Fin Maverick
Foundations VocabularyAccounting & ReportingEconomics & MacroQuant Methods & ProgrammingBusiness & Company AnalysisCorporate Finance & ValuationBehavioural Finance
Banking & Market InfrastructureFixed Income & RatesDerivatives & Structured ProductsPublic EquitiesTransactions & DealsPortfolio ConstructionFunds & AMCs
Private Markets & AlternativesRisk, Treasury & ControlAI & Digital FinanceStochastic Calculus & PricingWealth & Personal FinanceIndian Markets & RegulationProfessional Practice
CalculatorComparison
Frameworks
Explore Bootcamps
Equity ResearchPortfolio ManagementMutual Fund MasteryFinancial LiteracyInvestment Banking Analyst
Private Equity AnalystHedge Funds AnalystBreaking Into VCBreaking Into QuantsAI For Finance
Financial Analyst ProgramRisk Management ProgramPrivate Wealth ManagementDebt Capital MarketsDerivatives Foundation
Explore Internships
Equity Research InternMutual Fund Intern
Portfolio Management InternFinancial Literacy Intern
Explore Micro Courses

Equity Research6

Writing an Investment ThesisBuilding a Discounted Cash FlowReading an Annual Report FastReading a Sector Before a CompanySpotting Quality of Earnings Red FlagsBuilding a Revenue Forecast From Drivers

Portfolio Management3

Rebalancing: When, Why and What It CostsStrategic and Tactical Asset AllocationMeasuring Risk in a Portfolio

Mutual Fund Mastery3

Comparing Funds Without Being FooledHow a NAV Is Struck and Which Day You GetReading a Fund Factsheet Properly

Derivatives Unlocked4

Hedging a Real ExposureThe Greeks, PracticallyFutures, the Basis and What Moves ItReading an Option Payoff

AI For Finance2

Retrieval and Grounding for FinanceDocument Extraction in Finance

Breaking Into Quants4

Backtesting a StrategyHypothesis TestingCleaning Financial DataRegression for Finance

Breaking Into VC3

Sizing a MarketReading a Term Sheet as a FounderHow a Venture Round Actually Works

Financial Analyst Program4

Common Size and Trend AnalysisReading a Cash Flow StatementRatio Analysis That Says SomethingBuilding a Working Capital Schedule

Risk Management Program2

Credit Exposure and How It Is ReducedValue at Risk and What It Hides

Investment Banking Analyst3

Precedent Transactions and Why They DifferReading a Term Sheet StructurallyBuilding a Comparable Companies Table

Private Wealth Management3

Tax Aware Portfolio DecisionsBuilding a Client Risk ProfileGoal Based Planning Arithmetic

Debt Capital Markets3

Analysing an Issuer's CreditDuration and What It Does Not Tell YouBond Pricing and Yield Mechanics

Private Equity Analyst2

Fund Waterfalls and CarryThe LBO in Structure

Hedge Funds Analyst2

Short Selling MechanicsLong Short Mechanics
Courses
Explore Career Roadmaps
Investment Banking AnalystEquity Research AnalystVC AnalystPrivate Equity AnalystHedge Funds Analyst
Quant AnalystAI For FinanceFinancial Analyst ProgramPrivate Wealth ManagementDebt Capital Markets
Risk Management ProgramDerivatives FoundationPortfolio ManagementMutual Fund Mastery
PartnershipsShowdown
Log inSign up
Stochastic Calculus & Derivative Pricing Theory
1Probability Foundations
The Probability SpaceRandom VectorsSigma-AlgebraExpectationSample Space and EventsDensity and Distribution FunctionsRisk-Neutral ProbabilityState Price Density vs…
2Stochastic Processes and Jumps
Properties of a Stochastic ProcessMartingaleBrownian Motion and Its PropertiesBrownian Motion vs Geometric…Stopping TimeThe Markov PropertyState VariablesTransition ProbabilityQuadratic VariationQuadratic Variation vs Ordinary…Submartingale and SupermartingaleMartingale RepresentationMarkov Process vs MartingaleOptional StoppingFiltrationJump ProcessesThe Poisson ProcessLevy ProcessesJump Diffusion
3Ito Calculus
The Ito IntegralThe Ito Integral vs the Riemann IntegralInfinitesimals in Stochastic CalculusQuadratic CovariationIto's LemmaHow to Apply Ito's…The Infinitesimal GeneratorIto Calculus vs Ordinary Calculus
4Stochastic Differential Equations
Stochastic Differential EquationsStochastic Differential Equation vs…Drift and DiffusionStrong and Weak Solutions ComparedDiscretisationGeometric Brownian Motion
5Pricing Theory and No-Arbitrage
No-ArbitrageGirsanov, Radon-Nikodym and Change…Physical and Risk-Neutral Measures…The Fundamental Theorems of…The Law of One PriceThe Pricing KernelDiscount Factors and Zero-Coupon PricesReplication vs HedgingComplete Market vs Incomplete MarketClearing Margin Architecture
6Option Pricing Theory
European and American OptionsMonte Carlo European OptionThe Black-Scholes PDEBlack Scholes and the GreeksThe Payoff FunctionThe Binomial ModelBinomial Option PricingDelta Hedging in TheoryBoundary, Initial and Terminal ConditionsThe Exercise BoundaryHow to Check Put-Call…
7Volatility Models
Constant, Local and Stochastic…Vasicek Model vs CIR ModelThe Heston ModelThe SABR ModelThe Volatility ProcessImplied VolatilityVolatility Smile vs Skew vs Surface
8Interest Rate Models
Interest-Rate DerivativesMean ReversionThe Zero-Coupon BondThe Ornstein-Uhlenbeck ProcessThe Discount CurveZero RatesShort-Rate Model vs Market Model
9Numerical Pricing
Closed Form and Numerical…Monte Carlo PricingEuler and Milstein Schemes ComparedTree MethodsFinite Difference MethodsNumerical Error and StabilityVariance Reduction
10Calibration and Model Risk
Model OverrideMarket Price and Model PriceCalibrationHow to Document a Pricing ModelThe Educational Illustration LabelMarket ConventionsModel Uncertainty and LimitationsBacktesting a Pricing ModelIdentifiabilityCalibrated ParametersThe Calibration Loss Function

Delta Hedging in Theory: The Argument Behind the Price

The delta hedging argument establishes a price. Hold the contract against a quantity of the standard process chosen so the combined position has no first order response to the level, and what remains carries no randomness, so no-arbitrage forces its rate of return and the price follows. Delta and the hedge ratio are that one quantity named from two sides. The position must be adjusted because that quantity moves with the level.

A two-pan balance sits in the corner of every school laboratory, and it is the cleanest picture of the delta hedging argument. An unknown object goes on the left pan and brass weights are added to the right until the pointer stops moving. The moment the pointer stops, a weight has been established. The balance has not established that anybody is going to stand there holding the pans level for the rest of the afternoon. The balancing was scaffoldingSomething used to establish a result and then taken away, leaving the result standing on its own.. Once the object is lifted off, the pans swing wildly, and the weight that was measured is still the weight.

The delta hedging argument is that balance, and the price is the reading on it. Almost every difficulty a reader has with this argument comes from mistaking the scaffolding for the building: from reading a construction whose only job is to produce a number as though it were an instruction about what somebody must do. The scaffolding and the building come apart cleanly, and separating them is the whole of the difficulty.

The sensitivities themselves arrive already settled, and are covered separately. The contract also arrives already known, with what the contract pays covered separately. The contract appears only as a function whose response to the level is the quantity the argument needs.

What does the delta hedging argument establish?

The argument has three moves and only the first one contains a choice. Move one: form a combined position out of the contract and some quantity of the standard process, and leave that quantity unnamed for the moment. Move two: notice that the randomness in the combined position arrives multiplied by a single coefficient, and that the unnamed quantity sits inside exactly that coefficient, so there is one value of it that sets the coefficient to nought. Move three: point out that whatever is left over now carries no randomness at all, and that a position carrying no randomness has its rate of return settled by no-arbitrage rather than by preference, taste or forecast.

The third move is where the price comes from, and the kind of statement it makes is worth being precise about. The no-arbitrage step is not a measurement. Nobody went out and observed that positions with no randomness in them grow at the risk-free rate. The rate is imposed, on the grounds that any other rate would describe an arrangement the pricing framework has already refused to admit. So what the argument produces is a conditional statement: given that such arrangements are refused, the price is this one and no other. The conditional form is not a weakness. A condition can be inspected instead of a conclusion argued over, and inspection is what makes the result checkable.

Three moves produce a price. Only the first one contains a choice. ONE. COMBINE, AND LEAVE THE QUANTITY UNNAMED The contract, against some quantity of the standard process. The quantity gets chosen later, not now. TWO. THE RANDOM DRIVER CANCELS One equation, one unknown. Exactly one quantity sets the random coefficient to nought. THREE. NO-ARBITRAGE SETTLES THE RATE What is left carries no randomness, so its rate of return is settled rather than preferred. THE PRICE FOLLOWS BY REARRANGEMENT WHAT IT DOES NOT ESTABLISH That anybody holds the combined position, then or ever. That the position could be carried out at no cost. That the price is right if and only if somebody runs the offset. That its four assumptions are true of anything at all. A conditional statement: given that those arrangements are refused, the price is this one and no other.
The argument reaches a price in three moves, of which only the first contains a choice, and the dark panel names four claims that are commonly read into it and are not there.
The combined position, and the one quantity left to choose
$$ \Pi_t \;=\; V\!\left(S_t,\,t\right) \;-\; h_t\,S_t $$
\(\Pi_t\)the combined position at time \(t\), in rupees
\(V(S_t,t)\)the value of the contract as a function of the level and the time, which arrives already known
\(S_t\)the standard process at time \(t\), invented, starting at Rs 100/- exactly
\(h_t\)the quantity of the standard process held against the contract, deliberately unnamed at this stage
\(t\)a general time between nought and the horizon of one year
What it says in wordsThe combined position is the contract less some quantity of the standard process, and at this point in the argument that quantity is a free choice rather than a known number. Everything the argument achieves comes from choosing it well, and nothing whatever has been assumed about it yet.

The quantity is still free at this stage, and that is the reason the argument works at all. If the quantity had to be known in advance, the argument would need something it has not got. Because it does not, the algebra can be left to say what the quantity has to be, and the value it has to be turns out to be a quantity that already has a name.

Try it out

Once the randomness has been removed from the combined position, what does the argument do next?

Derivatives Foundation Bootcamp — Fin Maverick

Delta vs Hedge Ratio: are they one number or two?

Delta and the hedge ratio are one number. The two words are two vantage points on the same derivative, and the reason both words exist is that two different people needed to name the same thing for two different purposes.

Start from the contract's side. DeltaThe first order response of the contract's value to the level, meaning the part of the value change that is proportional to the move in the level. answers a question about the contract on its own: if the level moves by a small amount, how much of that move shows up in the contract's value? Delta is a property of the contract, computed by differentiating the value function with respect to the level, and it exists whether or not anybody ever forms a position against it.

Now start from the position's side. The hedge ratioThe quantity of the process held against the contract so that the combined position has no first order response to the level. The hedge ratio is the same number as delta. answers a question about a combination: how many units of the standard process must sit against the contract so that the combination stops responding to the level to first order? The hedge ratio is a property of a position, and it is a quantity somebody would have to go and choose.

The two questions are genuinely different. The reason they have the same answer is not a coincidence and it is not a definition. The identity is forced. A unit of the process responds to the level by exactly one, so the first order responseThe part of a change that is proportional to the move in the level, with everything of higher order set aside. of the combination is the contract's response less the quantity held. Setting that difference to nought has one solution, and the solution is the contract's response itself.

Why the hedge ratio is forced to equal delta
$$ \text{random part of } d\!\left(V - h\,S_t\right) \;=\; \sigma S_t\!\left(\frac{\partial V}{\partial S} - h\right) dW_t \;=\; 0 \quad\Longleftrightarrow\quad h \;=\; \frac{\partial V}{\partial S} \;=\; \Delta_t $$
\(\sigma\)the volatility of the standard process, 20 per cent a year, invented
\(W_t\)standard Brownian motion under the physical measure P, the single random driver
\(\partial V/\partial S\)the contract's first order response to the level, computed by differentiating the value function
\(h\)the quantity of the standard process held against the contract, still free until this line
\(\Delta_t\)delta at time \(t\), the name the contract's side gives to that derivative
What it says in wordsThe single random driver enters the combination multiplied by the gap between the contract's response to the level and the quantity held, so that gap is nought for exactly one choice of quantity, and that choice is the contract's response itself. The hedge ratio is not a second number picked for convenience: it is delta, arrived at from the other end.

One derivative, two vantage points, one number, and there is nothing further to reconcile between them. On the at-the-money contract on the standard process, struck at Rs 100/- with one year to run, that number is 0.636831. Ask the contract's side what happens when the level moves and the answer is 0.636831. Ask the position's side how much of the process has to sit against it and the answer is 0.636831.

The same derivative, approached from two ends, landing on the same number. FROM THE CONTRACT'S SIDE THE QUESTION ASKED How much of a move in the level shows up? WHAT IT IS A PROPERTY OF The contract, on its own, with no position THE NAME IT CARRIES Delta THE NUMBER AT RS 100/- 0.636831 = FROM THE POSITION'S SIDE THE QUESTION ASKED How many units offset that response? WHAT IT IS A PROPERTY OF A combination of the two, taken together THE NAME IT CARRIES The hedge ratio THE NUMBER AT RS 100/- 0.636831 TWO QUESTIONS, TWO NAMES, ONE DERIVATIVE, ONE NUMBER
Delta names the contract's response to the level and the hedge ratio names the quantity of the process that offsets it, and on the at-the-money contract both are 0.636831.
Try it out

Are delta and the hedge ratio two numbers or one?

Delta Hedging vs Replicating Portfolio: how do the two arguments relate?

Delta hedging and replication are the same argument, run in two settings, and the difference between the settings is the whole of the difference between the answers.

A replicating portfolioA holding of the process and cash, built so that it reproduces the contract's payoff exactly at every reachable outcome, in a setting with a finite number of steps. argument works in a world with a finite number of steps. Over one step the level can arrive at a small number of places, so a holding of the process plus a cash amount can be written down, with the pair required to reproduce the contract's value at every one of those places. The requirement is a system of equations with as many rows as there are places to arrive at, and where the rows and the unknowns match it has a solution. The two arrangements deliver the same thing everywhere, so once the system is solved, the cost of assembling that holding today is the contract's price.

The delta hedging argument works in a world with no smallest step. There is no list of places the level can arrive at over the next instant, so there is no system of equations to solve. A derivative stands in its place, and the derivative does the same job the system of equations did: it identifies the one quantity that makes the two arrangements agree, not at a finite list of outcomes, but to first order over an instant. The price then comes not from the cost of assembly but from the rate of return the leftover is forced to earn.

The one step holding, solved from two outcomes rather than differentiated
$$ h^{(1)} \;=\; \frac{V_u - V_d}{S_0\left(u - d\right)} \;=\; \frac{22.140276 - 0}{100 \left(1.221403 - 0.818731\right)} \;=\; 0.549834 $$
\(h^{(1)}\)the holding of the standard process in the one step replicating argument, a pure number
\(V_u,\;V_d\)the contract's value at the two places the level can arrive at after one step, Rs 22.140276/- and nought
\(u,\;d\)the up and down factors of the one step construction, 1.221403 and 0.818731, reciprocals of one another
\(S_0\)the level today, Rs 100/- exactly, invented
What it says in wordsIn a one step setting the holding is a difference quotient taken across the whole step: the change in the contract's value between the two reachable outcomes, divided by the change in the level between the same two. No limit is being taken, so the quotient is not a derivative, and it uses the whole width of the step rather than an instant at the start of it.

Notice what that expression is. The expression is a slope measured across a chord, from one end of the step to the other, and the chord has a width of Rs 40.267200/- because the level can land at Rs 122.1403/- or at Rs 81.8731/-. The continuous argument uses the slope of the tangent at the starting point instead. A chord across a curved function and a tangent at one end of it are different slopes, and that is the entire reason the two numbers differ.

Two settings, two holdings, and neither of them is the wrong answer. 0.50 0.68 0.59 0.549834 ONE STEP HOLDING a chord across the step +0.086997 THE GAP chord slope against tangent slope 0.636831 CONTINUOUS HEDGE QUANTITY a tangent at the starting point Vertical scale starts at 0.50, not at nought, because the whole gap is 0.086997 wide.
The continuous argument holds 0.636831 units and the one step replication holds 0.549834, and the two differ because a single step has no in-between moment at which to adjust.

Neither number is wrong, and this is worth saying flatly because it is where readers most often go looking for an error. The one step holding of 0.549834 is the exactly correct answer to the question a one step world poses, and it reproduces the contract's value at both outcomes to every decimal place worth writing. The continuous quantity of 0.636831 is the exactly correct answer to the question a continuous world poses. The two holdings differ because the questions differ, not because one calculation went astray.

One turns into the other under refinement. When the construction is refined so that instead of one step over the year there are two, then four, then twelve, then fifty, and the holding at the start is recomputed each time, the holding climbs toward 0.636831, and it gets most of the way there in the first refinement.

Steps over the yearHolding at the startDistance still to travel
10.5498340.086997
20.6222990.014532
40.6291640.007667
120.6342010.002630
500.6361940.000637
The continuous limit0.636831nought

One honest warning about that table: a reader who takes it as a smooth climb will be caught out. The five step counts were chosen to match the construction that is already published for this contract, and along that particular ladder the holding rises at every rung. Insert the odd step counts and it stops being a climb: at three steps the holding is 0.614086 and at five it is 0.623875, both below the four step figure of 0.629164. The approach to the limit oscillates between odd and even refinements rather than rising smoothly, exactly as the price of the same contract does, and a picture drawn as a smooth rise would be drawing something the arithmetic does not do. Convergence is a statement about the limit, not a promise that each rung sits above the one before it.

Try it out

The continuous argument gives 0.636831 and the one step replication gives 0.549834. Which one is right?

Breaking Into Quants Bootcamp — Fin Maverick

Why does the position have to be adjusted at all?

Because the quantity that removes the response is itself a function of the level, and the level moves. The moving level is the whole reason, and everything below makes it concrete.

Here is the everyday version. A cyclist going up a hill picks a gear that matches the gradient at the bottom. The gradient at the bottom is a fact about one point on the road, not about the road. Two hundred metres up, the slope has changed and the chosen gear no longer matches it. Nothing went wrong with the choice; the choice was correct where it was made and correct nowhere else. How often the gear has to change depends on how fast the gradient changes. The rate at which a gradient changes is a different property of the road from the gradient itself.

CurvatureHow delta itself changes as the level moves. Curvature is the second derivative of the contract's value with respect to the level, and it decides how fast a fixed holding goes stale. is that second property. Delta has a derivative of its own with respect to the level, and the size of that derivative is the rate at which a holding chosen at one level stops being the right holding at another. On the at-the-money contract on the standard process the curvature reads 0.018762 per rupee squared, and that number is settled separately in the treatment of the sensitivities.

Delta moves, and the rate at which it moves has its own name
$$ d\Delta_t \;=\; \Gamma_t\,dS_t \;+\; \left(\cdots\right)dt , \qquad \Gamma_t \;=\; \frac{\partial^2 V}{\partial S^2} \;=\; \frac{\varphi\!\left(d_1\right)}{S_t\,\sigma\sqrt{T-t}} $$
\(\Gamma_t\)the curvature at time \(t\), the derivative of delta with respect to the level, 0.018762 at Rs 100/-
\(\varphi\)the standard normal density
\(d_1\)the first intermediate quantity of the closed form, 0.350000 exactly on this contract
\(T-t\)the time still to run, one year at the start
\(\left(\cdots\right)dt\)the terms proportional to elapsed time, which do not depend on the level moving
What it says in wordsDelta changes when the level changes, and the coefficient on that change is the curvature, so a holding fixed at one level is already the wrong holding an instant after the level has moved. The size of the curvature is exactly how wrong, per rupee of movement, and a contract with no curvature would need no adjustment at all.

The curvature can be checked against the thing it claims to measure without any calculus. Delta at Rs 99/- is 0.617815 and delta at Rs 101/- is 0.655330. The change across those two rupees is 0.037515, so the change per rupee is 0.018757. The curvature quoted at Rs 100/- is 0.018762. The two do not match exactly, and they should not: one is a slope at a single point and the other is a slope measured across a two rupee span of a bending function. Over a span that short, agreement to four decimal places is what to expect.

Now push the level further and the fixed holding stops being nearly right. Freeze the quantity at 0.636831 and move the level to Rs 120/-, where the contract's own response has risen to 0.896455. The combination is now short of the offset by 0.259624 per rupee, and that leftover response is not a rounding error: it is more than a quarter of a unit of exposure that the frozen holding is no longer covering. Move the level down to Rs 80/- instead, where the response has fallen to 0.221922, and the frozen holding overshoots by 0.414909 in the other direction.

A holding frozen at the at-the-money quantity is correct at one level and nowhere else. 0 0.5 1.0 0.075875 at Rs 70/- 0.978941 at Rs 140/- 0.636831 at Rs 100/- holding frozen at 0.636831, correct at Rs 100/- and at no other level out by 0.414909 at Rs 80/- out by 0.259624 at Rs 120/- 70 80 90 100 110 120 130 140 Level of the standard process, in rupees. Educational illustration.
The hedge quantity is 0.075875 at Rs 70/- and 0.978941 at Rs 140/-, so a holding that removes the first order response at one level does not remove it at another.
Try it out

Why does a fixed holding stop working as the level moves?

Try it out

Before the worked figures: do the continuous hedge quantity and the one step replicating holding come out at the same number?

What do the two arguments give on the locked contract?

Everything above lands on one contract: the at-the-money contract struck at Rs 100/- with one year to run, on the standard process that starts at Rs 100/-, carries a volatility of 20 per cent a year and sits against a risk-free rate of 5 per cent a year continuously compounded.

QuantityReadingWhere it comes from
Delta at Rs 100/-0.636831The contract's first order response to the level, from the contract's side
Hedge ratio at Rs 100/-0.636831The same derivative, named from the position's side. Not a second calculation
Curvature at Rs 100/-0.018762Per rupee squared. The rate at which the holding above goes stale
Hedge quantity at Rs 70/-0.075875The same formula, evaluated thirty rupees below the strike
Hedge quantity at Rs 140/-0.978941The same formula, evaluated forty rupees above the strike
One step replicating holding0.549834A chord across a single step, with no in-between moment at which to adjust

Two lines in that table deserve to be read together rather than separately. The first two rows carry the identical number, and that is the answer to the naming question: one derivative, two vantage points. The last row carries a different number, and that is the answer to the settings question: a one step world poses a slightly different problem and gets a slightly different answer. A reader who expects all three to agree has merged two questions that are not the same question, and a reader who expects the first two to differ has split one question that is not two.

Try it out

The level is about to rise well above the strike. Before the control below is moved: what does the hedge quantity approach?

Play with it

Move the level and watch the hedge quantity climb

One variable moves: the level of the standard process, from Rs 70/- to Rs 140/-. One consequence follows: the hedge quantity is recomputed from the formula and redrawn. The flat dashed line is the one step replicating holding. A one step world has no in-between moment at which it could adjust, so that line does not move at all.

The hedge quantity moves with the level. The one step holding does not move at all. 0 0.5 1.0 one step replicating holding, 0.549834, fixed HEDGE QUANTITY AT RS 100/- 0.636831 IF THE LEVEL THEN ROSE BY RS 10/-, THE QUANTITY WOULD CHANGE BY 0.158924 70 80 90 100 110 120 130 140 Level of the standard process, in rupees. Educational illustration.
Rs 70/-Rs 105/-Rs 140/-
Level
Rs 100/-
Hedge quantity
0.636831
One step holding
0.549834
Distance between them
0.086997
At a level of Rs 100/- the hedge quantity is 0.636831, which is the worked figure above, while the one step replicating holding stays at 0.549834 whatever the level does. The two sit 0.086997 apart.
Held constant while the level moves: strike Rs 100/-, risk-free rate 5 per cent a year, volatility 20 per cent a year, one year to run. The hedge quantity is computed from the formula rather than sampled, so it reproduces on every reload. Educational illustration built from invented parameters, not an observation of any market.

The three readings worth carrying away from that control are these. At Rs 70/- the hedge quantity is 0.075875, at Rs 100/- it is 0.636831 and at Rs 140/- it is 0.978941. The one step replicating holding sits at 0.549834 and never moves. Neither the moving quantity nor the fixed one is the wrong answer; they belong to two different settings, and only the moving one belongs to the continuous setting.

What does the argument assume that an activity does not get?

Four things, and the list is what separates the argument from any activity resembling it. Naming them is not a disclaimer tacked on at the end. The argument's conclusion is conditional on exactly these four and on nothing else, so the list is the substance.

  1. Continuous adjustmentThe quantity held is changed at every instant, with no smallest gap between one change and the next. There is no first moment after the present one at which the holding is still yesterday's holding.
  2. Free tradingChanging the quantity costs nothing at all. No spread, no fee, no impact on the level from the act of changing, and no smallest size that can be traded.
  3. One borrowing rateCash can be borrowed and lent at the same rate, in any amount, in either direction. There is one rate of 5 per cent a year in the argument and it applies to both directions.
  4. Constant volatilityThe volatility of the standard process is 20 per cent a year at every level and at every moment, and it is known now rather than estimated from anything.

Continuous adjustmentChanging the holding at every instant, with no smallest gap between one change and the next. The argument assumes it; nothing else does. is the one that does the most work, and it is worth seeing what it buys with a number rather than an adjective. Over a step of finite width, the position that was built to carry no randomness carries something after all. The size of the leftover is set by the curvature and by the gap between the squared move that actually happened and the squared move the volatility allowed for.

What a step of finite width leaves behind
$$ \Pi_{t+\delta t} - \Pi_{t} \;\approx\; \tfrac{1}{2}\,\Gamma_t\,S_t^{2}\left[\left(\frac{\delta S}{S_t}\right)^{2} \;-\; \sigma^{2}\,\delta t\right] $$
\(\delta t\)the width of the step, one twelfth of a year where the step is a month
\(\delta S\)the move in the level over that step, in rupees
\(\Gamma_t\)the curvature, 0.018762 per rupee squared at Rs 100/-
\(\sigma^{2}\delta t\)the squared move the volatility allows for over that step, 0.003333 over one month
\(\Pi_t\)the combined position, which the continuous argument holds to carry no randomness at all
What it says in wordsOver a step of finite width the combined position is left holding a quantity proportional to its curvature and to the difference between the squared move that happened and the squared move that was allowed for, so it is nought only when those two agree. The continuous argument grants itself the limit in which the step width goes to nothing and the leftover disappears with it, and that grant is what the first assumption is.

Put the locked path through it and the leftover stops being abstract. Over the first month the level goes from Rs 100/- to Rs 97.64/-, a relative move of minus 0.023600, whose square is 0.00055696. The squared move allowed for over a month is 0.003333. Half the curvature multiplied by the level squared is 93.810087, so the leftover comes out at 93.810087 multiplied by minus 0.00277637, which is minus 0.260452 in rupees. The leftover is the price of a monthly step rather than a continuous one, and the argument does not pay it because the argument does not take steps.

Four things are asked for. Whether they are granted decides one thing and not the other. THE ARGUMENT ASKS FOR FOUR THINGS continuous adjustment free trading one borrowing rate constant volatility GRANTED NOT GRANTED INSIDE THE ARGUMENT All four are simply granted, because the argument is entitled to say what world it is reasoning inside. OUTSIDE IT None of the four is available. Adjustment happens at moments, changing a holding costs something, and volatility moves. OUTCOME The combined position carries no randomness and the price follows exactly, with nothing approximated anywhere in the chain. OUTCOME Carrying the position out becomes hard and imperfect. The price the argument settled is not altered by any of that.
Continuous adjustment, free trading, a single borrowing rate and a constant volatility are what the argument is allowed, and an activity has none of the four.
Try it out

Which of these is granted to the argument and not to anything resembling it in practice?

Risk Management Program Bootcamp — Fin Maverick Bond Pricing and Yield Mechanics — free micro-course from Fin Maverick

What does the argument establish, and what does it not?

The argument establishes one thing: if such arrangements are refused, the contract has this price and no other. The result is strong, and strong precisely because it does not depend on anybody's view about where the level is going. The drift of the standard process, 8 per cent a year, appears nowhere in the price. The argument removed the level's randomness before ever asking what the level was expected to do, so two people who disagree completely about that drift agree exactly about the price.

The argument does not establish that anybody holds the combined position. Nor does it establish that holding the position would be cheap, or possible, or wise. Nor does it establish that the four assumptions describe anything. And it does not establish that the price would be different if somebody tried and failed to carry out the offsetting. The balance in the laboratory makes the point: the reading is a weight, and the weight does not change once the pans are no longer held level.

The gap between what the argument establishes and what people take it to establish is the single most useful thing to carry away, and it is a gap about status rather than about arithmetic. Nothing in the algebra is subtle. The subtlety lies in what kind of claim comes out of the other end.

The failure: reading the argument as a description of what somebody does

Here is the mistake, in the form it actually takes. A reader follows the argument, sees a position being formed and a quantity being chosen, and concludes that the price is correct only on the condition that somebody is out there forming that position and adjusting it. Then the reader learns that adjustment at every instant is impossible, that changing a holding costs something, and that volatility does not sit still. The conclusion follows quickly: the price must therefore be wrong, or at least suspect, by an amount nobody can name.

Every step of that reasoning is reasonable except the first one. The argument establishes a price by showing what a particular combination is forced to return. The combination is a device inside a proof. The combination is never held by anybody for the price to be right, any more than the balance in the laboratory has to stay level for the object to keep weighing what it weighs.

The cost of the mistake is a correct price quietly discounted for a reason that has nothing to do with it, and discounted by an amount the reader cannot compute. There is no amount. A reader who has made this mistake will also reject the four assumptions as unrealistic, which they are, without noticing that unrealistic assumptions inside a conditional statement are not an error but the condition itself. A doubted assumption is answered by checking how the price moves when the assumption is relaxed, and that check is separate work with its own answers.

The artefact: one line in a review note that turns a proof into a condition. NOTE ON A VALUATION REVIEW Price accepted only if the offsetting position is actually run and maintained. Flagged: this is not what the argument says. The argument settles a price. It sets no condition on anybody doing anything at all. WHY NOBODY CATCHES IT The argument really does form a position and really does choose a quantity, so it reads like a set of instructions rather than a proof. The combination is a device inside a proof. It is never held by anybody for the price to be the right price. THE COST A correct price quietly discounted for a reason that has nothing to do with it, and discounted by an amount the reader cannot compute.
The combination is never held by anybody for the price to be right, so difficulty in carrying it out is not evidence against the price.
Try it out

Somebody says the price is only right if the offsetting position is actually carried out. What is wrong with that?

The argument establishes a price, not a trading instruction. See what continuous rebalancing assumes.

Who actually leans on this argument, and what does it settle for them?

Somebody reviewing a valuation is the clearest case, and what they get from this argument is a licence to stop arguing about one particular thing. The argument fixes everything else, so when two readings of the same contract disagree, the disagreement has to live in an input. The drift is not an input. Anybody's view of where the level is heading is not an input. So a disagreement about the price is a disagreement about the level, the strike, the horizon, the rate or the volatility, and four of those five are read off a specification or a calendar. The narrowing turns a long argument into a short one, and knowing where a disagreement can and cannot live is most of the work of settling it.

The second use is diagnostic rather than settling. If a valuation is quoted together with the offsetting quantity, the two have to be consistent with each other: the quantity has to be the derivative of that valuation with respect to the level. A quantity that does not sit as the slope of the valuation being quoted is a sign that the two came from different places, and it is a cheap check to run because it needs only the valuation at two nearby levels. Delta at Rs 99/- and at Rs 101/- differ by 0.037515, and any quoted quantity that misses the midpoint of that span by a wide margin is worth a question.

The third use is knowing what a difficulty means. Somebody who reports that keeping an offsetting position aligned is expensive is reporting something true about an activity and nothing whatever about the price. Somebody who reports that a valuation and its quoted quantity are inconsistent is reporting something about the valuation. The two reports look similar and mean entirely different things, and the delta hedging argument is what tells them apart.

What is covered elsewhere?

Carrying out an offsetting position is covered separately; it is an activity rather than an argument. The sensitivities themselves, including how each is computed and what unit each carries, are covered separately. The contract's payoff belongs with derivative instruments and arrives already settled. The equation the argument leads to is derived separately. The forced returnWhat no-arbitrage requires of a position that carries no randomness at all. The forced return is imposed by the framework rather than measured anywhere. that the argument invokes is a property of the framework rather than of any market.

References

SourceDocumentWhere
arXiv Quantitative FinancePreprint repository for statements of the hedging argument, the continuous limit and the leftover term over a step of finite widtharxiv.org
Social Science Research NetworkWorking paper repository for the same materialssrn.com
Black, Scholes and Merton, 1973The hedging argument and the closed form whose derivative is the quantity used herenamed in the text only
Cox, Ross and Rubinstein, 1979The finite step construction whose one step holding of 0.549834 is worked here; the construction itself is derived separatelynamed in the text only
ItoThe lemma by which the combined position is expanded, named wherever it is usednamed in the text only
Hull, Shreve and WilmottStandard texts on the hedging argument and its continuous limitnamed in the text only

The standard process and all four of its parameters are invented.
Educational material. Not advice on any investment, tax, budget or market position.

← PreviousNext →
Fin Maverick Micro CoursesExplore Micro Courses
Fin Maverick BootcampsExplore Bootcamps
Fin Maverick

Finance education that ends in a job, not a certificate that gathers dust. Built for young India.

LEARN
CalculatorsFrameworksComparisonsCareersShowdown
RESOURCES
All CoursesMicro CoursesBootcampsInternships
COMPANY
AboutJob openingPartnership
LEGAL
Privacy PolicyTerms & ConditionsContent LicenseReturn & Refund Policy
© 2026 FIN MAVERICK / BUILT FOR INDIA.DO FINANCE, DO NOT JUST READ ABOUT IT.