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Stochastic Calculus & Derivative Pricing Theory
1Probability Foundations
The Probability SpaceRandom VectorsSigma-AlgebraExpectationSample Space and EventsDensity and Distribution FunctionsRisk-Neutral ProbabilityState Price Density vs…
2Stochastic Processes and Jumps
Properties of a Stochastic ProcessMartingaleBrownian Motion and Its PropertiesBrownian Motion vs Geometric…Stopping TimeThe Markov PropertyState VariablesTransition ProbabilityQuadratic VariationQuadratic Variation vs Ordinary…Submartingale and SupermartingaleMartingale RepresentationMarkov Process vs MartingaleOptional StoppingFiltrationJump ProcessesThe Poisson ProcessLevy ProcessesJump Diffusion
3Ito Calculus
The Ito IntegralThe Ito Integral vs the Riemann IntegralInfinitesimals in Stochastic CalculusQuadratic CovariationIto's LemmaHow to Apply Ito's…The Infinitesimal GeneratorIto Calculus vs Ordinary Calculus
4Stochastic Differential Equations
Stochastic Differential EquationsStochastic Differential Equation vs…Drift and DiffusionStrong and Weak Solutions ComparedDiscretisationGeometric Brownian Motion
5Pricing Theory and No-Arbitrage
No-ArbitrageGirsanov, Radon-Nikodym and Change…Physical and Risk-Neutral Measures…The Fundamental Theorems of…The Law of One PriceThe Pricing KernelDiscount Factors and Zero-Coupon PricesReplication vs HedgingComplete Market vs Incomplete MarketClearing Margin Architecture
6Option Pricing Theory
European and American OptionsMonte Carlo European OptionThe Black-Scholes PDEBlack Scholes and the GreeksThe Payoff FunctionThe Binomial ModelBinomial Option PricingDelta Hedging in TheoryBoundary, Initial and Terminal ConditionsThe Exercise BoundaryHow to Check Put-Call…
7Volatility Models
Constant, Local and Stochastic…Vasicek Model vs CIR ModelThe Heston ModelThe SABR ModelThe Volatility ProcessImplied VolatilityVolatility Smile vs Skew vs Surface
8Interest Rate Models
Interest-Rate DerivativesMean ReversionThe Zero-Coupon BondThe Ornstein-Uhlenbeck ProcessThe Discount CurveZero RatesShort-Rate Model vs Market Model
9Numerical Pricing
Closed Form and Numerical…Monte Carlo PricingEuler and Milstein Schemes ComparedTree MethodsFinite Difference MethodsNumerical Error and StabilityVariance Reduction
10Calibration and Model Risk
Model OverrideMarket Price and Model PriceCalibrationHow to Document a Pricing ModelThe Educational Illustration LabelMarket ConventionsModel Uncertainty and LimitationsBacktesting a Pricing ModelIdentifiabilityCalibrated ParametersThe Calibration Loss Function

Levy Processes: The General Class Behind Every Jump Model

A Levy process is any process starting at zero with independent increments whose distribution depends only on the length of the stretch, and with paths that have no worse than jump discontinuities. The list is that short, and it is the whole definition. Every such process splits into exactly three parts: a steady drift, a continuous random part and a jump part.

Several processes have now been met one at a time, each with its own specification and its own picture. A definition short enough to memorise in a minute covers all of them, and a result then says that anything satisfying it is built from exactly three ingredients and nothing else. The definition is easy. The prize is the completeness of the result that follows from it: three slots, and no fourth slot exists. An unfamiliar process can then be taken up, three questions asked of it, and every part of its behaviour traced to its source.

What defines a Levy process, and how short is the list?

The shape of the definition is the surprise before any of its content is. Start there. The general description of processes that jump might reasonably be expected to be long and technical, full of conditions guarding against pathologies. The description is four lines. Three of those four lines appear word for word in the specification of Brownian motion. Only the fourth is different, and it is different by being weaker rather than stronger.

Line one says the process starts at zero. Starting at zero is bookkeeping and costs nothing. Any process can be shifted so it starts there, and the movement is what is being described rather than the starting level. Line two says that the change over one stretch of time carries no news about the change over a separate stretch. Line three says the distribution of an incrementThe change in a process between two times, being the value at the later time less the value at the earlier one. depends on the length of the stretch and on nothing else, so a one month change looks the same in January as in September. Line four is where everything that follows lives.

Brownian motion answers line four with never jumps. The general class answers it with jumps are allowed, but nothing worse than a jump is. Worse than a jump sounds like a joke. It is not, and the phrase needs unpacking. A path is required to be right continuous with left limitsAt any instant the path takes the value it is about to hold going forward, and the value it held an instant earlier always exists. A break is therefore a clean step with a definite value either side., which means two things in plain terms. At any instant the path has already taken its new value, and an instant before the break there was a definite old value. So a break is a clean step from one number to another number. Two kinds of path are forbidden: one that oscillates infinitely fast near a moment, and one that has no value approaching a moment from the left. For either, there is no saying what jumped to what.

One requirement removed. Everything else survives word for word. BROWNIAN MOTION, ALREADY MET THE GENERAL CLASS TREATED HERE 1. Starts at zero the level at time zero is nil and not random 1 Starts at zero identical, and it costs nothing to require 2. Independent increments one change says nothing about another 2 Independent increments identical, carried over unchanged 3. Depends on length alone and is normal, with variance equal to the length 3 Depends on length alone but the shape is no longer required to be normal 4. The path never jumps this is the line that gets struck out 4 Nothing worse than a jump a clean step with a definite value either side Lines one to three are carried over unchanged. Only line four is loosened. Loosening one line admits every jump process. It does not admit anything beyond them.
Three of the four specification lines are shared word for word with Brownian motion, and only the fourth changes, from a path that never jumps to a path allowed clean steps with a definite value on either side.

The everyday version comes from measuring rather than from anything financial. Consider pacing out a long wall with a metre rule, laying it end to end and writing down the running total. Every laying is the same operation, and the distribution of what gets added is the same each time. Line three holds. No laying is influenced by the last one. Line two holds. The tally started at nothing. Line one holds. And the running total either creeps up smoothly or steps by a whole rule length; what it never does is become undefined halfway along. The refusal to become undefined is line four, and stating it explicitly is what stops the mathematics from having to handle objects nobody wants.

The definition, all four lines
$$\begin{aligned} &\text{(i)}\quad X_{0}=0\\[2pt] &\text{(ii)}\quad X_{t_2}-X_{t_1}\ \text{and}\ X_{t_4}-X_{t_3}\ \text{are independent whenever } t_1\le t_2\le t_3\le t_4\\[2pt] &\text{(iii)}\quad X_{t+h}-X_{t}\ \stackrel{d}{=}\ X_{h}\quad\text{for every } t\ge 0\ \text{and every } h>0\\[2pt] &\text{(iv)}\quad t\mapsto X_{t}\ \text{is right continuous and has a left limit at every instant} \end{aligned}$$
\(X_{t}\)the value of a general process at time \(t\). The letter \(X\) is used here rather than \(S\) because the statement is about any process in the class and not about the standard process in particular
\(t_1,\dots,t_4\)four times in order, marking out two stretches of time that do not overlap
\(h\)the length of a stretch of time, measured in years throughout this guide
\(\stackrel{d}{=}\)read as has the same distribution as. It does not say the two quantities are equal, only that they follow the same law
\(t\mapsto X_{t}\)the path, meaning the whole record of values through time rather than any single value
What it says in wordsThe process begins at nothing. What it does over one stretch of time carries no information about what it does over a separate stretch. The distribution of a change depends only on how long the stretch was and not on when the stretch happened. And the path is allowed to break, provided each break is a clean step with a definite value an instant before and an instant after.

Notice one omission. The definition never names a distribution. Brownian motion pins its increments to the normal law; the definition here leaves the shape of the increment open and constrains only how increments relate to one another and to the clock. The refusal to name a shape is exactly why the class is large. The definition constrains the relationships between increments and says almost nothing about any single increment. Such generality is what makes it worth setting out on its own.

Try it out

Which of Brownian motion's four defining properties is dropped to get this class?

What three parts does every one of them split into?

Here is the result the class exists for, and it carries the names of Levy and Ito. Take any process satisfying those four lines. The process can be written as the sum of a straight line, a scaled Brownian motion and a jump part, and those three are all there is. Not usually. Not for the well behaved cases. For every process in the class, without exception and without further conditions.

The first part is the driftThe steady, non-random part of the movement. The drift advances by the same amount in every stretch of equal length., and it draws a straight line advancing at a constant rate. The drift has no randomness in it at all: over any stretch of a month it contributes exactly one twelfth of its annual rate, every month, forever. The second part is a Brownian motion multiplied by a constant, and it supplies the continuous randomness. Its size is quoted as a variance rateThe variance the continuous part contributes over one year. Its square root is the volatility, so a variance rate of 0.04 a year corresponds to a volatility of 0.20 a year., the amount of variance it contributes per year. The third part collects the jumps, described by how often they arrive and by how large they are when they do.

Because the three are exactly determined by three pieces of information, a process in the class is completely described by a rate, a variance rate and a jump specification. The three quantities together are called the characteristic tripletThe three pieces of information that pin down a process in this class completely: the drift rate, the variance rate of the continuous part, and the specification of the jumps., and once the triplet has been written down there is nothing further to say about the process. Two processes with the same triplet are the same process. The decomposition is a complete inventory rather than a convenient framing, and that completeness is the entire content of the result.

Three parts, and the result is that there is no fourth one to look for. ANY PROCESS SATISFYING THE FOUR LINES PART ONE, THE DRIFT a straight line, no randomness at all + PART TWO, THE CONTINUOUS Brownian motion, scaled, never breaks + PART THREE, JUMPS how often, and how large PART FOUR DOES NOT EXIST Nothing else can be present. That is the content of the result, not a simplification of it. Write down a rate, a variance rate and a jump specification and the process is fully described. Two processes carrying the same three pieces of information are the same process. Educational illustration. The paths sketched inside the boxes are indicative shapes, not measurements.
Drift, continuous randomness and jumps are the whole of any process in the class, and the crossed dashed box records that the result forbids a fourth ingredient rather than merely failing to mention one.

One practical caveat belongs here rather than later. Where arrivals come at a finite rate, meaning only finitely many of them in any year, the jump part can be written as a plain running sum of the sizes that have arrived. Every process in this guide has an intensity quotable as a number of arrivals a year, and every one of them is therefore of that kind. Where a process is allowed infinitely many tiny jumps in any stretch, the jump part still exists but has to be written with a correcting term so the sum stays finite. The correcting term changes the bookkeeping and changes nothing about the count of three.

The decomposition, and the three pieces that pin it down
$$X_{t}\;=\;\underbrace{b\,t}_{\text{drift}}\;+\;\underbrace{\sigma W_{t}}_{\text{continuous}}\;+\;\underbrace{\sum_{k=1}^{N^{J}_{t}} Y_{k}}_{\text{jumps}}$$ $$\text{triplet}\;=\;\bigl(b,\ \sigma^{2},\ \text{the jump specification}\bigr)$$
\(X_{t}\)the value at time \(t\) of a general process in the class
\(b\)the drift rate, in units of the process per year. The drift part advances by \(b\) over a year and by \(b/12\) over a month, always
\(\sigma\)the scale of the continuous part, so \(\sigma^{2}\) is the variance it contributes per year
\(W_{t}\)standard Brownian motion under the physical measure \(\mathbb{P}\), already met and not re-specified here
\(N^{J}_{t}\)the number of arrivals by time \(t\), written with the superscript \(J\) so it is never confused with the standard normal distribution function \(N\)
\(Y_{k}\)the size of the \(k\)th arrival, drawn from whatever size specification the process carries
What it says in wordsAny process in the class is a straight line plus a scaled Brownian motion plus a running total of the jump sizes that have arrived so far. Writing down the drift rate, the variance rate of the continuous part and the specification of the jumps describes the process completely, and there is no fourth quantity left to record.
Try it out

How many components does the decomposition allow?

Which of the processes already met sit inside the class?

Abstraction earns its keep only when it places things already known. So the four processes running through this reading order each have their three slots filled in, one at a time. All four numbers below belong to the standard process and are fixed in advance rather than observed. Every reading is therefore reproducible.

Brownian motion first. Standard Brownian motion has no steady advance. Its drift rate is zero. Its continuous part has a variance rate of 1.0 a year. Standard means exactly that: over one year the variance of the change is one. Its jump slot is empty. One slot filled out of three, and it is the simplest member of the class precisely because the other two boxes are blank.

The standard process in logarithms next, and this is the row worth checking by hand. The standard process has a drift of 8 per cent a year and a volatility of 20 per cent a year, both invented and fixed. Its logarithm advances at the drift less half the variance rate: 0.08 less 0.02, giving 0.06 a year exactly. Its continuous part carries the variance rate 0.04, being 0.20 squared. Its jump slot is empty. Two slots filled.

The counting process at an intensityThe average number of arrivals per unit of time, quoted here as arrivals per year. The intensity is the only freedom a counting process has. of 0.5 arrivals a year is the mirror image of Brownian motion. Its drift rate is zero, its continuous variance rate is zero, and its jump slot alone is filled, with arrivals at 0.5 a year and every arrival of size exactly one. Between arrivals it does not move at all; when it moves it only jumps. One slot filled, and a different one.

The jump diffusion that closes this reading order fills all three. Drift 0.06 a year, continuous variance rate 0.04 a year, and arrivals at 0.5 a year whose proportional size has a logarithm averaging minus 0.05 with a standard deviation of 0.10, so a typical arrival moves the level downward. The jump diffusion carries the name of Merton, 1976, in the literature.

ProcessDrift rate a yearContinuous variance rate a yearJump part
Brownian motion01.00none
The standard process in logarithms0.060.04none
The counting process000.5 a year, size exactly 1
The jump diffusion0.060.040.5 a year, log size averaging minus 0.05
Slots available in every row111

Read that table across and the general class stops being abstract. Four processes that look nothing like each other on paper turn out to be four different fillings of the same three boxes, and nothing in any row required a box the other rows did not have. Read down instead and a second reading appears: the drift column holds two zeros and two sixes, the continuous column holds a one, a zero and two identical variance rates, and the jump column holds two blanks and two intensities that agree.

Four processes, three slots, and every cell is either filled or deliberately empty. DRIFT SLOT CONTINUOUS SLOT JUMP SLOT Brownian motion empty 1.00 empty Standard process in logs 0.06 0.04 empty Counting process empty empty 0.5 a year Jump diffusion 0.06 0.04 0.5 a year Every column holds at least one filled cell and at least one empty one. So no slot is quietly standing in for another, and no row needed a box the other rows did not have. Educational illustration. Every parameter shown is invented and fixed in advance.
Brownian motion has only the continuous slot, the counting process has only the jump slot, the standard process in logarithms has drift and continuous randomness, and the jump diffusion has all three filled at once.
The standard process in logarithms, placed in the class
$$\log\frac{S_{t}}{S_{0}}=\Bigl(\mu-\tfrac{1}{2}\sigma^{2}\Bigr)t+\sigma W_{t}=0.06\,t+0.20\,W_{t}$$ $$b=0.06,\qquad \sigma^{2}=0.04,\qquad \lambda=0$$
\(S_{t}\)the level of the standard process at time \(t\), an invented traded quantity starting at Rs 100/-
\(\mu\)the drift of the standard process under the physical measure \(\mathbb{P}\), an invented 0.08 a year
\(\sigma\)the volatility, an invented 0.20 a year, whose square is the variance rate 0.04
\(b\)the drift rate of the logarithm, being 0.08 less 0.02, which is 0.06 a year exactly
\(\lambda\)the arrival intensity, which is nil here because this process has no jump part at all
\(W_{t}\)standard Brownian motion, the continuous ingredient the second slot is built from
What it says in wordsTaking logarithms turns the standard process into a straight line plus a scaled Brownian motion. The straight line advances at 0.06 a year, which is the drift of 0.08 reduced by half the variance rate of 0.04. The scaled Brownian motion contributes a variance of 0.04 a year. There is no third ingredient, so the jump slot is empty and the process is a member of the class with two of its three boxes filled.

Placing an unfamiliar process is therefore a three question routine rather than an act of judgement. Does it advance by a fixed amount in every stretch of equal length, whatever the randomness does. Does it wobble continuously between its breaks. Does it break at all. Three answers, three slots, and the process is placed.

Three questions, asked in any order, and the process is placed. 1 Does it advance by a fixed amount in every stretch of equal length? YES, DRIFT SLOT write the rate NO leave it empty 2 Does it wobble continuously in between any breaks? YES, CONTINUOUS write the variance NO leave it empty 3 Does the path break at all, and how often and how large? YES, JUMP SLOT write both NO leave it empty THREE ANSWERS GIVE THE WHOLE PROCESS There is no fourth question, because the decomposition says there is no fourth part to ask about. A process may answer no to two of the three and still be a perfectly good member of the class. Educational illustration.
Placing a process is a three question routine, one question per slot, and answering no to two of the three still leaves a perfectly ordinary member of the class such as Brownian motion or a counting process.
Try it out

The counting process at an intensity of 0.5. Which slots are filled?

Try it out

Four different processes, three component slots. Before the switch below: how many slots does Brownian motion fill?

Play with it

Switch the process and watch the same three slots fill and empty

One control, four processes. The three slots stay exactly where they are and only their contents change. The path below redraws in three layers, one for each slot's contribution to the movement. The grey line is the drift alone, the pine line adds the continuous part, and the red line adds the jumps.

THE SAME THREE SLOTS, WHICHEVER PROCESS IS SELECTED SLOT ONE, DRIFT RATE 0.06 a year, in logarithm units SLOT TWO, VARIANCE RATE 0.04 a year, so volatility 0.20 SLOT THREE, JUMPS empty this process never breaks THE STANDARD PROCESS IN LOGARITHMS vertical axis: change in the logarithm since the start 0.14 0.02 -0.10 0 6 12 months of the one year horizon drift only drift plus the continuous part jumps added, drawn only when the third slot is filled
Process selected
Standard process in logs
Drift rate
0.06
Variance rate
0.04
Slots filled
2 of 3
The standard process in logarithms fills two of the three slots, a drift rate of 0.06 a year and a continuous variance rate of 0.04 a year, and leaves the jump slot empty, so the pine line and the grey line separate but neither of them ever breaks.
Educational illustration. Every reading is computed from the locked parameters rather than sampled, so the default reproduces the worked instance above exactly on every reload. Brownian motion: drift 0, variance rate 1.00, no jumps. The standard process in logarithms: drift 0.06, variance rate 0.04, no jumps. The counting process: drift 0, variance rate 0, arrivals at 0.5 a year of size exactly 1. The jump diffusion: drift 0.06, variance rate 0.04, arrivals at 0.5 a year whose log size averages minus 0.05 with a standard deviation of 0.10. Nothing else can be present in any of the four, because the decomposition allows exactly three parts. Every drawn path uses the same twelve locked driving values and no fresh randomness, so the pictures are identical on every reload. The single arrival drawn in the two jump rows is placed at month six and takes the median size of the specification, which is the factor 0.951229, and the vertical axis rescales between processes because a variance rate of 1.00 and one of 0.04 cannot share a scale.

Why does the same description work at every time scale?

Lines two and three have a consequence that deserves its own block. The consequence is why these processes are convenient to compute with, and why the same three numbers can be quoted at any frequency. Take a change over one year. Cut the year into twelve months. The twelve monthly changes are independent by line two, and they all have the same distribution by line three, and they add up to the annual change by arithmetic. So the annual change has been written as a sum of twelve independent pieces that are identical to one another.

Now notice that nothing chose twelve. The same argument works for two halves, for four quarters, for 365 days, for any number at all. A quantity that can be written as a sum of any number of identical independent pieces is called infinitely divisibleA quantity that can be split into any number of identical independent pieces that add back to it. Every increment of a process in this class has this property., and every increment of every process in this class has that property automatically. Infinite divisibility is not an extra assumption; it falls straight out of the two lines already accepted.

Work it on the standard process in logarithms, where the annual triplet is a drift of 0.06, a variance rate of 0.04 and no jumps. Split the year in two and each half carries a drift of 0.03 and a variance of 0.02. Split it in four and each quarter carries 0.015 and 0.01. Split it in twelve and each month carries a drift of 0.005 and a variance of 0.003333, whose square root is a standard deviation of 0.057735. The monthly standard deviation is also the locked volatility of 0.20 multiplied by the square root of one twelfth, being 0.288675. The two routes are the same calculation written twice and agree to six decimals.

The same year, cut four ways. Every piece is identical to every other piece in its row. 1 PIECE drift 0.060000 . variance 0.040000 . intensity 0.500000 2 PIECES 0.030000 . 0.020000 . 0.250000 0.030000 . 0.020000 . 0.250000 4 PIECES 0.0150 . 0.0100 . 0.1250 0.0150 . 0.0100 . 0.1250 0.0150 . 0.0100 . 0.1250 0.0150 . 0.0100 . 0.1250 12 PIECES each month: drift 0.005000, variance 0.003333, intensity 0.041667 and the standard deviation of a month is 0.057735, being 0.20 times 0.288675 Twelve times 0.005 gives 0.06 and twelve times 0.003333 gives 0.04. The row adds back exactly. Intensity is shown for the jump diffusion row of the table. Educational illustration, invented parameters throughout. Nothing chose twelve. Any number of pieces works, which is what infinitely divisible means.
Splitting the year into two, four or twelve pieces divides the drift, the variance and the intensity by the same number every time, and the twelve monthly pieces add back to a drift of 0.06 and a variance of 0.04 exactly.

The reason to care is practical rather than decorative. Because the three quantities all scale in proportion to the length of the stretch, a triplet quoted per year can be converted to any other frequency by one division and never by a rule of thumb. Anything that does not scale that way has broken one of the two lines, and the failure will show up as a triplet that refuses to stay the same when the reading frequency changes.

Splitting an increment into identical independent pieces
$$X_{t}\;\stackrel{d}{=}\;\sum_{i=1}^{n} Z_{i},\qquad Z_{1},\dots,Z_{n}\ \text{independent, each}\ \stackrel{d}{=}\ X_{t/n}$$ $$b\!\left(\tfrac{t}{n}\right),\qquad \sigma^{2}\!\left(\tfrac{t}{n}\right),\qquad \lambda\!\left(\tfrac{t}{n}\right)\qquad\text{is the triplet of one piece}$$
\(X_{t}\)the change of the process over a stretch of length \(t\), taken here as one year
\(n\)the number of equal pieces the stretch is cut into. Any whole number at all is permitted
\(Z_{i}\)the change over the \(i\)th piece. The pieces are independent of each other and share one distribution
\(b\), \(\sigma^{2}\), \(\lambda\)the annual drift rate, variance rate and arrival intensity. Each is multiplied by the length of one piece
\(t/n\)the length of one piece in years, so one twelfth of a year for a month
What it says in wordsThe change over any stretch can be written as a sum of as many identical independent pieces as desired, and the triplet of one piece is the annual triplet multiplied by the length of that piece. Cutting a year into twelve months turns a drift of 0.06 into 0.005 a month, a variance rate of 0.04 into a variance of 0.003333 a month, and an intensity of 0.5 into 0.041667 arrivals a month.
Try it out

The standard process in logarithms carries a variance rate of 0.04 a year. Cut the year into twelve identical independent monthly pieces. What variance does one month carry?

Derivatives Foundation Bootcamp — Fin Maverick

What does the split buy that studying each process alone does not?

The honest answer is not elegance. The gain is a short list of suspects. When a process in this class behaves unexpectedly, the decomposition establishes that the behaviour has exactly three possible sources, and they can be gone through one at a time before running any calculation at all.

Here is a concrete instance built entirely from the locked figures. The locked path is the twelve step path published for this reading order, driven by twelve values that were constructed to sum to zero. Because they sum to zero, the Brownian motion ends the year exactly where it started, and therefore the standard process in logarithms ends the year sitting exactly on its own drift line at Rs 106.18/-. The landing on the drift line is a deliberate construction rather than a coincidence, and it makes the arithmetic that follows unusually clean.

Now suppose a year of that process is recorded and the level at the horizon comes out at Rs 101.01/- rather than Rs 106.18/-. The shortfall is Rs 5.18/-. In logarithms that is a gap of 0.05. Three candidates, and only three.

CandidateWhat it would have to beHow to tell
The drift slot is wrongA drift of 0.01 a year instead of 0.06, since 0.06 less 0.05 is 0.01The whole path sits low from the first month, not just the second half
The continuous slot did itA Brownian motion ending the year at minus 0.25 instead of noughtThe shortfall accumulates in wobbles, with no single instant carrying much of it
The jump slot is not emptyOne arrival whose proportional size is 0.951229, the median of the size specificationOne instant carries the entire 0.05, and the path is unremarkable either side of it
Number of candidates3and there is no fourth

All three explanations produce the identical year-end number, so the level at the horizon cannot tell them apart. The path can, instantly. The decomposition does not identify which of the three it was. The decomposition establishes that the list is three long and complete, and completeness turns an open question into a three way test run by looking at the picture.

A shortfall of Rs 5.18/- at the horizon. Three places it can be coming from, and no fourth. The locked path of the standard process, one year, twelve steps. All figures invented. Rs 111.08/- an instant before Rs 105.66/- an instant after 110 100 90 0 6 12 months gap Rs 5.18/- drift line ends Rs 106.18/- observed path ends Rs 101.01/- the gap between the two at the horizon SUSPECT ONE, THE DRIFT would need 0.01, not 0.06 SUSPECT TWO, THE CONTINUOUS would need an ending of minus 0.25 SUSPECT THREE, THE JUMPS one arrival at the factor 0.951229 All three give the identical year end. Only the path tells them apart, and the path is free to read. Educational illustration. Nothing here describes any market or any real instrument.
The drift line and the recorded path end Rs 5.18/- apart, and the decomposition supplies exactly three candidate sources for that gap, with the single break at month six being the one the drawn path actually shows.

The everyday version is a bathroom scale that reads two kilogrammes heavy. There are only so many places the error can live: the calibration is off by a constant, the mechanism is noisy, or somebody leant on it once. Knowing the list is short is what allows a check in a minute rather than a replacement of the scale. The decomposition is the same service performed for a process, with the added comfort that the list is not merely short but provably complete.

Try it out

A process in this class behaves unexpectedly. What does the decomposition give?

Try it out

The class is very general. What does it exclude?

What does the definition rule out, and where does that bite?

One exclusion is where the next several years of this subject come from, and it hides in the least conspicuous clause of the four.

Line three requires that the distribution of a change depends only on the length of the stretch. Read it again with an eye for what it forbids rather than what it permits. Line three says a one month change in January must follow the same law as a one month change in September. Not a similar law. The same one. The requirement is called stationary incrementsThe distribution of a change depends only on how long the stretch was, never on when it happened, so a one month change in January follows the same law as a one month change in September., and it is the quietest of the four lines and by far the most restrictive.

Now consider a process whose variance rate is 0.04 a year for the first six months and 0.09 a year for the second six. Nothing about it is exotic. Its increments are still independent, its starting level can be set anywhere, and its path is still perfectly continuous. But a one month change in the first half carries a variance of 0.003333 and a one month change in the second half carries 0.007500, and those are two different distributions over stretches of identical length. Line three is broken. The process is not in the class, and no amount of rewriting will put it there.

In practice the exclusion bites harder still. A process whose variance rate is itself random, moving through time under its own dynamics, breaks line three for the same reason and more thoroughly. The distribution of a change now depends on the level the variance happens to have reached. This class excludes every process whose volatility moves through time. The exclusion is the reason a whole later reading order in this subject exists. That later treatment does not extend the decomposition; it leaves the decomposition behind, because the three parts stop being constants and the result they belong to stops applying.

The stationarity clause, written as the exclusion it is
$$\text{In the class:}\qquad \operatorname{Var}\!\left(X_{t+h}-X_{t}\right)=\sigma^{2}h\quad\text{for every }t$$ $$\text{Outside it:}\qquad \operatorname{Var}\!\left(X_{t+h}-X_{t}\right)=\int_{t}^{t+h}\sigma^{2}_{u}\,du\quad\text{which moves with }t$$
\(X_{t}\)the value of the process at time \(t\)
\(h\)the length of the stretch, so one twelfth of a year for a month
\(\sigma^{2}\)the constant variance rate of a process in the class, 0.04 a year for the standard process in logarithms
\(\sigma^{2}_{u}\)a variance rate that itself changes with time, whether by a fixed schedule or at random. This is the object the class excludes
\(\operatorname{Var}\)the variance of the change over the stretch, being the spread the stretch is capable of producing
What it says in wordsInside the class the variance of a change is the variance rate multiplied by the length of the stretch, and where the stretch sits on the calendar makes no difference at all. Outside it the variance of a change depends on when the stretch happened, because the rate itself has moved. That single difference is the whole exclusion, and it is stated in the clause a reader is most likely to skim.
Variance of a one month change, month by month. Both processes have independent increments. INSIDE THE CLASS: EVERY MONTH CARRIES 0.003333 0.003333 every month, without exception month 1 month 12 OUTSIDE IT: THE RATE MOVES, SO TWO EQUAL STRETCHES DIFFER 0.003333 a month 0.007500 a month month 1 month 12 Same length of stretch, two different distributions. Line three is broken and the class is left. The lower process is still independent and still continuous. Only stationarity fails, and that is enough. Educational illustration. The two rates are invented for the contrast and describe nothing observed.
Twelve identical monthly variances of 0.003333 keep a process inside the class, while a rate that moves to give 0.007500 in the second half breaks the stationarity clause even though independence and continuity both survive untouched.

The error that gets made, and what it costs

Reading generality as universality, and expecting the decomposition to apply to a process whose volatility moves.

The class is genuinely large. The class contains every process built from a steady rate, a scaled Brownian motion and a stream of arrivals, in any combination, with any size specification. Having placed four different processes into it in the space of one table, a reader forms the reasonable impression that it contains everything worth having. It does not. The class excludes precisely what the later reading orders of this subject spend themselves on, and it excludes it through the clause that sounds least like a restriction.

The cost is time, and it is time spent in a particularly frustrating way. An analyst takes a process with moving volatility, goes looking for its three parts, and finds that they refuse to stay constant. The repair is then attempted by writing a time varying drift and a time varying variance rate, at which point there is no triplet but three functions, and the result that promised there was no fourth part was never about that object in the first place. Nothing in the arithmetic breaks loudly. The decomposition just quietly stops delivering the completeness that made it worth having.

The reason this survives is that the exclusion is invisible in the picture. A path with moving volatility looks like an ordinary path. Such a path starts at zero, its increments can be perfectly independent, and it need never break. Every property a reader would think to check is intact, and the one that fails is a statement about distributions over equal stretches rather than about anything visible in the path. Read line three as an exclusion rather than as a description, and it stops being the clause that gets skimmed.

Try it out

A model whose volatility moves randomly through time. Is it a Levy process?

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Why is this the right level of generality for jumps?

Generality is not automatically a virtue. A description broad enough to include everything says nothing, and a description narrow enough to be sharp usually covers one case. The question worth asking about any general class is what it buys and what it costs, in that order and concretely.

The class buys the completeness result. If the class had been drawn wider, by dropping stationarity as well, the decomposition would simply be false and there would be nothing to state. If it had been drawn narrower, by keeping continuity, the class would be back to Brownian motion alone and the counting process would sit outside, along with everything else in this reading order that breaks. So the boundary is not a matter of taste. The boundary sits at the widest point where the three part statement remains true, and that is what makes it worth learning as a boundary rather than as a category.

The cost is one clause. Processes whose randomness changes character through time are not members of the class. Losing them is a real cost, and not a small one.

There is a second gain that is easy to miss. The class is closed under additionAdding two independent processes from the class produces another process in the class, with the three parts of the sum being the parts of each added together.. Add two independent processes from the class and the sum is another process in the class, whose drift is the sum of the two drifts, whose variance rate is the sum of the two variance rates and whose arrivals are the two streams of arrivals merged. Closure is what makes the jump diffusion legitimate as an object rather than a construction requiring separate justification: a process with drift and continuous randomness is added to a process with jumps, and the sum is in the class by the closure alone. The three columns of the table are additive, so a process built by adding two members has its slots filled by adding their slots.

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How does somebody checking another person's model use this?

Very few people prove any of this. Plenty are handed a model with an unfamiliar name and thirty printed sides of notation and have to decide, quickly, what kind of object it is and where its behaviour is coming from. The four questions below do most of that work and none of them needs the code, the data or the fitted parameters.

  1. Write down the three slots before reading anything else. Ask what the drift rate is, what the variance rate of the continuous part is, and what the arrivals look like. If the notes answer all three with constants, the object is a member of the class and the decomposition applies.
    Three constants means three slots and no fourth. Anything unexplained afterwards has to be coming from one of them.
  2. Check whether any of the three quantities is written with a time subscript. A variance rate carrying a time subscript is the whole exclusion in one symbol. It means the rate moves, so the increments are not stationary, so this class does not contain the object however much it looks like it should.
    One subscript is the difference between a triplet and three functions, and between a completeness result and no result at all.
  3. Convert the triplet to a different frequency and see whether it survives. An annual drift of 0.06 has to be 0.005 a month and an annual variance rate of 0.04 has to give 0.003333 a month. If the notes quote monthly figures that do not divide cleanly, either the process is outside the class or somebody has converted with a rule of thumb.
    Division by twelve is the only permitted conversion here. Anything else is a signal to stop and ask.
  4. When a reading surprises, name which of the three slots stands accused. This is the check that saves the most time. Saying the model behaves oddly starts an open ended search. Saying the shortfall of Rs 5.18/- is either a drift of 0.01, an ending Brownian value of minus 0.25 or one arrival at the factor 0.951229 starts a three way test that the path itself settles.
    A complaint that does not name a slot has not used the decomposition at all, and the decomposition is free.

The second check is the difference between an hour and a week, and it is the one worth internalising. The check costs one glance at the notation, and it settles whether the rest of the material being read is even relevant to the object at hand.

One last note on scope prevents a wrong inference. No jurisdiction sets the definition of a process. The four lines are the same four lines everywhere, and the completeness of the three part split is the same result in every country and every decade.

The counting process in its own right is covered separately. Any specific model combining the three parts is covered separately and closes this reading order. Processes whose volatility moves through time are covered separately and much later. What a contract pays is covered separately.

References

SourceDocumentWhere
arXiv Quantitative FinancePreprint repository for the general class of processes with independent stationary incrementsarxiv.org
Social Science Research NetworkWorking paper repository for the same materialssrn.com
Levy and ItoThe decomposition into drift, continuous part and jumps, which carries both namesnamed in the text, no text reproduced
Merton, 1976The jump diffusion of 1976, combining drift, continuous randomness and lognormally sized arrivalsnamed in the text, no text reproduced
Hull, Shreve and WilmottStandard texts on stochastic calculus for financenamed in the text, no text reproduced

The standard process is invented.
Educational material. Not advice on any investment, tax, budget or market position.

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