coins 1-3 vs coins 4-6Left pan risesLight coin is 1, 2 or 3Weigh 1 vs 2132Pans balanceLight coin is 7, 8 or 9Weigh 7 vs 8798Right pan risesLight coin is 4, 5 or 6Weigh 4 vs 5465Nine end points for nine coins: every coin is found in exactly two weighings.Why not halves? Weighing 4 against 4 wastes the third outcome, the balance.Two weighings tell apart at most 3 x 3 = 9 cases; with halves you need 3 weighings for 9 coins.
    Weighing three coins against three leaves three suspects whatever the scale shows, and weighing two of those three against each other identifies the light coin, so two weighings cover all nine coins.

    How do you know two weighings is the minimum, and how far does this go?

    Count outcomes. One weighing has 3 outcomes, two have 3 x 3 = 9, and there are 9 possible light coins, so two weighings are just enough. The number of weighings needed is the smallest w with 3 to the power w at least the number of coins: 9 coins need 2, 27 coins need 3. One weighing can only handle 3 coins, so you cannot do 9 in one. Splitting into halves wastes the balance outcome and needs three weighings for nine coins.

    The relationship
    3w≥N  ⇒  w=⌈log⁡3N⌉,N=9:  w=23^w \ge N \;\Rightarrow\; w = \lceil \log_3 N \rceil, \qquad N = 9:\; w = 2
    wthe number of weighings
    Nthe number of coins, one of them light
    3the outcomes of one weighing: left rises, right rises, balance
    What it says in wordsEach weighing can at most divide the suspects by three, so the weighings needed grow with the logarithm to base three of the number of coins.

    The desk lesson is about information, not coins: a test with three outcomes is worth more than one with two, if you design it to use all three. The limit of the puzzle is that you are told the odd coin is lighter. If it could be heavier or lighter, each coin has two possible states, there are more cases to separate, and the strategy needs more care, which is the classic twelve-coin follow-up.

    Where candidates lose it

    The trap is splitting in halves: four against four, then two against two, then one against one. It works but takes three weighings, and the interviewer asked for two. Candidates who think in halves have missed that a balance is an answer too.

    The second miss is getting the method but not the reason. Say that a weighing has three outcomes and two weighings give nine, which is why nine coins is the most two weighings can handle.

    What the interviewer asks next

    • How many coins can you handle with three weighings?
    • Twelve coins, one odd, and you do not know whether it is heavier or lighter. Can you find it in three weighings?
    • You have a digital scale that shows exact weights instead. How many weighings do you need for nine coins?
  2. 076A market index has fallen five days in a row. Over its history it has risen on 52% of days, and each day's move is independent of the last. A client asks whether it is now due a rise. What is the chance the index rises tomorrow?Behavioural trapsWarm upWealth and advisoryDistribution and sales

    Try it first

    Your instinct, before any arithmetic.

    Show the worked solution

    52%, the same as on any other day. If each day's move is independent, the five falls carry no information about tomorrow. A run of five falls was unlikely before it began, 0.48 to the fifth power or about 2.5%, but that probability belonged to days that are now finished. Believing a rise is due is the gambler's fallacy.

    Why does the streak not make a rise more likely?

    A captain who has lost five tosses in a row walks out for the sixth feeling owed a win. The coin has no record of the first five and no sense of fairness to restore; it is still 50:50. Independence means past outcomes do not enter the calculation for the next one, so tomorrow's chance of a rise is the 52% it always was. The feeling that things must even out is real, and it has a name: the gambler's fallacy. It is strongest exactly when a streak is long, which is when it does the most damage to decisions.

    Five falls behind you, and tomorrow's odds have not movedDay 1fellDay 2fellDay 3fellDay 4fellDay 5fellDay 6: tomorrow52%chance of an up dayThe odds each morning, before the day's move: green up, red down52 / 4852 / 4852 / 4852 / 4852 / 4852 / 48, the same barBefore Monday: five falls in a row = 0.48 x 0.48 x 0.48 x 0.48 x 0.48 = 2.5%After Friday: that rare thing has already happened, and tomorrow is still 52%
    Each of the five days began with the same 52% chance of a rise, and so does tomorrow: the 2.5% chance of five falls in a row applied before the streak started, not after it has happened.

    Where does the tiny probability come from, and why is it the wrong number?

    It answers a different question. Standing on Monday morning, the chance of five falls in a row was 0.48 multiplied by itself five times, about 2.5%, and the chance of six in a row was about 1.2%, roughly one in 82. Once five falls have happened, the only uncertainty left is tomorrow, and for independent days the chance of a rise given the streak equals the chance of a rise on any day. Six falls in a row is rare only when viewed from the start; viewed from Friday evening, it needs just one more fall.

    The relationship
    P(up6∣5 downs)=0.485×0.520.485=0.52P(\text{up}_6 \mid \text{5 downs}) = \frac{0.48^5 \times 0.52}{0.48^5} = 0.52
    0.48^5the chance of the five falls that have already happened
    0.52the chance of a rise on any single day
    |read as given that
    What it says in wordsDivide the chance of the whole sequence by the chance of the part already seen, and the streak cancels out, leaving 52%.

    Is the independence assumption true for real markets?

    Not exactly, and saying so earns credit. Day-to-day direction in a broad index is very hard to predict from the previous days, but the size of moves does cluster: a run of falls often comes with bigger swings, so tomorrow's move may be larger even if its direction is a near coin toss. For an adviser the danger is not the arithmetic but the conversation: a client who believes a bounce is due will add money for the wrong reason, or hold out for a rebound the odds do not promise. A streak on its own is not a reason to act; any case for investing has to rest on the client's plan and horizon, not on the last five days.

    Where candidates lose it

    The trap is answering with the streak's rarity. Candidates say six falls in a row is roughly a one in 82 event, so a rise is almost certain, and in doing so treat days that are already over as if they were still uncertain. The interviewer is checking whether you can separate the probability of a sequence from the probability of the next step.

    The quieter loss is stopping at 52% without naming the assumption. Say independent, then add one sentence on what real markets do differently, such as swings clustering, and the answer sounds like someone who has watched markets rather than memorised a rule.

    What the interviewer asks next

    • What is the chance of at least one up day in the next five?
    • If an up day followed an up day 55% of the time, how would your answer change?
    • A client wants to invest only after a 5% fall. How would you explain the cost of waiting?
  3. 079Ten years ago a fund category had 100 schemes. Since then 30 were merged or closed after averaging 6% a year, and the 70 survivors averaged 12% a year. What was the true category average, and what does a database that shows only the survivors overstate?Statistics, correlation and diversificationCoreFund research and ratingsGlobal asset managers

    Try it first

    What was the average return across all 100 schemes?

    Show the worked solution

    The true average was 10.2% a year, and a survivor-only database overstates it by 1.8 points. Seventy funds at 12% and thirty at 6% average to 0.7 x 12% plus 0.3 x 6%, which is 10.2%. A database that drops merged and closed funds shows 12%, because the funds that disappeared were mostly the weak ones, and the gap compounds every year.

    Why do dead funds disappear from the numbers?

    Think of a coaching centre that advertises the average marks of students who stayed to the final exam. The ones who struggled and left are not in the average, so the centre looks better than its teaching. A fund database that lists only live schemes does the same: the funds that did badly were merged or shut, their records left the table, and the category average rose without anyone earning it. Fund houses merge weak schemes into stronger ones as a matter of routine, so the losers vanish quietly rather than with a headline. The name for this is survivorship bias.

    The funds that vanished take their bad returns with them70 survivors averaged 12% a year30 merged or closed averaged 6%Survivors only (what the database shows)12.0%All 100 funds (what investors earned)10.2%The 30 funds that disappeared6.0%Overstated by 1.8 points a year: Rs 1 lakh over ten years reads 3.11 lakh instead of 2.64 lakh
    Seventy surviving funds averaged 12% and thirty vanished funds averaged 6%, so the whole category earned 10.2%; a database that drops the dead funds reports the survivors' 12% and overstates the category by 1.8 points a year.
    The relationship
    rˉ=70×12%+30×6%100=10.2%\bar r = \frac{70 \times 12\% + 30 \times 6\%}{100} = 10.2\%
    70, 30the number of surviving and vanished funds
    12%, 6%each group's average annual return
    \bar rthe true average across every fund that existed ten years ago
    What it says in wordsWeight each group's return by how many funds were in it, including the ones no longer listed.

    How much does the gap matter over ten years?

    Compound it. Rs 1 lakh at 12% for ten years becomes about Rs 3.11 lakh; at 10.2% it becomes about Rs 2.64 lakh. A chart built on survivors shows roughly Rs 46,000 more per lakh than the category delivered to the average investor who chose a fund ten years ago. Compounding a category average is itself approximate, because each fund compounds on its own path, but the direction and the size of the gap are right.

    The bias leaks into rankings too. A fund that looks top quartile among survivors may be only average once the vanished funds are put back, because the bottom of the table has been cut off. Before comparing a fund with its category, ask whether the category figure includes funds that no longer exist. Good research databases keep dead funds in; if yours does not, treat its averages as a ceiling rather than a middle.

    Where candidates lose it

    The first loss is quoting 12% because that is what the screen shows. The interviewer built the question to see whether you ask what is missing from the data, which is most of the skill in fund research.

    The second is averaging 6% and 12% to get 9%. The groups are different sizes, so weight by count: seventy funds pull the average much closer to 12% than thirty pull it towards 6%, landing at 10.2%.

    What the interviewer asks next

    • If the closed funds had been larger than the survivors, would you weight by count or by assets, and what changes?
    • How would survivorship bias affect a backtest of a rule that buys last year's top funds?
    • Where else in finance does the data quietly leave out the failures?
  4. 080A fund holds 30% in IT stocks against a 20% benchmark weight. The IT sector returned 5% while the whole benchmark returned 12%. Separately, its bank stocks, a 25% weight, beat the bank index by 3 points. Split the fund's active return into an allocation effect and a selection effect.Performance measurement and returnsCoreFund research and ratingsIndian AMCs

    Try it first

    What did the IT overweight do to relative performance?

    Show the worked solution

    Allocation cost 0.70% and selection added 0.75%, a net active return of about plus 0.05%. The IT overweight is 10 points in a sector that trailed the benchmark by 7 points: 0.10 x (5% minus 12%) is minus 0.7%. The bank stocks beat their index by 3 points on a 25% weight: 0.25 x 3% is plus 0.75%. Good stock picking almost exactly paid for a poor sector bet.

    What is the difference between allocation and selection?

    Picture a selector who picks four spinners for a pitch that suits pace, but whose four spinners bowl better than any other spinners in the country would have. Two separate decisions: how many of each kind, and which ones. Allocation measures the first decision, sector weights against the benchmark's weights; selection measures the second, how the stocks chosen inside a sector did against that sector. Splitting them tells a fund research team whether a manager's skill lies in calling sectors or in picking stocks, which matters more than the total when deciding what to trust next.

    The relationship
    A=(wp−wb)(Rs−Rb)S=wp (rs−Rs)A = (w_p - w_b)(R_s - R_b) \qquad S = w_p\,(r_s - R_s)
    w_p, w_bthe fund's and the benchmark's weight in the sector
    R_sthe sector index return
    R_bthe whole benchmark's return
    r_sthe return on the stocks the fund actually held in that sector
    What it says in wordsAllocation is the extra weight times how the sector did against the whole benchmark; selection is the weight held times how the chosen stocks did against their sector.
    Two decisions, two effects: how much in each sector, and which stocksAllocation: the sector bet(30% - 20%) x (5% - 12%)overweight x IT against the whole index= -0.70%Selection: the stock picks25% x (banks held - bank index)weight x 3 points of outperformance= +0.75%0-0.5%+0.5%-0.70%+0.75%+0.05%AllocationSelectionActive returnGood picking almost exactly paid for the sector bet
    The 10 point IT overweight cost 0.70% because IT trailed the benchmark by 7 points, and bank stocks that beat their index by 3 points on a 25% weight added 0.75%, leaving an active return of only plus 0.05%.

    Why is allocation measured against the whole benchmark rather than against zero?

    Because the extra 10% in IT had to come from somewhere, and the alternative was the benchmark itself. An overweight in a sector that makes money still costs you if that sector made less than everything else you could have held. Say the assumptions behind the split out loud: the bank weight matches the benchmark's, so banks carry no allocation effect; the IT stocks held matched the IT index, so IT carries no selection effect; and the 10 points taken from other sectors came from sectors that earned the benchmark's 12%.

    One detail an interviewer may probe. Using the fund's 25% weight in the selection term folds in what the BrinsonThe Brinson method, named after the authors who set it out in the 1980s, splits a fund active return into allocation, selection and an interaction term. framework calls the interaction effect; the textbook version uses the benchmark's weight and reports interaction separately. With the bank weights equal here, both give the same 0.75%.

    Where candidates lose it

    Candidates multiply the overweight by IT's own return, 10% x 5%, and call the IT bet a gain of 0.5%. That ignores what the money would have earned in the rest of the benchmark, and it turns a costly decision into a profitable-looking one.

    The other slip is netting everything into plus 0.05% and calling the manager roughly neutral. The split is the whole point: plus 0.75 on stocks and minus 0.70 on sectors describes a good picker whose sector calls are giving the gains away.

    What the interviewer asks next

    • What if the fund had been underweight IT by 10 points instead?
    • The bank index itself beat the benchmark. Where does that show up?
    • Over three years, which of the two effects would you trust more as evidence of skill, and why?
  5. 081Scheme A, with a NAV of Rs 42.00, is merged into scheme B, whose NAV is Rs 18.00. How many units of B does an investor holding 1,000 units of A receive, and has anyone gained or lost in the swap?NAV, units and fund mechanicsWarm upFund operationsRegistrars and transfer agents

    Try it first

    How many units of scheme B does the investor receive?

    Show the worked solution

    2,333.333 units, and nobody gains or loses on the day. The holding is worth 1,000 x Rs 42, or Rs 42,000. Divided by B's NAV of Rs 18, that is 2,333.333 units, and 2,333.333 x Rs 18 is Rs 42,000 again. The swap ratio, 42 over 18, is 2.333 units of B per unit of A. A merger changes the unit count and the scheme, not the value held.

    Why does a lower NAV not make scheme B cheaper?

    Change a Rs 500 note into Rs 100 notes and you get five of them. You now hold more notes, but you are no richer. A NAV is the value of one unit, so the number of units you hold only means something when multiplied by the NAV; a merger at NAV swaps notes of one size for notes of another. Scheme B's Rs 18 NAV only says its units started at a lower price or have grown less since launch. It says nothing about whether B is cheap, good or bad.

    The unit count changes; the value held does notUnits heldBefore: scheme A1,000 unitsAfter: scheme B2,333.333Value held, Rs1,000 x Rs 42.00Rs 42,0002,333.333 x Rs 18.00Rs 42,000Swap ratio = NAV of A / NAV of B = 42 / 18 = 2.333 units of B for every unit of A
    The investor's 1,000 units of A become 2,333.333 units of B, but both holdings are worth Rs 42,000, because the swap ratio of 2.333 is set by the two NAVs on the merger date.
    The relationship
    uB=uA×NAVANAVB=1,000×4218=2,333.333u_B = u_A \times \frac{NAV_A}{NAV_B} = 1{,}000 \times \frac{42}{18} = 2{,}333.333
    u_A, u_Bunits held in scheme A before and scheme B after
    NAV_A, NAV_Beach scheme's net asset value per unit on the merger date
    What it says in wordsThe new unit count is the old count times the ratio of the two NAVs, which keeps the rupee value unchanged.

    So can a merger leave an investor worse off?

    Not on the day of the swap, when both schemes are valued at their closing NAVs. What a merger can change is everything after the swap: a different portfolio, a different expense ratio, a different level of risk, and possibly a tax event. If scheme B charges more, holds riskier bonds or follows another strategy, the investor's future returns change even though the swap itself was fair. That is why investors in a scheme being merged are generally offered a window to exit without an exit load; confirm the current rules on how that window works before relying on it.

    The three decimals are not decoration. Registrars in India commonly allot units to three decimal places, so the answer is 2,333.333 and not a rounded 2,333. Rounding down to whole units would take about Rs 6 from this investor, and across lakhs of folios that adds up, so fractional units exist precisely to keep the swap exact.

    Where candidates lose it

    The fast wrong answer is 1,000 units, as if a merger were a change of name. It would leave the investor with Rs 18,000 in place of Rs 42,000. The next wrong answer inverts the ratio and gives about 429 units. Both come from working with unit counts instead of rupees.

    State the rupee value first, Rs 42,000, and divide by the new NAV. Then add the sentence that shows judgement: the swap is fair on the day, and the real question is what the investor now owns and what it costs.

    What the interviewer asks next

    • Scheme B's expense ratio is 0.5 points higher. Roughly what does that cost on Rs 42,000 over ten years?
    • In what circumstances could the merger be a taxable event for the investor, and what would you check?
    • The investor had a monthly systematic investment plan into scheme A. What should happen to it?
  6. 082Without a calculator: at 8% a year, how long does Rs 1 lakh take to double, and how close does the rule of 72 get to the exact answer? Then do the same at 6% and at 12%.Compounding and time valueWarm upIndian AMCsDistribution and sales

    Try it first

    How far is the rule of 72 from the exact doubling time at 8%?

    Show the worked solution

    About 9 years at 8%; the exact figure is 9.006 years, so the rule of 72 is out by about 2 days. At 6% the rule gives 12 years against an exact 11.90, and at 12% it gives 6 years against an exact 6.12. In the range where fund returns usually sit, the rule is off by weeks, not years.

    Why does 72 divided by the rate give the doubling time?

    If the price of a Rs 100 thali rises 8% a year, it costs about Rs 200 in nine years. You did not need a calculator, only the fact that 72 over 8 is 9. The exact doubling time is ln 2 divided by ln(1 + r), and for rates of a few per cent ln(1 + r) is close to r, so the answer is close to 69.3 divided by the rate in per cent. Using 72 instead of 69.3 does two jobs: it nudges the answer up to correct for rates around 8%, and it divides cleanly by 2, 3, 4, 6, 8, 9 and 12, which is what makes it a mental tool.

    The relationship
    t=ln⁡2ln⁡(1+r)≈72100 r0.6931ln⁡1.08=9.006t = \frac{\ln 2}{\ln(1+r)} \approx \frac{72}{100\,r} \qquad \frac{0.6931}{\ln 1.08} = 9.006
    tyears for money to double
    rthe annual rate, as a decimal
    lnthe natural logarithm
    What it says in wordsThe exact doubling time is log 2 over log of one plus the rate, and 72 over the rate in per cent is a close, easy stand-in.
    Rule of 72 against the exact doubling time, in yearsAt 6% a yearrule is long by 38 days12.0011.90At 8% a yearrule is short by 2 days9.009.006At 12% a yearrule is short by 42 days6.006.12036912Years to doublerule of 72exact
    The rule of 72 gives 12, 9 and 6 years at 6%, 8% and 12%, against exact doubling times of 11.90, 9.006 and 6.12 years, so in the range fund returns occupy it is wrong by weeks at most.

    Where does the rule start to slip?

    At both ends, but slowly. At 6% it says 12 years and the truth is 11.90, so it is long by about 38 days. At 12% it says 6 years against 6.12, short by about 42 days. The rule is almost exact near 8% and drifts by a little over a month either side, which is far inside the uncertainty of any return assumption you would feed it. Only at high rates does the drift become worth mentioning: at 24% the rule says 3 years against an exact 3.22.

    Two uses in a fund interview. Turn a return into something a client can feel: at 8%, money doubles roughly every nine years, so it quadruples in about eighteen. And run a claim backwards to test it: a fund that says it tripled money in ten years has compounded at about 11.6% a year, because tripling is about 1.6 doublings, one every 6.3 years, and 72 over 6.3 is a little over 11.

    Where candidates lose it

    The common slip is dividing 100 by the rate, which gives 12.5 years at 8%. That is what simple interest would give, with no interest earned on interest, and it overstates the wait by about three and a half years.

    The quieter loss is presenting the rule as exact. Say 9 years, then add that the exact figure is 9.006, so the interviewer hears that you know what the shortcut is and where it stops working.

    What the interviewer asks next

    • How long does money take to triple at 8%?
    • Inflation runs at 6%. How long before Rs 1 lakh buys half what it buys today?
    • What number would you use in place of 72 for continuously compounded rates, and why?
  7. 083A fund charges 1.5% a year but has an active share of only 20%: the other 80% of the portfolio effectively is the index. If index exposure is worth 0.2% a year, what are you really paying for the active 20%?Costs and fee dragHardFund research and ratingsIndian AMCs

    Try it first

    What is the effective fee on the active slice?

    Show the worked solution

    About 6.7% a year for each rupee of genuine active management. The 80% that tracks the index is worth 0.2%, so it accounts for 0.8 x 0.2%, or 0.16 points, of the fee. The remaining 1.34 points pay for the 20% that differs from the index, and 1.34 divided by 0.20 is 6.7%. The active slice must beat the index by 6.7 points a year just to earn its fee.

    What is active share, and why does it change the price?

    Suppose a caterer charges a premium price per plate, but four of the five dishes are the same ones any local dhaba serves. You are paying the premium almost entirely for the fifth dish. Active shareThe share of a fund portfolio, by weight, that differs from its benchmark index. Zero means an exact copy of the index; 100% means no overlap at all. is the part of a fund's portfolio that differs from its benchmark; the rest is the index in disguise, and you could buy that part for an index fund's price. An active share of 20% means only a fifth of the money is doing anything the index would not.

    Most of the fee is paying for a small part of the portfolioThe portfolio, by what it does80% moves with the index20% activeThe 1.5% fee, split by what each part is worth0.161.34 points pay for the active 20%The index-like 80% of the money needs only 0.8 x 0.2% = 0.16 points of the feePrice per rupee of exposure, a yearIndex exposure0.2%The active slice1.34 / 0.20 = 6.7%A fund with 80% active share and the same 1.5% fee: about 1.8% per rupee of active management
    Priced at 0.2%, the index-like 80% of the portfolio accounts for only 0.16 points of the 1.5% fee, so the remaining 1.34 points pay for the 20% active slice, an effective 6.7% a year per rupee of active management.

    How do you split the fee between the two parts?

    Price each part at what it would cost on its own. The index-like 80% could be held through an index fund at 0.2%, so it deserves 0.8 x 0.2%, or 0.16 points of the fee. Everything left, 1.34 points, is the price of the active 20%, and expressed per rupee of active exposure that is 6.7% a year.

    The relationship
    factive=F−(1−AS) findexAS=1.5−0.8×0.20.2=6.7%f_{active} = \frac{F - (1 - AS)\,f_{index}}{AS} = \frac{1.5 - 0.8 \times 0.2}{0.2} = 6.7\%
    Fthe fund's total fee, 1.5%
    ASactive share, 20%
    f_{index}the price of index exposure, 0.2%
    f_{active}the effective price of each rupee of active management
    What it says in wordsTake the index part's fair cost out of the fee, then spread what is left over the active slice only.

    What would the active slice have to deliver?

    To merely match a cheap index fund after costs, the active 20% must beat the index by 6.7 points a year on its own money. Beating an index by that margin year after year is rare, which is why a high fee on a low active share is the first combination fund researchers flag. Compare a genuinely active fund with 80% active share charging the same 1.5%: its index part uses 0.04 points, and its active part costs about 1.8% per rupee. Same headline fee, well under a third of the effective price.

    Say the limitation too. Active share measures difference, not skill: a fund can be very different from its index and still lose. The point is narrower and firmer. A fund that is barely different from its index cannot justify an active fee, because most of what you pay for is available for a fraction of the price.

    Where candidates lose it

    Most candidates take 1.5% as the price, compare it with the index fund's 0.2%, and conclude the fund costs 1.3 points more. That understates the problem, because it spreads the extra cost over money that is not being actively managed at all.

    The second loss is reaching 6.7% and not saying what it means. Turn it into a hurdle: the active slice must beat the index by 6.7 points a year just to break even with the cheap alternative.

    What the interviewer asks next

    • At what active share would the effective active fee fall to 2%?
    • Why might a fund's active share drift down as its assets grow?
    • What else would you check before calling a fund a closet indexer?
  8. 084Two diversified funds each pick 50 stocks at random from the same universe of 100 stocks. How many stocks do you expect them to hold in common, and what does that suggest about a client who holds three large cap funds?Probability and expected valueHardIndian AMCsDistribution and sales

    Try it first

    How many stocks do you expect the two funds to share?

    Show the worked solution

    25 stocks, half of each fund, give or take about 2.5. Each of fund B's 50 picks has a 50 in 100 chance of being among fund A's, so the expected overlap is 50 x 0.5 = 25. Two funds fishing in the same pond share half their holdings by chance alone. With three such funds, about 12.5 stocks sit in all three, and together they hold only about 87.5 different names.

    Why is the overlap so large with no coordination?

    Two friends each order five dishes from a menu of ten without talking to each other. Each dish you pick has a 50% chance of being on your friend's list, so you expect to share about two and a half dishes. When each fund holds a large share of the same universe, overlap is not a coincidence to be explained; it is the default the arithmetic produces. The tool is linearity of expectation: go stock by stock, add up the chance that each one is in both funds, and the dependence between picks never needs to be modelled.

    The relationship
    E[shared]=N×kN×kN=100×0.5×0.5=25E[\text{shared}] = N \times \frac{k}{N} \times \frac{k}{N} = 100 \times 0.5 \times 0.5 = 25
    Nstocks in the universe, 100
    kstocks each fund holds, 50
    k/Nthe chance a given stock is in one fund
    What it says in wordsEach stock is in both funds with probability one half times one half, and there are 100 stocks, so expect 25 shared.
    Two funds, 50 random picks each from the same 100 stocksIn both funds25Fund A only25Fund B only25In neither25Expected shared stocks50 x 50/100= 25give or take 2.5Add a third such fundIn all three: 100 x 1/8 = 12.5 stocksDistinct names held: 87.5, from 150 holdingsOne random draw; the counts match the expected 25 in each group
    In one random draw of two 50-stock funds from 100 stocks, 25 stocks land in both, matching the expected 50 x 50/100, and a third such fund would leave only about 87.5 distinct names across 150 holdings.

    How firm is 25, and what changes with three funds?

    The count follows a hypergeometric distributionThe distribution of how many marked items you get when you draw a fixed number without replacement from a pool that holds a fixed number of marked items. with a standard deviation of about 2.5, so most random pairs share between 20 and 30 stocks. With three funds each holding half the universe, a stock is in all three with probability one in eight, about 12.5 stocks, and in none with probability one in eight too. Three such funds do not give three times the diversification: 150 holdings collapse to about 87.5 distinct stocks, and 50 of those are held by two or three of the funds at once.

    Real funds are not random, and the difference cuts one way. A large cap mandate points every manager at the same biggest companies, and benchmark weights pull portfolios further together, so real overlap between large cap funds tends to sit above this random baseline rather than below it. Use the random case as the floor: if two funds overlap much more than chance would give, the second fund adds little except a second fee.

    Where candidates lose it

    The instinct is that two independent managers should have little in common, so candidates guess 5 or 10. They forget that each fund covers half the universe, which makes sharing the norm, not the exception.

    The second loss is stopping at 25 without the portfolio point. The question is really about clients holding three or four funds from the same category who believe they are diversified; say what the overlap does to that belief, with the 87.5 distinct names as the number.

    What the interviewer asks next

    • If each fund picks only 20 of the 100 stocks, what overlap do you expect?
    • How would you measure overlap by portfolio weight rather than by count?
    • A client holds four large cap funds. What would you look at first?
  9. 085A fund's monthly returns have a standard deviation of 5%. What is that as an annual volatility, and is a month of minus 12% a rare event?Risk, volatility and drawdownWarm upRisk and complianceIndian AMCs

    Try it first

    What is the fund's annual volatility?

    Show the worked solution

    About 17.3% a year, and a minus 12% month is a 2.4 standard deviation event: rare, not freakish. Annual volatility is the monthly figure times the square root of 12: 5% x 3.46 is 17.3%. A minus 12% month is 12 divided by 5, or 2.4 monthly standard deviations. A normal curve puts that at about 0.8% of months, roughly once a decade, and real markets produce such months more often.

    Why does volatility scale with the square root of time?

    Take ten steps where each one goes left or right on a coin toss. You rarely end ten steps from where you began; lefts and rights cancel, and a typical distance is only about three steps, the square root of ten. Monthly returns behave the same way: good and bad months partly cancel, so variance adds up over time and the standard deviation grows only with the square root of the number of months. That is why the conversion uses the square root of 12, about 3.46, and not 12.

    The relationship
    σyear=σmonth12=5%×3.464=17.3%z=−12%5%=−2.4\sigma_{year} = \sigma_{month}\sqrt{12} = 5\% \times 3.464 = 17.3\% \qquad z = \frac{-12\%}{5\%} = -2.4
    \sigma_{month}the standard deviation of monthly returns, 5%
    \sqrt{12}the square root of the number of months in a year
    zhow many monthly standard deviations the fall is from an average month
    What it says in wordsScale volatility up by the square root of time, and measure a single month against the monthly figure, not the annual one.
    Monthly returns with a 5% standard deviation, and where minus 12% sits-15%-3 sd-10%-2 sd-5%-1 sd0%+5%+1 sd+10%+2 sd+15%+3 sdminus 12%= -12 / 5 = -2.4 sdShaded tail:0.82% of months, 1 in 122Annual volatility5% x the square root of 12= 17.3% a yearMonthly return
    With a monthly standard deviation of 5%, a minus 12% month lies 2.4 deviations below the centre, and the normal curve puts only 0.82% of months beyond it, about one in 122, while the same fund's annual volatility is 17.3%.

    So how rare is a minus 12% month?

    Measure it in monthly standard deviations. A minus 12% month is 2.4 monthly standard deviations below an average month taken as zero, which a normal curve puts at about 0.8% of months, roughly one in 122, or once a decade. If the fund's average month is plus 1%, the fall is 2.6 deviations and a normal curve makes it a little rarer, 0.47%. Against the 17.3% annual figure the fall sounds small, and that is the confusion to avoid: judge a month on a monthly scale.

    Now the limitation. Equity returns have fatter tails than the normal curve: large falls cluster in crises and turn up more often than the bell shape allows. Treat the normal figure as a floor on how often such a month arrives, not as a promise that it will be rare. For a client the useful sentence is plain: a fund with annual volatility near 17% will, from time to time, lose more than a tenth of its value in a single month.

    Where candidates lose it

    The first loss is scaling the wrong way. Multiplying by 12 gives 60%, which describes a far wilder fund than this one, and it comes from treating risk as if it added up like returns. Say variance adds, then take the square root.

    The second is judging the minus 12% month against the annual 17.3% and calling it ordinary. Put the move and the volatility on the same time scale before comparing them, and the month turns out to be a 2.4 deviation event.

    What the interviewer asks next

    • What is this fund's volatility over a single week?
    • The fund's worst month in ten years was minus 20%. What does that tell you about the normal assumption?
    • Why might reported annual volatility understate the risk of a bad month?
  10. 088Five funds, A to E, are ranked by one-year return with no ties. C beat A but trailed E. A was neither first nor last. B finished immediately behind A. B beat D. What is the order from first to last, and which of the clues did you not actually need?Logic and numeracy brainteasersHardIndian AMCsGlobal asset managers

    Try it first

    Which fund finished first?

    Show the worked solution

    E, C, A, B, D, and two of the clues were not needed. C beat A but trailed E gives E ahead of C ahead of A. B behind A extends the chain, and B beat D adds D at the end: one line of five, so the order is fixed. A being neither first nor last, and B being immediately rather than merely behind A, are both already true of that chain.

    Where do you start with a ranking puzzle?

    Seating guests at a dinner, you place the couple who must sit together before the guest who will sit anywhere. Start with the clues that relate two items directly, and join them into chains; a chain that runs through every item fixes the whole order at once. Here every 'beat' clue shares a fund with another clue: E over C, C over A, A over B, B over D. Each clue hands the next one a fund to hang on, so the chain builds without any guessing.

    Chain the 'beat' clues and the order falls outC beat A, trailed EECAB finished behind AECABB beat DECABDarrow = finished ahead ofPositionsE1stC2ndA3rdB4thD5thCheck: A is 3rd, neither first nor last. B is directly behind A. Both hold, and neither was needed.
    Joining the three ordering clues makes one chain of all five funds, E ahead of C ahead of A ahead of B ahead of D, so the positions are fixed before the clue about A's position or the word immediately is ever used.

    How do you know the order is the only one?

    Because the chain is complete. Every fund sits on one line of 'finished ahead of' links, so there is no fund whose position is free to move. When a chain touches all five items, uniqueness is proved, not hoped for. If any fund had hung off the chain, say D with only 'B beat D' and no other link, you would have had to test each place it could go. Checking uniqueness out loud is what separates a candidate who got lucky from one who reasoned.

    Why would an interviewer include clues you do not need?

    Two pieces of the puzzle are redundant. A being neither first nor last follows from A sitting third in the chain. And the word immediately adds nothing: B merely behind A is enough, because once E and C are ahead of A and D is behind B, there is no fund left that could sit between A and B. Spotting redundancy shows that you checked what each clue does rather than ticking them off. Interviewers also use extra clues to tempt you into starting from a weak one; A's 'neither first nor last' narrows A to three places, which feels like progress and fixes nothing.

    The fund-desk version of the same habit is reading a factsheet. A list of statements about a fund, its rank, its category, its risk grade, often contains claims that follow from each other, and the analyst's job is to find the few that carry information.

    Where candidates lose it

    The common loss is starting with 'A was neither first nor last', trying A in second, third and fourth place, and running a case for each. It works eventually, but it is slow and looks like guesswork, and under time pressure candidates drop a case and give a wrong order.

    The second loss is giving the right order without proving it is the only one. Say the chain touches all five funds, so nothing can move, then name the two clues you never used.

    What the interviewer asks next

    • Remove the clue that B beat D. How many orders are now possible?
    • Which single clue, if removed, would leave the order unchanged and still fully determined?
    • Six funds now, with F known only to have beaten C. Where can F go?
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