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Stochastic Calculus & Derivative Pricing Theory
1Probability Foundations
The Probability SpaceRandom VectorsSigma-AlgebraExpectationSample Space and EventsDensity and Distribution FunctionsRisk-Neutral ProbabilityState Price Density vs…
2Stochastic Processes and Jumps
Properties of a Stochastic ProcessMartingaleBrownian Motion and Its PropertiesBrownian Motion vs Geometric…Stopping TimeThe Markov PropertyState VariablesTransition ProbabilityQuadratic VariationQuadratic Variation vs Ordinary…Submartingale and SupermartingaleMartingale RepresentationMarkov Process vs MartingaleOptional StoppingFiltrationJump ProcessesThe Poisson ProcessLevy ProcessesJump Diffusion
3Ito Calculus
The Ito IntegralThe Ito Integral vs the Riemann IntegralInfinitesimals in Stochastic CalculusQuadratic CovariationIto's LemmaHow to Apply Ito's…The Infinitesimal GeneratorIto Calculus vs Ordinary Calculus
4Stochastic Differential Equations
Stochastic Differential EquationsStochastic Differential Equation vs…Drift and DiffusionStrong and Weak Solutions ComparedDiscretisationGeometric Brownian Motion
5Pricing Theory and No-Arbitrage
No-ArbitrageGirsanov, Radon-Nikodym and Change…Physical and Risk-Neutral Measures…The Fundamental Theorems of…The Law of One PriceThe Pricing KernelDiscount Factors and Zero-Coupon PricesReplication vs HedgingComplete Market vs Incomplete MarketClearing Margin Architecture
6Option Pricing Theory
European and American OptionsMonte Carlo European OptionThe Black-Scholes PDEBlack Scholes and the GreeksThe Payoff FunctionThe Binomial ModelBinomial Option PricingDelta Hedging in TheoryBoundary, Initial and Terminal ConditionsThe Exercise BoundaryHow to Check Put-Call…
7Volatility Models
Constant, Local and Stochastic…Vasicek Model vs CIR ModelThe Heston ModelThe SABR ModelThe Volatility ProcessImplied VolatilityVolatility Smile vs Skew vs Surface
8Interest Rate Models
Interest-Rate DerivativesMean ReversionThe Zero-Coupon BondThe Ornstein-Uhlenbeck ProcessThe Discount CurveZero RatesShort-Rate Model vs Market Model
9Numerical Pricing
Closed Form and Numerical…Monte Carlo PricingEuler and Milstein Schemes ComparedTree MethodsFinite Difference MethodsNumerical Error and StabilityVariance Reduction
10Calibration and Model Risk
Model OverrideMarket Price and Model PriceCalibrationHow to Document a Pricing ModelThe Educational Illustration LabelMarket ConventionsModel Uncertainty and LimitationsBacktesting a Pricing ModelIdentifiabilityCalibrated ParametersThe Calibration Loss Function

Sigma-Algebra: Which Events Are Measurable, and Why It Matters

A sigma-algebra is the collection of subsets that a probability may be attached to. Three properties define it: it holds the whole outcome set, it holds the opposite of everything it holds, and it holds the joining of any listable sequence of its members. Beneath that formal job sits a second one, and it is the one this subject leans on: the collection states what is known.

The three properties are not a matter of taste, and they are not a list somebody chose to be careful. The list is the smallest set of closures that let the word probability behave. If it is possible to ask whether an event happened, it must be possible to ask whether it did not. If it is possible to ask about each of a listable sequence of events, it must be possible to ask whether at least one of them happened. With either closure removed, ordinary reasoning about chance breaks down halfway through a sentence.

The probability space named three objects and opened only the first. The outcome set was settled there. The measure comes later. Between the outcome set and the measure sits the collection, the object that decides which questions the measure will ever be handed. Fixing the collection fixes, in advance and independently of any number, the entire set of questions the model is capable of answering.

What three properties define a sigma-algebra?

Begin with the outcome set. Written with a capital omega, the outcome set lists everything that could happen. Any subset of it is a candidate event. The natural guess is that probability is a rule handing a number to every subset. It is not. A sigma-algebraThe collection of subsets that may be assigned a probability. is a named collection of subsets, and probability is a rule handing a number only to the members of that collection.

Here is the everyday version. A weighing scale on a grain counter reads to the nearest kilogram. Ask it whether the sack is heavier than three kilograms and it answers. Ask it whether the sack is exactly 3.4 kilograms and it has nothing to say. The silence is not shyness about the answer and it is not a small probability. The instrument simply has no such reading, and no amount of staring at the dial produces one. A collection of subsets is an instrument, and its members are the readings it can take.

The three defining properties
$$ \begin{aligned} &\text{(i)}\quad \Omega \in \mathcal{F} \\ &\text{(ii)}\quad A \in \mathcal{F} \;\Longrightarrow\; A^{c} \in \mathcal{F} \\ &\text{(iii)}\quad A_{1}, A_{2}, A_{3}, \ldots \in \mathcal{F} \;\Longrightarrow\; \textstyle\bigcup_{i=1}^{\infty} A_{i} \in \mathcal{F} \end{aligned} $$
\(\Omega\)the outcome set, listing every way the world could turn out
\(\mathcal{F}\)the collection under discussion, the object being defined here
\(A\)one subset of the outcome set, that is, one candidate event
\(A^{c}\)the complement of \(A\), meaning every outcome not in \(A\)
\(\bigcup\)the union, the outcomes lying in at least one of the listed sets
What it says in wordsA collection is a sigma-algebra when it contains the whole outcome set, contains the complement of every set it contains, and contains the union of every endless but listable sequence of sets it contains.
Three properties. Not chosen. Forced by the words not and or. ONE The whole outcome set is a member. There is always something to ask about. TWO if a set A is a member an answerable question: did A happen? then everything outside A is a member too THREE if A1, A2, A3, ... are members a listable sequence of them then the outcomes lying in at least one of them are too Take away the second and asking whether something happened would not entail being able to ask whether it did not. The properties are closures, not preferences.
Each property is a premise forcing a consequence: containing a set forces containing its complement, and containing a listable sequence forces containing the outcomes in at least one of them.

Two useful things follow immediately and cost nothing extra. Because the whole outcome set is a member and complements are members, the empty set is a member too. Because a finite list can be padded out to an endless one by repeating the empty set, closure under a countable unionThe set of outcomes lying in at least one member of an endless but listable collection. already gives closure under a union of two or of ten. Nothing has to be added for the finite case.

Intersection comes free as well, and intersection is the closure most often expected as a fourth property. Intersection is not one. Where complements and unions can be taken, intersections can be taken too. The outcomes lying in every one of the sets are exactly the outcomes not lying outside at least one of them. De Morgan's identity does the work. The collection is closed under and, or and not with only three requirements stated, and that is why the list is three long rather than four or five.

Why and is not a fourth property
$$ \bigcap_{i=1}^{\infty} A_{i} \;=\; \left( \bigcup_{i=1}^{\infty} A_{i}^{\,c} \right)^{c} $$
\(\bigcap\)the intersection, the outcomes lying in every one of the listed sets
\(A_{i}^{\,c}\)the complement of the \(i\)th set in the sequence
What it says in wordsThe outcomes lying in all of a listable sequence of sets are exactly the outcomes not lying in at least one of the complements, an identity due to De Morgan, so closure under intersection follows from the two closures already stated rather than being demanded separately.
Try it out

A collection contains an event but does not contain everything outside that event. Is it a sigma-algebra?

Why can a probability not simply be given to every subset?

On a finite outcome set it can. Take four paths and the power setThe collection of every subset, which is the finest collection there is. has sixteen members, every one of them can carry a number, and the three properties hold without effort. So on any lattice that can be drawn, the question does not bite. The reason the collection is named separately is that the outcome sets that matter are not finite.

A continuous quantity lives on the line. There the demands on an assignment of probability can be written down. First, every subset should get a number. Second, length does not care where anybody stands, so sliding a subset along the line should not change its number. Third, the pieces should add: if a set is cut into a listable sequence of parts that overlap nowhere, the numbers of the parts should sum to the number of the whole, and the unit interval should read one.

The three demands, written out
$$ \begin{aligned} &P\left( \bigcup_{i=1}^{\infty} A_{i} \right) = \sum_{i=1}^{\infty} P(A_{i}) \quad \text{whenever } A_{i} \cap A_{j} = \emptyset \text{ for } i \neq j \\ &P(A + x) = P(A) \quad \text{for every shift } x \\ &P\bigl([0,1]\bigr) = 1 \end{aligned} $$
\(P\)the physical measure, the rule handing a number to a set
\(A_{i}\)pieces that overlap nowhere, listed one after another
\(A + x\)the set \(A\) slid bodily along the line by an amount \(x\)
\([0,1]\)the unit interval, taken as the reference set of size one
What it says in wordsProbability should add over pieces that overlap nowhere, should not change when a set is slid along the line, and should read one on the unit interval, and no rule defined on every single subset of the line manages all three at once.

The closing clause of that summary is a theorem, not a caution. There exists a subset of the line to which no consistent number can be given under those demands, a result due to Vitali in 1905. The collection of allowed subsets exists to exclude that subset, not to encourage general carefulness. Once such a set is known to exist, naming a collection stops looking fussy and starts looking forced, exactly like the three closures above.

Three demands on one assignment. Nothing meets all three. A DEMAND LIST FOR GIVING PROBABILITY TO EVERY SUBSET OF THE LINE 1 Every subset of the line is given a number between zero and one. 2 Sliding a subset along the line leaves its number unchanged. 3 Pieces that overlap nowhere add up, and the unit interval reads one. No assignment satisfies all three. A result due to Vitali, 1905. So the collection of allowed subsets is named separately, and the offending sets are left out of it. Only the existence of such a subset does any work here.
Three natural demands on an assignment of probability to every subset of the line cannot hold together, a result due to Vitali in 1905, and that impossibility is what forces a collection to be named.

The construction of that set picks one representative from each of uncountably many groups at once, and watching it done teaches the construction and nothing new about the collection. Only the existence of such a set does any work. Because one bad subset exists, the collection of allowed subsets has to be part of the model rather than an afterthought about it.

Try it out

Why is the collection restricted at all, rather than simply taking every subset of the outcome set?

What has any of this to do with knowing rather than with size?

Everything after this point in the subject uses a second reading of the same object, and the second reading is not a metaphor laid over the first. The second reading is what the definition already says, read from a different angle. A set is a member of the collection exactly when an observer standing at that point could answer yes or no to the question did this happen. The collection is therefore a list of answerable questions, and a list of answerable questions is a statement about what is known.

Consider a lift in an eight storey building. The indicator reads the floor and nothing else. Asked whether the lift is on the third floor, it answers. Asked whether the lift is on the third floor or the fourth, it answers. One floor or another floor is a union of two readings the indicator already has. Asked whether the lift is in the corner room, it cannot answer, ever, no matter how long the wait. The sets the indicator can resolve are the floors and their unions, and that collection is the exact content of what the indicator knows.

The indicator reads the floor. It cannot read the room. floor 4 floor 3 floor 2 floor 1 dashed walls separate rooms the indicator cannot tell apart WHAT THE INDICATOR READS FLOOR 3 ANSWERABLE is this floor 3? is this floor 3 or floor 4? NOT ANSWERABLE is this the corner room? is this the room facing the road? The readable sets are the floors and their unions. Nothing finer exists to be asked.
An indicator that reads only the floor makes the floors and their unions answerable and leaves every finer question unanswerable, which is exactly how a collection encodes what is known.

A set that belongs to the collection is called measurableBelonging to the collection, so capable of carrying a probability at all. with respect to it. In this subject the collection carried by a moment in time is written as a script F with that time as a subscript, and it is read aloud as the information available at that time rather than as an inventory of sets. Both readings describe the same object. The formal one names what a probability may attach to and the informational one names what somebody standing there could answer.

How does a coarser collection say that less is known?

A coarserContaining fewer sets, so drawing fewer distinctions and representing less knowledge. collection is one with fewer members. Every collection in this subject sits somewhere between the two extremes. At one end sits the collection holding only the empty set and everything, a collection that distinguishes nothing at all. At the other end, on a finite outcome set, sits the power set. The power set distinguishes everything. Coarsening means moving toward the first, and moving toward the first means giving up distinctions.

Here is the part that trips people. Coarsening does not change any answer. Coarsening removes questions. The measure never depended on which other sets happened to be in the collection alongside a given event, so an event that survives the coarsening keeps precisely the number it had. The scale that reads to the nearest kilogram and the scale that reads to the nearest gram agree exactly on whether the sack is over three kilograms. The two scales differ only in what else can be asked.

Same four outcomes. One collection asks less than the other. COARSER: 4 SETS up, then up up, then down down, then up down, then down block A block B ANSWERABLE did the first move go up? answer 0.553908 FINER: 16 SETS up, then up up, then down down, then up down, then down its own set its own set its own set its own set ANSWERABLE did the first move go up? answer 0.553908 and also: did it finish at Rs 100/-? The finer collection adds questions. It does not change the answer to any question the coarser one could already ask.
Moving from a coarser collection to a finer one adds questions that can be asked and leaves the answers to the questions already askable exactly where they were.

The number 0.553908 in that figure is the weight the two step lattice puts on an up move under the risk-neutral measure Q, and 0.446092 is the weight it puts on a down move. Both follow from the four locked parameters rather than from any reading of a market. The same answer appears on both sides of the coarsening, and neither side of the figure has more or less probability in it than the other. One side simply has fewer questions.

Try it out

A coarser collection is adopted. Does an event that was already a member of both collections get a different probability?

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What do the three properties look like on four paths?

Everything above becomes countable on a small lattice. Take the standard process, an invented two step model that starts at Rs 100/-, and let it move twice over one year. The two step lattice locked for this subject multiplies by 1.151910 on an up move and by 0.868123 on a down move, and those two factors are exact reciprocals, so an up followed by a down returns to precisely where it started. Four paths result, and the outcome set has four members.

PathAfter the first moveAt the horizonWritten as
up, then upRs 115.19/-Rs 132.69/-the first path
up, then downRs 115.19/-Rs 100.00/-the second path
down, then upRs 86.81/-Rs 100.00/-the third path
down, then downRs 86.81/-Rs 75.36/-the fourth path

Counting the collection at three moments makes this concrete. Before anything happens, the outcome set has not been divided at all, so the only members are the empty set and all four paths together: two sets. After the first move the two paths that began up can be told from the two that began down. The split leaves the outcome set in two pieces, and the collection has four members. After both moves every path is distinguishable, and the collection is the whole power set of four paths: sixteen members.

Counting the collection on a partition
$$ |\mathcal{F}| \;=\; 2^{k} $$
\(|\mathcal{F}|\)the number of sets in the collection
\(k\)the number of pieces in the split of the outcome set the collection is built on
\(\mathcal{F}_{t}\)the collection carried at time \(t\), read as the information available then
What it says in wordsA collection built on a split of the outcome set into pieces that overlap nowhere and cover everything holds exactly two to the power of the number of pieces. A member is precisely a choice of which pieces to include, and on the four path lattice that gives two, then four, then sixteen.
Four paths, and the collection grows as the moves resolve. BEFORE AFTER ONE MOVE AFTER BOTH Rs 100/- Rs 115.19/- Rs 86.81/- up, then up Rs 132.69/- up, then down Rs 100.00/- down, then up Rs 100.00/- down, then down Rs 75.36/- The two marked in light green both finish at Rs 100/-, one from each branch, and that pair is the event this guide turns on. 2 sets one piece 4 sets two pieces 16 sets four pieces
On the four path lattice the collection holds two sets before anything happens, four after one move and sixteen after both, and the growing count is the growing knowledge.

The event that the process finishes at exactly Rs 100/- holds on the second path and on the third path, one path from each of the two halfway pieces. The event is therefore not a union of those pieces, so it is one of the sixteen and not one of the four. Halfway through, that event cannot be given a probability, and the reason is not that the chance is small but that the collection at that moment cannot express the set at all.

Try it out

Working with the halfway collection, can a probability be assigned to the event that the process finishes at exactly Rs 100/-?

Try it out

Four paths. Before the control below is moved, how many sets can be assigned a probability at the halfway stage, when only the first move is known?

Play with it

Watch the paths group, and count what can be asked

One control, three positions. Nothing about likelihood moves. The control changes which questions exist rather than which answers they get. Before anything happens the four paths form one piece and the collection holds 2 sets. After the first move they form two pairs, up first and down first, and the collection holds 4 sets. After both moves they form four pieces and the collection holds 16 sets. At the halfway stage the event of finishing at Rs 100/- takes one path from each pair, so it is not among the 4.

before anything happensafter the first moveafter both moves
Pieces in the split
2
Sets that can be assigned a probability
4
Finishing at Rs 100/- is
not expressible

After the first move the four paths fall into two pieces, so the collection holds 4 sets, and the event of finishing at exactly Rs 100/- is not one of them.

Educational illustration. Four paths only, on the two step lattice locked for this subject, with up factor 1.151910 and down factor 0.868123 from a start of Rs 100/-. Every count on screen is produced by listing the sets and counting them, never by sampling, so the reading is identical on every reload. The control is about what can be asked rather than about what is probable.
Try it out

A quantity takes only two different values across the whole outcome set. How many sets are in the collection it generates?

What is the collection generated by a quantity?

Most collections in practice are not written down set by set. A collection arrives attached to a quantity: somebody says the only thing observed is the reading of this instrument, and the collection follows from that. The generated collectionThe smallest collection in which a stated quantity can be read. is built by a procedure with a stopping rule, and both the procedure and the stopping rule matter.

The collection generated by a quantity
$$ \sigma(X) \;=\; \bigl\{\, X^{-1}(B) \;:\; B \in \mathcal{B}(\mathbb{R}) \,\bigr\}, \qquad X^{-1}(B) \;=\; \{\, \omega \in \Omega \;:\; X(\omega) \in B \,\} $$
\(X\)a quantity read off an outcome, here a general one rather than the standard process
\(\omega\)one outcome, one member of the outcome set
\(B\)a range of values on the line, such as an interval
\(\mathcal{B}(\mathbb{R})\)the Borel collection, the smallest one on the line holding every interval, named for Borel
\(X^{-1}(B)\)the outcomes whose reading lands inside \(B\)
What it says in wordsThe collection generated by a quantity is every set of outcomes that can be picked out by asking whether that quantity lands inside some range of values, and it is the smallest collection with the three properties in which the quantity can be read.
Generating a collection is a procedure, and it has a stopping rule. STEP ONE List the values the quantity takes across the outcomes. STEP TWO For each range of values, gather the outcomes landing in it. STEP THREE Close that list under the three properties: whole, not, or. STEP FOUR Stop. Nothing further is added. Smallest, not largest. The result is the smallest collection in which that quantity can be read. Anything more would be knowledge the quantity does not actually carry.
The collection generated by a quantity is built by taking every set the quantity can separate and then adding only what the three closure properties force, and nothing beyond that.

The stopping rule is where the meaning sits. Taking the smallest collection is what makes the phrase this is all that is observed precise. Any larger collection would credit the observer with distinctions the instrument never made, and a model built on it would answer questions the observer had no business answering. The word smallest in that definition is not tidiness, it is the honesty condition of the whole apparatus.

Two different quantities can generate the very same collection, and the four path lattice shows it plainly. Take the event that the process finishes above Rs 100/-, the region where the at-the-money contract at Rs 100/- would be in the money, and the event that it finishes above Rs 110/-, the region where the out-of-the-money contract at Rs 110/- would be. On this lattice the terminal values are Rs 132.69/-, Rs 100.00/-, Rs 100.00/- and Rs 75.36/-, so both events pick out the first path and only the first path. Two different contracts, identical generated collections of four sets each, and therefore identical information. The lattice is simply too coarse to tell the two apart.

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Why does any of this change what can be said about a price?

One consequence pays for all of this. The collection is fixed before any probability is named, and it does not move when the probability changes. The physical measure P and the risk-neutral measure Q sit on the same four paths and on the same sixteen sets. Swapping one for the other changes every number and changes not one membership. A change of measure alters the answers; only a change of collection alters the questions.

So when somebody reports a number about a price, there are two separate things to check and they fail in different ways. The first is whether the arithmetic is right under the measure being used. The second check comes first in logic and is skipped far more often. Ask whether the event being priced is even a member of the collection the information supports. A number can survive the first check perfectly and fail the second completely.

Halfway through. One question has no answer here; one does. CANNOT BE POSED HALFWAY What is the chance of finishing at exactly Rs 100/-? The event takes one path from each block, so the halfway collection cannot express it. Not unlikely. Not small. There is no number to give. CAN BE POSED HALFWAY Given which way the first move went, what is the chance of finishing at exactly Rs 100/-? first move up 0.446092 first move down 0.553908 One number for each block is exactly what the halfway collection can carry. The useful reply is not silence. It is naming the question that fits the information.
A question that cuts across the halfway blocks has no answer at that stage, while the same question asked separately within each block has one number per block and is perfectly well posed.

The two numbers in that figure are the weights the locked two step lattice puts on the remaining move under the risk-neutral measure Q, one weight for each halfway block. Their shape matters rather than their size. One value per block is the most detailed thing the halfway collection can hold, and offering that pair is a complete and honest reply where a single number would have been a fabrication.

Try it out

Somebody asks for the probability that the process finishes at exactly Rs 100/-, using only what is known halfway. What is the honest reply?

Try it out

The physical measure P is swapped for the risk-neutral measure Q on the same four paths. How many sets can now be assigned a probability at the end?

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Who reaches for this, and what do they actually do with it?

The arithmetic is the part a machine already got right, so somebody reviewing a model does not usually check it first. A reviewer checks the pairing between a reported quantity and the information it claims to rest on. The question they ask, in whatever words their team uses, is which collection this number was computed against, and whether that collection is the one the situation actually supplies.

The check has a clean shape and applies to anything. The outcome set is named. The moment at which the number is supposed to be known is named. The split of the outcome set into pieces that could be told apart is then written down. The question is then whether the event at issue is a union of those pieces. If it is, the number is a statement about that moment. If it is not, the number belongs to some other, finer collection and has been quietly relabelled.

The reason this check is worth its minute is that nothing else will ever flag the failure. A quantity attached to the wrong collection is not out of range, does not break a constraint, does not produce an error and does not look odd. A misattached quantity looks like a number and is read like a number while behaving like an assumption. The same discipline lets somebody say honestly that a question is not answerable yet. Such a sentence is far more useful than a confident figure with nothing underneath it.

A valid number, attached to a collection that cannot hold it. REPORTED AS KNOWN AT THE HALFWAY STAGE Chance of finishing at exactly Rs 100/- 0.494188 no line of the arithmetic behind it is wrong That event is not in the halfway collection. The number belongs to a finer one. THE FOUR PATHS, SPLIT AS THE HALFWAY COLLECTION SPLITS THEM up, then up up, then down down, then up down, then down The shaded pair is the event. The dashed line is the only split the halfway collection can see, and the event straddles it.
A number computed on the finer collection and reported as a halfway stage figure describes an event that straddles the only split the halfway collection can see.

The error that gets made, and what it costs

Assuming that anything describable in a clear sentence is an event that can be priced. Finishing at exactly Rs 100/- is plain English, it names a definite set of paths, and at the halfway stage it carries no probability at all. The collection is fixed by what is known, and a perfectly clear description can sit outside it.

The figure 0.494188 above is not a mistake in itself. The figure is correct on the collection that separates all four paths, and every step producing it is valid. The error is the label. Reported as something known halfway, it attaches a quantity to information that could not support it, and from that moment it reads as a number while behaving as an assumption.

The cost is that nothing downstream ever catches it. No step of the arithmetic was wrong at any point, so there is no failed check, no range violation and no warning. The mistake was made before the arithmetic began, in deciding which collection the question belonged to, and that decision leaves no trace in the output.

How the collection grows through time as a nested sequence is set out under filtration. The construction of the set that carries no consistent probability is a separate matter. Expectation taken against a collection is the general machinery behind the one number per block reply above, and is set out under expectation. No jurisdiction sets a probability axiom, so the mathematics here holds everywhere and no conduct rule qualifies it.
A reviewer asks which collection the number rests on. See what the algebra fixes.

References

SourceDocumentWhere
arXiv, Quantitative FinancePreprints on measure-theoretic probability in derivative pricingarxiv.org
Social Science Research NetworkWorking papers on probability foundations for pricing theoryssrn.com
Giuseppe Vitali, 1905Sul problema della misura dei gruppi di punti di una retta, the construction of a subset of the line that carries no consistent measureGamberini e Parmeggiani, Bologna
Steven E. ShreveStochastic Calculus for Finance II: Continuous-Time Models, the treatment of a collection as the information available at a momentSpringer

The standard process and the two step lattice are invented.
Educational material. Not advice on any investment, tax, budget or market position.

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