Fin Maverick
Foundations VocabularyAccounting & ReportingEconomics & MacroQuant Methods & ProgrammingBusiness & Company AnalysisCorporate Finance & ValuationBehavioural Finance
Banking & Market InfrastructureFixed Income & RatesDerivatives & Structured ProductsPublic EquitiesTransactions & DealsPortfolio ConstructionFunds & AMCs
Private Markets & AlternativesRisk, Treasury & ControlAI & Digital FinanceStochastic Calculus & PricingWealth & Personal FinanceIndian Markets & RegulationProfessional Practice
CalculatorComparison
Frameworks
Explore Bootcamps
Equity ResearchPortfolio ManagementMutual Fund MasteryFinancial LiteracyInvestment Banking Analyst
Private Equity AnalystHedge Funds AnalystBreaking Into VCBreaking Into QuantsAI For Finance
Financial Analyst ProgramRisk Management ProgramPrivate Wealth ManagementDebt Capital MarketsDerivatives Foundation
Explore Internships
Equity Research InternMutual Fund Intern
Portfolio Management InternFinancial Literacy Intern
Explore Micro Courses

Equity Research6

Writing an Investment ThesisBuilding a Discounted Cash FlowReading an Annual Report FastReading a Sector Before a CompanySpotting Quality of Earnings Red FlagsBuilding a Revenue Forecast From Drivers

Portfolio Management3

Rebalancing: When, Why and What It CostsStrategic and Tactical Asset AllocationMeasuring Risk in a Portfolio

Mutual Fund Mastery3

Comparing Funds Without Being FooledHow a NAV Is Struck and Which Day You GetReading a Fund Factsheet Properly

Derivatives Unlocked4

Hedging a Real ExposureThe Greeks, PracticallyFutures, the Basis and What Moves ItReading an Option Payoff

AI For Finance2

Retrieval and Grounding for FinanceDocument Extraction in Finance

Breaking Into Quants4

Backtesting a StrategyHypothesis TestingCleaning Financial DataRegression for Finance

Breaking Into VC3

Sizing a MarketReading a Term Sheet as a FounderHow a Venture Round Actually Works

Financial Analyst Program4

Common Size and Trend AnalysisReading a Cash Flow StatementRatio Analysis That Says SomethingBuilding a Working Capital Schedule

Risk Management Program2

Credit Exposure and How It Is ReducedValue at Risk and What It Hides

Investment Banking Analyst3

Precedent Transactions and Why They DifferReading a Term Sheet StructurallyBuilding a Comparable Companies Table

Private Wealth Management3

Tax Aware Portfolio DecisionsBuilding a Client Risk ProfileGoal Based Planning Arithmetic

Debt Capital Markets3

Analysing an Issuer's CreditDuration and What It Does Not Tell YouBond Pricing and Yield Mechanics

Private Equity Analyst2

Fund Waterfalls and CarryThe LBO in Structure

Hedge Funds Analyst2

Short Selling MechanicsLong Short Mechanics
Courses
Explore Career Roadmaps
Investment Banking AnalystEquity Research AnalystVC AnalystPrivate Equity AnalystHedge Funds Analyst
Quant AnalystAI For FinanceFinancial Analyst ProgramPrivate Wealth ManagementDebt Capital Markets
Risk Management ProgramDerivatives FoundationPortfolio ManagementMutual Fund Mastery
PartnershipsShowdown
Log inSign up
Stochastic Calculus & Derivative Pricing Theory
1Probability Foundations
The Probability SpaceRandom VectorsSigma-AlgebraExpectationSample Space and EventsDensity and Distribution FunctionsRisk-Neutral ProbabilityState Price Density vs…
2Stochastic Processes and Jumps
Properties of a Stochastic ProcessMartingaleBrownian Motion and Its PropertiesBrownian Motion vs Geometric…Stopping TimeThe Markov PropertyState VariablesTransition ProbabilityQuadratic VariationQuadratic Variation vs Ordinary…Submartingale and SupermartingaleMartingale RepresentationMarkov Process vs MartingaleOptional StoppingFiltrationJump ProcessesThe Poisson ProcessLevy ProcessesJump Diffusion
3Ito Calculus
The Ito IntegralThe Ito Integral vs the Riemann IntegralInfinitesimals in Stochastic CalculusQuadratic CovariationIto's LemmaHow to Apply Ito's…The Infinitesimal GeneratorIto Calculus vs Ordinary Calculus
4Stochastic Differential Equations
Stochastic Differential EquationsStochastic Differential Equation vs…Drift and DiffusionStrong and Weak Solutions ComparedDiscretisationGeometric Brownian Motion
5Pricing Theory and No-Arbitrage
No-ArbitrageGirsanov, Radon-Nikodym and Change…Physical and Risk-Neutral Measures…The Fundamental Theorems of…The Law of One PriceThe Pricing KernelDiscount Factors and Zero-Coupon PricesReplication vs HedgingComplete Market vs Incomplete MarketClearing Margin Architecture
6Option Pricing Theory
European and American OptionsMonte Carlo European OptionThe Black-Scholes PDEBlack Scholes and the GreeksThe Payoff FunctionThe Binomial ModelBinomial Option PricingDelta Hedging in TheoryBoundary, Initial and Terminal ConditionsThe Exercise BoundaryHow to Check Put-Call…
7Volatility Models
Constant, Local and Stochastic…Vasicek Model vs CIR ModelThe Heston ModelThe SABR ModelThe Volatility ProcessImplied VolatilityVolatility Smile vs Skew vs Surface
8Interest Rate Models
Interest-Rate DerivativesMean ReversionThe Zero-Coupon BondThe Ornstein-Uhlenbeck ProcessThe Discount CurveZero RatesShort-Rate Model vs Market Model
9Numerical Pricing
Closed Form and Numerical…Monte Carlo PricingEuler and Milstein Schemes ComparedTree MethodsFinite Difference MethodsNumerical Error and StabilityVariance Reduction
10Calibration and Model Risk
Model OverrideMarket Price and Model PriceCalibrationHow to Document a Pricing ModelThe Educational Illustration LabelMarket ConventionsModel Uncertainty and LimitationsBacktesting a Pricing ModelIdentifiabilityCalibrated ParametersThe Calibration Loss Function

The Fundamental Theorems of Asset Pricing, Stated Plainly

The first theorem links no arbitrage to the existence of a pricing measure: one holds exactly when the other does. The second links completeness to that measure being the only one. Together they say that the assumption buys a price, and buys exactly one price only when every payoff can be built. Neither says how to find anything.

Two results carry the whole of this subject, and both of them are usually met in the wrong order. The notation comes first, a line of symbols with a double arrow in the middle, and the words arrive afterwards as a translation of something already skipped. Meeting the symbols before the sentences is why the two results get misquoted more than anything else in derivative pricing. Both statements read perfectly well in ordinary words, with no symbols at all, and both are set out that way below, before a single letter of notation appears. The notation comes second, as a compression of sentences already agreed to, and by then it has nothing left to hide.

Every worked number runs on one invented quantity, called the standard process and written S with a time subscript. The standard process starts at Rs 100/-. Its volatility is 20 per cent a year. The risk-free rate is 5 per cent a year, continuously compounded, so cash grows by a factor of 1.051271 over the one year horizon and the discount factor back is 0.951229. A single change to the worked instance, adding one outcome and nothing else, moves it from the world where both theorems bite to the world where only the first one does, and both worlds can be computed to six decimal places.

What do the two results say, before any notation at all?

Here are both results, in words. Both repay a second reading. Everything that follows is these two sentences worked out.

The first result, in words

There is no way to make something out of nothing exactly when there is a consistent set of weights under which the discounted value of every traded thing is, on average, what it is worth today.

The second result, in words

Every payoff that could be written down can be built out of what is already traded exactly when that consistent set of weights is the only one there is.

The two sentences just given are the first fundamental theoremThe result linking the absence of arbitrage to the existence of a set of pricing weights, in both directions. and the second fundamental theoremThe result linking the ability to build every payoff to those pricing weights being the only ones, in both directions. of asset pricing. The set of weights has a name, the pricing measure, and its construction is covered separately rather than introduced here. The ability to build every payoff out of what is already traded has a name too, completenessThe property of a market in which every payoff can be reproduced exactly by trading what is already priced.. Completeness itself is defined separately.

Consider what neither sentence contains. Neither says how to find the weights. Neither says what the weights are. Neither says whether a particular market has the building property or not. Each one says that two things go together, and stops. The entire content of both results is that two conditions are the same condition wearing different clothes. Saying so is worth a great deal, and it is not the same as being handed a number.

The abstraction is doing a lot of lifting. Here is an everyday version. Suppose a set of scales is handed over, without any sight of the weights inside, together with an assurance that whatever weights are inside the machine, they are consistent: the same object placed on it twice reads the same, and two objects together read the sum of their separate readings. The assurance is a statement of exactly the kind these theorems make. The assurance rules out an enormous amount of nonsense, and it does not say what any object weighs.

Breaking Into Quants Bootcamp — Fin Maverick

What does the first result link, and which way does the link run?

The first theorem links two conditions. On one side, no arbitrage: there is no trade that can be put on today, costing nothing, that can never lose and might win. On the other side, the existence of a pricing measure: a set of weights on the future outcomes, positive on every outcome the real world thinks is possible, under which the discounted value of the traded process is on average today's value.

The result says those two conditions hold together and fail together. Not that the first causes the second, not that the second is evidence for the first. No arbitrage and the existence of a pricing measure are the same condition. The names attached to it are Harrison and Kreps, 1979, and Harrison and Pliska, 1981, who established it in the finite and the discrete-time settings, and Delbaen and Schachermayer, 1994, whose version handles the continuous-time case, where the plain phrase no arbitrage has to be sharpened before the statement is true at all. The sharpening is real work and is covered separately, and the shape of the result survives it exactly.

The first result, now in notation
$$ \text{no arbitrage} \;\iff\; \exists\;\mathbb{Q}\sim\mathbb{P}\;\text{ such that }\; \frac{S_t}{B_t}\;\text{is a }\mathbb{Q}\text{-martingale} $$
\(\mathbb{P}\)the physical measure, the weights the real world puts on outcomes
\(\mathbb{Q}\)the pricing measure, a different set of weights on the same outcomes
\(\sim\)equivalent, meaning the two measures agree about which outcomes are possible at all, and disagree only about how much weight each one carries
\(S_t\)the standard process at time \(t\), an invented quantity starting at Rs 100/-
\(B_t\)the value of cash held at the risk-free rate, growing to 1.051271 over the horizon
\(\iff\)holds exactly when, in both directions
What it says in wordsThere is no way to make something out of nothing exactly when there exists a second set of weights, agreeing with the real world about what is possible, under which the process divided by cash has today's value as its average future value.

The equivalent word in that term table is the one people drop, and dropping it breaks the result. A set of weights that put zero on an outcome the real world thinks can happen would price away a genuine possibility, and the theorem would be false. The pricing measure is allowed to disagree with the real world about how likely anything is, and is not allowed to disagree about what is possible.

What does the second result link, and which way does that link run?

The second theorem also links two conditions, and it takes the first one as already settled. Assume there is no arbitrage, so at least one pricing measure exists. Then: the market is complete exactly when that pricing measure is the only one.

UniquenessThere being exactly one object with the stated property, rather than at least one. is the whole of the second result, and it is a much stronger claim than existence. Existence says the set of pricing measures is not empty. Uniqueness says it has exactly one member. Between those two sits everything interesting: the set could be empty, could have one member, or could have infinitely many, and which of the three holds decides whether a payoff has a price, one price, or a range of them.

The second result, now in notation
$$ \text{every payoff is attainable} \;\iff\; \mathcal{Q} \;=\; \{\mathbb{Q}\}\;\text{ has exactly one member} $$
\(\mathcal{Q}\)the set of all pricing measures equivalent to \(\mathbb{P}\), which the first result says is not empty
\(\mathbb{Q}\)a pricing measure, one member of that set
attainablereproducible exactly by holding some quantity of the process and some amount of cash, with no money added or taken out along the way
\(\iff\)holds exactly when, in both directions
What it says in wordsAssuming no arbitrage, every payoff that could be written down can be reproduced by trading the process and cash exactly when the set of pricing measures has precisely one member in it.

The everyday version is counting. Suppose a jar is known to hold fourteen coins worth Rs 100/- in total, and the coins come in exactly two denominations. Two facts, two unknowns, and the composition is pinned: there is one answer and it can be found. Now allow three denominations. The same two facts are still true, they still rule out most compositions, and they no longer pin one. The question has moved from one with an answer to one with a range of answers, and nothing about the two facts got weaker. The second theorem is that arithmetic and nothing more: as many independent instruments as outcomes pins the weights, and one instrument short of that leaves a range.

Which result applies is settled by which question is being asked. WHAT IS BEING ASKED? Is there a price at all? Is it the only price? Which price inside the range? THE FIRST RESULT existence THE SECOND RESULT uniqueness NEITHER RESULT both are silent here Most misquoting comes from answering the middle question with the left result, or the right question with either.
The question being asked decides which result applies, and the third question, which price to pick inside a range, is answered by neither of them.

Why is each result an equivalence rather than a one way street?

Both results are stated with a double arrow, and the double arrow is not decoration. An equivalenceTwo conditions that stand or fall together, so establishing either one establishes the other. is two implications bundled: the left gives the right, and the right gives the left. Running both ways is what makes these results usable from either end, and it is exactly the property that gets lost when somebody quotes them as a slogan.

The first result read rightwards starts from the assumption that there is no arbitrage and concludes that a pricing measure exists. The rightward reading licenses the whole apparatus of pricing by expectation: it says the object the computation needs is there to be computed with.

Read leftwards, the same result starts from a pricing measure exhibited by construction, on a lattice or in a model, and concludes that the market has no arbitrage in it. Exhibiting one set of weights is a finite job, and checking every possible trade for arbitrage is not, so the leftward direction is the one that does the work in practice. The leftward direction is how anybody ever verifies a model is arbitrage free: build one measure, and the theorem does the rest.

The same holds for the second result. Rightwards: assume every payoff can be built, conclude the measure is the only one. Leftwards: show that two different measures both work, conclude that some payoff cannot be built. The second direction is how incompleteness is usually demonstrated, and it is precisely what the worked instance below does, by exhibiting a whole interval of measures.

Each result is a two way link between two conditions, never a one way implication. THE FIRST RESULT no arbitrage nothing out of nothing a pricing measure exists at least one set of weights holds exactly when usable from either end THE SECOND RESULT every payoff builds out of what is traded that measure is the only one the set has one member holds exactly when usable from either end Read left to right, each result shows what the assumption buys. Read right to left, each shows how to verify the assumption. Quoting either one as a single arrow throws away the half that gets used most.
Each result joins two conditions with an arrow that runs both ways, so establishing either condition delivers the other and the result can be worked from whichever end is easier.
Try it out

Is the first result a one way implication?

Risk Management Program Bootcamp — Fin Maverick

What happens in the balanced case, two outcomes against two instruments?

Time to make all of this arithmetic. One step, one year, the standard process starting at Rs 100/-. Over the step it moves to one of two values: up to Rs 122.140276/- or down to Rs 81.873075/-. Cash held at the risk-free rate grows from 1 to 1.051271 over the same step. The process and cash are the only two instruments in existence here.

Try it out

Two outcomes and two instruments. How many pricing measures should be expected?

The pricing measure here is a single number: the weight on the up outcome, with the rest going to the down outcome. The condition it has to satisfy is the one in the first result, that the discounted average of the two outcomes is today's value. The condition is one equation in one unknown, and one equation in one unknown has one answer.

The weight, solved
$$ q \;=\; \frac{e^{rT}-d}{u-d} \;=\; \frac{1.051271-0.818731}{1.221403-0.818731} \;=\; 0.577493 $$
\(q\)the weight the pricing measure puts on the up outcome, with \(1-q=0.422507\) on the down outcome
\(u\)the up factor, 1.221403, taking Rs 100/- to Rs 122.140276/-
\(d\)the down factor, 0.818731, taking Rs 100/- to Rs 81.873075/-
\(e^{rT}\)the growth of cash over the horizon, 1.051271 at \(r=0.05\) and \(T=1\)
What it says in wordsThe one weight that makes the average of the two outcomes grow at exactly the rate cash grows is the distance from the down factor to the cash factor, divided by the whole distance between the two factors, and on these numbers it is 0.577493.

Now hand over a payoff, as numbers, with no explanation of what produced it. The payoff pays Rs 22.140276/- if the process finishes at Rs 122.140276/-, and nothing if it finishes at Rs 81.873075/-. Those two numbers are the entire specification. The argument never needs to know what contract produced them: a payoff is a list of numbers attached to outcomes, and the machinery prices lists.

The price of the payoff
$$ V_0 \;=\; e^{-rT}\,\mathbb{E}^{\mathbb{Q}}[X] \;=\; 0.951229\times\bigl(0.577493\times 22.140276 \;+\; 0.422507\times 0\bigr) \;=\; 12.162285 $$
\(V_0\)the price today, in rupees, Rs 12.162285/-
\(X\)the payoff handed over as numbers: Rs 22.140276/- at the up outcome, nothing at the down outcome
\(\mathbb{E}^{\mathbb{Q}}\)the average taken under the pricing measure, not under the physical measure \(\mathbb{P}\)
\(e^{-rT}\)the discount factor over the horizon, 0.951229
What it says in wordsThe price is the average of the payoff taken with the pricing weights and then discounted back, which on these numbers is Rs 12.162285/- and is the only number consistent with no arbitrage.
Two outcomes, two instruments, one weight that works. CASH GROWS BY 1.051271 TODAY Rs 100/- weight 0.577493 weight 0.422507 UP OUTCOME Rs 122.140276/- DOWN OUTCOME Rs 81.873075/- PAYOFF HANDED OVER Rs 22.140276/- PAYOFF HANDED OVER nothing One equation, one unknown, one answer: the payoff prices at Rs 12.162285/- and at nothing else.
With two outcomes and two instruments exactly one weight satisfies the pricing condition, so the payoff handed over has exactly one price of Rs 12.162285/-.

Both results are satisfied here, and it is worth saying which does which. The first is satisfied because a measure exists: the number 0.577493 sits strictly between nothing and one, so it is a legitimate set of weights and no arbitrage is available. The second is satisfied because it is the only such number: the equation had one solution, so every payoff on this lattice can be built and every payoff has one price. The comfort of the balanced case comes entirely from the count of outcomes matching the count of instruments.

What changes when a third outcome appears and nothing else does?

Change one thing. The process can now finish at Rs 122.140276/-, at Rs 100/-, or at Rs 81.873075/-. The starting value has not moved. The rate has not moved. The up and down values have not moved. No new instrument has been introduced: there is still the process and there is still cash, and that is all. One outcome has been added to the list of things that can happen.

Try it out

A third outcome is about to be added, with no new instrument. Before the control below is moved: does no arbitrage still hold?

Play with it

Watch a single price open into a range

One step. Three outcomes: Rs 122.140276/-, Rs 100/- and Rs 81.873075/-. Two instruments only, the process and cash, and no new one is added at any setting. The control moves the weight on the up outcome across the whole permitted interval, from 0.231574 at the bottom to 0.577493 at the top, and the other two weights follow from the two conditions that all three weights sum to one and the discounted average returns Rs 100/-. The price of the payoff is 0.951229 times the up weight times Rs 22.140276/-, computed from that formula and never sampled, so it reproduces exactly on every reload. At the top the price is Rs 12.162285/-, exactly the two outcome price. At the bottom the price is Rs 4.877058/-, being Rs 100/- times one less the discount factor of 0.951229. Every value in between is a legitimate price, and no argument from no arbitrage picks one of them over another.

The marker moves. The permitted band does not. The check at the bottom never moves at all. THE PRICE OF THE PAYOFF, IN RUPEES ruled out ruled out 4 5 6 7 8 9 10 11 12 13 4.877058 12.162285 Rs 12.162285/- THE THREE WEIGHTS, WHICH ALWAYS SUM TO ONE 0.577493 0.422507 up outcome middle outcome down outcome THE CONDITION THAT NEVER BREAKS, RECOMPUTED AT EVERY SETTING 0.577493 times Rs 122.140276/- gives Rs 70.535534/- plus 0.000000 times Rs 100/- gives Rs 0.000000/-, plus 0.422507 times Rs 81.873075/- gives Rs 34.591576/- total Rs 105.127110/- discounted Rs 100.000000/- At the top of the range the middle outcome carries no weight, so the model has collapsed to the two outcome one.
weight 0.231574weight 0.577493
Price of the payoff
12.162285
Weight, up outcome
0.577493
Weight, middle outcome
0.000000
Weight, down outcome
0.422507
The control is at the top of the permitted range.
Assumptions on screen: one step over one year, two instruments only, being the standard process and cash at 5 per cent continuously compounded, and three outcomes. Every reading is computed from the pricing formula rather than drawn at random. Educational illustration built on invented parameters, describing no market anywhere.

So the answer to the prediction is that no arbitrage survives untouched. A pricing measure still exists: put 0.40 on the up outcome, 0.394284 on the middle and 0.205716 on the down, and check it. All three weights are positive, and their discounted average is exactly Rs 100/-. A measure exists, so by the first result there is no arbitrage. The first theorem is completely undisturbed by the third outcome, and only the second one breaks.

Why does one extra outcome leave a range instead of a price?

Count the equations. There are now three unknown weights. There are two conditions on them: they sum to one, and the discounted average of the three outcomes returns today's value. Three unknowns, two equations, and one degree of freedom left over. Every value of that free parameter which keeps all three weights positive is a legitimate pricing measure, and there is a continuous interval of them.

The system with three outcomes
$$ \begin{aligned} a + b + c &= 1 \\[2pt] a\,S_0u \;+\; b\,S_0 \;+\; c\,S_0d &= S_0\,e^{rT} \\[2pt] a > 0,\quad b &> 0,\quad c > 0 \end{aligned} $$
\(a\)the weight on the up outcome, Rs 122.140276/-
\(b\)the weight on the middle outcome, Rs 100/-
\(c\)the weight on the down outcome, Rs 81.873075/-
\(S_0e^{rT}\)Rs 105.127110/-, being today's value grown at the risk-free rate over the horizon
What it says in wordsThree unknown weights are held down by only two equations plus the requirement that each one is positive, so one degree of freedom survives and the solutions form a continuous interval rather than a single point.

The two equations do impose real structure, and it is worth seeing exactly what. Solving them shows that the weights move together in a fixed proportion: every unit of weight added to the up outcome forces exactly 1.221403 units onto the down outcome, and the pair of them is taken out of the middle weight. The middle weight therefore falls by 2.221403 units. The ratio of 1.221403 is not a rounding artefact. The up outcome overshoots today's value and the down outcome undershoots it in exactly that proportion, so the ratio is the up factor itself.

Which means the interval ends where one of the three weights runs out. Push the up weight down and the down weight vanishes first, at an up weight of 0.231574. Push the up weight up and the middle weight vanishes first, at 0.577493. Outside those two points a weight would have to be negative, and a negative weight is not a set of odds at all. The permitted weights form a closed interval from 0.231574 to 0.577493, and no argument from no arbitrage picks a point inside it.

Weight on upWeight on middleWeight on downDiscounted averagePrice of the payoff
0.2315740.7684260.000000Rs 100.000000/-Rs 4.877058/-
0.2800000.6608520.059148Rs 100.000000/-Rs 5.896935/-
0.3400000.5275680.132432Rs 100.000000/-Rs 7.160564/-
0.4000000.3942840.205716Rs 100.000000/-Rs 8.424193/-
0.4600000.2610000.279000Rs 100.000000/-Rs 9.687822/-
0.5200000.1277160.352284Rs 100.000000/-Rs 10.951451/-
0.5774930.0000000.422507Rs 100.000000/-Rs 12.162285/-
Every column is a legitimate pricing measure. The interval ends where a weight runs out. 1 0 a = 0.231574 Rs 4.877058/- no down weight a = 0.280000 Rs 5.896935/- a = 0.340000 Rs 7.160564/- a = 0.400000 Rs 8.424193/- a = 0.460000 Rs 9.687822/- a = 0.520000 Rs 10.951451/- a = 0.577493 Rs 12.162285/- no middle weight up outcome middle outcome down outcome Adding one unit to the up weight forces 1.221403 onto the down weight and takes 2.221403 from the middle.
Seven legitimate pricing measures on the same three outcomes, with the down weight vanishing at the left end of the interval and the middle weight vanishing at the right end.
Try it out

Three outcomes and two instruments. How many pricing measures are there?

And because the price of the payoff is a straight multiple of the up weight, the interval of measures becomes an interval of prices. The payoff pays only at the up outcome, so its price is the discount factor times the up weight times Rs 22.140276/-, or Rs 21.060482/- for every unit of up weight. Run the up weight across its permitted interval and the price runs from Rs 4.877058/- to Rs 12.162285/-, a price rangeThe interval of prices that no arbitrage permits when more than one pricing measure exists. Rs 7.285227/- wide on a payoff that a moment ago had one answer.

One outcome added, no instrument added, and the answer stops being a number. TWO OUTCOMES: ONE PRICE Rs 12.162285/- THREE OUTCOMES: A RANGE Rs 4.877058/- Rs 12.162285/- every price in here is permitted 0 2 4 6 8 10 12 14
The single price of Rs 12.162285/- becomes a range from Rs 4.877058/- to Rs 12.162285/- once a third outcome appears, with no new instrument introduced.

Where do the two ends of the range come from?

Both ends are exact, and neither is a coincidence. A range whose ends look like arbitrary numbers reads as a mess. A range whose ends can be derived reads as structure.

Take the top end first. At an up weight of 0.577493 the middle outcome carries a weight of exactly nothing. A weight of nothing on an outcome means the outcome plays no part in any average taken under that measure, so the three outcome model is doing arithmetic identical to the two outcome model, with the same two surviving weights of 0.577493 and 0.422507. A weight of nothing on an outcome is a collapseA model reducing exactly to a simpler one when a weight or a parameter goes to zero.: the larger model becomes the smaller one, not approximately but identically. The collapse is why the top of the range is the two outcome price to the last decimal.

At the top of the range the larger model is doing the smaller model's arithmetic exactly. THREE OUTCOMES, TOP OF THE RANGE up, Rs 122.140276/- 0.577493 middle, Rs 100/- 0.000000 down, Rs 81.873075/- 0.422507 PRICE OF THE PAYOFF Rs 12.162285/- the middle outcome carries no weight, so it takes no part in the average THE TWO OUTCOME MODEL up, Rs 122.140276/- 0.577493 no middle outcome exists absent down, Rs 81.873075/- 0.422507 PRICE OF THE PAYOFF Rs 12.162285/- the same two weights, the same average, the same price The collapse is identical rather than approximate, which is why the top of the range is the complete-market price exactly.
At the top of the range the middle outcome carries no weight, so the three outcome model reproduces the two outcome model exactly and returns the same price.

Now the bottom end, the prettier of the two. At an up weight of 0.231574 the down outcome carries nothing, and the whole weight is shared between the up outcome and the middle one. Work through what the price becomes and the up factor cancels out completely, leaving a quantity with no lattice in it at all.

The bottom of the range, derived rather than observed
$$ V_{\min} \;=\; e^{-rT}\,a_{\min}\,S_0(u-1),\qquad a_{\min}=\frac{e^{rT}-1}{u-1} \;\;\Longrightarrow\;\; V_{\min}=e^{-rT}S_0\bigl(e^{rT}-1\bigr)=S_0\bigl(1-e^{-rT}\bigr) $$
\(V_{\min}\)the bottom of the permitted price range, Rs 4.877058/-
\(a_{\min}\)the smallest permitted weight on the up outcome, 0.231574, at which the down weight is exactly nothing
\(S_0(u-1)\)the payoff at the up outcome, Rs 22.140276/-, being the up value less Rs 100/-
\(1-e^{-rT}\)one less the discount factor, being 1 less 0.951229, which is 0.048771
What it says in wordsAt the bottom of the range the up factor cancels out of the price entirely, leaving today's value multiplied by one less the discount factor, which is Rs 100/- times 0.048771 and so Rs 4.877058/- exactly.

The bottom of the range is Rs 100/- times one less 0.951229, and that identity holds whatever the up factor is. The bottom of the range is therefore a structural fact about the lattice rather than an artefact of these particular numbers. Changing the volatility, and with it the up and down values, moves the top of the range while the bottom stays exactly where it is. The two ends are answering different questions: the top is about the shape of the lattice, and the bottom is only about the rate and the horizon.

Try it out

The price range runs from Rs 4.877058/- to Rs 12.162285/-. Which end is the two outcome price?

What do the two results not promise?

More than most readers expect, and this is where the misuse lives. Taken one at a time, each denial is a direct reading of the two statements themselves, not an extra caveat bolted on.

  1. Neither states what the measure isThe first result says a pricing measure exists. It does not produce one, name one, or narrow the search for one. On a lattice with three nodes it can be solved for by hand. On a model with a continuum of outcomes and several driving factors, finding it is the entire job of work, and the theorem has contributed a licence to look rather than a place to look.
    Existence, not construction.
  2. Neither states whether a given market is completeThe second result says the measure is unique exactly when every payoff can be built. It does not say which side of that equivalence a given market sits on. Deciding whether the instruments span the outcomes is a modelling question for the analyst, and the theorem states only what follows once that question has been answered.
    A link between two conditions, not a test.
  3. Neither picks a price inside the rangeWhen the measure is not unique, no arbitrage rules out everything outside the interval and nothing inside it. Picking a point requires an argument of a different kind entirely, about preferences, about hedging error, about which risks somebody is willing to carry. Both results are silent on all of it.
    The interval is the whole of their output.
  4. Neither says anything about whether a model is any goodThe theorems operate inside whatever model was written down. A model that is arbitrage free and complete can still be a poor description of anything, and the results will price payoffs in it with perfect internal consistency regardless.
    Internal consistency, not external truth.

The everyday version, again from counting. Being told that the drawer contains a matching pair of socks is a statement about the drawer, and it is genuinely useful: it establishes that the search is not hopeless. The statement is not the pair. Someone who reads it as the pair will plan their morning badly. Both results are existence resultsStatements that something exists, carrying no method whatever for finding it., and an existence result is a licence to search rather than the end of the search.

Try it out

The market is incomplete. Which result says which measure to use?

Derivatives Foundation Bootcamp — Fin Maverick Bond Pricing and Yield Mechanics — free micro-course from Fin Maverick

What goes wrong when a theorem is quoted as though it produced something?

The plan built on a promise nobody made

A project is scoped on the strength of a theorem. The reasoning runs: the model has no arbitrage in it, the first result says a pricing measure exists, therefore the pricing part is settled and the effort belongs elsewhere. Every step of that reasoning is true except the word therefore.

The theorem has established only that the search will not be futile. The measure itself remains unestablished, along with the method of finding it, the amount of computation it needs, and whether the answer will be a number or an interval. If the model turns out to be incomplete, and models with more sources of randomness than traded instruments generally are, the honest output was never a price at all. The honest output was a range plus a stated argument for choosing inside it, and that argument is a separate task that nobody scoped.

The cost is not a wrong number. Somebody would catch a wrong number. The cost is a plan whose hardest task was assumed away by a result that never claimed to do it.

What both results hand over, printed in full. WHAT THE RESULTS SUPPLY A pricing measure exists, because there is no arbitrage. It is the only one exactly when every payoff can be built. WHAT IS STILL BLANK the measure itself whether this market is complete A statement that a matching pair is somewhere in the drawer has not handed over the pair. Both lines above the divider are existence claims, and neither constructs a single thing.
Both results supply two statements and leave two blanks, so a plan that treats either statement as a delivered object has skipped the work the blanks represent.
Try it out

The first result says a pricing measure exists. Does it say what it is?

The theorem says a measure exists and hands over none. See what construction adds.

How does someone building a valuation actually use these two results?

As a scoping test, run before any arithmetic and again whenever the model changes. The test takes three questions and about ten minutes, and it decides what the deliverable can honestly be.

  1. Can one set of pricing weights be written down?Not the right one, just one that is positive on every possible outcome and returns today's value on average after discounting. If it can, the first result establishes that the model is arbitrage free, verified by exhibiting an object rather than by checking every trade. If it cannot, the model has an arbitrage in it and every price it produces is meaningless.
    On the three outcome lattice: 0.40, 0.394284, 0.205716, all positive, discounted average Rs 100/-.
  2. Count the outcomes against the instrumentsAs many independent instruments as outcomes and the weights are pinned. One short and they are not. On the two outcome lattice the count is two against two and the answer is Rs 12.162285/-. On the three outcome lattice it is three against two, and no amount of care changes that.
    The count decides the shape of the answer before any arithmetic is done.
  3. Decide what is being delivered before computing itIf the counts balance, the deliverable is a number. If they do not, the deliverable is an interval plus a written argument for the point chosen inside it, and that argument is a separate task with its own effort attached to it.
    Rs 4.877058/- to Rs 12.162285/- is a complete and honest answer. A single number pulled from inside it, without the argument, is not.
Two questions, three worlds, and the deliverable is different in each. THE MEASURE IS UNIQUE THE MEASURE IS NOT UNIQUE A PRICING MEASURE EXISTS One price Rs 12.162285/- two outcomes, two instruments deliverable: a number A range Rs 4.877058/- to Rs 12.162285/- three outcomes, two instruments deliverable: an interval plus an argument NO PRICING MEASURE EXISTS Arbitrage is present, and uniqueness has nothing to be about The first result has failed, so there is no price for the second result to make unique. Deliverable: a corrected model, because nothing computed here would mean anything. The top row is the whole of pricing. The bottom row is a modelling fault, and it is found by trying to build one set of weights and failing. Which of the three applies is settled before any arithmetic, by counting.
Crossing existence against uniqueness gives three worlds, and each one makes a different deliverable the honest answer to a valuation request.

Why are these two results the spine of everything that follows?

Because everything later in this subject is one of these two statements applied to a harder model. The claim is not a figure of speech, and the mapping follows.

Pricing by discounted expectation under a different set of weights is the first result, used leftwards: the measure was constructed, so the model is arbitrage free, so the expectation is a price. The change of measure machinery exists to construct that object, and the theorem is what makes constructing it worth the effort. Every lattice, every partial differential equation, every numerical scheme in this subject is a method for computing an average under weights whose existence the first result licensed.

Every hedging argument is the second result, used rightwards or leftwards depending on which end is in hand. Showing that a payoff can be replicated shows that the price is unique. Showing that two measures both price the model shows that some payoff cannot be replicated. The whole distinction between a market where hedging removes risk and a market where it only reduces it sits in that one equivalence.

And every model that adds a source of randomness without adding an instrument, among them the models for a moving volatility and the models that let a path jump, lands in the same place the three outcome lattice landed: existence intact, uniqueness gone, an interval instead of a point. The three outcome lattice above is the smallest possible working example of every incomplete model that comes later, and it can be computed by hand in under a minute.

Try it out

What do the two results together buy?

One closing observation about the two ends of the range. The top and the bottom are not only the extreme measures. The two ends are also the cheapest cost of a position that always pays at least the payoff, and the dearest value of one that never pays more than it. That second reading of the same two numbers belongs to replication and to incomplete markets, both covered separately.

How the pricing measure is constructed is set out under physical and risk-neutral measures. The detailed comparison of the two kinds of market is set out under complete market versus incomplete market. What any contract pays is covered separately: the payoff was handed over here as two numbers attached to two outcomes, and the argument needed nothing else. The continuous-time versions of both results require the plain phrase no arbitrage to be sharpened, and that sharpening carries the names of Delbaen and Schachermayer and is covered separately. No regulator anywhere sets the content of a theorem, and the mathematics is universal, so no jurisdiction is engaged.

References

SourceDocumentWhere
arXiv Quantitative FinancePreprint repository for the fundamental theorems of asset pricing and their continuous-time versionsarxiv.org
Social Science Research NetworkWorking paper repository for the same material, including treatments of pricing in incomplete marketsssrn.com
Harrison and Kreps, 1979The paper establishing the link between no arbitrage and a pricing measure in a multiperiod securities marketJournal of Economic Theory
Harrison and Pliska, 1981The paper giving both results their martingale formulationStochastic Processes and their Applications
Delbaen and Schachermayer, 1994The paper sharpening no arbitrage so that the first result holds in continuous timeMathematische Annalen
Cox, Ross and Rubinstein, 1979The paper introducing the lattice used for the worked instanceJournal of Financial Economics
Hull, Shreve and WilmottStandard textbook treatments of derivative pricing and stochastic calculustextbooks

The standard process and its parameters are invented.
Educational material. Not advice on any investment, tax, budget or market position.

← PreviousNext →
Fin Maverick Micro CoursesExplore Micro Courses
Fin Maverick BootcampsExplore Bootcamps
Fin Maverick

Finance education that ends in a job, not a certificate that gathers dust. Built for young India.

LEARN
CalculatorsFrameworksComparisonsCareersShowdown
RESOURCES
All CoursesMicro CoursesBootcampsInternships
COMPANY
AboutJob openingPartnership
LEGAL
Privacy PolicyTerms & ConditionsContent LicenseReturn & Refund Policy
© 2026 FIN MAVERICK / BUILT FOR INDIA.DO FINANCE, DO NOT JUST READ ABOUT IT.