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Stochastic Calculus & Derivative Pricing Theory
1Probability Foundations
The Probability SpaceRandom VectorsSigma-AlgebraExpectationSample Space and EventsDensity and Distribution FunctionsRisk-Neutral ProbabilityState Price Density vs…
2Stochastic Processes and Jumps
Properties of a Stochastic ProcessMartingaleBrownian Motion and Its PropertiesBrownian Motion vs Geometric…Stopping TimeThe Markov PropertyState VariablesTransition ProbabilityQuadratic VariationQuadratic Variation vs Ordinary…Submartingale and SupermartingaleMartingale RepresentationMarkov Process vs MartingaleOptional StoppingFiltrationJump ProcessesThe Poisson ProcessLevy ProcessesJump Diffusion
3Ito Calculus
The Ito IntegralThe Ito Integral vs the Riemann IntegralInfinitesimals in Stochastic CalculusQuadratic CovariationIto's LemmaHow to Apply Ito's…The Infinitesimal GeneratorIto Calculus vs Ordinary Calculus
4Stochastic Differential Equations
Stochastic Differential EquationsStochastic Differential Equation vs…Drift and DiffusionStrong and Weak Solutions ComparedDiscretisationGeometric Brownian Motion
5Pricing Theory and No-Arbitrage
No-ArbitrageGirsanov, Radon-Nikodym and Change…Physical and Risk-Neutral Measures…The Fundamental Theorems of…The Law of One PriceThe Pricing KernelDiscount Factors and Zero-Coupon PricesReplication vs HedgingComplete Market vs Incomplete MarketClearing Margin Architecture
6Option Pricing Theory
European and American OptionsMonte Carlo European OptionThe Black-Scholes PDEBlack Scholes and the GreeksThe Payoff FunctionThe Binomial ModelBinomial Option PricingDelta Hedging in TheoryBoundary, Initial and Terminal ConditionsThe Exercise BoundaryHow to Check Put-Call…
7Volatility Models
Constant, Local and Stochastic…Vasicek Model vs CIR ModelThe Heston ModelThe SABR ModelThe Volatility ProcessImplied VolatilityVolatility Smile vs Skew vs Surface
8Interest Rate Models
Interest-Rate DerivativesMean ReversionThe Zero-Coupon BondThe Ornstein-Uhlenbeck ProcessThe Discount CurveZero RatesShort-Rate Model vs Market Model
9Numerical Pricing
Closed Form and Numerical…Monte Carlo PricingEuler and Milstein Schemes ComparedTree MethodsFinite Difference MethodsNumerical Error and StabilityVariance Reduction
10Calibration and Model Risk
Model OverrideMarket Price and Model PriceCalibrationHow to Document a Pricing ModelThe Educational Illustration LabelMarket ConventionsModel Uncertainty and LimitationsBacktesting a Pricing ModelIdentifiabilityCalibrated ParametersThe Calibration Loss Function

Brownian Motion vs Geometric Brownian Motion

Brownian motion moves by adding a random amount, so it can take any value including a negative one, and its level is normally distributed. Geometric Brownian motion moves by multiplying by a random factor, so it cannot reach zero from above, and it is the logarithm of its level that is normally distributed. Everything else separating the two follows from additive against proportional.

One of these two processes builds itself by adding the randomness to the level. The other builds itself by multiplying the level by it. The choice between adding and multiplying is the whole of the difference. Every other contrast between them, in what values they reach, in what shape their outcomes take, in what is normally distributed and in what each one is used for, is a consequence of that one choice rather than a separate fact to memorise.

The distinction is familiar from ordinary life without the names. A thermometer that reads two degrees high reads two degrees high at forty degrees and at minus five degrees alike: that error is additiveA change added to the level, so its size does not depend on the level.. A shop offering twenty per cent off takes Rs 200/- off a Rs 1,000/- item and Rs 20/- off a Rs 100/- one: that discount is proportionalA change applied as a multiple, so its size scales with the level.. The two behave differently everywhere, and the mathematics below is that same difference stated precisely and then followed to its consequences.

What is Brownian motion, defined from scratch?

Brownian motion is written W with a time subscript, and W at time zero is zero. Four statements fix it completely, and there is nothing else to it. The process starts at zero. Its path is continuous, so it has no gaps and no sudden jumps. Its incrementsThe change in a process from one time to a later one, taken as a quantity in its own right. over intervals that do not overlap are independent of one another, so the next move does not consult the last one. And the increment over an interval of any length is normally distributed with an average of zero and a variance equal to the length of that interval.

Read those four statements again and notice what is absent: not one of them mentions the level the process is currently sitting at. The size of the next move depends on how much time passes and on nothing else. A Brownian motion at plus fifty and a Brownian motion at minus fifty face exactly the same distribution of next moves. The absence of the level from all four statements is where everything in this guide comes from.

Brownian motion, the whole definition
$$ W_0 = 0, \qquad W_t - W_s \;\sim\; \mathcal{N}\bigl(0,\; t-s\bigr) \quad \text{for all } 0 \le s < t $$
\(W_t\)Brownian motion at time \(t\), under the physical measure \(\mathbb{P}\)
\(W_0\)the starting value, which is zero by definition and not by choice
\(t-s\)the length of the interval, in years
\(\mathcal{N}(0,\,t-s)\)the normal distribution with an average of zero and a variance equal to that length
\(\mathbb{P}\)the physical measure, the rule under which these averages are taken here
What it says in wordsBrownian motion starts at zero, and the change in it between any two times is a normally distributed quantity centred on zero whose variance is exactly the number of years that passed, with changes over separate stretches of time independent of one another.
Four statements fix it completely. There is nothing else to the definition. 1 It starts at zero not a choice, part of the definition of the standard version 2 Its path is continuous no gaps and no sudden jumps anywhere along it 3 Separate steps are independent the next move never consults the one before it 4 A step is normal, centred on nil its variance is the elapsed time, and nothing else enters Not one of the four mentions the level the process is currently at.
Brownian motion is fixed by four statements about its start, its continuity, its independence and its normal steps, and none of the four refers to the level it currently sits at.

Put numbers on it using the partition this subject works with throughout. The year is cut into twelve equal steps, so each step has a length of one twelfth of a year and the square root of that length is 0.288675. The driving valuesThe published numbers that generate the locked path, identical for both processes here. are the twelve published numbers minus 0.5, 1.6, minus 1.3, minus 0.1, 0.1, 1.5, minus 1.3, minus 0.5, minus 1.4, 0.4, 0.9 and 0.6, and each one is multiplied by 0.288675 to give that month's increment. The increments added up in sequence give the path.

Doing that gives readings of minus 0.144338, 0.317543, minus 0.057735, minus 0.086603, minus 0.057735, 0.375278, zero, minus 0.144338, minus 0.548483, minus 0.433013, minus 0.173205 and zero. The twelve driving values were constructed to sum to zero, so the path sits below zero at eight of its twelve monthly readings, touches zero exactly twice, and finishes the year at exactly zero. The twelve values are fixed rather than sampled afresh, and they are carried to six decimal places, so every path drawn in this subject rests on the same twelve numbers.

What is geometric Brownian motion, defined from scratch?

Geometric Brownian motionA process whose proportional changes are driven by Brownian motion. is written S with a time subscript. Its level at any time is its starting level multiplied by an exponential whose exponent has two pieces: a straight-line term in elapsed time, and the volatility multiplied by the Brownian motion at that time. Equivalently, and this is the version worth holding, the logarithm of the level is a Brownian motion with a straight-line trend added to it.

The standard process used throughout this subject is one of these. The process, an invented one, starts at Rs 100/- exactly, its drift is 8 per cent a year, its volatility is 20 per cent a year and the horizon is one year. Its variance rate, being the volatility squared, is 0.04 exactly, and half of that is 0.02 exactly.

Geometric Brownian motion, the whole definition
$$ S_t \;=\; S_0 \, \exp\!\Bigl[\,\bigl(\mu - \tfrac{1}{2}\sigma^{2}\bigr)t \;+\; \sigma W_t \,\Bigr] $$
\(S_t\)the standard process at time \(t\), in rupees
\(S_0\)the starting level, Rs 100/- exactly
\(\mu\)the drift, 8 per cent a year, decimal 0.08
\(\sigma\)the volatility, 20 per cent a year, decimal 0.20
\(\tfrac{1}{2}\sigma^{2}\)half the variance rate, 0.02 exactly, the correction sitting in the exponent
\(W_t\)the same Brownian motion defined in the block above
What it says in wordsThe level of the process at any time is its starting level multiplied by an exponential, and the exponent is the drift less half the variance rate multiplied by the elapsed time, plus the volatility multiplied by the Brownian motion at that time.

Two things about that exponent are worth pausing on. The first is that the whole Brownian motion sits inside an exponential, and an exponential of any real number is a positive number, so the level is a positive number multiplied by a positive number and can never be anything but positive. The second is the correction of half the variance rateThe gap between the growth of a process and the growth of its logarithm. subtracted from the drift. The growth of the logarithm carries a correction of half the variance rate. The derivation is the chain rule result for processes of this kind, covered separately later in this subject. Take the correction as given and watch what it does.

The definition also reads perfectly well as a recipe. The path starts at Rs 100/-. Each month, the exponent for that month is worked out and the level is multiplied by the resulting factor. Twelve repetitions give the path. The factors for the first three months of the locked path, computed from the same driving values, are 0.976415, 1.102275 and 0.932342.

Every step is a factor applied to whatever level the process has reached. Rs 100.00/- start times 0.976415 a fall of Rs 2.36/- Rs 97.64/- month 1 times 1.102275 a rise of Rs 9.99/- Rs 107.63/- month 2 times 0.932342 a fall of Rs 7.28/- Rs 100.35/- month 3 Three factors, three different rupee moves. The factor is the fixed thing; the rupee move is not. A positive level multiplied by a positive factor stays positive, whatever the factor is.
Each monthly step of the proportional process is a factor applied to the level already reached, so three factors produce three different rupee moves and the level stays positive throughout.
Try it out

Which of the two definitions never mentions the level the process is currently sitting at?

What single choice separates the two processes?

Set beside each other, the two definitions differ in one word. The first adds its random quantity to the level. The second multiplies the level by a factor built out of the same random quantity. Everything else in this guide is downstream of that.

Writing the two as one step on the twelve step partition makes the difference visible without any machinery at all. On the additive process the step is a quantity in the units of the process, subtracted or added regardless of where the process stands. On the proportional process the step is a ratio, and the level is multiplied by it.

One month of each, on the twelve step partition
$$ \underbrace{W_{k} - W_{k-1} \;=\; \sqrt{\Delta t}\;z_k}_{\text{added}} \qquad\qquad \underbrace{\frac{S_{k}}{S_{k-1}} \;=\; \exp\!\Bigl[\bigl(\mu-\tfrac{1}{2}\sigma^{2}\bigr)\Delta t + \sigma\sqrt{\Delta t}\,z_k\Bigr]}_{\text{multiplied}} $$
\(k\)the month, running from 1 to 12
\(\Delta t\)the length of one step, one twelfth of a year
\(\sqrt{\Delta t}\)0.288675, the number every driving value is multiplied by
\(z_k\)the driving value for month \(k\), from the twelve published numbers
\(\mu, \sigma\)the drift 0.08 and the volatility 0.20 of the standard process
What it says in wordsOn the left the month is a quantity added to the process, and on the right the month is a factor the process is multiplied by, and the same driving value feeds both of them.

The left hand side of the first expression is a difference and the left hand side of the second is a ratio, and that is the entire root of the comparison. A difference does not care what it is a difference from. A ratio only means anything relative to what it is applied to.

Four criteria. They differ on all four, and all four trace back to one choice. THE CRITERION BROWNIAN MOTION GEOMETRIC BROWNIAN How the change is applied Added to the level Multiplied into it What values it can reach Every number, either sign Only above zero What is normally distributed The level itself Its logarithm, not the level What it is commonly used for Quantities that can be negative Quantities that cannot Row one is the choice. Rows two, three and four are its consequences.
The two processes are set against four criteria and differ on every one, with the first row being the construction choice and the other three following from it.

The abstraction becomes concrete on the locked path, in the sharpest small illustration available. The driving value minus 1.3 appears twice, in month 3 and again in month 7. The additive process receives an identical step both times, to six decimal places. The proportional process receives an identical percentage step both times, also to six decimal places. But the rupee move differs. The process was standing at Rs 107.63/- the first time and at Rs 111.08/- the second.

The same driving value, minus 1.3, arriving at two different levels. MONTH 3 MONTH 7 Level it starts the month at Rs 107.63/- Rs 111.08/- Step of the additive process minus 0.375278 minus 0.375278 Step of the proportional process minus 6.7658 per cent minus 6.7658 per cent The same step, in rupees minus Rs 7.28/- minus Rs 7.52/- Three rows identical to six decimals. The fourth row differs by Rs 0.23/-, and that is proportionality. What is held fixed differs: a quantity for one process, a ratio for the other.
The same driving value gives the additive process an identical step both times and the proportional process an identical percentage but two different rupee moves.
Try it out

What single choice do all the differences between the two processes come from?

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What values can each of the two reach?

The additive process can reach any number at all. Give it enough time and there is no value, however far above or below zero, that it does not reach with certainty. Nothing in its definition refers to the level, so nothing in it places a floor or a ceiling anywhere.

The proportional process can reach any value strictly above zero and nothing else. The process cannot reach zero and cannot pass below it. The reason is arithmetic rather than deep: the level at any time is a positive starting value multiplied by an exponential, an exponential is always positive, and a positive number multiplied by a positive number is positive. No factor in the sequence is ever zero, so no sequence of steps reaches zero.

The proportional process does not reach zero and then stop there. Zero is not on the list of values it can reach at all. A level that can be reached and never left is called absorbingA level that, once reached, can never be left, which this process never reaches., and the proportional process does not have one. The level can become arbitrarily small. Zero itself stays out of reach.

Set it against two everyday measurements. A temperature reading can sit below zero perfectly sensibly, and a scale that reads two degrees high does so at every temperature: that is an additive quantity. The number of people waiting in a queue cannot be negative, and it cannot be halved indefinitely into a negative either: quantities that are counted or measured as a size behave more like the second process. Choosing a process means deciding which of those two a quantity is.

The set of values each process can reach, drawn on the same line. Brownian motion zero reachable reachable every value, either side Geometric Brownian motion zero, and it is not reachable never reached reachable, arbitrarily close to zero The open circle is the point of the picture: approached without limit, never arrived at.
The additive process reaches every value on the line while the proportional one reaches only values above zero, coming arbitrarily close to zero without ever arriving there.
Try it out

Why can the proportional process not reach zero from above?

Which of the two is normally distributed?

The question of which process is normally distributed is answered wrongly more often than any other in the comparison, and the wrong answer is not a slip of the tongue. The wrong answer changes the arithmetic downstream.

The additive process is normally distributed at every horizon, straight from its definition. The level at one year is the increment from time zero to one year, and that increment is normal with an average of zero and a variance of one, hence a standard deviation of exactly 1.000000.

The proportional process is not normally distributed at any horizon. The logarithm of its level is what is normally distributed. At the one year horizon that logarithm is normal with an average of 4.665170 and a standard deviation of 0.20 exactly. A quantity whose logarithm is normal is called lognormalThe distribution of a quantity whose logarithm is normal., and a lognormal shape is not a normal shape stretched a bit; it is a different shape with different properties.

What each process is distributed as, at the one year horizon
$$ W_T \;\sim\; \mathcal{N}\bigl(0,\;1\bigr) \qquad\qquad \ln S_T \;\sim\; \mathcal{N}\bigl(4.665170,\;0.20^{2}\bigr) $$
\(T\)the horizon, one year
\(W_T\)the additive process at the horizon, whose level is normal
\(\ln S_T\)the natural logarithm of the proportional process at the horizon
\(4.665170\)the logarithm of Rs 100/- plus 0.06, the drift less half the variance rate
\(0.20\)the standard deviation of that logarithm, being the volatility times the square root of the horizon
What it says in wordsAt the horizon the level of the additive process is normally distributed with an average of nil and a standard deviation of one, while for the proportional process it is the logarithm of the level that is normally distributed, with an average of 4.665170 and a standard deviation of 0.20.

The difference between the two shapes is not cosmetic. One is symmetricA shape whose two sides are mirror images, which the normal is and the lognormal is not.. Its two sides are mirror images, and its average, its middle outcome and its most likely outcome are one and the same number. The other leans right, stops dead at zero on the left, and has an average, a middle outcome and a most likely outcome that are three different numbers.

Two shapes at the same horizon. Only one of them is symmetric. The additive process at one year nil average, middle and peak all here the left side and the right side are mirror images of each other The proportional process at one year Rs 0/- the shape stops dead here and trails away to the right with no limit on that side average, middle and peak are three different numbers
At the horizon the additive process is symmetric about nil while the proportional one leans right with a hard floor at zero, so their two sides behave differently.

Saying only that the shape leans right gives nothing to check, so the three numbers are worth naming. The most likely outcome is Rs 102.02/-, the middle outcome is Rs 106.18/- and the average is Rs 108.33/-. The three run in that order, and the order is a property of the shape rather than a coincidence of these parameters.

Three answers to the question where is the middle, and they are three different numbers. Rs 96/- Rs 100/- Rs 104/- Rs 108/- Rs 112/- Rs 116/- Rs 102.02/- most likely outcome Rs 106.18/- middle outcome Rs 108.33/- average outcome Rs 4.16/- Rs 2.15/-
The most likely, the middle and the average outcomes of the proportional process are Rs 102.02/-, Rs 106.18/- and Rs 108.33/-, three separate numbers on one scale.

For a symmetric shape those three markers would sit on top of one another, and here they are spread across Rs 6.31/- of the scale. The gap between the middle outcome and the average is Rs 2.15/- exactly, and that gap is the half variance rate correction made visible: Rs 100/- grown at the drift of 8 per cent gives Rs 108.33/-, and Rs 100/- grown at the drift less half the variance rate, which is 6 per cent, gives Rs 106.18/-.

Try it out

Which of the two is normally distributed at the horizon: the level of the additive process, or the level of the proportional one?

Try it out

The additive path goes below zero at eight of its twelve readings. How many of the proportional path's readings go below zero?

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Why do the same twelve driving values produce two different shapes?

Here is the claim this guide exists to make. Both paths drawn here come from one set of twelve numbers. Not two sets, not two samples, not two runs of anything. The identical twelve driving values are fed into both constructions, and what comes out looks nothing alike.

The shared randomness can be checked by looking at where each path turns. The additive path turns upward or downward in months 2, 4, 6 and 9. A turn happens when the driving value changes sign, and both processes see the same driving values, so the proportional path turns at exactly the same four months. The turning points are shared. Everything else is not.

One set of twelve driving values. Two constructions. Two shapes. ADDED: BROWNIAN MOTION 0 ends at 0.000000 eight of the twelve readings sit below the line and the line itself is not a floor MULTIPLIED: GEOMETRIC BROWNIAN MOTION 100 ends at Rs 106.18/- the low is Rs 93.74/- and zero is far below the bottom of this panel month 2 month 4 month 6 month 9 Both paths turn at the same four months, because both read the same driving values.
The same twelve driving values produce a path that spends most of the year below zero and a path that never approaches zero, and both turn at the same four months.

The randomness feeding those two pictures is not merely similar but identical, so every difference between them belongs to the construction. Choosing between these two processes is not choosing between two kinds of randomness. The choice is what is done with one kind.

Try it out

The twelve driving values sum to exactly zero. Before the control below is moved: where does the proportional process finish?

Play with it

Turn the volatility up and watch one set of numbers make two shapes

Both paths below are built from the same twelve driving values at every setting. Move the volatility and both redraw. At the locked 20 per cent the additive path finishes at 0.000000 and the proportional path finishes at Rs 106.18/-, the two published figures. At 40 per cent half of 0.16 is exactly the drift of 0.08, the two cancel, and the proportional path finishes at exactly Rs 100.0000/-. Tap a month to place a reading marker on both paths.

ADDED: THE ADDITIVE PATH 0 0.000000 MULTIPLIED: THE PROPORTIONAL PATH 100 Rs 106.18/- today one year volatility 20 per cent
Reading marker
Volatility
20 per cent
Additive finish
0.000000
Proportional finish
Rs 106.1837/-
At a volatility of 20 per cent the additive path finishes at 0.000000 and the proportional path finishes at Rs 106.1837/-, and at month 12 they read 0.000000 and Rs 106.1837/-.
Educational illustration. Both paths are computed from the same twelve published driving values and never sampled, so the default reproduces the worked example exactly on every reload. The additive path is the published Brownian path scaled by the volatility setting divided by 20 per cent, so at the default it is exactly the published path. The proportional path uses a drift of 8 per cent a year over a one year horizon.
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Where does the growth come from when the randomness cancels?

The twelve driving values were constructed to sum to exactly zero. The additive path therefore returns to exactly where it started. The proportional path, fed the same twelve values, finishes at Rs 106.18/-. So the randomness contributed nothing over the year, and the process still gained Rs 6.18/-. Where did that come from?

From the straight-line term in the exponent, and nowhere else. With the Brownian motion at zero at the horizon, the exponent is the drift less half the variance rate multiplied by one year. The arithmetic is 0.08 less 0.02, giving 0.06 exactly. Rs 100/- multiplied by the exponential of 0.06 is Rs 106.1837/-, the published finishing value to four decimal places.

The randomness gave nothing over the year. The process still moved. Rs 100/- Rs 106.18/- Rs 108.33/- randomness exactly nil the twelve values summed to zero growth of Rs 6.18/- 6 per cent, from the exponent alone Rs 2.15/- the middle outcome sits below the average Rs 100/- times the exponential of 0.06 is Rs 106.1837/-. Times the exponential of 0.08 it is Rs 108.3287/-.
The twelve driving values summed to zero and the proportional process still finished at Rs 106.18/-, because six per cent of growth sits in the process independently of the randomness.

Here are both paths month by month, from the same twelve driving values. The two number columns, read against each other, hold the whole comparison.

MonthDriving valueAdditive pathProportional path
Startnil0.000000Rs 100.00/-
1minus 0.5minus 0.144338Rs 97.64/-
21.60.317543Rs 107.63/-
3minus 1.3minus 0.057735Rs 100.35/-
4minus 0.1minus 0.086603Rs 100.27/-
50.1minus 0.057735Rs 101.35/-
61.50.375278Rs 111.08/-
7minus 1.30.000000Rs 103.56/-
8minus 0.5minus 0.144338Rs 101.12/-
9minus 1.4minus 0.548483Rs 93.74/-
100.4minus 0.433013Rs 96.41/-
110.9minus 0.173205Rs 102.06/-
120.60.000000Rs 106.18/-
The average and the middle outcome, and the gap between them
$$ \mathbb{E}[S_T] = S_0 e^{\mu T} = \text{Rs }108.33/\text{-} \qquad \text{median}(S_T) = S_0 e^{(\mu-\frac{1}{2}\sigma^{2})T} = \text{Rs }106.18/\text{-} $$
\(\mathbb{E}[S_T]\)the average of the level at the horizon, over every possible path
\(\text{median}\)the middle outcome, with half the outcomes above and half below
\(\mu T\)0.08, the drift over one year
\((\mu-\tfrac{1}{2}\sigma^{2})T\)0.06 exactly, the drift less half the variance rate over one year
What it says in wordsThe average level at the horizon is the starting level grown at the drift, while the middle outcome is the starting level grown at the drift less half the variance rate, and the whole gap of Rs 2.15/- between them is that half variance rate correction.

The error that gets made, and what it costs

Saying that geometric Brownian motion is normally distributed. The logarithm is the normal one, and the difference is not pedantic bookkeeping. A normal shape is symmetric, this one is not, and every number taken off the shape changes accordingly.

Consider what happens if somebody builds a range the symmetric way. The average at the horizon is Rs 108.33/- and the standard deviation of the level is Rs 21.88/-. The average plus and minus 1.959964 standard deviations, the usual construction for a central 95 per cent range, gives Rs 65.44/- to Rs 151.22/-. The true central 95 per cent range for this process is Rs 71.75/- to Rs 157.14/-.

So the symmetric range reaches Rs 6.31/- too far down and stops Rs 5.92/- short at the top. The range is wrong on both sides at once, and no arithmetic step anywhere in the calculation was performed incorrectly. Go further out and it gets worse rather than better: at the one in a thousand mark the symmetric construction stops at Rs 175.96/- where the true shape reaches Rs 197.00/-.

The symmetric shape also carries on below zero. The process cannot go there. At this volatility that misplaced weight is about four parts in ten million, small enough to shrug at. Raise the volatility to 40 per cent a year and the same construction puts 0.82 per cent of its weight on levels the process is unable to reach. The cost is a range that is quietly wrong in both directions, produced by a calculation that looks entirely clean.

Two central 95 per cent ranges for the same process, on one scale. Rs 0/- Rs 50/- Rs 100/- Rs 150/- Rs 200/- THE TRUE RANGE Rs 71.75/- Rs 157.14/- BUILT AS IF SYMMETRIC Rs 65.44/- Rs 151.22/- too far down by Rs 6.31/- short by Rs 5.92/- Wrong below and wrong above at the same time, from arithmetic with no incorrect step in it.
A range built as though the level were symmetric reaches Rs 6.31/- too far down and stops Rs 5.92/- short at the top, so it is wrong in both directions at once.
Try it out

A symmetric range is built around the average of Rs 108.33/-. Name what it gets wrong.

The driving values summed to zero and the path gained. See where growth arrived.

Which of the two should be reached for?

One question settles it in almost every case, and it is not a question about mathematics at all. The question is whether the quantity being modelled can sensibly take a negative value.

If it can, the additive process fits, and its ability to go below zero is a feature rather than a defect to be worked around. If it cannot, the proportional process fits. A floor at zero is built into it rather than bolted on afterwards. Prices are commonly modelled with the proportional process for exactly that reason. A process is a model and never a description, so commonly modelled with is not the same as what prices do.

One question, asked before any mathematics, settles the choice. Can the quantity sensibly be negative? YES NO Brownian motion the additive construction going below zero is wanted here Geometric Brownian motion the proportional construction the floor at zero comes built in The choice is made on what the quantity is, not on which mathematics looks nicer.
Whether the quantity can sensibly be negative is the question that decides between the additive and the proportional process in almost every case.

The additive process is not a poor relation left over once the proportional one has taken the interesting work. There is a whole later part of this subject built on quantities where going below zero is exactly what the model has to be able to do, and forcing such a quantity through a construction with a floor at zero would be the error rather than the fix. The two processes are tools for two different jobs, and neither is more advanced than the other.

Try it out

A quantity being modelled can sensibly be negative. Which process fits?

How does somebody reviewing a model use this distinction?

Using any of this requires no rebuilding of anybody's model. Two checks, both cheap, catch most of what goes wrong with these two processes in practice, and both can be run on a printed sheet of output with nothing else to hand.

  1. Ask what the quoted range is symmetric about Find any range or interval in the output and see whether the number in the middle is exactly halfway between the two ends. If it is, and the quantity has a floor at zero, the range was almost certainly built the symmetric way.
    On the standard process the symmetric build reaches Rs 6.31/- too far down and stops Rs 5.92/- short at the top.
  2. Ask whether the average or the middle outcome is being quoted For a symmetric shape the question is empty because they are the same number. For the proportional process they are Rs 108.33/- and Rs 106.18/-, and which of the two is meant changes the answer by Rs 2.15/- before anything else is discussed.
    A document that says the expected level without saying which of the two it means has left a Rs 2.15/- ambiguity unresolved.

Both checks ask one question twice: has the person treated a shape that leans right as though it were symmetric? The question is worth carrying away even if every formula here fades. It catches the error long after the arithmetic has been forgotten.

There is a household version of the second check that makes it stick. Told that a shop's prices fell by 50 per cent and then rose by 50 per cent, most people will say the price is back where it started. The price is not back where it started: Rs 100/- falls to Rs 50/- and rises to Rs 75/-. Proportional changes do not add up the way additive ones do, the average of the moves is not the move of the average, and the whole of the half variance rate correction lives in that gap. Anybody who has been caught by the 50 per cent example has already met the idea this guide is about.

Why the growth of the logarithm carries a correction of half the variance rate is the chain rule result for processes of this kind, covered separately later in this subject. Fitting either process to observations is covered separately. The equation either process obeys is covered separately. Processes that jump are covered separately. What any contract pays is a separate subject. No jurisdiction sets the definition of either process, and no rule, threshold or period is engaged by any of it: the mathematics is the same everywhere.
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References

SourceDocumentWhere
arXiv Quantitative FinancePreprint repository for work on diffusion processes and their distributionsarxiv.org
Social Science Research NetworkWorking paper repository for the same materialssrn.com
Hull, Shreve and WilmottStandard texts on stochastic calculus for finance, for notation and orderingin print

The standard process, its four parameters and the twelve driving values are invented.
Educational material. Not advice on any investment, tax, budget or market position.

Comparison

Other comparisons in Stochastic Processes and Jumps

Comparison

Quadratic Variation vs Ordinary Variation

Comparison

Markov Process vs Martingale: Two Different Promises

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