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Stochastic Calculus & Derivative Pricing Theory
1Probability Foundations
The Probability SpaceRandom VectorsSigma-AlgebraExpectationSample Space and EventsDensity and Distribution FunctionsRisk-Neutral ProbabilityState Price Density vs…
2Stochastic Processes and Jumps
Properties of a Stochastic ProcessMartingaleBrownian Motion and Its PropertiesBrownian Motion vs Geometric…Stopping TimeThe Markov PropertyState VariablesTransition ProbabilityQuadratic VariationQuadratic Variation vs Ordinary…Submartingale and SupermartingaleMartingale RepresentationMarkov Process vs MartingaleOptional StoppingFiltrationJump ProcessesThe Poisson ProcessLevy ProcessesJump Diffusion
3Ito Calculus
The Ito IntegralThe Ito Integral vs the Riemann IntegralInfinitesimals in Stochastic CalculusQuadratic CovariationIto's LemmaHow to Apply Ito's…The Infinitesimal GeneratorIto Calculus vs Ordinary Calculus
4Stochastic Differential Equations
Stochastic Differential EquationsStochastic Differential Equation vs…Drift and DiffusionStrong and Weak Solutions ComparedDiscretisationGeometric Brownian Motion
5Pricing Theory and No-Arbitrage
No-ArbitrageGirsanov, Radon-Nikodym and Change…Physical and Risk-Neutral Measures…The Fundamental Theorems of…The Law of One PriceThe Pricing KernelDiscount Factors and Zero-Coupon PricesReplication vs HedgingComplete Market vs Incomplete MarketClearing Margin Architecture
6Option Pricing Theory
European and American OptionsMonte Carlo European OptionThe Black-Scholes PDEBlack Scholes and the GreeksThe Payoff FunctionThe Binomial ModelBinomial Option PricingDelta Hedging in TheoryBoundary, Initial and Terminal ConditionsThe Exercise BoundaryHow to Check Put-Call…
7Volatility Models
Constant, Local and Stochastic…Vasicek Model vs CIR ModelThe Heston ModelThe SABR ModelThe Volatility ProcessImplied VolatilityVolatility Smile vs Skew vs Surface
8Interest Rate Models
Interest-Rate DerivativesMean ReversionThe Zero-Coupon BondThe Ornstein-Uhlenbeck ProcessThe Discount CurveZero RatesShort-Rate Model vs Market Model
9Numerical Pricing
Closed Form and Numerical…Monte Carlo PricingEuler and Milstein Schemes ComparedTree MethodsFinite Difference MethodsNumerical Error and StabilityVariance Reduction
10Calibration and Model Risk
Model OverrideMarket Price and Model PriceCalibrationHow to Document a Pricing ModelThe Educational Illustration LabelMarket ConventionsModel Uncertainty and LimitationsBacktesting a Pricing ModelIdentifiabilityCalibrated ParametersThe Calibration Loss Function

Jump Processes: How Intensity and Jump Size Are Set

A jump process moves by sudden discontinuous steps rather than only by continuous drift. Two things specify it, and they are set separately. The intensity is how often arrivals come. The size distribution is how large a move is when one does. The intensity says nothing whatever about the size, and that separation is the whole point.

Everything here follows from a single surrender. Up to now every path in this reading order joined up: a pencil could trace the whole year without once lifting from the paper. A jump processA process that moves by sudden discontinuous steps, so that its path does not join up at the moments those steps happen. gives that up on purpose. At certain random moments the level is one number an instant before and a different number an instant after, and there is no instant in between at which it was anything else. Once that is accepted, two questions open up that were never separate questions before. A continuous path never had to answer either of them. How often does that happen? And when it does, how far does the level move? The two questions have two separate answers, set by two separate pieces of the specification, and nothing in the model ties one to the other. The separation of the two is the whole subject, and everything below either unpacks it or follows from it.

An everyday example is worth having in place before the notation arrives. A lift in a building reports only which floor it is on. Most of the time nothing has changed, so nothing is reported at all. Then a report arrives. Two entirely separate facts govern what is observed: how often reports come, and how many floors the lift moved when one did. Knowing that reports arrive about twice a day says precisely nothing about whether the lift went up one floor or fell fourteen. The second fact is needed, and no amount of staring at the first will produce it.

What does a jump add that a continuous path cannot produce?

A jump produces a move that skips. The one word skips is the honest answer, and it is doing all the work. Continuity means that a continuous path travelling from Rs 111/- to Rs 90/- has to be at Rs 100/- at some instant on the way. A jump of the same size is at Rs 111/- and then at Rs 90/-, and there is no instant at which it was at Rs 100/-. The value was crossed without ever being attained.

The distinction sounds like a technicality and is not. Every rule that watches for a level, every trigger, every barrier, every stop, is a rule about attainment. A continuous path cannot get past a level without touching it, so a rule that watches a level cannot be evaded. A path with a discontinuityA moment at which the path does not join up, so the value an instant before and the value an instant after are different and nothing lies between them. can get past a level without ever being at it, and every rule built on the earlier assumption quietly changes meaning. Adding jumps does not make a model slightly rougher; it removes the guarantee that levels are attained, and that guarantee was load bearing.

One occurrence of a jump is called an arrivalOne occurrence of a jump. The word comes from counting: arrivals are what the counting process counts., and the word is worth adopting early because it keeps the two specifications apart. Arrivals are counted. Sizes are measured. Counting and measuring are different verbs applied to different objects, and confusing the two is the commonest error made about jumps.

One arrival at month six. Watch what the level never was. Rs 100/-, where the year started Rs 111.08/- an instant before Rs 89.64/- an instant after the same move made continuously, drawn faint, would sit on Rs 100/- at the marked instant the jump is never at Rs 100/- at any instant month 0 month 6 month 12 Same start, same finish, and only one of the two routes ever touched the marked level.
An arrival at month six takes the standard process from Rs 111.08/- to Rs 89.64/- with no instant in between, so Rs 100/- is crossed without ever being attained, while the faint continuous route of the same size sits on Rs 100/- at a definite moment.
Try it out

A jump moves the level from Rs 105/- to Rs 95/-. Did the process pass through Rs 100/-?

What does jump intensity fix, and what does it leave completely open?

The jump intensityThe average number of arrivals per unit of time. Written lambda. It governs counting and nothing else. fixes how often, and it leaves everything about how large completely open. The intensity is a single positive number, written lambda, and it is read as an average count per unit of time. Set to 0.5 a year, it says that arrivals come at an average rate of half of one per year. The intensity says nothing else at all.

From that one number the entire counting behaviour follows. The chance of seeing exactly nought, one, two or three arrivals inside a year is fully determined once lambda is fixed, and there is no freedom left in it. The appeal of the intensity is exactly that: a single figure settles a whole distribution, and a single figure is easy to state, easy to compare and easy to put in a summary line. Hold on to that last observation. Ease of statement is what turns into the failure later.

What the intensity settles, in full
$$ \mathbb{P}\bigl(N^{J}_{T}=k\bigr) \;=\; e^{-\lambda T}\,\frac{(\lambda T)^{k}}{k!}, \qquad \mathbb{E}\bigl[N^{J}_{T}\bigr]\;=\;\lambda T $$
\(N^{J}_{T}\)the counting process at the horizon, being how many arrivals have happened by then. Written with the superscript J throughout this guide so it is never confused with \(\mathcal{N}\), the normal distribution used further down for the size
\(\lambda\)the intensity, being the average number of arrivals per unit of time. Set to 0.5 a year throughout
\(T\)the horizon, one year here, so that \(\lambda T\) is 0.5
\(k\)a count: nought, one, two and so on
\(k!\)the factorial of that count, being one for nought and one, two for two, six for three
What it says in wordsThe chance of seeing exactly a given number of arrivals inside the horizon is fixed entirely by the intensity multiplied by the horizon, and the average number of arrivals over the horizon is that same product, so one number settles the whole of the counting and leaves nothing about counting undecided.

With the locked figure in, the four chances come out. At an intensity of 0.5 a year over a one year horizon, the chance of no arrival at all is 0.606531, of exactly one is 0.303265, of exactly two is 0.075816 and of exactly three is 0.012636. Taking the first away from one gives the chance of at least one arrival, 0.393469. In roughly three years out of five nothing arrives at all, and that fact alone is what makes a low intensity feel so reassuring to read.

There is a second reading of the same number that is worth having, and it is the one that makes the intensity concrete. If arrivals come at an average rate of half of one a year, the average gap between one arrival and the next is two years exactly. The gap has a name, the waiting timeThe gap between one arrival and the next, or between now and the first arrival. It is itself random, with a distribution set by the intensity., and it is itself random rather than fixed. The waiting time has a distribution, and the distribution is settled by the intensity too.

How long until the next arrival
$$ \mathbb{P}(\tau > t) \;=\; e^{-\lambda t}, \qquad \mathbb{E}[\tau] \;=\; \frac{1}{\lambda}, \qquad \text{median}(\tau) \;=\; \frac{\ln 2}{\lambda} $$
\(\tau\)the waiting time until the next arrival, measured in years
\(\lambda\)the same intensity, 0.5 a year
\(t\)an amount of elapsed time under consideration
\(\ln 2\)0.693147, the natural logarithm of two
What it says in wordsThe chance of still waiting after a given stretch of time falls away at a rate set by the intensity, the average wait is one divided by the intensity, and the wait that half of all waits come in under is the logarithm of two divided by the intensity, which is a shorter number than the average.

Run both through the locked intensity. The average wait is one divided by 0.5, or two years exactly. The median wait is 0.693147 divided by 0.5, or 1.386294 years. The average and the median are two different numbers describing the same waiting time, and the gap between them is not a rounding artefact. Waiting times are skewed, so the typical wait is meaningfully shorter than the average wait, and a reader who treats the average as the typical case has already misread the intensity before ever reaching the size.

How long the wait runs, at an intensity of 0.5 a year. Two different waits, both correct. YEAR ONE 0.606531 chance the first arrival is still to come when the year ends 1.0 0.5 0.0 0 2 years 4 years 6 years typical wait 1.386294 years average wait 2.000000 years the same waiting time, measured two ways Every figure here came out of the intensity alone. Not one of them says how far the level moves.
At an intensity of 0.5 a year the chance that no arrival has happened by the end of the year is 0.606531, the typical wait is 1.386294 years and the average wait is 2.000000 years, and none of those three figures says anything about how large an arrival is.
Try it out

An intensity of 0.5 a year. What share of years see no arrival at all?

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Why is jump size a distribution rather than a single number?

Because arrivals are not all the same size, and a model that said they were would be making a claim nobody believes. The jump sizeHow large a move is when an arrival happens, given as a distribution rather than as a single number, because arrivals differ from one another. is therefore given as a shape: a distribution, with its own parameters, entirely separate from the intensity. Fixing the intensity says nothing about this shape. Fixing this shape says nothing about the intensity.

The size is almost always given as a proportional jumpA jump applied as a multiple of the level rather than as a fixed amount, so a five per cent fall is a five per cent fall whether the level is Rs 100/- or Rs 1,000/-. rather than as an amount in rupees, and there is a plain reason for that. A jump specified as a fall of Rs 20/- means something completely different at Rs 100/- and at Rs 1,000/-, and at Rs 15/- it would take the level negative. A jump specified as a multiplier behaves the same way at any level and can never take a positive level below zero. So the size is a multiplier, and the natural way to describe a multiplier is through its logarithm.

The size specification
$$ Y_i \;=\; e^{J_i}, \qquad J_i \sim \mathcal{N}\bigl(a,\,b^{2}\bigr), \qquad \mathbb{E}[Y_i] \;=\; e^{\,a+b^{2}/2} $$
\(Y_i\)the multiplier applied at the i-th arrival, so the level goes from \(S\) to \(S\,Y_i\)
\(J_i\)the logarithm of that multiplier, and the distribution is placed on that logarithm
\(\mathcal{N}\)the normal distribution. Written in this script so it is never read as \(N^{J}\), the counting process above
\(a\)the average of the logarithm of the multiplier. Minus 0.05 throughout this guide
\(b\)the standard deviation of that logarithm. 0.10 throughout this guide
What it says in wordsEvery arrival multiplies the level by a factor whose logarithm is drawn from a normal distribution with a stated average and a stated spread, so the size of an arrival is described by two numbers of its own, neither of which is the intensity and neither of which the intensity has any influence over.

Put the locked figures in. The logarithm of the multiplier has an average of minus 0.05 and a standard deviation of 0.10. The middle multiplier, the one half of all arrivals land below, is the exponential of minus 0.05, or 0.951229. On a level of Rs 100/- that is a fall to Rs 95.12/-. The average multiplier is not that number. The average multiplier is the exponential of minus 0.05 plus half of 0.01, giving 0.955997, or Rs 95.60/-. Averaging a multiplier and exponentiating the average of its logarithm are two different operations, and here they differ by 0.004768, or Rs 0.48/- on a Rs 100/- level.

The spread is what makes this a distribution rather than a figure. Run out the quantiles and the range is wide: the fifth percentile multiplier is 0.806957, a fall to Rs 80.70/-, and the ninety fifth is 1.121296, a rise to Rs 112.13/-. Note that last one. The average logarithm is negative, so the typical arrival is downward. Even so, the specification allows upward arrivals, and the chance an arrival moves the level up is 0.308538. Roughly three arrivals in ten are increases. The upward share is a fact about the size and could not have been recovered from the intensity by any route.

The size specification, on its own, with the intensity nowhere in it. Rs 80.70/- 1 in 20 below Rs 95.12/-, the middle arrival Rs 112.13/- 1 in 20 above arrivals that move the level down: 0.691462 arrivals that move it up: 0.308538 no change The same shape magnified around its centre, so two figures that look identical above come apart 0.004768 apart, or Rs 0.48/- middle 0.951229 average 0.955997 0.945 0.950 0.955 0.960 0.965 Two parameters produced every number on this figure, and neither of them was the intensity.
With the logarithm of the multiplier averaging minus 0.05 at a spread of 0.10, the middle arrival takes Rs 100/- to Rs 95.12/-, one arrival in twenty falls past Rs 80.70/-, one in twenty rises past Rs 112.13/-, and the average multiplier of 0.955997 sits 0.004768 above the middle one.
Try it out

Is the jump size a number or a distribution?

Try it out

The logarithm of the multiplier has an average of minus 0.05. Is the average multiplier therefore 0.951229?

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Why are the two set separately rather than rolled into one figure?

Because they are separate facts about the world, they are estimated by different means, they are argued about by different people, and rolling them together would destroy information that the model needs. The separation is the organising idea here, so it is worth taking slowly.

Start with what the separation means formally. The counting and the sizes are independent of each other. Independence here is a precise claim rather than a loose one. The chance of a particular count and the chances of particular sizes multiply. Nothing about the count shifts the size distribution and nothing about the sizes shifts the count distribution. Independence is not an approximation made for convenience. Independence is written into the specification as a condition, and any model that wants the two linked has to say so and pay for it in extra parameters.

The independence, written out
$$ \mathbb{P}\bigl(N^{J}_{T}=k,\; Y_1\in A_1,\dots,Y_k\in A_k\bigr) \;=\; \mathbb{P}\bigl(N^{J}_{T}=k\bigr)\prod_{i=1}^{k}\mathbb{P}\bigl(Y_i\in A_i\bigr) $$
\(N^{J}_{T}=k\)the event that exactly k arrivals happened by the horizon
\(Y_i\in A_i\)the event that the i-th multiplier landed in some stated range
\(\prod\)a product taken over the arrivals, one factor for each
\(A_i\)any range of multipliers under consideration, such as a fall of more than a fifth
What it says in wordsThe chance of seeing a given number of arrivals with given sizes is the chance of that number multiplied by the separate chance of each size, so the count carries no information about the sizes and the sizes carry no information about the count, and this factorisation is the formal content of the claim that the two specifications are independent.

Now the practical half, and it matters more. The two are estimated by different means. Counting how often something happened is a question about frequency, and frequency is the easier of the two to pin down because every quiet stretch is evidence: a decade with two arrivals is real information about the intensity. Measuring how large arrivals are is a question about magnitude, and magnitude is far harder. The whole point of the specification is the rare large move, and rare large moves are, by construction, the ones observed least often. The intensity is estimated from many observations of nothing happening. The size distribution is estimated from a handful of observations of something happening, and the second is always the weaker of the two.

The asymmetry in the evidence is why the two are argued about differently. A disagreement about the intensity is a disagreement about a count, and counts can be compared. A disagreement about the size distribution is a disagreement about the shape of a tail, and two people can hold wildly different views of a tail without either being contradicted by anything on record. Fold the two into one number and that whole argument disappears from view without being settled. For a quantity nobody is confident about, that is exactly the wrong outcome.

Two specifications. One process. No wire between them. HOW OFTEN: THE INTENSITY 0.5 a year chance of no arrival in a year 0.606531 average wait between arrivals 2 years Settles the count. Settles nothing else. HOW LARGE: THE SIZE SHAPE log average minus 0.05, spread 0.10 middle arrival takes Rs 100/- to Rs 95.12/- about 3 arrivals in 10 move the level up Settles the size. Settles nothing else. NO INFLUENCE neither reads the other ONE JUMP PROCESS, AND IT NEEDS BOTH Take either box away and the process is not specified. Change either box and the other is untouched. The crossed link is the claim: knowing one box says nothing at all about the other.
The intensity settles the counting and the size shape settles the magnitude, the crossed link between them carries no information in either direction, and a jump process needs both boxes because neither can be recovered from the other.
Try it out

At an intensity of 0.5 a year, what is the average waiting time between arrivals?

What do the two specifications say about one year of the standard process?

Now both halves on the same year, with the result read off. The standard process starts the year at Rs 100/-, and here it is carried by arrivals alone so that the two specifications can be seen without anything else moving. The intensity is 0.5 a year. The size shape has a logarithm averaging minus 0.05 with a spread of 0.10. Nothing else is set, and nothing else needs to be.

The path, built from both halves
$$ S_T \;=\; S_0 \prod_{i=1}^{N^{J}_{T}} Y_i $$
\(S_T\)the level of the standard process at the horizon, in rupees
\(S_0\)the level at the start, Rs 100/- exactly
\(N^{J}_{T}\)how many arrivals happened, settled by the intensity alone
\(Y_i\)the multiplier at each arrival, settled by the size shape alone
\(\prod\)a product: the multipliers compound, they do not add
What it says in wordsThe level at the end of the year is the level at the start multiplied by one factor for each arrival that happened, so the count decides how many factors there are and the size shape decides what each factor is, and the two enter the same formula through two entirely different doors.

The formula shows the separation in the notation itself. The upper limit of the product comes from one specification. The thing being multiplied comes from the other. Changing the intensity changes the number of factors while every factor stays drawn from the same shape. Changing the size shape changes every factor while the number of them stays the same. The two specifications occupy two different positions in the same expression, and neither can be inferred from the other.

How the year turns outChanceWhere Rs 100/- lands on a middle arrival
No arrival at all0.606531Rs 100.00/-
Exactly one arrival0.303265Rs 95.12/-
Exactly two arrivals0.075816Rs 90.48/-
Exactly three arrivals0.012636Rs 86.07/-
At least one arrival0.393469varies with the count

Two readings of that table are worth making explicitly. The first: in a clear majority of years the standard process is untouched by this mechanism entirely, finishing at Rs 100.00/- because nothing arrived. The second: the right hand column was computed from the size shape and the left hand column from the intensity, and the two columns were produced by two calculations that share no input. With the right hand column covered, it cannot be reconstructed from what remains. With the left covered, that column cannot be reconstructed either.

One caution on the right hand column. The column is an illustration rather than a promise, and it shows where a middle sized arrival lands, compounding the multiplier 0.951229 once, twice and three times. A real year with two arrivals would compound two draws from the shape rather than two copies of its middle, and those two draws could be anything the shape allows, including one large fall and one rise. The column is there to show that the size half exists and is doing work, not to summarise it.

Try it out

The intensity is about to rise from 0.5 to 2.0 a year. Before it is moved: what happens to the size distribution drawn beside it?

Play with it

Move the intensity and watch the size specification refuse to respond

The left panel is computed from the intensity. The right panel is computed from the size shape. One slider moves the first specification. The second is recomputed from scratch on every single move, and the ledger underneath records whether any of its five figures ever changed.

One slider. One panel answers to it. The other does not. WHAT MOVES: THE COUNTING CHANCES chance of exactly this many arrivals in one year none one two three chance of at least one arrival in the year 0.393469 WHAT DOES NOT MOVE: THE SIZE SHAPE where one arrival takes the level, as a multiplier middle arrival Rs 95.12/- no change down 0.691462 up 0.308538 HELD FIXED ON PURPOSE log average minus 0.05, spread 0.10, at every setting If the right panel ever moved, the two specifications would not be independent.
0.1 a year1.02.03.0 a year
Intensity
0.5
No arrival
0.606531
At least one
0.393469
Average wait
2.00 yrs
At an intensity of 0.5 a year the chance of no arrival is 0.606531 and the chance of at least one is 0.393469, the average wait between arrivals is 2.00 years, and the size shape beside it is unchanged: the middle arrival still takes Rs 100/- to Rs 95.12/-.
These answered the slider
No arrival0.606531at default
Exactly one0.303265at default
Exactly two0.075816at default
Exactly three0.012636at default
Average wait2.00 yrsat default
These were recomputed and did not
Middle arrivalRs 95.12/-unchanged
Average arrivalRs 95.60/-unchanged
One in twenty belowRs 80.70/-unchanged
One in twenty aboveRs 112.13/-unchanged
Chance an arrival is upward0.308538unchanged
The right hand column has been recomputed 0 times so far, and has returned the same five figures on 0 of those 0 occasions.
Educational illustration. Every chance here is computed from the counting formula rather than sampled, so the default intensity of 0.5 reproduces the worked figures of 0.606531, 0.303265, 0.075816 and 0.012636 exactly on every reload. The horizon is one year throughout. The size shape is held at a logarithm average of minus 0.05 and a spread of 0.10 on purpose: it is recomputed from those two constants on every move of the slider, and the ledger records that the answer never differs, because the intensity is not an input to it.
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What breaks in a model that assumed the path never jumped?

Three things break, and they break in order, each one because of the one before it. The temptation is to think of jumps as an addition. What jumps actually do is withdraw permissions, and the order of the three is worth walking through slowly.

The first is continuity itself, and it fails outright rather than partially. A path with arrivals is not a continuous path with a rough patch; it is a path that is discontinuous at certain moments and continuous everywhere else, and the definition of continuity is not the kind of thing that survives a single exception. Everything that was licensed by continuity has to be re-derived or dropped.

The second follows immediately. Continuity was what forced a small step in time to produce a small move in level. Removing it removes that implication: an interval of one second can contain an arrival, and an arrival is not small. A great deal of practical reasoning silently assumes that watching more often means seeing smaller moves, and losing that guarantee is more disruptive than it sounds. On a path with arrivals, watching more often does not shrink the moves observed. Watching more often only shrinks the chance of seeing a move at all.

The third is the one this reading order has been building toward. On a continuous path the sum of squared changes settled on the elapsed time. On a path with arrivals it does not, and the reason is exact rather than approximate.

What the squared total becomes
$$ [X]_T \;=\; \underbrace{[X^{c}]_T}_{\text{from the continuous part}} \;+\; \underbrace{\sum_{0
\([X]_T\)the quadratic variation of the path over the horizon, being the limit of the sum of squared changes
\([X^{c}]_T\)the part contributed by the continuous movement, which is the elapsed time scaled by the variance rate
\(\Delta X_s\)the size of the jump at the moment s, being the level just after less the level just before
\(\sum_{0a sum over the moments at which an arrival happened, and over no other moments
What it says in wordsThe squared total splits cleanly into a piece that accumulates gradually from the continuous movement and a piece that is the sum of the squared jump sizes, and the second piece is added in complete lumps at single instants, so the total is no longer the elapsed time and no refinement of the grid will make it so.

The second term has a clear origin. A continuous path builds its squared total gradually, a sliver at a time, and each piece contributes in proportion to its own length. Refining the grid therefore does not change the answer. An arrival contributes its entire squared size at one instant. No grid can split an instant, so the same amount is contributed whatever grid is used. Refining the grid shrinks every contribution from the continuous part and shrinks nothing at all from the arrivals. The squared total therefore gains a term that has no relationship to elapsed time.

Put the locked numbers on it. Over one year the continuous part of the logarithm of the standard process contributes 0.040000, being the variance rate multiplied by the elapsed year. A single arrival of middle size adds the square of minus 0.05, or 0.002500, taking the total to 0.042500. Averaged across all years at an intensity of 0.5, the arrivals contribute 0.006250, being the intensity multiplied by the average squared logarithm of the multiplier, so the expected total is 0.046250. The expected total is 15.625 per cent above what the elapsed time alone would give, and every rupee of it came from the size specification.

The squared total over one year, built in two pieces that arrive in completely different ways. the dashed line marks what the elapsed time alone gives: 0.040000 0.040000 THE CONTINUOUS PART built up a sliver at a time plus 0.006250 THE ARRIVALS delivered whole, at single instants a middle sized single arrival adds 0.002500 0.046250 THE TOTAL 15.625 per cent above the elapsed time reading shrinks as the grid refines refining changes it by nothing so the equality is gone No grid can split an instant, so no refinement can shrink the middle bar.
Over one year the continuous part contributes 0.040000 to the squared total and the arrivals add 0.006250 in expectation at an intensity of 0.5, giving 0.046250, which is 15.625 per cent above what the elapsed time alone would have given.
Each property revisited in turn. None of the three is patched; each is withdrawn. ONE: THE PATH JOINS UP Held on every path built in this reading order so far. FAILS OUTRIGHT TWO: SMALL STEP, SMALL MOVE Followed from the first, and falls with it immediately. FAILS WITH IT THREE: SQUARED TOTAL IS TIME Gains a term of 0.006250 that is not made of time. EQUALITY IS GONE One assumption withdrawn at the left, and the two boxes to its right follow without any further argument. A jump is not a rough patch on a continuous path. It removes what the continuity was licensing.
Continuity fails outright once arrivals enter, the guarantee that a small time step gives a small move falls with it, and the squared total gains a term of 0.006250 that is not made of elapsed time.

There is a further consequence in the drift. Because arrivals move the level on average, a model that wants its average growth to stay where it was has to subtract the average effect of the arrivals from the drift, and the adjustment that does this is called the compensatorThe adjustment that removes the average effect of the arrivals from the drift, so that what is left has no built in tendency of its own.. Putting arrivals and continuous movement into one model together is covered separately.

Try it out

Why does the squared total stop being the elapsed time once arrivals enter?

The error that gets made, and what it costs

Reading a low intensity as a small risk. The intensity is a real fact about the model, it is the easier of the two halves to state, and it sounds like a summary. No misreading is more natural. An intensity of 0.5 a year means that nothing arrives in 60.7 per cent of years. The intensity says nothing whatever about the other 39.3 per cent. A specification the intensity has no contact with settles what happens in those years.

The demonstration is short and it is decisive. Take three models that share the intensity of 0.5 a year exactly. Give the first a size shape whose logarithm averages minus 0.005 with a spread of 0.01, so a middle arrival takes Rs 100/- to Rs 99.50/-. Give the second the locked shape, so a middle arrival takes it to Rs 95.12/-. Give the third a shape whose logarithm averages minus 0.50 with a spread of 0.30, so a middle arrival takes it to Rs 60.65/-. All three produce identical counting chances of 0.606531, 0.303265, 0.075816 and 0.012636, and all three are exactly as consistent with the quoted intensity as each other. The squared movement the arrivals add over a year is 0.000063 in the first and 0.170000 in the third, a factor of 2,720 between two models that a frequency summary would report identically.

The cost lands as a risk figure summarised by the frequency alone, and the error is close to invisible because nothing about it is false. The frequency is right. The arithmetic behind it is right. The missing part is the half of the specification that carries all of the consequence, and the summary line has no gap in it where that half should have been. Somebody reading it sees a complete sentence about a rare event and has no way to tell that the sentence describes only how rare, and not at all how bad.

Three models. One shared intensity. Compare the top halves, then the bottom halves. MODEL WITH TINY ARRIVALS intensity 0.5 a year counting chances 0.607 0.303 0.076 0.013 one middle arrival takes Rs 100/- to Rs 99.50/- a fall of Rs 0.50/-, barely a line here squared movement added in a year 0.000063 THE MODEL IN THIS GUIDE intensity 0.5 a year counting chances 0.607 0.303 0.076 0.013 one middle arrival takes Rs 100/- to Rs 95.12/- a fall of Rs 4.88/- squared movement added in a year 0.006250 MODEL WITH SEVERE ARRIVALS intensity 0.5 a year counting chances 0.607 0.303 0.076 0.013 one middle arrival takes Rs 100/- to Rs 60.65/- a fall of Rs 39.35/- squared movement added in a year 0.170000 Identical top halves. A factor of 2,720 between the bottom halves of the outer two.
Three models sharing an intensity of 0.5 a year produce identical counting chances of 0.606531, 0.303265, 0.075816 and 0.012636, while a middle arrival takes Rs 100/- to Rs 99.50/-, Rs 95.12/- or Rs 60.65/- depending only on the size shape, a spread of 2,720 times in the squared movement added.
The artefact the mistake actually arrives in, and it contains no wrong number. MODEL NOTE, ONE PAGE, INVENTED Sudden move risk Jump intensity 0.5 a year Years with no arrival at all 60.7 per cent Jump size shape no entry anywhere on the note Conclusion: arrivals are infrequent, so the exposure is small. Every figure above is correct. WHY NOBODY CATCHES IT The note contains no error. The intensity is a real property of the model and 60.7 per cent follows from it exactly. What is absent is the half that carries the consequence, and the sentence reads complete without it. Only how rare. Never how bad. A summary can be entirely accurate and still describe none of what matters.
A note quoting an intensity of 0.5 a year and no size shape at all contains no wrong figure, yet the line it leaves blank is the one that decides what an arrival costs.
Try it out

A model has an intensity of 0.5 a year. What does that say about the size of an arrival?

A path that never jumps prices the tail at nothing. See what jumps carry.

How does somebody reading another model use this rather than building one?

The move is a question rather than a calculation, and it works on somebody else's model without any access to how their figures were produced. Whenever a jump risk is described, both halves of the specification are to be found before any view is formed at all. If only one half is present, the description supplied is not a description of the risk but a description of the frequency.

An everyday version makes the discipline obvious. The statement that a road floods about twice a decade conveys something real and conveys nothing about whether the flood is ankle deep or waist deep. Nobody would accept the first sentence as a description of the risk of living on that road, and yet the same sentence in a model note routinely passes. The test is not whether the figure quoted is correct; it is whether the figure quoted is one of two figures or both of them.

  1. Find the intensity, and then find the size shape The size shape needs both a centre and a spread, so two separate numbers at minimum and usually three. A description carrying only the first is incomplete by construction rather than by oversight.
    In this guide the two halves are 0.5 a year, and a logarithm averaging minus 0.05 at a spread of 0.10.
  2. Ask what the size shape allows at its extremes, not at its centre Arrivals matter through their tail, so the centre of the shape is the least interesting thing about it. Ask where the fifth and the ninety fifth percentile sit before asking where the middle sits.
    The locked shape puts one arrival in twenty past Rs 80.70/- and one in twenty past Rs 112.13/-.
  3. Ask which half the evidence actually supported The intensity is estimated from long quiet stretches and is usually the better supported of the two. The size shape is estimated from the few arrivals on record and is usually the weaker. A model that speaks with equal confidence about both has not said where its confidence came from.
    A decade with two arrivals is real evidence about the count and two observations about the size.
  4. Change one half and see whether the conclusion survives Hold the intensity and widen the size shape, then do the reverse. If the headline conclusion is unmoved by a large change in the size shape, the conclusion was never about the risk.
    Three models at the same intensity ranged from 0.000063 to 0.170000 in squared movement added.

None of those four steps needs data, software or market access. The four steps are questions asked of a description somebody else wrote. The fourth resolves most disagreements on its own. A conclusion that survives a factor of 2,720 change in the size shape has announced that it was reading only the frequency.

Universality deserves one closing note. People often look for a rule here. No authority anywhere sets what an intensity is or what a size distribution has to be. No jurisdiction publishes a value for either, and no convention alters the counting formula or the way the squared total splits. The mathematics is the same everywhere and belongs to nowhere.

The counting process that generates the arrivals is treated on its own and comes next. The general class of processes built out of jumps is covered separately. Putting arrivals and continuous movement into a single model is covered separately and closes this stretch of the subject. What any contract pays is a separate subject, and estimating either half from observed data sits under quantitative methods.
Breaking Into Quants Bootcamp — Fin Maverick

References

SourceDocumentWhere
arXiv Quantitative FinancePreprint repository for jump specifications, arrival intensities and size distributionsarxiv.org
Social Science Research NetworkWorking paper repository for the same materialssrn.com
Merton, 1976The proportional jump specification with a normally distributed logarithm that carries his namenamed in the text only
Hull, Shreve and WilmottStandard texts on jump specifications, notation and orderingnamed in the text only

The standard process is invented.
Educational material. Not advice on any investment, tax, budget or market position.

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